I am getting the exception o.h.e.j.s.SqlExceptionHelper | Bad value for type int : 9dac4fd2-a04c-4be7-976b-d880a43ea25a. It seems to want to put a UUID in an Integer field here.
I have the following tables, which admittedly are a bit complex in terms of compound keys:
CREATE TABLE public.event (
id uuid NOT NULL,
...
CONSTRAINT event_pkey PRIMARY KEY (id)
);
CREATE TABLE public.condition_set (
api_id uuid NOT NULL,
version integer NOT NULL,
...,
CONSTRAINT condition_set_pkey PRIMARY KEY (api_id, version)
);
CREATE TABLE public.condition_set_event (
condition_set_api_id uuid NOT NULL,
condition_set_version integer NOT NULL,
event_id uuid NOT NULL,
CONSTRAINT condition_set_event_pkey PRIMARY KEY (condition_set_api_id, condition_set_version, event_id),
CONSTRAINT fk_condition_set FOREIGN KEY (condition_set_api_id, condition_set_version) REFERENCES public.condition_set(api_id, version) ON DELETE CASCADE,
CONSTRAINT fk_event FOREIGN KEY (event_id) REFERENCES public.event(id) ON DELETE CASCADE
);
In my model I have the Event class which is fairly straightforward. The ConditionSet class has a compound primary key matching the database structure, as follows:
#Entity
public class ConditionSet {
#EmbeddedId
private ConditionSetId id;
}
which looks like:
#Embeddable
public class ConditionSetId implements Serializable {
private static final long serialVersionUID = 8110138933878596476L;
private UUID apiId;
private Integer version;
}
The tricky part is the ConditionSetEvent junction table which ALSO consists of a compound key, of which one is the compound key of ConditionSet
#Entity
public class ConditionSetEvent {
#EmbeddedId
private ConditionSetEventId id;
#ManyToOne(fetch = FetchType.LAZY)
#OnDelete(action = OnDeleteAction.CASCADE)
#MapsId("conditionSetId")
#JoinColumns(foreignKey = #ForeignKey(name = "fk_condition_set"), value = {
#JoinColumn(nullable = false, name = "conditionSetApiId"),
#JoinColumn(nullable = false, name = "conditionSetVersion")
})
private ConditionSet conditionSet;
#ManyToOne(fetch = FetchType.LAZY)
#OnDelete(action = OnDeleteAction.CASCADE)
#MapsId("eventId")
#JoinColumn(foreignKey = #ForeignKey(name = "fk_event"))
private Event event;
public ConditionSetEvent(ConditionSet conditionSet, Event event) {
this.conditionSet = conditionSet;
this.event = event;
this.id = new ConditionSetEventId(conditionSet.getId(), event.getId());
}
}
with its EmbeddedId:
#Embeddable
public class ConditionSetEventId implements Serializable {
private static final long serialVersionUID = -6269791751266804667L;
private ConditionSetId conditionSetId;
private UUID eventId;
}
However, if I try to query this junction table with this repository method:
public interface ConditionSetEventRepository extends JpaRepository<ConditionSetEvent, ConditionSetEventId> {
#Query("select cse from ConditionSetEvent cse where cse.id.eventId = :eventId")
List<ConditionSetEvent> findByEventId(UUID eventId);
}
then I get the error as mentioned on top (where the uuid in the exception is a valid ConditionSet.apiId, but that somehow seems to be re-used.
With trace logging:
DEBUG | org.hibernate.SQL | select conditions0_.condition_set_api_id as conditio0_8_, conditions0_.event_id as event_id1_8_, conditions0_.condition_set_api_id as conditio2_8_, conditions0_.condition_set_version as conditio3_8_ from condition_set_event conditions0_ where conditions0_.event_id=?
TRACE | o.h.t.d.sql.BasicBinder | binding parameter [1] as [OTHER] - [be1ec45d-6533-4e77-98b7-f9a357cda052]
TRACE | o.h.t.d.s.BasicExtractor | extracted value ([conditio0_8_] : [OTHER]) - [9dac4fd2-a04c-4be7-976b-d880a43ea25a]
WARN | o.h.e.j.s.SqlExceptionHelper | SQL Error: 0, SQLState: 22003
ERROR | o.h.e.j.s.SqlExceptionHelper | Bad value for type int : 9dac4fd2-a04c-4be7-976b-d880a43ea25a
So it does manage to extract that UUID value initially (the last trace line), but on the next step (for the Integer) it still is trying to use the UUID instead of the Integer.
Am I doing something wrong here?
I don't think you need the #JoinColumns and it is messing up which id column maps to which id field in ConditionSetEventId
#Entity
public class ConditionSetEvent {
#EmbeddedId
private ConditionSetEventId id;
#ManyToOne(fetch = FetchType.LAZY)
#OnDelete(action = OnDeleteAction.CASCADE)
#MapsId("conditionSetId")
private ConditionSet conditionSet;
....
I have been trying to map some "OneToOne" relationships between two users via an intermediate class called Guardian. When i try to retrieve a user (and his guardians) i get an internal server error in return from Glassfish (Open edition v4.0). There is however no stack trace of any kind or any error displayed in the logs. I suspect that the issue is my mapping within the JPA classes.
Starting the server i get two warnings related to the Guardian class which I don't really understand:
WARNING: The reference column name [GUARDIAN] mapped on the element [method getGuardianUserBean] does not correspond to a valid id or basic field/column on the mapping reference. Will use referenced column name as provided.
WARNING: The reference column name [OWNER] mapped on the element [method getOwnerUserBean] does not correspond to a valid id or basic field/column on the mapping reference. Will use referenced column name as provided.
SQL create statements:
create table HOMEFREE."user" (
userid integer GENERATED ALWAYS AS IDENTITY,
name varchar(255) not null,
displayname varchar(255) unique not null,
password varchar(255) not null,
tlf integer,
facebookID varchar(255),
googleid varchar(255),
authtoken varchar(255),
email varchar(255) unique not null,
primary key(userid)
);
create table HOMEFREE."guardian" (
guardianId integer GENERATED ALWAYS AS IDENTITY,
owner integer not null,
guardian integer not null,
confirmed boolean not null,
primary key(guardianId),
foreign key(owner) references homeFree."user"(userid),
foreign key(guardian) references homeFree."user"(userid)
);
Relevant fields/annotations in entity classes:
#Entity
#Table(name = "\"user\"", schema = "HOMEFREE")
public class User implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int userId;
#OneToMany(mappedBy = "ownerUserBean", fetch = FetchType.EAGER)
private List<Guardian> guardians;
}
#Entity
#Table(name="\"guardian\"", schema="HOMEFREE")
public class Guardian implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int guardianId;
#OneToOne
#PrimaryKeyJoinColumn(name="OWNER", referencedColumnName="USERID")
private User ownerUserBean;
#OneToOne
#PrimaryKeyJoinColumn(name="GUARDIAN", referencedColumnName="USERID")
private User guardianUserBean;
private boolean confirmed;
}
Try using #JoinColumn instead of #PrimaryKeyJoinColumn.
#OneToOne
#JoinColumn(name="OWNER", referencedColumnName="USERID")
private User ownerUserBean;
#OneToOne
#JoinColumn(name="GUARDIAN", referencedColumnName="USERID")
private User guardianUserBean;
According to spec the latter should be used to join the primary table of an entity subclass in the JOINED mapping strategy to the primary table of its superclass (exact definition available here)
I have a simple model in Play Framework 2, and I would like to specify a default value to be inserted on a specify INT column if none is provided when the INSERT is performed.
Model:
#Entity
#Table(name = "DashboardOptions", schema = "dbo")
public class DashboardOptions extends Model implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "id")
public Long id;
#Basic(optional = false)
#Column(name = "userId")
public Long userId;
#Column(name = "chartType")
public String chartType;
public String name;
public Integer size = 2;
I'd like to have the size column populate with 2 by default, however, if I specify the default value as above, my database evolution does not reflect this:
create table dbo.DashboardOptions (
id numeric(19) identity(1,1) not null,
userId numeric(19) not null,
chartType varchar(255),
name varchar(255),
size integer,
constraint pk_DashboardOptions primary key (id))
;
What I would expect to see is this:
create table dbo.DashboardOptions (
id numeric(19) identity(1,1) not null,
userId numeric(19) not null,
chartType varchar(255),
name varchar(255),
size integer default 2,
constraint pk_DashboardOptions primary key (id))
;
Use own columnDefinition like this:
#Column(columnDefinition = "integer default 2")
public Integer size = 2;
Another option is to use #PrePersist tag package javax.persistence. you can have a method decorated in your bean with #PrePersist and that method is called before Ebean.save call. so in this case the following code would set the default value of size to 2.
#PrePersist
protected void onCreate {
if (this.size == null)
this.size = 2;
}
This approach is applicable only within the context of ORM (Ebean) and obviously wouldn't work directly with SQL. The advantage of this method is that this is more database neutral in the sense that integer default 2 might not be a valid column definition string in some unknown strange RDBMS systems.
I have a domain class name DataList
#Entity
#Table(name = "list_data")
public class ListData {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private int id;
#Column(name = "sys_id")
private String sysId;
#Column(name = "name")
private String name;
#Column(name = "detail")
private String detail;
#Column(name = "values")
private String values;
//getters and setters
}
I have some others domain class..
I'm using hibernate 3.6 everything alright.
but somehow Im unsuccessful while creating this table.
2012-02-25 03:31:52,166 ERROR SchemaExport:274 Unsuccessful: create table list_data (id >integer not null auto_increment, detail varchar(255), name varchar(255), sys_id varchar(255), >values varchar(255), primary key (id))
2012-02-25 03:31:52,167 ERROR SchemaExport:275 You have an error in your SQL syntax; check the >manual that corresponds to your MySQL server version for the right syntax to use near 'values >varchar(255), primary key (id))' at line 1
I know my hibernate configuration is fine, I have some other domain class, they are working just fine.
I think that you cannot use values as a column name since it is a MySQL keyword (INSERT INTO ... VALUES() ).
I'm facing what I think is a simple problem with Hibernate, but can't solve it (Hibernate forums being unreachable certainly doesn't help).
I have a simple class I'd like to persist, but keep getting:
SEVERE: Field 'id' doesn't have a default value
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [hibtest.model.Mensagem]
at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103)
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91)
[ a bunch more ]
Caused by: java.sql.SQLException: Field 'id' doesn't have a default value
[ a bunch more ]
The relevant code for the persisted class is:
package hibtest.model;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Inheritance;
import javax.persistence.InheritanceType;
#Entity
#Inheritance(strategy = InheritanceType.JOINED)
public class Mensagem {
protected Long id;
protected Mensagem() { }
#Id
#GeneratedValue
public Long getId() {
return id;
}
public Mensagem setId(Long id) {
this.id = id;
return this;
}
}
And the actual running code is just plain:
SessionFactory factory = new AnnotationConfiguration()
.configure()
.buildSessionFactory();
{
Session session = factory.openSession();
Transaction tx = session.beginTransaction();
Mensagem msg = new Mensagem("YARR!");
session.save(msg);
tx.commit();
session.close();
}
I tried some "strategies" within the GeneratedValue annotation but it just doesn't seem to work. Initializing id doesn't help either! (eg Long id = 20L).
Could anyone shed some light?
EDIT 2: confirmed: messing with#GeneratedValue(strategy = GenerationType.XXX) doesn't solve it
SOLVED: recreating the database solved the problem
Sometimes changes made to the model or to the ORM may not reflect accurately on the database even after an execution of SchemaUpdate.
If the error actually seems to lack a sensible explanation, try recreating the database (or at least creating a new one) and scaffolding it with SchemaExport.
If you want MySQL to automatically produce primary keys then you have to tell it when creating the table. You don't have to do this in Oracle.
On the Primary Key you have to include AUTO_INCREMENT. See the example below.
CREATE TABLE `supplier`
(
`ID` int(11) NOT NULL **AUTO_INCREMENT**,
`FIRSTNAME` varchar(60) NOT NULL,
`SECONDNAME` varchar(100) NOT NULL,
`PROPERTYNUM` varchar(50) DEFAULT NULL,
`STREETNAME` varchar(50) DEFAULT NULL,
`CITY` varchar(50) DEFAULT NULL,
`COUNTY` varchar(50) DEFAULT NULL,
`COUNTRY` varchar(50) DEFAULT NULL,
`POSTCODE` varchar(50) DEFAULT NULL,
`HomePHONENUM` bigint(20) DEFAULT NULL,
`WorkPHONENUM` bigint(20) DEFAULT NULL,
`MobilePHONENUM` bigint(20) DEFAULT NULL,
`EMAIL` varchar(100) DEFAULT NULL,
PRIMARY KEY (`ID`)
)
ENGINE=InnoDB DEFAULT CHARSET=latin1;
Here's the Entity
package com.keyes.jpa;
import java.io.Serializable;
import javax.persistence.*;
import java.math.BigInteger;
/**
* The persistent class for the parkingsupplier database table.
*
*/
#Entity
#Table(name = "supplier")
public class supplier implements Serializable
{
private static final long serialVersionUID = 1L;
#Id
**#GeneratedValue(strategy = GenerationType.IDENTITY)**
#Column(name = "ID")
private long id;
#Column(name = "CITY")
private String city;
#Column(name = "COUNTRY")
private String country;
#Column(name = "COUNTY")
private String county;
#Column(name = "EMAIL")
private String email;
#Column(name = "FIRSTNAME")
private String firstname;
#Column(name = "HomePHONENUM")
private BigInteger homePHONENUM;
#Column(name = "MobilePHONENUM")
private BigInteger mobilePHONENUM;
#Column(name = "POSTCODE")
private String postcode;
#Column(name = "PROPERTYNUM")
private String propertynum;
#Column(name = "SECONDNAME")
private String secondname;
#Column(name = "STREETNAME")
private String streetname;
#Column(name = "WorkPHONENUM")
private BigInteger workPHONENUM;
public supplier()
{
}
public long getId()
{
return this.id;
}
public void setId(long id)
{
this.id = id;
}
public String getCity()
{
return this.city;
}
public void setCity(String city)
{
this.city = city;
}
public String getCountry()
{
return this.country;
}
public void setCountry(String country)
{
this.country = country;
}
public String getCounty()
{
return this.county;
}
public void setCounty(String county)
{
this.county = county;
}
public String getEmail()
{
return this.email;
}
public void setEmail(String email)
{
this.email = email;
}
public String getFirstname()
{
return this.firstname;
}
public void setFirstname(String firstname)
{
this.firstname = firstname;
}
public BigInteger getHomePHONENUM()
{
return this.homePHONENUM;
}
public void setHomePHONENUM(BigInteger homePHONENUM)
{
this.homePHONENUM = homePHONENUM;
}
public BigInteger getMobilePHONENUM()
{
return this.mobilePHONENUM;
}
public void setMobilePHONENUM(BigInteger mobilePHONENUM)
{
this.mobilePHONENUM = mobilePHONENUM;
}
public String getPostcode()
{
return this.postcode;
}
public void setPostcode(String postcode)
{
this.postcode = postcode;
}
public String getPropertynum()
{
return this.propertynum;
}
public void setPropertynum(String propertynum)
{
this.propertynum = propertynum;
}
public String getSecondname()
{
return this.secondname;
}
public void setSecondname(String secondname)
{
this.secondname = secondname;
}
public String getStreetname()
{
return this.streetname;
}
public void setStreetname(String streetname)
{
this.streetname = streetname;
}
public BigInteger getWorkPHONENUM()
{
return this.workPHONENUM;
}
public void setWorkPHONENUM(BigInteger workPHONENUM)
{
this.workPHONENUM = workPHONENUM;
}
}
Take a look at GeneratedValue's strategy. It typically looks something like:
#GeneratedValue(strategy=GenerationType.IDENTITY)
you must be using update in your hbm2ddl property. make the changes and update it to Create so that it can create the table.
<property name="hbm2ddl.auto">create</property>
It worked for me.
Dropping the table from the database manually and then re-running the application worked for me. In my case table was not created properly(with constraints) I guess.
I had this issue. My mistake was i had set the insertable and updatable fileds as false and was trying to set the field in the request. This field is set as NON NULL in DB.
#ManyToOne
#JoinColumn(name="roles_id", referencedColumnName = "id", insertable = false, updatable = false, nullable=false)
#JsonBackReference
private Role role;
Later I changed it to - insertable = true, updatable = true
#ManyToOne
#JoinColumn(name="roles_id", referencedColumnName = "id", insertable = true, updatable = true, nullable=false)
#JsonBackReference
//#JsonIgnore
private Role role;
It worked perfectly later.
I came here because of the error message, turns out I had two tables with the same name.
I had the same problem. I found the tutorial Hibernate One-To-One Mapping Example using Foreign key Annotation and followed it step by step like below:
Create database table with this script:
create table ADDRESS (
id INT(11) NOT NULL AUTO_INCREMENT,
street VARCHAR(250) NOT NULL,
city VARCHAR(100) NOT NULL,
country VARCHAR(100) NOT NULL,
PRIMARY KEY (id)
);
create table STUDENT (
id INT(11) NOT NULL AUTO_INCREMENT,
name VARCHAR(100) NOT NULL,
entering_date DATE NOT NULL,
nationality TEXT NOT NULL,
code VARCHAR(30) NOT NULL,
address_id INT(11) NOT NULL,
PRIMARY KEY (id),
CONSTRAINT student_address FOREIGN KEY (address_id) REFERENCES ADDRESS (id)
);
Here is the entities with the above tables
#Entity
#Table(name = "STUDENT")
public class Student implements Serializable {
private static final long serialVersionUID = 6832006422622219737L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
}
#Entity
#Table(name = "ADDRESS")
public class Address {
#Id #GeneratedValue
#Column(name = "ID")
private long id;
}
The problem was resolved.
Notice: The primary key must be set to AUTO_INCREMENT
Another suggestion is to check that you use a valid type for the auto-generated field. Remember that it doesn't work with String, but it works with Long:
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
public Long id;
#Constraints.Required
public String contents;
The above syntax worked for generating tables in MySQL using Hibernate as a JPA 2.0 provider.
Just add not-null constraint
I had the same problem. I just added not-null constraint in xml mapping. It worked
<set name="phone" cascade="all" lazy="false" >
<key column="id" not-null="true" />
<one-to-many class="com.practice.phone"/>
</set>
Maybe that is the problem with the table schema. drop the table and rerun the application.
In addition to what is mentioned above, do not forget while creating sql table to make the AUTO INCREMENT as in this example
CREATE TABLE MY_SQL_TABLE (
USER_ID INTEGER NOT NULL AUTO_INCREMENT PRIMARY KEY,
FNAME VARCHAR(50) NOT NULL,
LNAME VARCHAR(20) NOT NULL,
EMAIL VARCHAR(50) NOT NULL
);
When your field is not nullable it requires a default value to be specified on table creation. Recreate a table with AUTO_INCREMENT properly initialized so DB will not require default value since it will generate it by itself and never put NULL there.
CREATE TABLE Persons (
Personid int NOT NULL AUTO_INCREMENT,
LastName varchar(255) NOT NULL,
FirstName varchar(255),
Age int,
PRIMARY KEY (Personid)
);
https://www.w3schools.com/sql/sql_autoincrement.asp
I solved it changuing #GeneratedValue(strategy = GenerationType.IDENTITY) by #GeneratedValue(strategy = GenerationType.AUTO)
By the way i didn't need to put it to create, just:
spring.jpa.hibernate.ddl-auto: update
Please check whether the Default value for the column id in particular table.if not make it as default
I had the same problem. I was using a join table and all I had with a row id field and two foreign keys. I don't know the exact caused but I did the following
Upgraded MySQL to community 5.5.13
Rename the class and table
Make sure I had hashcode and equals methods
#Entity
#Table(name = "USERGROUP")
public class UserGroupBean implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
#Column(name = "USERGROUP_ID")
private Long usergroup_id;
#Column(name = "USER_ID")
private Long user_id;
#Column(name = "GROUP_ID")
private Long group_id;
The same exception was thrown if a DB table had an old unremoved column.
For example:
attribute_id NOT NULL BIGINT(20), and attributeId NOT NULL BIGINT(20),
After removing the not used attribute, in my case contractId, the problem was resolved.
This happened to me with a #ManyToMany relationship. I had annotated one of the fields in the relationship with #JoinTable, I removed that and used the mappedBy attribute on #ManyToMany instead.
I tried the code and in my case the code below solve the issue. I had not settled the schema properly
#Entity
#Table(name="table"
,catalog="databasename"
)
Please try to add ,catalog="databasename" the same as I did.
,catalog="databasename"
In my case,
I altered that offending tables and the field "id" in question I made it AUTO_INCREMENT, I still need to figure out why on deployment time it was not making it "AUTO_INCREMENT" so that I have to do it by myself!
What about this:
<set name="fieldName" cascade="all">
<key column="id" not-null="true" />
<one-to-many class="com.yourClass"/>
</set>
I hope it helps you.
Try to change Long object type to long primitive type (if using primitives is ok for you).
I had the same problem and changing type helped me.
I had this issue, by mistake I had placed #Transient annotation above that particular attribute. In my case this error make sense.
"Field 'id' doesn't have a default value" because you didn't declare GenerationType.IDENTITY in GeneratedValue Annotation.
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
This issue is because sometimes you need to again update/create the database or sometimes if you have added the field in db table but not not entity class then it can not insert any null value or zero so this error came.
So check both side.Db and Entity class.
i have got such error in GCP cloud sql when model field didn't match correct table field in db.
Example:
when in model field is fieldName
table in db should have field field_name
Fixing table field name helped me.
I solved similar problem, when I altered the database column type , and did not add auto_increment. After adding back auto_increment in the alter table command (as in my original table creation) it worked
In my case I have not added the below property in my application.properties file:
spring.jpa.database-platform = org.hibernate.dialect.MySQL5InnoDBDialect
And added the following annotation to my entity class's Id column:
#GeneratedValue(strategy = GenerationType.IDENTITY)
And after adding this I have also drop my table manually from datatbase and run my project again that creates a new table with all default constraints for the table.
To delete just delete your schema is a really bad suggestion. There is a problem and it's best to find and fix it.
In my case I was using Envers this creates an Audit table for when entries are updated. But this audit table does not get updated itself it seems when the schema updates (At least not ID and it's relationships)
I just eddited the audit tables offending property and done. Everything back to normal.
To find what the issue is turn the following properties on in application.properties file
spring.jpa.show-sql=true
spring.jpa.properties.hibernate.format_sql=true
logging.level.org.hibernate.SQL=DEBUG
logging.level.org.hibernate.type.descriptor.sql.BasicBinder=TRACE
This will show you what SQL it is trying to executing and hopefully it will provide clarity on real issue.
Add a method hashCode() to your Entity Bean Class and retry it