Multiple column IN clause spring data jpa - java

Is it possible to have multiple columns in IN clause?
#Query(nativeQuery = true, value = "select * from table where (column1, column2) in (:column1, :column2)")
List<Table> findByColumn1Column2In(#Param("column1") List<BigDecimal> column1, #Param("column2") List<BigDecimal> column2);`
Expecting a query like this:
select * from table where (column1, column2) in ((1,2), (3,4), (5,6))

Since JPA doesn't support multi-columns IN clauses I overcome this by using SQL CONCAT function on the DB values, and of course, on the supplied range values, as follows:
first, create the range we looking for:
List<String> columns;
for (i=0, i<column1.size(), i++){
columns.add(column1.get(i) + '-' + column2.get(i));
}
Modify the query:
#Query(nativeQuery = true,
value = "select * from table where CONCAT(column1, '-', column2) in (:columns)")
List<Table> findByColumn1Column2In(#Param("columns") List<String> columns);
And there you nail that :-)

Multiple column with IN clause in not yet supported by Spring data. You can use #Query annotation for custom query as below:
#Query( "select o from MyObject o where id in :ids" )
List findByIds(#Param("ids") List inventoryIdList);

Yes, It is possible to have multiple "In" clause in a method.
Using spring data jpa and spring boot we can achieve this as below:
For your case you can just write the below method in your repository and it would work fine.
List<Table> findByColumn1InAndColumn2In(List<BigDecimal> column1,List<BigDecimal> column2);

Related

JOOQ - Select count inside select query

I have a problem while converting the following statement into jooq API:
SELECT t1.col1, t1.col2, t1.col3, (SELECT count(*) FROM table2 where table2.col2 = t1.col1)
FROM table1 t1
I tried it with DSL.count() and DSL.selectCount() but I failed while searching a way to add the where clause to the count subquery.
The database is PostgreSQL 9.6.
Lukas suggestion to use DSL.field is the better solution because it preserves the <T> type.
More typesafe version:
TableField<Table1Record, Long> col1 = TABLE1.COL1;
Field<Integer> count = DSL.field(DSL.selectCount().from(TABLE2).where(TABLE2.COL2.eq(col1)));
using(configuration).select(col1, count).from(TABLE1).fetch();
My first (less typesafe) solution:
TableField<Table1Record, Long> col1 = TABLE1.COL1;
Field count = DSL.selectCount().from(TABLE2).where(TABLE2.COL2.eq(col1)).asField("count");
using(configuration).select(col1, count).from(TABLE1).fetch();
Maybe there is a more elegant solution, but it works. The generated query looks like my original query.
Here is another example using DSL.field(...):
Field<Integer> COUNT = DSL.field("COUNT(*) OVER ()", Integer.class);
List<Map<String, Object>> records = DSL.select(ACCESSORY.ID,
ACCESSORY.NAME,
ACCESSORY.TYPE,
ACCESSORY.PRICE,
BRAND.NAME,
COUNT.as("total"))
.from(ACCESSORY)
.innerJoin(BRAND).onKey()
.fetchMaps();
The ResultSet will contain a column called total which will be treated as a type java.lang.Integer. This works with PostgreSQL 9.6.
A detailed description of COUNT(*) OVER () can be found here: here.

createNativeQuery will not return rows in java but will in db2 sql [duplicate]

I know I can pass a list to named query in JPA, but how about NamedNativeQuery? I have tried many ways but still can't just pass the list to a NamedNativeQuery. Anyone know how to pass a list to the in clause in NamedNativeQuery? Thank you very much!
The NamedNativeQuery is as below:
#NamedNativeQuery(
name="User.findByUserIdList",
query="select u.user_id, u.dob, u.name, u.sex, u.address from user u "+
"where u.user_id in (?userIdList)"
)
and it is called like this:
List<Object[]> userList = em.createNamedQuery("User.findByUserIdList").setParameter("userIdList", list).getResultList();
However the result is not as I expected.
System.out.println(userList.size()); //output 1
Object[] user = userList.get(0);
System.out.println(user.length); //expected 5 but result is 3
System.out.println(user[0]); //output MDAVERSION which is not a user_id
System.out.println(user[1]); //output 5
System.out.println(user[2]); //output 7
The above accepted answer is not correct and led me off track for many days !!
JPA and Hibernate both accept collections in native query using Query.
You just need to do
String nativeQuery = "Select * from A where name in :names"; //use (:names) for older versions of hibernate
Query q = em.createNativeQuery(nativeQuery);
q.setParameter("names", l);
Also refer the answers here which suggest the same (I picked the above example from one of them)
Reference 1
Reference 2 which mentioned which cases paranthesis works which giving the list as a parameter
*note that these references are about jpql queries, nevertheless the usage of collections is working with native queries too.
A list is not a valid parameter for a native SQL query, as it cannot be bound in JDBC. You need to have a parameter for each argument in the list.
where u.user_id in (?id1, ?id2)
This is supported through JPQL, but not SQL, so you could use JPQL instead of a native query.
Some JPA providers may support this, so you may want to log a bug with your provider.
Depending on your database/provider/driver/etc., you can, in fact, pass a list in as a bound parameter to a JPA native query.
For example, with Postgres and EclipseLink, the following works (returning true), demonstrating multidimensional arrays and how to get an array of double precision. (Do SELECT pg_type.* FROM pg_catalog.pg_type for other types; probably the ones with _, but strip it off before using it.)
Array test = entityManager.unwrap(Connection.class).createArrayOf("float8", new Double[][] { { 1.0, 2.5 }, { 4.1, 5.0 } });
Object result = entityManager.createNativeQuery("SELECT ARRAY[[CAST(1.0 as double precision), 2.5],[4.1, 5.0]] = ?").setParameter(1, test).getSingleResult();
The cast is there so the literal array is of doubles rather than numeric.
More to the point of the question - I don't know how or if you can do named queries; I think it depends, maybe. But I think following would work for the Array stuff.
Array list = entityManager.unwrap(Connection.class).createArrayOf("int8", arrayOfUserIds);
List<Object[]> userList = entityManager.createNativeQuery("select u.* from user u "+
"where u.user_id = ANY(?)")
.setParameter(1, list)
.getResultList();
I don't have the same schema as OP, so I haven't checked this exactly, but I think it should work - again, at least on Postgres & EclipseLink.
Also, the key was found in: http://tonaconsulting.com/postgres-and-multi-dimensions-arrays-in-jdbc/
Using hibernate, JPA 2.1 and deltaspike data I could pass a list as parameter in query that contains IN clause. my query is below.
#Query(value = "SELECT DISTINCT r.* FROM EVENT AS r JOIN EVENT AS t on r.COR_UUID = t.COR_UUID where " +
"r.eventType='Creation' and t.eventType = 'Reception' and r.EVENT_UUID in ?1", isNative = true)
public List<EventT> findDeliveredCreatedEvents(List<String> eventIds);
can be as simple as:
#Query(nativeQuery =true,value = "SELECT * FROM Employee as e WHERE e.employeeName IN (:names)")
List<Employee> findByEmployeeName(#Param("names") List<String> names);
currently I use JPA 2.1 with Hibernate
I also use IN condition with native query. Example of my query
SELECT ... WHERE table_name.id IN (?1)
I noticed that it's impossible to pass String like "id_1, id_2, id_3" because of limitations described by James
But when you use jpa 2.1 + hibernate it's possible to pass List of string values. For my case next code is valid:
List<String> idList = new ArrayList<>();
idList.add("344710");
idList.add("574477");
idList.add("508290");
query.setParameter(1, idList);
In my case ( EclipseLink , PostGreSQL ) this works :
ServerSession serverSession = this.entityManager.unwrap(ServerSession.class);
Accessor accessor = serverSession.getAccessor();
accessor.reestablishConnection(serverSession);
BigDecimal result;
try {
Array jiraIssues = accessor.getConnection().createArrayOf("numeric", mandayWorkLogQueryModel.getJiraIssues().toArray());
Query nativeQuery = this.entityManager.createNativeQuery(projectMandayWorkLogQueryProvider.provide(mandayWorkLogQueryModel));
nativeQuery.setParameter(1,mandayWorkLogQueryModel.getPsymbol());
nativeQuery.setParameter(2,jiraIssues);
nativeQuery.setParameter(3,mandayWorkLogQueryModel.getFrom());
nativeQuery.setParameter(4,mandayWorkLogQueryModel.getTo());
result = (BigDecimal) nativeQuery.getSingleResult();
} catch (Exception e) {
throw new DataAccessException(e);
}
return result;
Also in query cannot use IN(?) because you will get error like :
Caused by: org.postgresql.util.PSQLException: ERROR: operator does not exist: numeric = numeric[]
'IN(?)' must be swapped to '= ANY(?)'
My solution was based on Erhannis concept.
In jpa, it worked for me
#Query(nativeQuery =true,value = "SELECT * FROM Employee as e WHERE e.employeeName IN (:names)")
List<Employee> findByEmployeeName(#Param("names") List<String> names);
Tried in JPA2 with Hibernate as provider and it seems hibernate does support taking in a list for "IN" and it works. (At least for named queries and I believe it will be similar with named NATIVE queries)
What hibernate does internally is generate dynamic parameters, inside the IN same as the number of elements in the passed in list.
So in you example above
List<Object[]> userList = em.createNamedQuery("User.findByUserIdList").setParameter("userIdList", list).getResultList();
If list has 2 elements the query will look like
select u.user_id, u.dob, u.name, u.sex, u.address from user u "+
"where u.user_id in (?, ?)
and if it has 3 elements it looks like
select u.user_id, u.dob, u.name, u.sex, u.address from user u "+
"where u.user_id in (?, ?, ?)
you should do this:
String userIds ="1,2,3,4,5";
List<String> userIdList= Stream.of(userIds.split(",")).collect(Collectors.toList());
Then, passes like parameter inside your query, like this:
#NamedNativeQuery(name="User.findByUserIdList", query="select u.user_id, u.dob, u.name, u.sex, u.address from user u where u.user_id in (?userIdList)")
It's not possible with standard JPA. Hibernate offers the proprietary method setParameterList(), but it only works with Hibernate sessions and is not available in JPA's EntityManager.
I came up with the following workaround for Hibernate, which is not ideal but almost standard JPA code and has some nice properties to it.
For starters you can keep the named native query nicely separated in a orm.xml file:
<named-native-query name="Item.FIND_BY_COLORS" result-class="com.example.Item">
<query>
SELECT i.*
FROM item i
WHERE i.color IN ('blue',':colors')
AND i.shape = :shape
</query>
</named-native-query>
The placeholder is wrapped in single quotes, so it's a valid native JPA query. It runs without setting a parameter list and would still return correct results when other matching color parameters are set around it.
Set the parameter list in your DAO or repository class:
#SuppressWarnings("unchecked")
public List<Item> findByColors(List<String> colors) {
String sql = getQueryString(Item.FIND_BY_COLORS, Item.class);
sql = setParameterList(sql, "colors", colors);
return entityManager
.createNativeQuery(sql, Item.class)
.setParameter("shape", 'BOX')
.getResultList();
}
No manual construction of query strings. You can set any other parameter as you normally would.
Helper methods:
String setParameterList(String sql, String name, Collection<String> values) {
return sql.replaceFirst(":" + name, String.join("','", values));
}
String getQueryString(String queryName, Class<?> resultClass) {
return entityManager
.createNamedQuery(queryName, resultClass)
.unwrap(org.hibernate.query.Query.class) // Provider specific
.getQueryString();
}
So basically we're reading a query string from orm.xml, manually set a parameter list and then create the native JPA query. Unfortunately, createNativeQuery().getResultList() returns an untyped query and untyped list even though we passed a result class to it. Hence the #SuppressWarnings("unchecked").
Downside: Unwrapping a query without executing it may be more complicated or impossible for JPA providers other than Hibernate. For example, the following might work for EclipseLink (untested, taken from Can I get the SQL string from a JPA query object?):
Session session = em.unwrap(JpaEntityManager.class).getActiveSession();
DatabaseQuery databaseQuery = query.unwrap(EJBQueryImpl.class).getDatabaseQuery();
databaseQuery.prepareCall(session, new DatabaseRecord());
Record r = databaseQuery.getTranslationRow();
String bound = databaseQuery.getTranslatedSQLString(session, r);
String sqlString = databaseQuery.getSQLString();
An alternative might be to store the query in a text file and add code to read it from there.
You can pass in a list as a parameter, but:
if you create a #NamedNativeQuery and use .createNamedQuery(), you don't use named param, you used ?1(positional parameter). It starts with 1, not 0.
if you use .createNativeQuery(String), you can use named param.
You can try this :userIdList instead of (?userIdList)
#NamedNativeQuery(
name="User.findByUserIdList",
query="select u.user_id, u.dob, u.name, u.sex, u.address from user u "+
"where u.user_id in :userIdList"
)

Return single column from multi-group Hibernate projection

What I want to achieve:
Select a susbset of entities that have a property value that exists in a List of values. This list is returned by another Query.
In plain SQL, this can be easily achieved with subqueries. This is the Criteria query that returns the relevant values:
DetachedCriteria subq = DetachedCriteria.forClass(MyClass.class)
.setProjection(
Projections.projectionList()
.add(Projections.alias(Projections.max("interestingVal"), "interestingVal"))
.add(Projections.groupProperty("someval1"))
.add(Projections.groupProperty("someval2"))
.add(Projections.groupProperty("someval3"))
);
I would then like to select the entities that have a value of interesting_val that was returned by the above query. Like so:
List<MyClass> resultList = sessionFactory.getCurrentSession().createCriteria(MyClass.class)
.add(Subqueries.propertyIn("interestingVal", subq))
.list();
Unfortunately, the subq subquery returns a List of Object-arrays with length 4, since I have 4 Projection values. All projection values seem to be automatically added to the SELECT clause. This results in an
SQLSyntaxErrorException: ORA-00913: too many values.
How can I either tell my second Criteria query to only use the first element in the Object array or only retrieve the first column in my subquery?
Instead of propertyIn try propertiesIn.
String[] vals = new String[]{"interestingVal", "someval1", "someval2", "someval3"};
List<MyClass> resultList = sessionFactory.getCurrentSession().createCriteria(MyClass.class)
.add(Subqueries.propertiesIn(vals, subq))
.list();

JPA and JPQL: NoResultException when selecting from multiple tables where one value is null

I'm using Java EE 6 and query a database using JPA's javax.persistence.Entitymanager. I have a JPQL query code snippet that looks like something like this:
Query query = entityManager.createQuery("
select A.propertyX, B.propertyY, C.propertyZ
from TableA A, TableB B, TableC C
where A.id = :id and B.id = A.id and C.type = B.type
");
query.setParameter("id", id);
Object[] result = (Object[]) query.getSingleResult();
Where propertyX/Y/X all are references to other entities. In my case, a matching row from TableA, TableB, and TableC all exist. For the matching rows, TableA.propertyX and TableB.propertyY hold values whereas TableC.propertyZ is null (and non-required).
I expect this to execute and return an Object[] array with values for the first two elements (propertyX and propertyY) and null for the third element (propertyZ).
However, when propertyZ is null, a NoResultException is thrown. If I change the data so that propertyZ is not null, the query executes and returns a value.
Is this expected JPQL behavior?
How can I ensure that my query will behave as I originally expected?
The obvious work-around is to select the entire root entity than any sub-property, e.g. 'C' rather than 'C.propertyZ', and then get the property out of the entity object. However, I'd like for this to work as I expect it to without doing so.
If, for a given row in A and B, there is a row in C where C.type = B.type, but the propertyZ column for that row is null, then you are right that your query should return a record.
However if for that given row in A and B, there is no matching row in C where C.type = B.type, then your query will return no result. This has nothing to do with JPQL, but with SQL
If you want the latter case to still return a record with null in the propertyZ field, you need to use OUTER JOINs
HTH

hibernate SQLquery extract variable

How can I extract variables total, min, max from hibernate SQL queries and assign them to java variables?
(select count(*) as total, min(price) as min, max(price) as max from product).addScalar("total", Hibernate.INTEGER).addScalar("min", Hibernate.INTEGER).addScalar("max", Hibernate.INTEGER);
This post should help you.
Later edit:
String sQuery = "select min(myEntity.x), max(myEntity.y) from MyEntity myEntity";
Query hQuery = session.createQuery(sQuery);
List result = hQuery.list();
Iterator iterator = result.iterator();
while (iterator.hasNext()) {
Object[] row = (Object[])iterator.next();
for (int col = 0; col < row.length; col++) {
System.out.println(row[col]);
}
}
Scalar queries return a List of Object arrays (Object[]) - or a single Object[] in your case.
It is however possible to return non-managed entities using a ResultTransformer. Quoting the Hibernate 3.2: Transformers for HQL and SQL blog post:
SQL Transformers
With native sql returning non-entity
beans or Map's is often more useful
instead of basic Object[]. With
result transformers that is now
possible.
List resultWithAliasedBean = s.createSQLQuery(
"SELECT st.name as studentName, co.description as courseDescription " +
"FROM Enrolment e " +
"INNER JOIN Student st on e.studentId=st.studentId " +
"INNER JOIN Course co on e.courseCode=co.courseCode")
.addScalar("studentName")
.addScalar("courseDescription")
.setResultTransformer( Transformers.aliasToBean(StudentDTO.class))
.list();
StudentDTO dto =(StudentDTO) resultWithAliasedBean.get(0);
Tip: the addScalar() calls were
required on HSQLDB to make it match a
property name since it returns column
names in all uppercase (e.g.
"STUDENTNAME"). This could also be
solved with a custom transformer that
search the property names instead of
using exact match - maybe we should
provide a fuzzyAliasToBean() method
;)
See also
16.1.5. Returning non-managed entities

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