I want to create a new site in Alfresco through the REST API first i tried with the url /alfresco/service/api/sites the site was created but i could not open it. I read the method description and it says
Note: this method only creates a site at the repository level, it
does not create a fully functional site. It should be considered for
internal use only at the moment. Currently, creating a site
programmatically needs to be done in the Share context, using the
create-site module. Further information can be found at the address
http://your_domain:8080/share/page/index/uri/modules/create-site.post
within your Alfresco installation.
I tried to go to the suggested url but it gives 404 !
Any help or suggestions ?
Note - the links/references in this answer all assume you've got the Alfresco Share application installed and available at http://localhost:8081/share/ - tweak as needed for your machine
When wanting to understand or discover webscripts, the first place you want to head to is http://localhost:8081/share/service/index - the Share WebScripts home. (The Alfresco repo tier has an equivalent one too, available at a similar URL).
When there, you'll see all of the Share-side WebScripts listed, of which there are a lot. You could search through that list for create-site. However, you can restrict the webscript listing by URL or by module. For the Create Site webscripts, the URL to see just those is http://localhost:8081/share/page/index/uri/modules/create-site
Head there, and you'll discover there are two create site related webscripts, a get and a post. As you've discovered already, the one you'll want is the POST webscript. Click on that to get the details, at http://localhost:8081/share/page/script/org/alfresco/modules/create-site.post - that's the latest (Alfresco 5.x) URL for the thing you've been directed to in your question. If your Share installation is at a different URL, then once you've navigated from the Share webscripts home, you'll get the specific one for your machine
Finally, you'd need to post the required JSON to that webscript's URI, which is given in the webscript listing, eg http://localhost:8081/share/page/modules/create-site . Easiest way to see exactly what JSON you need is to use firebug / developer tools / etc to see the handful of keys/values that Share sends when you create one through the UI.
Related
I've recently been working on an enhancement for an application at work that will allow users to delete presentations stored not on their local machine but on a Linux server present on the internal network. My problem is that I am not sure how to go about performing this delete. The location of the files are as follows:
http://ipaddress/dataconf/productusers/**ACCOUNT**/presentations/
I have access to the ACCOUNT name which is a parameter that will need to be passed in to navigate to the right directory. I will also have access to the presentation name which will be needed to specify the correct presentation to delete.
What I am having trouble with is where to begin.
I am using the Spring framework so my code is a mixture of Java, JSP, and JavaScript.
Essentially I have a .jsp page where I layout the presentations that are associated with each account. I.E when you click on an account it makes a call to a database and lists the presentations that are associated with that account. You can then select individual accounts and delete, or press one delete all button and delete them all.
I currently have it working so that when you delete a presentation in my application, it deletes the appropriate record from the database, but I also need to delete the physical presentation which is the basis for this question. Just as an FYI, these requests (get presentations from database, remove presentations from database) are all being handled through AJAX and JSON.
I am hoping to learn how to create a connection to the correct server, navigate to the proper directory as specified above, and issue the Linux command "sudo rm file-name" all in the same delete process that I described in the prior paragraph.
If you could point me in the right direction, any help would be much appreciated. Also, if you need any further clarification please feel free to let me know.
Thanks again,
Dave
This will not be easy. Or maybe it will. Please understand first that simply knowing where some files are published on an HTTP server is basically useless in terms of manipulating those files.
So I understand the following: You have your own web application on server A, a database somewhere, and some files located on another web server B. Internally on server B, the files will be in some weird directory e.g. /var/www/docs/whoknowswhat/somefolder/dataconf/productusers.
What you need to do is to somehow expose this folder from within server B over the network to your server A. Talk to your admin people. Maybe NFS is an option, or maybe Samba, or SSHFS. Make sure you have write permissions, and also make sure that noone else does.
Once you have mounted the location from B in your server A and it is available to you as some directory /mnt/serverB/productusers, then all you have to do is something like this, i.e. File f = ...; f.delete();
I did a little research and stumbled upon a neat solution to accomplish what I am trying to do. If you take a look at the following link:
http://www.journaldev.com/246/java-program-to-run-shell-commands-on-ssh-enabled-system
The above site describes a method in which you can open an ssh connection in Java and execute commands as if you were running them from the terminal. It has come in handy for my problem and I hope that if anyone else is experiencing the same problem that this will help them as well. Feel free to let me know what you think.
Before asking my question (which is basically what the title says) I want to provide some background, so as to give a better knowledge about my situation.
I am writing a little application in Java, mainly for academic purposes, but also with a very specific task in mind. What this application does is basically build an URL hierarchy starting from a base URL, and later on give the ability to organize the links and perform some actions on them.
Imagine the following URLs:
http://www.example.com
http://www.example.com/sub001
http://www.example.com/sub002
http://www.example.com/sub002/ultrasub
I would like my program to retrieve this hierarchy when provided with the base URL http://www.example.com (or http://www.example.com/).
In my code I have a class capable of encoding URLs and I have already thought of a way to validate them, I just couldn't find a way to find out the URL hierarchy beneath the base URL.
Is there a direct way of doing it, or do I just have to download the files from the base URL and start building the hierarchy from the relative and absolute links present in the file?
I am not asking for specific code, just a (somewhat) complete explanation of what way I could take to do it, with maybe some skeleton code to guide me.
Also, I am storing the URLs in a TreeMap<URL,Boolean> structure, in which the Boolean states if the URL has already been analyzed or not. I chose this structure after a quick peek in the Java 7 API specification, but do you suggest any structure that's better for this specific purpose?
Thanks in advance :)
There is no way in the HTTP protocol to request all the URL's that are 'under' a given URL. You are out of luck.
Some protocols (ftp://... for example) do have explicit mechanisms.....
Some HTTP Servers will print an index page if you request a 'directory' but this practice is not recommended and not many servers will do that.
Bottom line is that you have to follow links in order to determine what the server hierarchy is, and even then you may not discover a link to all the areas of the hierarchy.
EDIT: I should add that you should, as a well-behaved nettizen, obey the robots.txt file on any servers you access....
EDIT2: (after comment on FTP mechanism)
The FTP protocol has many commands: See this wiki list. One of the commands is: NLIST which "Returns a list of file names in a specified directory."
The URL specification makes special provision in the URL format for FTP protocol URL's, and in section 3.2.2 :
The url-path of a FTP URL has the following syntax:
<cwd1>/<cwd2>/.../<cwdN>/<name>;type=<typecode>
....
If the typecode is "d", perform a NLST (name list) command with as the argument, and interpret the results as a file directory listing.
I can see the effects when I try this from the commandline (not from a browser):
rolf#home ~ $ curl 'ftp://sunsite.unc.edu/README'
Welcome to ftp.ibiblio.org, the public ftp server of ibiblio.org. We
hope you find what you're looking for.
If you have any problems or questions, please see
http://www.ibiblio.org/help/
Thanks!
and type=d I get:
rolfl#home ~ $ curl 'ftp://sunsite.unc.edu/README;type=d'
HEADER.images
incoming
HEADER.html
pub
unc
README
I have created a subpackage of views in order to customize the default look of securesocial's templates. (I have used https://github.com/ngarera/securesocial-custom-views-sample as an example and basically copied the relevant files)
There are two i18n-files (messages.en, messages.de) in my /conf folder.
Viewing the main page confirms that the messages.en is correctly used.
However, when calling /login (and therefore displaying the custom template), no messages-key is correctly looked up - instead only the key itself (e.g. "auth.login") is displayed, when really it should show "Login".
I have seen a similar request at Stackoverflow (How to change text in SecureSocial) where it was stated to remove the .en file extension. Doing that will show the correct Message...but creating one messages file is not really the point of internationalization...
I have confirmed that my browser sends the correct language (http://www.mybrowserinfo.com/detail.asp?bhcp=1) so messages.de should work...(which it does when I open a self-made controller - only the custom-securesocial-view is not working...)
Does anybody have similar problems?
And why does the localization work for securesocial's messages?
Regards,
David
PS: using Play 2.1.3, Java
There were some issues in the SecureSocial code that prevented i18n from working properly.
This has been fixed and is currently available in the master-SNAPSHOT version because a stable version with those changes has not been released yet.
I've been having tremendous problems with connecting my android app to the youtube API. Firstly I tried to go along the route of using the native youtube gdata java client(http://code.google.com/p/gdata-java-client/). I had read that this could then be integrated into an android app easily enough and so I set about doing that but I would stumble every time at the line
YouTubeService ytservice = new YouTubeService("AppName",Dev_Key);
I'd enter the correct details here, even have all the necessary external jars but every time I would be given a NoClassDefFoundError reporting that YouTubeService could not be found and neither could it's superclass, MediaService. (Just so you know, I had gdata-youtube-2.0.jar, gdata-client-1.0.jar, gdata-media-1.0.jar, guava.11.0.2.jar and jsr305.jar)
So then I tried which appeared to support android (http://code.google.com/p/google-api-java-client/wiki/Android). There was even a sample example where google tasks had been integrated so it looked promising. It didn't have an actual YouTube class like it did have a taskService but it did support OAuth 2.0 login which I could work with by just sending off URL requests to the youtube API with OAuth 2.0 authentication. I tried this but when the only key I could get from it in combination with android's AccountManager was an auth key token. Posting this with the URL request to google resulted in an 'authentication required' response from youtube(because i was providing an incorrect access token, it was at least twice the size of a working access token i was comparing it with).
How can I find the access token that I need for the youtube API from the AccountManager? Or even better, how can I get the YouTubeservice to work?
Thanks
rory
Edit
Amad, thanks for the answer but unfortunately that is what i am already doing:
(source: themobilelook.com)
maybe it'll help if i supply my project folder: here it's a barebones setup, literally just to test if the YouTubeService works.
using adt 20, jdk compliance level 1.6
if you manage to create a working version then itnwoild be great if you could share it
The YouTube API library/libraries must be included in the project. By going to the Project Properties > Build Path > Order and Export tab, you can tick the checkbox next to the all YouTube-API-related libraries to ensure that they will be included in the project when you export it. Make sure to clean and rebuild after doing this.
As for the access token... not totally sure. The documentation may help there. This Google Groups thread may help also.
If you get NoClassDefFoundError during Runtime, then I suspect you did not include them to work at runtime. You have to check the checkbox for each .jar like this:
(Of course you have to add them to your java build path first)
I am trying to download the contents of a site. The site is a magneto site where one can filter results by selecting properties on the sidebar. See zennioptical.com for a good example.
I am trying to download the contents of a site. So if we are using zennioptical.com as an example i need to download all the rectangular glasses. Or all the plastic etc..
So how do is send a request to the server to display only the rectangular frames etc?
Thanks so much
You basic answer is you need to do a HTTP GET request with the correct query params. Not totally sure how you are trying to do this based on your question, so here are two options.
If you are trying to do this from javascript you can look at this question. It has a bunch of answers that show how to perform AJAX GETs with the built in XMLHttpRequest or with jQuery.
If you are trying to download the page from a java application, this really doesn't involve AJAX at all. You'll still need to do a GET request but now you can look at this other question for some ideas.
Whether you are using javascript or java, the hard part is going to be figuring out the right URLs to query. If you are trying to scrape someone else's site you will have to see what URLs your browser is requesting when you filter the results. One of the easiest ways to see that info is in Firefox with the Web Console found at Tools->Web Developer->Web Console. You could also download something like Wireshark which is a good tool to have around, but probably overkill for what you need.
EDIT
For example, when I clicked the "rectangle frames" option at zenni optical, this is the query that fired off in the Web Console:
[16:34:06.976] GET http://www.zennioptical.com/?prescription_type=single&frm_shape%5B%5D=724&nav_cat_id=2&isAjax=true&makeAjaxSearch=true [HTTP/1.1 200 OK 2328ms]
You'll have to do a sufficient number of these to figure out how to generate the URLs to get the results you want.
DISCLAIMER
If you are downloading someone's else data, it would be best to check with them first. The owner of the server may not appreciate what they might consider stealing their data/work. And then depending on how you use the data you pull down, you could be venturing into all sorts of ethical issues... Then again, if you are downloading from your own site, go for it.