Spring boot inject mongodb datasource - java

I am trying to deploy a spring boot application connected to a mongodb instance to cloud foundry.
cf create-service MongoService default my-mongo
cf push myapp --no-start
cf bind-service myapp my-mongo
cf start myapp
The connection details to the mongodb instance are in the VCAP_SERVICES environment variable. When deploying my application to cloudfoundry spring boot is trying to access mongodb on localhost:27017 and obviously fails.
I would like to parse the VCAP_SERVICES environment variable, construct some mongodb connection details from it and provide this as a spring bean. Which class should I use for these configuration details?

With Spring Boot, you don't need to manually parse VCAP_SERVICES. If you are using MongoTemplate or MongoRepository, it will automatically connect to the bound instance.
Make sure that you have spring-boot-starter-parent identified as the parent artifact in your pom.xml.
You can add the following to your pom.xml to ensure that the cloud connector code is getting picked up:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-cloud-connectors</artifactId>
</dependency>
Of course, you also need the MongoDB Spring Data dependency:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-mongodb</artifactId>
</dependency>

You may want to try setting up the configuration parameters, like a workaround I had to implement with MySQL, check this question.
For me it all came down to properly defining following properties:
spring:
datasource:
url: jdbc:mysql://${vcap.services.mydb.credentials.host}:${vcap.services.mydb.credentials.port}/${vcap.services.mydb.credentials.name}
driver-class-name: com.mysql.jdbc.Driver
username: ${vcap.services.mydb.credentials.user}
password: ${vcap.services.mydb.credentials.password}

Related

Override properties from Azure App Configuration Store

TL;DR
How to have system properties on CLI or environment variables override properties that are provided by an Azure App Configuration Store? Or is this maybe not possible at all?
Longer story
Let us assume a property named app.prop. Let us further assume the following entry in application.yml or in application-<profile>.yml:
app:
prop: Default
Usually, you are able to start the Spring Boot application and provide a system property (e.g. -Dapp.prop=SYS) or an environment variable (e.g. export APP_PROP=ENV) with the effect that the latter overrides the value of the YML config files. If you - for example - provided the environment variable, your application has the value ENV for the property app.prop.
When reading the same property from an Azure App Configuration Store, you can provide a system property or an environment variable as you like. But the value is not overridden anymore; it is the value that is stored in the Azure App Configuration Store.
Some code
I am using Spring Boot version 2.5.7:
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.5.7</version>
</parent>
Further, I am using the following library for accessing the Azure App Configuration Store:
<properties>
<azure-spring-cloud.version>2.7.0</azure-spring-cloud.version>
</properties>
<dependencyManagement>
<dependencies>
<dependency>
<groupId>com.azure.spring</groupId>
<artifactId>azure-spring-cloud-dependencies</artifactId>
<version>${azure-spring-cloud.version}</version>
<type>pom</type>
<scope>import</scope>
</dependency>
</dependencies>
</dependencyManagement>
<dependencies>
<dependency>
<groupId>com.azure.spring</groupId>
<artifactId>azure-spring-cloud-appconfiguration-config</artifactId>
</dependency>
</dependencies>
Additionally, for starting the application, I am providing the following property:
spring.cloud.azure.appconfiguration.stores[0].connection-string = ...
This all works very well. In the Azure App Configuration Store, I have the following property:
app.prop = Azure
If now starting the application with the following environment variable APP_PROP = ENV, the value of the property app.prop is still Azure, and not ENV.
Is there any setting missing, so that I can have the same behavior that I had without the above mentioned library?
Actually, I searched a lot, but did not find anything except for some statements regarding overriding values of remote properties in the Spring Cloud documentation, which is not really my case (I am using Azure App Configuration Store).
The whole point of using Azure App Configuration is to store your config in one place and easily manage it without redeploying / restarting the app. Therefore I don't think this is should be even possible.
I would recommend to use labels to load specific version of your prop based on labels data. Few cases:
If you need this property only locally, don't specify it in App Configuration.
If you need multiple versions of it, then just create same property with multiple labels and use your spring.profile (or other conf-property) to distinguish the version.
If you need to load multiple versions of it, load multiple labels:
As described here: https://learn.microsoft.com/en-us/java/api/overview/azure/spring-cloud-starter-appconfiguration-config-readme?view=azure-java-stable#load-from-multiple-labels
You can use this sample to see how it works:
https://github.com/Azure/azure-sdk-for-java/tree/azure-spring-boot_3.6.0/sdk/appconfiguration/spring-cloud-starter-azure-appconfiguration-config

Spring Cloud Configuration - Access shared properties file in all microservices

Inside my spring cloud config server application.properties. I have passed #EnableConfigServer in my application class
spring.application.name=CONFIG_SERVER
server.port=1080
spring.cloud.config.server.git.uri=PATH_TO_GITHUB_REPO
spring.cloud.config.server.git.username=USNM
spring.cloud.config.server.git.password=PWD
spring.cloud.config.server.git.skip-ssl-validation=true
Inside my git repo application.properties
third-party-cred=MY_VALUE
In my spring cloud config client bootstrap.properties
server.port=1081
spring.application.name=MY_SERVICE
spring.cloud.config.uri=http://localhost:1080
I am trying to access property present in git repo using #Value inside my microservice but it is giving error Could not resolve placeholder 'third-party-cred' in value "${third-party-cred}"
Solution
bootstrap.properties is not enable by default. Please add this dependency inside your microservice.
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-bootstrap</artifactId>
</dependency>

Spring Boot - Initialization Order of Dependencies

I have a Spring Boot Project which uses Jasypt for encrypting properties in the application.yml file.
Jasypt has always initialized and decrypted the passwords, before any dependecy which uses the decrypted password, asked for it.
However I now want to use Azure Key Vault aswell. This dependency now tries to access its properties before they have been decrypted by Jasypt.
How can I change the order in which Spring Boot initializes these dependencies?
For both dependencies I do not have defined any #Bean in the application.
I have created a Demo-Repository.
Its a plain Spring Boot Project. Only thing which is changed is the following:
Added both dependencies in pom.xml:
<!-- Azure Key Vault -->
<dependency>
<groupId>com.microsoft.azure</groupId>
<artifactId>azure-keyvault-secrets-spring-boot-starter</artifactId>
<version>2.2.5</version>
</dependency>
<!-- Jasypt -->
<dependency>
<groupId>com.github.ulisesbocchio</groupId>
<artifactId>jasypt-spring-boot-starter</artifactId>
<version>2.1.2</version>
</dependency>
And in application.yml:
jasypt:
encryptor:
password: test
azure:
keyvault:
enabled: true
uri: ENC(1pGS+OSU9a9Bs+2iAjhyVd8NonXkLp0BsPBOuUzcyJSFnABs+bc5jw==)
client-id: test
client-key: test
tenant-id: test
The Error:
java.lang.IllegalArgumentException: The Azure Key Vault url is malformed.
(...)
Caused by: java.net.MalformedURLException: no protocol: ENC(1pGS+OSU9a9Bs+2iAjhyVd8NonXkLp0BsPBOuUzcyJSFnABs+bc5jw==)
As you can see, first Azure Key Vault Initializes itself, tries to use the azure.keyvault.uri but Jasypt hasn't decrypted it yet.
What I would expect in this case is that it tries to connect but isn't able to connect because the URL doesn't exist. But it atleast should use the decrypted version.
I am greatful for any suggestions.
I actually found the solution with the help of the Jasypt docs on GitHub (Section: Custom Environment)
#SpringBootApplication
public class DemoApplication {
public static void main(String[] args) {
//Doesn't work
//SpringApplication.run(DemoApplication.class, args);
//This works:
new SpringApplicationBuilder().environment(new StandardEncryptableEnvironment())
.sources(DemoApplication.class).run(args);
}
}
(...) While not required in most scenarios could be useful when customizing Spring Boot's init behavior or integrating with certain capabilities that are configured very early, such as Logging configuration. (...)
The important part is that you specify the StandardEncryptableEnvironment.
This will make it that the very first thing Spring (Jasypt) does is decrypt the Variables. Everything else stays in the same order.

Spring Cloud; CloudFoundry; spring.jpa properties

I am using spring cloud to bind services to a spring boot application deployed to CloudFoundry. When running locally, I can pass Java options to the application as follows:
-Dspring.jpa.hibernate.ddl-auto=create-drop
Now I would like to do the same thing when running the application on CloudFoundry. What's the usual way to do this?
An alternative to setting a system property or environment variable is to set this as a Spring property in src/main/resources/application.properties or src/main/resources/application.yml.
application.properties:
spring.jpa.hibernate.ddl-auto=create-drop
application.yml
spring:
jpa:
hibernate:
ddl-auto: create-drop
With this approach, the configuration will be applied regardless of now the app is deployed - locally, on CF, or on another platform.
You can put an env entry in your manifest.yml file like so:
env:
spring.jpa.hibernate.ddl-auto: create-drop
See more information here:
http://docs.cloudfoundry.org/devguide/deploy-apps/manifest.html#env-block

Spring Boot - EnableAutoConfiguration with Exclude not working

I am using the latest spring boot version and I am trying to setup an application but I want to disable the DataSource configuration. My configuration class looks like this:
#Configuration
#ComponentScan
#EnableAutoConfiguration(exclude={DataSourceAutoConfiguration.class})
public class ApiApplicationConfig { }
but when I run the application, I am getting the following stacktrace:
Caused by: org.springframework.beans.factory.BeanCreationException: Cannot determine embedded database driver class for database type NONE. If you want an embedded database please put a supported one on the classpath.
at org.springframework.boot.autoconfigure.jdbc.DataSourceProperties.getDriverClassName(DataSourceProperties.java:137)
at org.springframework.boot.autoconfigure.jdbc.DataSourceAutoConfiguration$NonEmbeddedConfiguration.dataSource(DataSourceAutoConfiguration.java:116)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:162)
... 31 more
Am I missing anything in my configuration to completely disable datasource configuration? I will be manually setting up a DataSource, so I dont want spring to handle this for me.
This seems to be a weird situation where DataSourceAutoConfiguration.NonEmbeddedDataSourceCondition finds a DataSource class loader, but no DataSource. We had this problem with spring-boot 1.2.2 while running an integration test.
Anyway, we ran gradle dependencies to find out what was pulling in tomcat-jdbc and ended up replacing our spring-boot-jdbc dependency with plain spring-jdbc. If you don't have tomcat-jdbc in your dependencies, it may help to set a breakpoint in DataSourceAutoConfiguration.NonEmbeddedDataSourceCondition.getDataSourceClassLoader() to find out what driver it finds.
When you manually configure your datasource, spring Boot will use your configuration and wouldn't try to initialize embedded datasource.
BTW, Spring boot by default uses these properties from application.properties to create datasource bean:
spring.datasource.url=jdbc:mysql://localhost/test
spring.datasource.username=dbuser
spring.datasource.password=dbpass
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
Take a look at this section of Spring Boot docs for more details about data source auto-configuration
The only thing that helped my exclusion problem was to exclude the tomcat jdbc dependency from the spring configuration:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-jdbc</artifactId>
<exclusions>
<exclusion>
<groupId>org.apache.tomcat</groupId>
<artifactId>tomcat-jdbc</artifactId>
</exclusion>
</exclusions>
</dependency>
I had an issue when using #Configuration, #EnableAutoConfiguration and #ComponentScan while trying to exclude specific configuration classes, the thing is it didn't work!
Eventually I solved the problem by using #SpringBootApplication, which according to Spring documentation does the same functionality as the three above in one annotation.
#SpringBootApplication(exclude= {Foo.class})
public class MySpringConfiguration {}
#Configuration
#EnableAutoConfiguration(exclude = {DataSourceAutoConfiguration.class, DataSourceTransactionManagerAutoConfiguration.class, HibernateJpaAutoConfiguration.class})
By using this we can disable the spring boot embedded database configuration.
Its because when you disable the datasource config, spring boot uses in-memory database which is not present in your classpath. You have to add in-memory database dependency in your classpath -
<dependency>
<groupId>com.h2database</groupId>
<artifactId>h2</artifactId>
<scope>test</scope>
</dependency>
This is the same issue occurs when you using #DataJpaTest for testing.

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