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Override eclipse Plugin in Project explorer

In my project the user sees the red cross icon on the file containing an error and the folders above. When the (modelling nature of the sirius) plugin is added to the project the red cross dissapears on the file (not on the folders).
How can i keep the error icon on the file?
I can get information about the content extension which probably causes the problem
IWorkbenchPage page = PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage(); ProjectExplorer expl = (ProjectExplorer) page.findView(IPageLayout.ID_PROJECT_EXPLORER);
INavigatorContentService content = expl.getNavigatorContentService();
INavigatorContentExtension siriusext = content.getContentExtensionById("org.eclipse.sirius.ui.resource.content.session");
siriusext.getDescriptor().getAppearsBeforeId();
The problem is probably the sirius INavigatorContentService because it is set to appear before id "org.eclipse.jdt.java.ui.javaContent"
(siriusext.getDescriptor().getAppearsBeforeId())
How can i (have the modelling nature and) keep the error icon on the file?
Any help is appreciated!

I answered your question on the Sirius forum [1].
The problem seems to come from the getImage() implementation in the label provider used by the INavigatorExtension provided by Sirius.
A workaround could be to try to provide your own navigator content with an Override element targeting the Sirius Content Management (org.eclipse.sirius.ui.resource.content.session) as suppressed extension and provide your own label provider (which could extend the Sirius one and specifically handle the file case in getImage, but you might loose the M decorator on files handled by Sirius).
Could you open a bugzilla [2] to track the issue ? Then the team will have the possibility to analyze the issue and try to find a proper solution.
Regards,
Maxime
[1] https://www.eclipse.org/forums/index.php?t=msg&th=877968&goto=1498330&#msg_1498330
[2] https://bugs.eclipse.org/bugs/enter_bug.cgi?product=sirius

Getting the active working set programatically in Eclipse

Can anyone please tell me how to get the current or active working set and also to get all the projects in the working set in IProject type? I am trying to achieve it by using the below code -
IWorkbenchWindow window = PlatformUI.getWorkbench().getActiveWorkbenchWindow();
IWorkbenchPage page = window.getActivePage();
IWorkingSetManager manager = window.getWorkbench().getWorkingSetManager();
IWorkingSet[] workingSets = manager.getWorkingSets();
This will get me all the working sets that are present in eclipse? The IWorkingSet.getElements() provides all the project details in the IAdaptable type which I cannot cast into IProject?
Thank You in Advance!

You convert an IAdaptable value to an IProject using:
IProject project = (IProject)adaptable.getAdapter(IProject.class);
I am not sure if the working set element provides an adapter directly to IProject, you might need to use:
IResource resource = (IResource)adaptable.getAdapter(IResources.class);
if (resource instanceof IProject)
{
}

Hiding and showing Eclipse view programmatically

I am showing and hiding Eclipse view with code below. It works perfectly with Eclipse 3.3, but with Eclipse Juno (version 4.3) it's not showing the first time but showing when I fire the event for the second time.
IWorkbenchPage page = PlatformUI.getWorkbench().getActiveWorkbenchWindow()
.getActivePage();
page.showView(UserView.ID);
page.hideView(page.findView(UserView.ID));
Is somebody come across with this situation before?

I am not sure why you are not getting it the first time. Check to see if you dont have null pointer errors when you fire it the first time.
PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage()
can return a null if the workbench is not yet loaded.

I faced the same issue with the minimized state, so I tried chaging the view's state forcing it to appear after page.showView(UserView.ID);
this piece of code got my viewPart to show :
page.showView(UserView.ID);
IWorkbenchPartReference ref = page.getReference(searchResultUI);
page.setPartState(ref,IWorkbenchPage.STATE_RESTORED); //or STATE_MAXIMIZED

How to programmatically change the selection within package explorer

I am currently developing a plugin for eclipse that analyzes dependencies and references between projects within the Eclipse Workspace and displays them in its own View in a UML-like diagram.
To increase the usefulness of my plugin, I wish to add interactivity to the diagram by allowing users to open a project in the package explorer and if applicable open it in an editor by clicking on the graph displayed.
However, my problem is that while I know how to obtain a given selection from the package explorer, I have not been able to find a way to change the selection or simply open up a project in the package explorer programmatically.
Does anyone have a solution for this problem?

This answer extends what the accepted answer states but takes it further for folks who mind the "Discouraged Access" warning on the use of PackageExplorerPart.
Exact warning (more for easier searching off Google) that you see is
Discouraged access: The type PackageExplorerPart is not accessible due
to restriction on required library
/eclipse_install_path/eclipse/plugins/org.eclipse.jdt.ui_3.9.1.v20130820-1427.jar
Code Sample:
final IWorkbenchPart activePart = getActivePart();
if (activePart != null && activePart instanceof IPackagesViewPart) {
((IPackagesViewPart) activePart).selectAndReveal(newElement);
}
Supporting Code:
private IWorkbenchPart getActivePart() {
final IWorkbench workbench = PlatformUI.getWorkbench();
final IWorkbenchWindow activeWindow = workbench.getActiveWorkbenchWindow();
if (activeWindow != null) {
final IWorkbenchPage activePage = activeWindow.getActivePage();
if (activePage != null) {
return activePage.getActivePart();
}
}
return null;
}

I have found the solution. Eclipse does offer direct access to the package explorer in org.eclipse.jdt.internal.ui.packageview.PackageExplorerPart , but it is discouraged.
import org.eclipse.jdt.internal.ui.packageview.PackageExplorerPart;
...
PackageExplorerPart part= PackageExplorerPart.getFromActivePerspective();
IResource resource = /*any IResource to be selected in the explorer*/;
part.selectAndReveal(resource);
This will highlight whatever IResource resource is and expand the tree as necessary.

How to get the selected node in the package explorer from an Eclipse plugin

I'm writing an Eclipse command plugin and want to retrieve the currently selected node in the package explorer view. I want to be able to get the absolute filepath, where the selected node resides on the filesystem (i.e. c:\eclipse\test.html), from the returned result.
How do I do this ?

The first step is to get a selection service, e.g. from any view or editor like this:
ISelectionService service = getSite().getWorkbenchWindow()
.getSelectionService();
Or, as VonC wrote, you could get it via the PlatformUI, if you are neither in a view or an editor.
Then, get the selection for the Package Explorer and cast it to an IStructuredSelection:
IStructuredSelection structured = (IStructuredSelection) service
.getSelection("org.eclipse.jdt.ui.PackageExplorer");
From that, you can get your selected IFile:
IFile file = (IFile) structured.getFirstElement();
Now to get the full path, you will have to get the location for the IFile:
IPath path = file.getLocation();
Which you then can finally use to get the real full path to your file (among other things):
System.out.println(path.toPortableString());
You can find more information on the selection service here: Using the Selection Service.

The code would be like:
IWorkbenchWindow window =
PlatformUI.getWorkbench().getActiveWorkbenchWindow();
ISelection selection = window.getSelectionService().getSelection("org.eclipse.jdt.ui.PackageExplorer");
You view an example in an Action like this LuaFileWizardAction class.