When I try to run the code:
import java.io.*;
import java.util.*;
class dothis {
public static void main (String [] args) throws IOException {
BufferedReader f = new BufferedReader(new FileReader("ride.in"));
PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("ride.out")));
StringTokenizer st = new StringTokenizer(f.readLine());
String s1 = st.nextToken();
String s2 = st.nextToken();
char[] arr = new char[6];
if (find(s1, arr, 1) == find(s2, arr, 1)) {
out.print("one");
} else {
out.println("two");
}
out.close();
}
}
With the data file:
ABCDEF
WERTYU
it keeps on outputting:
Exception_in_thread_"main"_java.util.NoSuchElementException
at_java.util.StringTokenizer.nextToken(StringTokenizer.java:349)
at_dothis.main(Unknown_Source)
I did see a similar question on Stack Overflow, but in that case, the second line of the text file is blank, therefore there wasn't a second token to be read. However, the two first lines of this data file both contain a String. How come a token would not be read for the second line?
the StringTokenizer docs say that if you don't pass a token delimiter in the constructor, it's assumed to be:
" \t\n\r\f": the space character, the tab character, the newline character, the carriage-return character, and the form-feed character
. you're then asking for two tokens to be read out of the string returned by f.readLine(), which is ABCDEF (with no delimiters), so an exception is thrown.
You are creating the StringTokenizer class from the first line and so when you are setting the value of s2, there is no token left because s1 has the first and only token (ABCDEF). If I am not wrong, you are getting the exception when you are trying to set s2?
When you read a line it will return a String till it found "\n" or "\r" and in your case you have token in each line (i believe).
You really don't need StringTokenizer.
Each line you read is actually a token for you.
Also, if you are expecting each-line to have more than one token than you need to make sure you supply the delimiter to your tokenizer to understand the same.
StringTokenizer uses the default delimiter set, which is " \t\n\r\f": the space character, the tab character, the newline character, the carriage-return character, and the form-feed character. Delimiter characters themselves will not be treated as tokens.
If you are ready for Java 7/8, you could make it even simpler without the need of StringTokenizer.
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.*;
class dothis {
public static void main (String [] args) throws IOException {
String contents = new String(Files.readAllBytes(Paths.get("ride.in")));
String[] lines= contents.split("\n");
PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("ride.out")));
String s1 = lines[0];
String s2 = lines[1];
char[] arr = new char[6];
if (find(s1, arr, 1) == find(s2, arr, 1)) {
out.print("one");
} else {
out.println("two");
}
out.close();
}
}
In your code:
StringTokenizer st = new StringTokenizer(f.readLine());//f.readLine() method reads only 1 line
String s1 = st.nextToken();
String s2 = st.nextToken();//there is no second line, so this will give you error
Try this:
String result = "";
String tmp;
while((tmp = f.readLine())!= null)
{
result += tmp+"\n";
}
StringTokenizer st = new StringTokenizer(result);
ArrayList<String> str = new ArrayList<String>();
int count = st.countTokens();
for(int i=0; i< count; i++)
{
str.add(st.nextToken());
}
Now check by using the above arraylist.
As StringTokenizer is depricated, it is suggested to use split() method of String class.
Related
I am reading a file with comma separated values which when split into an array will have 10 values for each line . I expected the file to have line breaks so that
line = bReader.readLine()
will give me each line. But my file doesnt have a line break. Instead after the first set of values there are lots of spaces(465 to be precise) and then the next line begins.
So my above code of readLine() is reading the entire file in one go as there are no lined breaks. Please suggest how best to efficiently tackle this scenario.
One way is to replace String with 465 spaces in your text with new line character "\n" before iterating it for reading.
I second Ninan's answer: replace the 465 spaces with a newline, then run the function you were planning on running earlier.
For aesthetics and readability I would suggest using Regex's Pattern to replace the spaces instead of a long unreadable String.replace(" ").
Your code could like below, but replace 6 with 465:
// arguments are passed using the text field below this editor
public static void main(String[] args)
{
String content = "DOG,CAT MOUSE,CHEESE";
Pattern p = Pattern.compile("[ ]{6}",
Pattern.DOTALL | Pattern.CASE_INSENSITIVE);
String newString = p.matcher(content).replaceAll("\n");
System.out.println(newString);
}
My suggestion is read file f1.txt and write to anther file f2.txt by removing all empty lines and spaces then read f2.txt something like
FileReader fr = new FileReader("f1.txt");
BufferedReader br = new BufferedReader(fr);
FileWriter fw = new FileWriter("f2.txt");
String line;
while((line = br.readLine()) != null)
{
line = line.trim(); // remove leading and trailing whitespace
if (!line.equals("")) // don't write out blank lines
{
fw.write(line, 0, line.length());
}
}
Then try using your code.
You might create your own subclass of a FilterInputStream or a PushbackInputStream and pass that to an InputStreamReader. One overrides int read().
Such a class unfortunately needs a bit of typing. (A nice excercise so to say.)
private static final int NO_CHAR = -2;
private boolean fromCache;
private int cachedSpaces;
private int cachedNonSpaceChar = NO_CHAR;
int read() throws IOException {
if (fromCache) {
if (cachecSpaces > 0) ...
if (cachedNonSpaceChar != NO_CHAR) ...
...
}
int ch = super.read();
if (ch != -1) {
...
}
return ch;
}
The idea is to cache spaces till either a nonspace char, and in read() either take from the cache, return \n instead, call super.read() when not from cache, recursive read when space.
My understanding is that you have a flat CSV file without proper line break, which supposed to have 10 values on each line.
Updated:
1. (Recommended) You can use Scanner class with useDelimiter to parse csv effectively, assuming you are trying to store 10 values from a line:
public static void parseCsvWithScanner() throws IOException {
Scanner scanner = new Scanner(new File("test.csv"));
// set your delimiter for scanner, "," for csv
scanner.useDelimiter(",");
// storing 10 values as a "line"
int LINE_LIMIT = 10;
// implement your own data structure to store each value of CSV
int[] tempLineArray = new int[LINE_LIMIT];
int lineBreakCount = 0;
while(scanner.hasNext()) {
// trim start and end spaces if there is any
String temp = scanner.next().trim();
tempLineArray[lineBreakCount++] = Integer.parseInt(temp);
if (lineBreakCount == LINE_LIMIT) {
// replace your own logic for handling the full array
for(int i=0; i<tempLineArray.length; i++) {
System.out.print(tempLineArray[i]);
} // end replace
// resetting array and counter
tempLineArray = new int[LINE_LIMIT];
lineBreakCount = 0;
}
}
scanner.close();
}
Or use the BufferedReader.
You might not need the ArrayList to store all values if there is memory issue by replacing your own logic.
public static void parseCsv() throws IOException {
BufferedReader br = new BufferedReader(new FileReader(file));
// your delimiter
char TOKEN = ',';
// your requirement of storing 10 values for each "line"
int LINE_LIMIT = 10;
// tmp for storing from BufferedReader.read()
int tmp;
// a counter for line break
int lineBreakCount = 0;
// array for storing 10 values, assuming the values of CSV are integers
int[] tempArray = new int[LINE_LIMIT];
// storing tempArray of each line to ArrayList
ArrayList<int[]> lineList = new ArrayList<>();
StringBuilder sb = new StringBuilder();
while((tmp = br.read()) != -1) {
if ((char)tmp == TOKEN) {
if (lineBreakCount == LINE_LIMIT) {
// your logic to handle the current "line" here.
lineList.add(tempArray);
// new "line"
tempArray = new int[LINE_LIMIT];
lineBreakCount = 0;
}
// storing current value from buffer with trim of spaces
tempArray[lineBreakCount] =
Integer.parseInt(sb.toString().trim());
lineBreakCount++;
// clear the buffer
sb.delete(0, sb.length());
}
else {
// add current char from BufferedReader if not delimiter
sb.append((char)tmp);
}
}
br.close();
}
I have a file in the following format, records are separated by newline but some records have line feed in them, like below. I need to get each record and process them separately. The file could be a few Mb in size.
<?aaaaa>
<?bbbb
bb>
<?cccccc>
I have the code:
FileInputStream fs = new FileInputStream(FILE_PATH_NAME);
Scanner scanner = new Scanner(fs);
scanner.useDelimiter(Pattern.compile("<\\?"));
if (scanner.hasNext()) {
String line = scanner.next();
System.out.println(line);
}
scanner.close();
But the result I got have the begining <\? removed:
aaaaa>
bbbb
bb>
cccccc>
I know the Scanner consumes any input that matches the delimiter pattern. All I can think of is to add the delimiter pattern back to each record mannully.
Is there a way to NOT have the delimeter pattern removed?
Break on a newline only when preceded by a ">" char:
scanner.useDelimiter("(?<=>)\\R"); // Note you can pass a string directly
\R is a system independent newline
(?<=>) is a look behind that asserts (without consuming) that the previous char is a >
Plus it's cool because <=> looks like Darth Vader's TIE fighter.
I'm assuming you want to ignore the newline character '\n' everywhere.
I would read the whole file into a String and then remove all of the '\n's in the String. The part of the code this question is about looks like this:
String fileString = new String(Files.readAllBytes(Paths.get(path)), StandardCharsets.UTF_8);
fileString = fileString.replace("\n", "");
Scanner scanner = new Scanner(fileString);
... //your code
Feel free to ask any further questions you might have!
Here is one way of doing it by using a StringBuilder:
public static void main(String[] args) throws FileNotFoundException {
Scanner in = new Scanner(new File("C:\\test.txt"));
StringBuilder builder = new StringBuilder();
String input = null;
while (in.hasNextLine() && null != (input = in.nextLine())) {
for (int x = 0; x < input.length(); x++) {
builder.append(input.charAt(x));
if (input.charAt(x) == '>') {
System.out.println(builder.toString());
builder = new StringBuilder();
}
}
}
in.close();
}
Input:
<?aaaaa>
<?bbbb
bb>
<?cccccc>
Output:
<?aaaaa>
<?bbbb bb>
<?cccccc>
Below is what the text document looks like. The first line is the number of elements that I want the array to contain. The second is the ID for the product, separated by # and the third line is the total price of the products once again separated by #
10
PA/1234#PV/5732#Au/9271#DT/9489#HY/7195#ZR/7413#bT/4674#LR/4992#Xk/8536#kD/9767#
153#25#172#95#235#159#725#629#112#559#
I want to use the following method to pass inputFile to the readProductDataFile method:
public static Product[] readProductDataFile(File inputFile){
// Code here
}
I want to create an array of size 10, or maybe an arrayList. Preferably to be a concatenation of Customer ID and the price, such as Array[1] = PA/1234_153
There you go the full class, does exactly what you want:
import java.io.BufferedReader;
import java.io.FileReader;
import java.util.Arrays;
import java.io.FileNotFoundException;
import java.io.IOException;
class myRead{
public static void main(String[] args) throws FileNotFoundException, IOException {
BufferedReader inputFile = new BufferedReader(new FileReader("test.txt"));
String numberOfElements = inputFile.readLine();
//this is the first line which contains the number "10"
//System.out.println(numberOfElements);
String secondLine = inputFile.readLine();
//this is the second line which contains your data, split it using "#" as a delimiter
String[] strArray = secondLine.split("#");
//System.out.println(Arrays.toString(strArray));
//System.out.println(strArray[0]);
String thirdLine = inputFile.readLine();
//this is the third line which contains your data, split it using "#" as a delimiter
String[] dataArray = thirdLine.split("#");
//combine arrays
String[] combinedArray = new String[strArray.length];
for (int i=0;i<strArray.length;i++) {
combinedArray[i]=strArray[i]+"_"+dataArray[i];
System.out.println(combinedArray[i]);
}
}
}
OUTPUT:
PA/1234_153
PV/5732_25
Au/9271_172
DT/9489_95
HY/7195_235
ZR/7413_159
bT/4674_725
LR/4992_629
Xk/8536_112
kD/9767_559
The trick in what I am doing is using a BufferedReader to read the file, readLine to read each of the three lines, split("#"); to split each token using the # as the delimiter and create the arrays, and combinedArray[i]=strArray[i]+"_"+dataArray[i]; to put the elements in a combined array as you want...!
public static Product[] readProductDataFile(File inputFile){
BufferedReader inputFile = new BufferedReader(new FileReader(inputFile));
// the rest of my previous code goes here
EDIT: Everything together with calling a separate method from inside the main, with the file as an input argument!
import java.io.BufferedReader;
import java.io.FileReader;
import java.util.Arrays;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.File;
class myRead{
public static void main(String[] args) throws FileNotFoundException, IOException {
File myFile = new File("test.txt");
readProductDataFile(myFile);
}
public static String[] readProductDataFile(File inputFile) throws FileNotFoundException, IOException{
BufferedReader myReader = new BufferedReader(new FileReader("test.txt"));
String numberOfElements = myReader.readLine();
//this is the first line which contains the number "10"
//System.out.println(numberOfElements);
String secondLine = myReader.readLine();
//this is the second line which contains your data, split it using "#" as a delimiter
String[] strArray = secondLine.split("#");
//System.out.println(Arrays.toString(strArray));
//System.out.println(strArray[0]);
String thirdLine = myReader.readLine();
//this is the third line which contains your data, split it using "#" as a delimiter
String[] dataArray = thirdLine.split("#");
//combine arrays
String[] combinedArray = new String[strArray.length];
for (int i=0;i<strArray.length;i++) {
combinedArray[i]=strArray[i]+"_"+dataArray[i];
System.out.println(combinedArray[i]);
}
return combinedArray;
}
}
OUTPUT
PA/1234_153
PV/5732_25
Au/9271_172
DT/9489_95
HY/7195_235
ZR/7413_159
bT/4674_725
LR/4992_629
Xk/8536_112
kD/9767_559
You don't even need the first line. Just read the second line directly into a single string and then split it by using String,split() method.
Read more for split method here.
You could use something like this (Be aware that i can't test it at the moment)
BufferedReader in = null;
try {
in = new BufferedReader(new FileReader("fileeditor.txt"));
String read = null;
String firstLine=in.readLine();
//reads the first line
while ((read = in.readLine()) != null) {
// reads all the other lines
read = in.readLine();
String[] splited = read.split("#");
//split the readed row with the "#" character
for (String part : splited) {
System.out.println(part);
}
}
} catch (IOException e) {
System.out.println("There was a problem: " + e);
e.printStackTrace();
} finally {
try {
//close file
in.close();
} catch (Exception e) {
}
}
This is how you can do it using Java (don't forget to import):
public static Product[] readProductDataFile(File inputFile){
Scanner s = new Scanner(inputFile);
String data = "";
while(s.hasNext())
data += s.nextLine();
String[] dataArray = data.split("#");
}
You can try this way ..
Reading line by line and storing each row in a array.
Use while storing so it will split and save .
String[] strArray = secondLine.split("#");
Now use the for loop and concat the values as u wish and save ina third array .
For(int i=0 ;i< file.readline;i++)
{
string s = a[customerid];
s.concat(a[productid]);
a[k] =s;
}
I am submitting the following input through stdin:
4 2
30 one
30 two
15 three
25 four
My code is:
public static void main(String[] args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
String submittedString;
System.out.flush();
submittedString = stdin.readLine();
zipfpuzzle mySolver = new zipfpuzzle();
mySolver.getTopSongs(submittedString);
}
Which calls:
//Bringing it all together
public String getTopSongs(String myString) {
setUp(myString);
calculateQuality();
qualitySort();
return titleSort();
}
Which calls
public void setUp(String myString) {
String tempString = myString;
//Creating array where each element is a line
String[] lineExplode = tempString.split("\\n+");
//Setting up numSongsAlbum and songsToSelect
String[] firstLine = lineExplode[0].split(" ");
numSongsAlbum = Integer.parseInt(firstLine[0]);
songsToSelect = Integer.parseInt(firstLine[1]);
System.out.println(lineExplode.length);
//etc
}
However, for some reason lineExplode.length returns value 1... Any suggestions?
Kind Regards,
Dario
String[] lineExplode = tempString.split("\\n+");
The argument to String#split is a String that contains a regular expression
Your String#split regex will work file on Strings with newline characters.
String[] lineExplode = tempString.split("\n");
The problem is that your tempString has none of these characters, hence the size of the array is 1.
Why not just put the readLine in a loop and add the Strings to an ArrayList
String submittedString;
while (!(submittedString= stdin.readLine()).equals("")) {
myArrayList.add(submittedString);
}
Are you sure the file is using UNIX-style line endings (\n)? For a cross-platform split, use:
String[] lineExplode = tempString.split("[\\n\\r]+");
You should use "\\n" character to separate by new line but check that not all OS use the same separators ( http://en.wikipedia.org/wiki/Newline )
To solve this is very useful the system property line.separator that contains the current separator charater(s) for the current OS that is running the application.
You should use:
String[] lineExplode = tempString.split("\\\\n");
using \n as separator
Or:
String lineSeparator = System.getProperty("line.separator");
String[] lineExplode = tempString.split(lineSeparator);
Using the current OS separator
Or:
String lineSeparator = System.getProperty("line.separator");
String[] lineExplode = tempString.split(lineSeparator + "+");
Using the current OS separator and requiring one item
Its better to use this split this way:
String[] lineExplode =
tempString.split(Pattern.quote(System.getProperty("line.separator")) + '+');
To keep this split on new line platform independent.
UPDATE: After looking at your posted code it is clear that OP is reading just one line (till \n) in this line:
submittedString = stdin.readLine();
and there is no loop to read further lines from input.
So I can search for a string in my text file, however, I wanted to sort data within this ArrayList and implement an algorithm. Is it possible to read from a text file and the values [Strings] within the text file be stored in a String[] Array.
Also is it possible to separate the Strings? So instead of my Array having:
[Alice was beginning to get very tired of sitting by her sister on the, bank, and of having nothing to do:]
is it possible to an array as:
["Alice", "was" "beginning" "to" "get"...]
.
public static void main(String[]args) throws IOException
{
Scanner scan = new Scanner(System.in);
String stringSearch = scan.nextLine();
BufferedReader reader = new BufferedReader(new FileReader("File1.txt"));
List<String> words = new ArrayList<String>();
String line;
while ((line = reader.readLine()) != null) {
words.add(line);
}
for(String sLine : words)
{
if (sLine.contains(stringSearch))
{
int index = words.indexOf(sLine);
System.out.println("Got a match at line " + index);
}
}
//Collections.sort(words);
//for (String str: words)
// System.out.println(str);
int size = words.size();
System.out.println("There are " + size + " Lines of text in this text file.");
reader.close();
System.out.println(words);
}
To split a line into an array of words, use this:
String words = sentence.split("[^\\w']+");
The regex [^\w'] means "not a word char or an apostrophe"
This will capture words with embedded apostrophes like "can't" and skip over all punctuation.
Edit:
A comment has raised the edge case of parsing a quoted word such as 'this' as this.
Here's the solution for that - you have to first remove wrapping quotes:
String[] words = input.replaceAll("(^|\\s)'([\\w']+)'(\\s|$)", "$1$2$3").split("[^\\w']+");
Here's some test code with edge and corner cases:
public static void main(String[] args) throws Exception {
String input = "'I', ie \"me\", can't extract 'can't' or 'can't'";
String[] words = input.replaceAll("(^|[^\\w'])'([\\w']+)'([^\\w']|$)", "$1$2$3").split("[^\\w']+");
System.out.println(Arrays.toString(words));
}
Output:
[I, ie, me, can't, extract, can't, or, can't]
Also is it possible to separate the Strings?
Yes, You can split string by using this for white spaces.
String[] strSplit;
String str = "This is test for split";
strSplit = str.split("[\\s,;!?\"]+");
See String API
Moreover you can also read a text file word by word.
Scanner scan = null;
try {
scan = new Scanner(new BufferedReader(new FileReader("Your File Path")));
} catch (FileNotFoundException e) {
e.printStackTrace();
}
while(scan.hasNext()){
System.out.println( scan.next() );
}
See Scanner API