java lwjgl setting the mouses position without changing dx or dy - java

Hello I am making a 3D game and now that I've started making something that lets the user interact with a mouse I have been a little stuck (well really stuck).
What I'm trying to do is when the user moves the mouse it gets moved back to the centre (or were the coordinates I entered are) without effecting the Mouse.getDX() and Mouse.getDY().
Here is my code for the part were I test for moving the mouse.
public void onMouser(){
yaw+=Mouse.getDX();
pitch-=Mouse.getDY();
Mouse.setCursorPosition(750, 500);
}
Thanks in Advance

public void calculatePitchAndYaw() {
pitch += Mouse.getY() - HEIGHT /2;
yaw += Mouse.getX - WIDTH / 2;
Mouse.setCursorPosition(WIDTH / 2, HEIGHT /2);
}
Try something like this. So you wont turn back to your initial position.

You can't change position of mouse with serCursorPosition without affect the Mouse.getDX();
You can try save vars before change cursos position:
int saveDX = Mouse.getDX();
int saveDY = Mouse.getDY();
Mouse.setCursorPosition(750, 500);
Regards.

Related

Changing color of sphere with time (processing)

I am a new coder on processing, because of this reason please be gentle.
Normally my code is more longer and complex but I wrote a simple code for you, which I can adapt on my code:
int speed = 1;
int x, z = 50;
void setup() {
size(400, 400, P3D);
}
void draw() {
background(0);
noStroke();
lights();
translate(x, height/2, z);
fill(255,0,0);
sphere(25);
if (x > width -50)
noLoop();
x += speed;
}
So, like you see, sphere starts with color of red and it reaches end of the window. I want to change it's color from red to white and it should take 30 sec. to reach end of the window. However I don't know how. If you help me I will be happy.
Note: I tried lerpColor function but didn't help me.
Math is the secret. Is often is.
There are a couple things you'll need to keep track of to accomplish this: the time it takes to cross the screen (you said 30 seconds), the speed of the sphere, the speed at which the color changes.
Before we start, I suggest that you use float for your variables which are positions and speeds. Integers will do the job, but at some point when you want precision you may regret not using floats or a similar type.
There are 2 ways to deal with changes over time: you can calculate time and draw what needs to be drawn where it's supposed to be, or calculate how many frames will be drawn in a certain amount of time and move things accordingly. The first technique has the advantage of being able to draw things where they are supposed to be even if the system is laggy (Processing will lower the framerate if it's not able to respect it), while the second is often easier to work with. We'll go with the framerate technique, as this is not supposed to be complicated and because most programs won't need so much resource that it'll lower the framerate.
The framerate, in Processing, is also the rate at which the main loop (the draw() loop) run. So we'll choose a framerate which will let us calculate the speed of the sphere and the speed at which the color change. The rest is just watching it move.
Here's your example, but modified so it works approximately as you told:
float speed;
float x, z = 50;
float greenBlueStrength = 0;
float colorFadeRate = 1;
int fadeTimeInFrames;
void setup() {
size(400, 400, P3D);
frameRate(60); // 60 is the default framerate per second
// so 30 seconds == (30*60) == 1800 frames
// so you must have the speed to match
fadeTimeInFrames = 60 * 30;
speed = (width - 50) / (float)fadeTimeInFrames;
colorFadeRate = 255 / (float)fadeTimeInFrames;
println(colorFadeRate);
}
void draw() {
background(0);
textSize(30);
text((millis()/1000) + " s. // color: " + (int)greenBlueStrength, 20, 50);
// this is just to keep track of changes while they happen
noStroke();
lights();
translate(x, height/2, z);
fill(255, greenBlueStrength, greenBlueStrength);
sphere(25);
if (x > width -50) {
noLoop();
} // no actual change, but use brackets anyway, it's easier to read
// updating what needs to be updated
x += speed;
greenBlueStrength += colorFadeRate;
}
I'll hang around so don't hesitate if you have questions.
Have fun!
I think something like that would work:
int r=255,b=255,g=255;
...
void draw(){
...
int percent=x/width*100;
fill(r,b*percent,g*percent)
sphere(25)
...
}
so the sphere would be red only on the left of the screen and white on the right

Shooting object based on arm rotation in libgdx java

I am trying to shoot an object(a spell) depending on the rotation of the players arm. The spell is supposed to come out of the hand and shoot towards where the mouse cicked(the arm rotates and points to where the mouse is). This is how the arm rotates in game.
public boolean mouseMoved(int screenX, int screenY) {
tmp.x = screenX;
tmp.y = screenY;
tmp.z = 0;
cam.unproject(tmp);
rot = MathUtils.radiansToDegrees * MathUtils.atan2((float)tmp.y - (float)player.getArmSprite().getY() - player.getArmSprite().getHeight(),
tmp.x -player.getArmSprite().getX() - player.getArmSprite().getWidth());
if (rot < 0) rot += 360;
//Last right or left means if hes looking left or right
if(player.lastRight)
player.setObjectRotation(rot + 80);
if(player.lastLeft)
player.setObjectRotation(-rot - 80);
And this is how the spell is supposed to shoot based off rotation
//destination is a vector of where on screen the mouse was clicked
if(position.y < destination.y){
position.y += vel.y * Gdx.graphics.getDeltaTime();
}
if(position.x < destination.x){
position.x += vel.x * Gdx.graphics.getDeltaTime();
}
However this is very wonky and never really reacts the way it supposed to with a few exceptions. It fires from the hand and then if the y axis is equal it completely evens out and goes till it reaches the x position, I want it to fire from the hand to the position clicks perfectly straight from point a to point b, this is clearly a rotation problem that I just can't seem to figure out how to tackle.
Here is an image of what is happening
Example image
The red indicates where I clicked, as you can see it reached the x pos first and now is traveling to the y when it should have reached the x and y pos of where I clicked first
Any help with this problem is extremely appreciated!
I'm pretty bad at radians and tangents but luckily we have vectors.
Since you have the rot ation in degrees of the arm. I advice to use Vectors to use for any Vector related math now.
//A vector pointing up
Vector2 direction = new Vector2(0, 1);
//Let's rotate that by the rotation of the arm
direction.rotate(rot);
Now direction is the direction the arm is pointing. If your rotation is calculated where up = 0. So you might need to rotate it 180, 90 or -90 degrees. Or in the case you did something silly any degrees.
Your spell should have a Vector too for it's position. Set that to the hand or wherever you want to start from. Now all you need to do is scale that direction since it's currently has a length of 1. If you want to move 5 units each frame you can do direction.scl(5) now it is of length 5. But technically speaking it's no direction anymore now everybody calls it velocity so let's do.
//when you need to fire
float speed = 5;
Vector2 velocity = direction.cpy().scl(speed);
//update
position.add(velocity);
draw(fireballImage, position.x, position.y);
I copied direction first, otherwise it would also be scaled. Then I just added the velocity to the position and draw using that Vector.
And to show Vectors are awesome you should see this awesome badlogic vs mouse program I created. https://github.com/madmenyo/FollowMouse there are just a view lines of my own code. It just takes a little bit of vector knowledge and it's very readable.

Creating "stick controls" for android game?

I'm trying to create a simple Android game, a 2D action shooter which has 2 control sticks (circles) on the screen, the left one is movement control and the right one weapon control. Direction is being controlled by the position of your thumb relative to the circle’s center.
I've been following a tutorial on this site: http://www.kilobolt.com/day-7-creating-an-android-game-from-start-to-finish.html but it only gave me the base to work on. I have no programming experience so I'm quite lost now.
I got the movement working only on TOUCH_DOWN event, the hero moves to about where it should but to change direction I have to lift my thumb and touch the circle again. TOUCH_DRAGGED (or ACTION_MOVE) is broken because if I drag my finger across the circle the character moves really fast. I guess the problem is too many touch events are being handled, but I have no idea how to fix it.
How can I change this so that I can drag my thumb around the circle and the hero will change its direction instantly, and keep its speed constant all the time? Also the speed should be the same no matter how close or far from the center of the circle you touch.
private void updateRunning(List<TouchEvent> touchEvents, float deltaTime) {
int len = touchEvents.size();
for (int i = 0; i < len; i++) {
TouchEvent event = touchEvents.get(i);
if (event.type == TouchEvent.TOUCH_DOWN || event.type == TouchEvent.TOUCH_DRAGGED) {
if (inBounds(event, 50, 300, 150, 150, 'c')) {
ctrl.setX(event.x);
ctrl.setY(event.y);
ctrl.direction();
hero.move(ctrl.getDirX(), ctrl.getDirY());
}
}
if (event.type == TouchEvent.TOUCH_UP) {
if (inBounds(event, 0, 0, 35, 35,'r')) {
pause();
}
hero.stopMove();
}
}
hero.update();
The movement: hero's speedX and speedY are added to hero's centerX and centerY on every hero.update() call.
public void move(float x, float y) {
speedX += x * MOVESPEED;
speedY += y * MOVESPEED;
}
This method that handles the x & y speed. Found it here at stackoverflow, and because touch_down event is working ok, I guess it's doing it's job. Although I feel it's not exactly how it's supposed to be. L_STICK_C is a constant with values of 100 and 350 (center of the circle).
public void direction() {
dir.x = x - L_STICK_C.x;
dir.y = y - L_STICK_C.y;
double hyp = Math.sqrt(dir.x * dir.x + dir.y * dir.y);
dir.x = (float) (dir.x / hyp);
dir.y = (float) (dir.y / hyp);
}
I suggest you look into some game programming tutorials. You usually would not move the character directly from the touch input. You'd set a game state variable once a game loop which would correspond to the position of your thumb inputs. Then you'd only update the hero once per game loop based on those inputs. This lets allows you to keep the game input control code, and hero code separate, and makes it re-usable for other parts of your game.
EDIT:
Based on your code, every time you drag your finger, you generate a bunch of dragged events. So you are adding onto your characters speed for each event. You should probably just be looking at the distance to center and x / y of the input on the last touch event, not all of them.

How to have a "Camera" only show a portion of a loaded area

I'm having a little problem with figuring something out (Obviously).
I'm creating a 2D Top-down mmorpg, and in this game I wish the player to move around a tiled map similar to the way the game Pokemon worked, if anyone has ever played it.
If you have not, picture this: I need to load various areas, constructing them from tiles which contain an image and a location (x, y) and objects (players, items) but the player can only see a portion of it at a time, namely a 20 by 15 tile-wide area, which can be 100s of tiles tall/wide. I want the "camera" to follow the player, keeping him in the center, unless the player reaches the edge of the loaded area.
I don't need code necessarily, just a design plan. I have no idea how to go about this kind of thing.
I was thinking of possibly splitting up the entire loaded area into 10x10 tile pieces, called "Blocks" and loading them, but I'm still not sure how to load pieces off screen and only show them when the player is in range.
The picture should describe it:
Any ideas?
My solution:
The way I solved this problem was through the wonderful world of JScrollPanes and JPanels.
I added a 3x3 block of JPanels inside of a JScrollPane, added a couple scrolling and "goto" methods for centering/moving the JScrollPane around, and voila, I had my camera.
While the answer I chose was a little more generic to people wanting to do 2d camera stuff, the way I did it actually helped me visualize what I was doing a little better since I actually had a physical "Camera" (JScrollPane) to move around my "World" (3x3 Grid of JPanels)
Just thought I would post this here in case anyone was googling for an answer and this came up. :)
For a 2D game, it's quite easy to figure out which tiles fall within a view rectangle, if the tiles are rectangular. Basically, picture a "viewport" rectangle inside the larger world rectangle. By dividing the view offsets by the tile sizes you can easily determine the starting tile, and then just render the tiles in that fit inside the view.
First off, you're working in three coordinate systems: view, world, and map. The view coordinates are essentially mouse offsets from the upper left corner of the view. World coordinates are pixels distances from the upper left corner of tile 0, 0. I'm assuming your world starts in the upper left corner. And map cooridnates are x, y indices into the map array.
You'll need to convert between these in order to do "fancy" things like scrolling, figuring out which tile is under the mouse, and drawing world objects at the correct coordinates in the view. So, you'll need some functions to convert between these systems:
// I haven't touched Java in years, but JavaScript should be easy enough to convey the point
var TileWidth = 40,
TileHeight = 40;
function View() {
this.viewOrigin = [0, 0]; // scroll offset
this.viewSize = [600, 400];
this.map = null;
this.worldSize = [0, 0];
}
View.prototype.viewToWorld = function(v, w) {
w[0] = v[0] + this.viewOrigin[0];
w[1] = v[1] + this.viewOrigin[1];
};
View.prototype.worldToMap = function(w, m) {
m[0] = Math.floor(w[0] / TileWidth);
m[1] = Math.floor(w[1] / TileHeight);
}
View.prototype.mapToWorld = function(m, w) {
w[0] = m[0] * TileWidth;
w[1] = m[1] * TileHeight;
};
View.prototype.worldToView = function(w, v) {
v[0] = w[0] - this.viewOrigin[0];
v[1] = w[1] - this.viewOrigin[1];
}
Armed with these functions we can now render the visible portion of the map...
View.prototype.draw = function() {
var mapStartPos = [0, 0],
worldStartPos = [0, 0],
viewStartPos = [0, 0];
mx, my, // map coordinates of current tile
vx, vy; // view coordinates of current tile
this.worldToMap(this.viewOrigin, mapStartPos); // which tile is closest to the view origin?
this.mapToWorld(mapStartPos, worldStartPos); // round world position to tile corner...
this.worldToView(worldStartPos, viewStartPos); // ... and then convert to view coordinates. this allows per-pixel scrolling
mx = mapStartPos[0];
my = mapStartPos[y];
for (vy = viewStartPos[1]; vy < this.viewSize[1]; vy += TileHeight) {
for (vx = viewStartPos[0]; vx < this.viewSize[0]; vy += TileWidth) {
var tile = this.map.get(mx++, my);
this.drawTile(tile, vx, vy);
}
mx = mapStartPos[0];
my++;
vy += TileHeight;
}
};
That should work. I didn't have time to put together a working demo webpage, but I hope you get the idea.
By changing viewOrigin you can scroll around. To get the world, and map coordinates under the mouse, use the viewToWorld and worldToMap functions.
If you're planning on an isometric view i.e. Diablo, then things get considerably trickier.
Good luck!
The way I would do such a thing is to keep a variable called cameraPosition or something. Then, in the draw method of all objects, use cameraPosition to offset the locations of everything.
For example: A rock is at [100,50], while the camera is at [75,75]. This means the rock should be drawn at [25,-25] (the result of [100,50] - [75,75]).
You might have to tweak this a bit to make it work (for example maybe you have to compensate for window size). Note that you should also do a bit of culling - if something wants to be drawn at [2460,-830], you probably don't want to bother drawing it.
One approach is along the lines of double buffering ( Java Double Buffering ) and blitting ( http://download.oracle.com/javase/tutorial/extra/fullscreen/doublebuf.html ). There is even a design pattern associated with it ( http://www.javalobby.org/forums/thread.jspa?threadID=16867&tstart=0 ).

How to position a Node along a circular orbit around a fixed center based on mouse coordinates (JavaFX)?

Im trying to get into some basic JavaFX game development and I'm getting confused with some circle maths.
I have a circle at (x:250, y:250) with a radius of 50.
My objective is to make a smaller circle to be placed on the circumference of the above circle based on the position of the mouse.
Where Im getting confused is with the coordinate space and the Trig behind it all.
My issues come from the fact that the X/Y space on the screen is not centered at 0,0. But the top left of the screen is 0,0 and the bottom right is 500,500.
My calculations are:
var xpos:Number = mouseEvent.getX();
var ypos:Number = mouseEvent.getY();
var center_pos_x:Number = 250;
var center_pos_y:Number = 250;
var length = ypos - center_pos_y;
var height = xpos - center_pos_x;
var angle_deg = Math.toDegrees(Math.atan(height / length));
var angle_rad = Math.toRadians(angle_deg);
var radius = 50;
moving_circ_xpos = (radius * Math.cos(angle_rad)) + center_pos_x;
moving_circ_ypos = (radius * Math.sin(angle_rad)) + center_pos_y;
I made the app print out the angle (angle_deg) that I have calculated when I move the mouse and my output is below:
When the mouse is (in degrees moving anti-clockwise):
directly above the circle and horizontally inline with the center, the angle is -0
to the left and vertically centered, the angle is -90
directly below the circle and horizontally inline with the center, the angle is 0
to the right and vertically centered, the angle is 90
So, what can I do to make it 0, 90, 180, 270??
I know it must be something small, but I just cant think of what it is...
Thanks for any help
(and no, this is not an assignment)
atan(height/length) is not enough to get the angle. You need to compensate for each quadrant, as well as the possibility of "division-by-zero". Most programming language libraries supply a method called atan2 which take two arguments; y and x. This method does this calculation for you.
More information on Wikipedia: atan2
You can get away without calculating the angle. Instead, use the center of your circle (250,250) and the position of the mouse (xpos,ypos) to define a line. The line intersects your circle when its length is equal to the radius of your circle:
// Calculate distance from center to mouse.
xlen = xpos - x_center_pos;
ylen = ypos - y_center_pos;
line_len = sqrt(xlen*xlen + ylen*ylen); // Pythagoras: x^2 + y^2 = distance^2
// Find the intersection with the circle.
moving_circ_xpos = x_center_pos + (xlen * radius / line_len);
moving_circ_ypos = y_center_pos + (ylen * radius / line_len);
Just verify that the mouse isn't at the center of your circle, or the line_len will be zero and the mouse will be sucked into a black hole.
There's a great book called "Graphics Gems" that can help with this kind of problem. It is a cookbook of algorithms and source code (in C I think), and allows you to quickly solve a problem using tested functionality. I would totally recommend getting your hands on it - it saved me big time when I quickly needed to add code to do fairly complex operations with normals to surfaces, and collision detections.

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