I need some help here. It is redicolous, but my TomCat just does not take the file I want. I am trying to read some properties from a xml file. When I startup tomcat with the WAR file inside it makes a folder "MyApp".
My program points to MyApp\WebContent\myXmlFile.xml
It used to work fine, but i needed to edit the myXmlFile.xml so I did by adding two more properties, but it just doesnt read the new data. How is this even possible? I keep removing the "MyApp" folder from inside tomcat\webapps\ so it makes a new one, but it just keeps getting other data. My code is refreshed, but this file doesn't.
Some help would be appreciated a lot.
I am running Tomcat 7
More detail:
The myXmlFile.xml is inside the WAR file. I am not modifying it in runtime. It is suppose to be some sort of a configuration file. It reads the file once everytime there is a call done to this function. It just reads the xml files and puts properties inside a string.
When i upload the WAR file. I will first use shutdown.bat, than I will use startup.bat when the WAR file is in webapps.
Try restarting Tomcat. In Linux, type
/etc/init.d/tomcat8 restart
Ensure you don't have any other copy of this file with the old values in another folder. I would try to delete (or rename) myXmlFile.xml from the WAR and see what is generated in the Tomcat deploy folder.
Related
I have a spring application packed in war file. If i deploy in tomcat, i can go to file directory and find properties and xml files, and i can make changes, for example the name of the JNDI conexion, i restart the server, and everything is ok with new value. But now i have to deploy my app in weblogic 10.3, i can deploy and it runs, but if i want to change some properties of one properties file, i have to make a new war file and deploy again.
So my question is, how can i find this files without making a new war file? What is the best option to save this properties than can be changed in the future?
I want to make only one deployment, and after this, if changes properties are needed, any user can make this changes as easily as possible, for example changing a value of properties file.
Thanks!
You're probably looking for Weblogic deployment plans.
Read http://docs.oracle.com/cd/E11035_01/wls100/deployment/config.html#wp1065363 for details.
I have developed a web application which will create an xml file based on the user Input. It has some more functionality. I configured my application to store the xml file(s) in the project root folder. When I run it through eclipse It stores in the specified location. But If I manually put the war file in apache tomcat and run the application those newly created xml files are going into bin directory since I used relative path. Now I dont want it to be created under bin directory. I want those files to be created somewhere local in the system. Is there any way to do it ? Or else what is the best way to deal with those xml files. I am using spring MVC.
You could use a variable in your code would contain the first part of the path (the real location where you want to write the file). And inject the value of that variable from a properties file, that way you wouldn't hardcode anything, and still would be able to provide only the relative path in your code.
I am using CLIPSJNI.
What I have is:
Environment clips = new Environment();
clips.load("main.clp");
where main.clp is put in the same level as src and bin folder.
This runs fine in Eclipse. However when I export to JAR. It cannot work.
I understand that there are some problems with the path when we export to JAR.
So I've seen people suggesting using this.getClass().getResourceStream() but this is not the case. Because what I need is the name of the file, not its content.
Any suggestions on how to fix this?
The issue is that the load is being done within the native library on the C side which is being passed a file name as an argument. The C code has no concept of a JAR file or how to extract files embedded within one. I think what you would need to do is always place your .clp files within the JAR file and then have a routine which extracts the data from the JAR file and saves it to a file. You can then load it using the load method and delete the file once done.
I'm trying to read from a text file in Netbeans. In the top level of my project directory I have foo.txt. Then in my code I have:
File file = new File("foo.txt");
It throws a FileNotFoundException, however. It's a Java web application using Spring and Tomcat, but I'm not sure if those details matter since I'm running the whole thing inside Netbeans. Basically, I just want to know where I need to put the file so Netbeans will read it.
Update - good call guys, it's looking in Tomcat's bin directory. Now this may be a stupid question but, how would I go about getting it to look in my top level project directory? I feel like dropping text files into tomcat's bin would be innapropriate.
You can try printing the absolute path of the File object to see where it is looking on the filesystem.
System.out.println(file.getAbsolutePath());
I would use the following to figure out where to put the file:
System.out.println(System.getProperty("user.dir"));
To directly answer your question, If you're running an application on Tomcat, files will be opened from the current working directory. That will likely be the bin/ folder in your tomcat directory.
You can find out for sure where your program is looking by examining the result of file.getAbsolutePath().
However, for web applications, I would suggest putting files you need to read in your classpath so you don't have to depend on a certain file structure when you deploy your web application.
try System.getProperty("user.dir") to get current working directory
I already searched StackOverflow for "properties inside war", but none of the results worked for my case.
I am using Eclipse Galileo and GlassFish v3 to develop a set of web services. I am using a "dynamic web project" with the following structure
Src
-java_code_pkg_1
-java_code_pkg_2
-com.company.config
--configfile.properties WebContent
-META-INF
-WEB-INF
--log4jProperties
--web.xml
--applicationContext.xml
--app-servlet.xml
I want to access the "configfile.properties" inside one of the source files in "java_code_pkg1". I am using the Spring Framework and this file will be instantiated once the application starts on the server.
I have tried the following with no luck
getResourceAsStream("/com.company.config/configfile.properties");
getResourceAsStream("/com/company/config/configfile.properties");
getResourceAsStream("com/company/config/configfile.properties");
getResourceAsStream("/configfile.properties");
getResourceAsStream("configfile.properties");
getResourceBundle(..) didn't work either.
Is it possible to access a file when it's not under the WEB-INF/classes path? if so then how?
Properties props = new Properties();
props.load(this.getClass().getResourceAsStream("/com/company/config/file.properties"));
works when I'm in debug mode. I can see the values in the debugger, but I get a NullPointerException right after executing the "props.load" line and before going into the light below it.
That's a different issue. At least now I know this is the way to access the config file.
Thank you for your help.
If you are in a war, your classpath "current directory" is "WEB-INF/classes". Simply go up two levels.
getResourceAsStream("../../com/company/config/configfile.properties");
It is horrible but it works. At least, it works under tomcat, jboss and geronimo and It works today.
P.S. Your directory structure is not very clear. Perhaps it is:
getResourceAsStream("../../com.company.config/configfile.properties");
Check the location of the properties file in WAR file.
If it is in WEB-INF/classes directory under com/company/config directory
getResourceAsStream("com/company/config/configfile.properties") should work
or getResourceAsStream(" This should work if the config file is not under WEB-INF/classes directoy
Also try using getClass().getClassLoader().getResourceAsStream.
Are you sure the file is being included in your war file? A lot of times, the war build process will filter out non .class files.
What is the path once it is deployed to the server? It's possible to use Scanner to manually read in the resource. From a java file within a package, creating a new File("../applications/") will get you a file pointed at {glassfish install}\domains\{domain name}\applications. Maybe you could alter that file path to direct you to where you need to go?
Since you are using Spring, then use the Resource support in Spring to inject the properties files directly.
see http://static.springsource.org/spring/docs/3.0.x/reference/resources.html
Even if the class that requires the properties file is not Spring managed, you can still get access to the ApplicationContext and use it to load the resource
resource would be something like, classpath:settings.properties, presuming that your properties file got picked up by your build and dropped in the war file.
You can also inject directly, from the docs:
<property name="template" value="classpath:some/resource/path/myTemplate.txt">