Maven generate zip instead of just WAR file - java

Here's the plugin for maven WAR plugin:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>2.3</version>
<configuration>
<archiveClasses>true</archiveClasses>
<webResources>
<!-- in order to interpolate version from pom into appengine-web.xml -->
<resource>
<directory>${basedir}/src/main/webapp/WEB-INF</directory>
<filtering>true</filtering>
<targetPath>WEB-INF</targetPath>
</resource>
</webResources>
</configuration>
</plugin>
What plugin can generate a ZIP file containing the same files in the WAR?

A possible solution is to create a custom assembly with the use of the maven-assembly-plugin.
The following descriptor declares an assembly of format zip. It uses a <dependencySet> to declare the dependency towards the WAR packaged by the Maven build. This WAR is unpacked so that the final ZIP has the exact same content has the WAR file.
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3 http://maven.apache.org/xsd/assembly-1.1.3.xsd">
<id>zip</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<includes>
<include>${project.groupId}:${project.artifactId}:war:${project.version}</include>
</includes>
<unpack>true</unpack>
</dependencySet>
</dependencySets>
</assembly>
Save this file, for example in src/assembly/assembly.xml. Then, in your POM, you need to declare an execution of this plugin:
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<id>make-zip</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptors>
<descriptor>src/assembly/assembly.xml</descriptor>
</descriptors>
<appendAssemblyId>false</appendAssemblyId>
</configuration>
</execution>
</executions>
</plugin>
When you invoke Maven with mvn clean install, this plugin will be executed and it will create the wanted ZIP file inside the target folder.

Related

How do I set file permissions on a file when deploying an AWS Serverless Application with Maven

I want to deploy an AWS lambda function using the AWS Serverless Application Model with Maven. In the lambdas deployment zip file I want to include two external files (file1 and file2) that need to have executable permisions. (chmod 755 / -rwxr-xr-x). The files are both 64-bit ELFs
The files on my local machine have those permisions, however when built and deployed to AWS I can export and download the function from the online AWS lambda console to a ZIP and see that the deployed files now have the permisions -rw-r--r-- (chmod 644).
I have fixed this issue in Gradle before by quite simply doing something like filesMatching('file1') { mode = 0755 }
I am using:
java11
maven-shade-plugin 3.2.2
How do I achieve this in Maven? Here is the build portion of my pom.xml
<build>
<resources>
<resource>
<directory>files</directory>
<includes>
<include>file1</include>
<include>file2</include>
</includes>
</resource>
</resources>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-shade-plugin</artifactId>
<version>3.2.2</version>
<configuration>
</configuration>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>shade</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
For anyone else having this issue, I ended up using maven-assembly-plugin as suggested by khmarbaise. My solution ended up looking like this:
This was the build section of my pom.xml
<build>
<plugins>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>3.2.0</version>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptors>
<descriptor>distribution.xml</descriptor>
</descriptors>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
Then I added the file "distribution.xml" to the same directory as the POM.xml. Which looked like this.
<assembly
xmlns="http://maven.apache.org/ASSEMBLY/2.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0 http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>aws-lambda-package</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>files</directory>
<outputDirectory>./</outputDirectory>
<includes>
<include>file1</include>
<include>file2</include>
</includes>
<fileMode>0755</fileMode>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
</dependencySet>
</dependencySets>
As a side effect of doing this I could no longer use the name of the function as the value for the codeURI in the template.yaml. So I needed to change it to the location of the zip file created when maven clean install is ran. Which in most peoples cases will be located: <functionName>/target/<fileName>.zip.

How to Build Java Project including all Dependencies as Jars [duplicate]

We're trying to build a client jar that includes unpacked dependent jar's. And the manifest should have class-path entries to the dependent jars. The snippet below works but the jars are unpacked - how can we stop the jars from being unpacked?
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
Indeed, assembling using jar-with-dependencies causes maven to unpack all the dependencies as ${assembly.dependencySets.dependency.unpack} is set to true in the corresponding assembly descriptor.
A simple fix would be to provide an assembly descriptor similar to the jar-with-dependencies.xml and modify ${assembly.dependencySets.dependency.unpack} to false, like this:
EDIT: For an unknown reason, the behavior when using <unpack>false</unpack> is not exactly the same and it seems necessary to add <outputDirectory>/</outputDirectory> to the fileSet or you don't get the expected result.
<assembly>
<id>uberjar</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<unpack>false</unpack>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
<fileSets>
<fileSet>
<directory>${project.build.outputDirectory}</directory>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
</assembly>
You can add your dependencies as jar files to your jar:
assembly-descriptor.xml
<assembly>
<id>uberjar</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<unpack>false</unpack>
<scope>runtime</scope>
<useProjectArtifact>false</useProjectArtifact>
</dependencySet>
</dependencySets>
<fileSets>
<fileSet>
<directory>${project.build.outputDirectory}</directory>
<outputDirectory>.</outputDirectory>
</fileSet>
</fileSets>
</assembly>
pom.xml
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<id>make-uberjar</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptor>src/main/assemble/assembly-descriptor.xml</descriptor>
</configuration>
</execution>
</executions>
</plugin>
But unfortunately you can't use the Class-Path header in manifest.mf, see Adding Classes to the JAR File's Classpath:
Note: The Class-Path header points to classes or JAR files on the local network, not JAR files within the JAR file or classes accessible over Internet protocols. To load classes in JAR files within a JAR file into the class path, you must write custom code to load those classes. For example, if MyJar.jar contains another JAR file called MyUtils.jar, you cannot use the Class-Path header in MyJar.jar's manifest to load classes in MyUtils.jar into the class path.
The solution proposed by Pascal Thivent defines a new assembly for the Maven assembly plugin. The Maven assembly plugin offers defaults assemblies which are 'bin', 'jar-with-dependencies', 'project' and 'src' producing various predefined bundles.
A new assembly has to be defined in a new xml file, most of the time located in src/assemble. Then it will be loaded instead of the predefined one, this way:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2-beta-5</version>
<configuration>
<!-- disabled predefined assembly -->
<!--
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
-->
<descriptors>
<descriptor>src/assemble/myAssembly.xml</descriptor>
</descriptors>
</configuration>
</plugin>

Filtered runable fat .jar in maven with maven-assembly-plugin

I'm currently moving a small project in to Maven and I am having some trouble.
The setup is as follows
Where a setting file is used in a my resource folder for running the application in eclipse. But when i create a fat jar the setting file is packed in side the jar. I want to filter the setting file so it is outside the jar (I understand this makes the file brittle, but that is by design) and still have it available to the application from the same folder as the jar. I have achieved this with an eclipse runnable jar and and Ant file. But I cannot seem to get it to work with maven. Any insight you have would be very useful.
Her are examples of my plugin and filter file. Any Ideas on this would be great as this has been driving me insane
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>3.1.0</version>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<filters>
<filter>src/assembly/filter.properties</filter>
</filters>
<archive>
<manifest>
<mainClass>ie.business.project.artifact</mainClass>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id> <!-- this is used for inheritance merges -->
<phase>package</phase> <!-- bind to the packaging phase -->
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
and my filter
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0
http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>distribution</id>
<formats>
<format>jar</format>
</formats>
<files>
<file>
<source>settings.ini</source>
<outputDirectory>/</outputDirectory>
<filtered>true</filtered>
</file>
</files>
</assembly>
So I have tired something else. If I define an exclusion in my jar-plugin in addition to using maven-assembly, the setting file dose not end up in the fat jar. I'm unsure if this is the right way to do this but it has worked.
Please let me know if there in a better way to do this.
I added the following plugin to my pom
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>3.0.2</version>
<configuration>
<excludes>
<exclude>setting.ini</exclude>
</excludes>
</configuration>
</plugin>
It seems that you are not using the assembly plugin pointing to the assembly in your question. If you look at the plugin configuration you are using:
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
Actually you should be pointing to the relative path of the assembly file, like e.g:
<configuration>
<descriptors>
<descriptor>src/assembly/assembly.xml</descriptor>
</descriptors>
</configuration>
Now the assembly file for the creation of a fat jar should be changed to create the fat jar and exclude some files. This example is just to give you an idea:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0 http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>jar-with-dependencies</id>
<formats>
<format>jar</format>
</formats>
<fileSets>
<fileSet>
<directory>${basedir}</directory>
<excludes>
<exclude>settings.ini</exclude>
</excludes>
</fileSet>
</fileSets>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<outputDirectory>/</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<unpack>true</unpack>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
</assembly>

Is the content of the Maven Assesmnly plugin's jar-with-dependencies descriptorRef documented as an example assembly descriptor file anywhere?

The following see How can I create an executable jar with dependencies using Maven? shows how to create an executable jar with the Maven plugin.
<build>
<plugins>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<archive>
<manifest>
<mainClass>fully.qualified.MainClass</mainClass>
</manifest>
</archive>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
</configuration>
</plugin>
</plugins>
</build>
However I wish to exclude some of the dependencies which are in my POM. All I want to do is to add
<dependencySets>
<dependencySet>
<useStrictFiltering>true</useStrictFiltering>
<scope>compile</scope>
<excludes>
<exclude>com.excluded:artifact</exclude>
</excludes>
</dependencySet>
</dependencySets>
to the above but I cannot , because I need to add that in a separate assembly descriptor. What I want to do is exactly the same as jar-with-dependencies but with the exclusion. Is there somewhere where an equivalent assembly descriptor file is described so I can edit it? Is there any way to 'inherit' jar-with-dependencies and add my exclusions?
I think that you can use scope "compile" :
<dependency>
<groupId>com.xxxx</groupId>
<artifactId>xxxxxx</artifactId>
<version>3.x</version>
<scope>compile</scope>
</dependency>
See The Maven Documentation on pre defined descriptors for the equivalent of jar-with-depedencies.
So I can change the POM I am using to build 'super jar' as follows;
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.4</version>
<configuration>
<archive>
<manifest>
<mainClass>my.Main</mainClass>
</manifest>
</archive>
<descriptors>
<descriptor>src/main/assembly/assembly.xml</descriptor>
</descriptors>
</configuration>
<!-- Uncomment this for automatic creation of the Complete jar
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
-->
</plugin>
And in the directory src/main/assembly/assembly.xml I can put the following which is essentially the same as the jar-with-dependencies descriptor with my exclusions;
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<!-- TODO: a jarjar format would be better -->
<id>jar-with-dependencies</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<outputDirectory>/</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<unpack>true</unpack>
<scope>runtime</scope>
<excludes>
<exclude>com.local.depedency:artifact_id</exclude>
<exclude>transitive.depedency.so.way.down:artifact_id</exclude>
</excludes>
</dependencySet>
</dependencySets>
</assembly>

How do you create a standalone application with dependencies intact using Maven?

I have a desktop Java application built using Maven 2 (but I could upgrade to Maven 3 if that helps) with a number of open source dependencies. I'm now trying to package it up as a standalone to make it available to end users without them needing to install maven or anything else.
I've successfully used maven-assembly-plugin to build a single jar containing all dependencies but this is not really what I want because when using LGPL libraries you are meant to redistribute the libraries you are using as separate jars.
I want Maven to build a zip containing a jar with my code and a MANIFEST.MF that refers to the other jars I need together with the other jars. This seems like standard practice but I cannot see how to do it.
Here's an extract from my pom
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<encoding>UTF-8</encoding>
<compilerVersion>1.6</compilerVersion>
<source>1.6</source>
<target>1.6</target>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<configuration>
<argLine>-Dfile.encoding=UTF-8</argLine>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.4</version>
<configuration>
<archive>
<manifest>
<mainClass>com.company.widget.Main</mainClass>
<packageName>com.company.widget</packageName>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.3</version>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<mainClass>com.company.widget.Main</mainClass>
<packageName>com.company.widget</packageName>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
EDIT:Taken on Kals idea
created a file called descriptor.xml
<?xml version="1.0" encoding="UTF-8"?>
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>distribution</id>
<formats>
<format>zip</format>
</formats>
<dependencySets>
<dependencySet>
<scope>runtime</scope>
<outputDirectory>lib</outputDirectory>
<unpack>false</unpack>
</dependencySet>
</dependencySets>
</assembly>
and pom contains:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.3</version>
<configuration>
<descriptors>
<descriptor>assembly.xml</descriptor>
</descriptors>
<archive>
<manifest>
<mainClass>com.company.widget.cmdline.Main</mainClass>
<packageName>com.company.widget</packageName>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
Now maintains the jar and puts them all in the lib folder, including my own code
You should check out the Maven Appassembler plugin. You can get a lot more robust package using it than rolling your own assembly.
It generates helpful startup scripts for Unix and Windows that allow you to set predefined JAVA VM options, commandline parameters and classpath.
It also has a concept of configuration directory where you can copy default configurations that user can later change. You can also set the configuration directory to be available on the classpath.
Dependencies can be saved in a Maven style "repo" or you can use a flat style "lib" directory.
You still need the assembly plugin for creating a zip or tar archive.
Here's an example appassembler configuration:
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>appassembler-maven-plugin</artifactId>
<version>1.2.2</version>
<configuration>
<programs>
<program>
<mainClass>com.mytools.ReportTool</mainClass>
<name>ReportTool</name>
</program>
</programs>
<assembleDirectory>${project.build.directory}/ReportTool</assembleDirectory>
<repositoryName>lib</repositoryName>
<repositoryLayout>flat</repositoryLayout>
</configuration>
<executions>
<execution>
<id>assembly</id>
<phase>package</phase>
<goals>
<goal>assemble</goal>
</goals>
</execution>
</executions>
</plugin>
To get a zip archive I use the this assembly:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${project.build.directory}/ReportTool</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>/**</include>
</includes>
</fileSet>
</fileSets>
</assembly>
Try creating a custom assembly descriptor and add a dependencySet and make sure you specify, unpack as false.
Use this as assembly descriptor,
<?xml version="1.0" encoding="UTF-8"?>
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>distribution</id>
<formats>
<format>zip</format>
</formats>
<dependencySets>
<dependencySet>
<scope>runtime</scope>
<outputDirectory>lib</outputDirectory>
<useProjectArtifact>false</useProjectArtifact>
<unpack>false</unpack>
</dependencySet>
</dependencySets>
</assembly>
Store this file to say src/main/assembly/assembly.xml and update your assembly plugin configuration in pom.xml like this.
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.1</version>
<executions>
<execution>
<id>assembly</id>
<phase>package</phase>
<goals>
<goal>attached</goal>
</goals>
<configuration>
<descriptor>${basedir}/src/main/assembly/assembly.xml</descriptor>
</configuration>
</execution>
</executions>
</plugin>
Here is assembly descriptor reference if you need anything more
http://maven.apache.org/plugins/maven-assembly-plugin/assembly.html
As far as I know it is possible to redistribute also LGPL libraries into your own packages as long as they are untouched. The maven assembly plugin creates a jar that contains the original jars inside a lib folder of the archive. So far you are fulfilling the LGPL.
Maybe this question gives some more information about this topic.
(Disclaimer: I'm not a lawyer, so please crosscheck this information ;) )
Add the following plugins in pom.xml. Check the value at mainClass,classpathPrefix,addClasspath tags.
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.4</version>
<configuration>
<archive>
<manifest>
<mainClass>org.apache.camel.spring.Main</mainClass>
<classpathPrefix>lib/</classpathPrefix>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.4</version>
<configuration>
<descriptors>
<descriptor>src/assembly/some-assembly.xml</descriptor>
</descriptors>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
Create some-assembly.xml under src/assembly as below.
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>distribution</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>true</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.build.directory}</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>*.jar</include>
</includes>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<scope>runtime</scope>
<outputDirectory>/lib</outputDirectory>
<useProjectArtifact>false</useProjectArtifact>
<unpack>false</unpack>
</dependencySet>
</dependencySets>
Note that useProjectArtifact flag to false, unpack flag to false. If root folder inside zip file is not required,then one can make includeBaseDirectory to false.
This will create name-version-distribution.zip file. Inside zip file, there will be folder name-version. Inside this folder, your executable jar and lib folder containing all dependency jars will be present.
Check manifest.MF file of executable jar. It contains both main class and classpath information.

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