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An illegal attempt was made to upload a document

Response:400 - {"error":"An illegal attempt was made to upload a document"}
Getting the above error while uploading a file through HttpURLconnection Java. Tried all the methods for converting file to bytearray > byte[] bytes = Files.readAllBytes(file.toPath());
and > byte[] bytes = FileUtils.readFileToByteArray(file);
Can anyone help me to fix the code?
public static Response upload(HttpURLConnection connection, String request, String filePath) throws IOException, InterruptedException
{
String response = "";
Integer code = -1;
String boundary = "*****";
String crlf = "\r\n";
String twoHyphens = "--";
String type = "144";
String parentID = "601903197";
connection.setUseCaches(false);
connection.setDoOutput(true); /* indicates POST method */
connection.setDoInput(true);
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Cache-Control", "no-cache");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
File file = new File(filePath);
String fileBaseName = FilenameUtils.getBaseName(file.toString());
request = request.trim();
if (request != "") {
try (DataOutputStream dos = new DataOutputStream(connection.getOutputStream())) {
dos.writeBytes(twoHyphens + boundary + crlf);
dos.writeBytes("Content-Disposition: form-data; name=\"parent_id\""+crlf);
dos.writeBytes("Content-Type: text/plain; charset=utf-8"+crlf);
dos.writeBytes(crlf);
dos.writeBytes(parentID+crlf);
dos.flush();
dos.writeBytes(twoHyphens + boundary + crlf);
dos.writeBytes("Content-Disposition: form-data; name=\"type\""+crlf);
dos.writeBytes("Content-Type: text/plain; charset=utf-8"+crlf);
dos.writeBytes(crlf);
dos.writeBytes(type+crlf);
dos.flush();
dos.writeBytes(twoHyphens + boundary + crlf);
dos.writeBytes("Content-Disposition: form-data; name=\"name\""+crlf);
dos.writeBytes("Content-Type: text/plain; charset=utf-8"+crlf);
dos.writeBytes(crlf);
dos.writeBytes(fileBaseName+crlf);
dos.flush();
dos.writeBytes(twoHyphens + boundary + crlf);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename\""+file.getName()+"\""+crlf);
String mimetype = connection.guessContentTypeFromName(file.getName());
mimetype = mimetype == null ? "application/octet-stream" : mimetype;
dos.writeBytes("Content-Type: " + mimetype + crlf);
dos.writeBytes("Content-Transfer-Encoding: binary"+crlf);
dos.writeBytes(crlf);
FileInputStream inputStream = new FileInputStream(file);
byte[] bytes = new byte[4096];
int bytesRead = -1;
while ((bytesRead = inputStream.read(bytes)) != -1) {
dos.write(bytes, 0, bytesRead);
}
inputStream.close();
dos.writeBytes(crlf);
dos.writeBytes(twoHyphens + boundary + twoHyphens + crlf);
dos.flush();
}
}
code = connection.getResponseCode();
var errorStream = connection.getErrorStream();
InputStream stream = errorStream != null ? errorStream : connection.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(stream));
String inputLine;
StringBuffer responseBuffer = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
responseBuffer.append(inputLine);
}
in.close();
connection.disconnect();
response = responseBuffer.toString();
return new Response(code, response);
}

Android multipart file upload with OkHttp

I am using this for audio records and video file and it is working but i want to replace it with OkHttp. I didnt figure it out. Can anyone help me about it?
public class HttpMultipartUpload {
static String lineEnd = "\r\n";
static String twoHyphens = "--";
static String boundary = "AaB03x87yxdkjnxvi7";
public static String upload(URL url, File file, String fileParameterName, HashMap<String, String> parameters)
throws IOException {
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream dis = null;
FileInputStream fileInputStream = null;
byte[] buffer;
int maxBufferSize = 20 * 1024;
try {
//------------------ CLIENT REQUEST
fileInputStream = new FileInputStream(file);
// open a URL connection to the Servlet
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + fileParameterName
+ "\"; filename=\"" + file.toString() + "\"" + lineEnd);
dos.writeBytes("Content-Type: text/xml" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
buffer = new byte[Math.min((int) file.length(), maxBufferSize)];
int length;
// read file and write it into form...
while ((length = fileInputStream.read(buffer)) != -1) {
dos.write(buffer, 0, length);
}
for (String name : parameters.keySet()) {
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + name + "\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(parameters.get(name));
}
// send multipart form data necessary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
} finally {
if (fileInputStream != null) fileInputStream.close();
if (dos != null) dos.close();
}
//------------------ read the SERVER RESPONSE
try {
dis = new DataInputStream(conn.getInputStream());
StringBuilder response = new StringBuilder();
String line;
while ((line = dis.readLine()) != null) {
response.append(line).append('\n');
}
return response.toString();
} finally {
if (dis != null) dis.close();
}
}
}
How can I change it with OkHttp. Any code please. I dont have good knowledge about on OkHttp. I was using (HttpURLConnection) but it seems not effective now.

See the documentation example on posting form data
https://github.com/square/okhttp/blob/master/samples/guide/src/main/java/okhttp3/recipes/PostMultipart.java
RequestBody requestBody = new MultipartBody.Builder()
.setType(MultipartBody.FORM)
.addFormDataPart("title", "Square Logo")
.addFormDataPart("image", "logo-square.png",
RequestBody.create(
new File("docs/images/logo-square.png"),
MEDIA_TYPE_PNG))
.build();
Request request = new Request.Builder()
.header("Authorization", "Client-ID " + IMGUR_CLIENT_ID)
.url("https://api.imgur.com/3/image")
.post(requestBody)
.build();

Which content-type to use when Uploading sqlite .db file to a server?

I want to upload a .db (SQLite) file from my android app to a server and I'm wondering if I can use "multipart/form-data" as the content-type. Is there any specific type for .db file as for pdf files which is "application/pdf" ?

I actually got it working with just the "multipart/form-data" as the content type. When I tried the 'application/x-sqlite3', I had an error.
Here is the code snippet I used to post the .db file to server, borrowed from this link:
public int uploadFile(String sourceFileUri) {
String fileName = sourceFileUri; // the path to my .db file
HttpURLConnection connection = null;
DataOutputStream dataOutputStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
Log.e("uploadFile", "Source File not exist ");
return 0;
} else {
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true); // Allow Inputs
connection.setDoOutput(true); //Triggers http POST method.
connection.setUseCaches(false); // Don't use a Cached Copy
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("ENCTYPE", "multipart/form-data");
connection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
//conn.setRequestProperty("Content-Type", "application/x-sqlite3; boundary=" + boundary);// when I tried this it didn't work, so you can delete this line
connection.setRequestProperty("uploadedfile", fileName);
dataOutputStream = new DataOutputStream(connection.getOutputStream());
dataOutputStream.writeBytes(twoHyphens + boundary + lineEnd);
dataOutputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=" + fileName + "" + lineEnd);
dataOutputStream.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dataOutputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dataOutputStream.writeBytes(lineEnd);
dataOutputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = connection.getResponseCode();
String serverResponseMessage = connection.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
String msg = "server respose code ";
Log.i(TAG, msg + serverResponseCode);
StringBuilder result = new StringBuilder();
InputStream in = new BufferedInputStream(connection.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
//JSONObject mResponseJSONObject = new JSONObject(String.valueOf(result)); //convert the respons in json
Log.i(TAG, msg + result);
}
//close the streams //
fileInputStream.close();
dataOutputStream.flush();
dataOutputStream.close();
} catch (MalformedURLException ex) {
ex.printStackTrace();
Log.e(TAG, "MalformedURLException Exception : check script url.");
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
e.printStackTrace();
Log.e(TAG, "Upload file to server Exception : " + e.getMessage(), e);
}
return serverResponseCode;
} // End else block
} //[End uploadFileToServer method]
This is php script I used on the server side:
<?php
if(isset($_FILES)) {
if(move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], "./data/".$_FILES["uploadedfile"]["name"]."_".time())) {
echo " file recieved successfully"
exit;
}
}
echo "Error";
?>

java httpurlconnection "failed to read: line to long:"

I'm using httpurlconnection for uploading files to different servers.
For some hosts the following code is working and I'm able to upload files, but when I'm trying to upload to another host, I get an error message
"failed to read: line too long: \nContent-Disposition: form-data; name...
What does this error mean? I couldn't find any hints with google. Hope you can help. :)
private void upload(){
response = "";
DataOutputStream outputStream = null;
InputStream inputStream = null;
String twoHyphens = "--";
String boundary = "--------"+Long.toString(System.currentTimeMillis());
String lineEnd = "\n";
try {
File file = getFile();
StringBuffer sb = new StringBuffer();
sb.append(twoHyphens + boundary + lineEnd);
sb.append("Content-Disposition: form-data; name=\"file1\"; filename=\"" + getFilename() +"\"" + lineEnd);
sb.append("Content-Type: " + getMime() + lineEnd);
sb.append("Content-Transfer-Encoding: binary" + lineEnd);
sb.append(lineEnd);
FileInputStream fileInputStream = new FileInputStream(file);
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setFixedLengthStreamingMode((uploadContainer.getFilesize() + sb.length() + lineEnd.length() + twoHyphens.length() + boundary.length() + twoHyphens.length() + lineEnd.length()));
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("User-Agent", USER_AGENT);
connection.setRequestProperty("Content-Type", "multipart/form-data; boundary="+boundary);
outputStream = new DataOutputStream(connection.getOutputStream());
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream.writeBytes("Content-Disposition: form-data; name=\"file1\"; filename=\"" + getFilename() +"\"" + lineEnd);
outputStream.writeBytes("Content-Type: " + getMime() + lineEnd);
outputStream.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
outputStream.writeBytes(lineEnd);
int bytesRead = -1;
byte[] buffer = new byte[4096];
boolean cancelled = false;
while ((bytesRead = fileInputStream.read(buffer)) > 0){
outputStream.write(buffer, 0, bytesRead);
if(Thread.currentThread().isInterrupted()){
cancelled = true;
break;
}
}
if(cancelled == false){
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
outputStream.flush();
inputStream = connection.getInputStream();
response = convertStreamToString(inputStream);
inputStream.close();
} else {
// ...
}
fileInputStream.close();
} catch(Exception e) {/e.printStackTrace();
} finally {
try {
outputStream.close();
} catch (IOException e) {e.printStackTrace();
}
}
}

String lineEnd = "\n";
The problem is here. The line terminator in HTTP is defined as \r\n, not \n.

Get the upload progress

My upload method as below:
private void upload(String Server, String FilePath, String SavePath, String NewName) {
String end = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
try {
URL url = new URL(ActionUrl);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setDoInput(true);
con.setDoOutput(true);
con.setUseCaches(false);
con.setRequestMethod("POST");
con.setRequestProperty("Connection", "Keep-Alive");
con.setRequestProperty("Accept", "text/*");
con.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
ds = new DataOutputStream(con.getOutputStream());
ds.writeBytes(twoHyphens + boundary + end);
ds.writeBytes("Content-Disposition: form-data;" + "name=\"folder\"" + end + end);
ds.write(SavePath.getBytes("UTF-8"));
ds.writeBytes(end);
ds.writeBytes(twoHyphens + boundary + end);
ds.writeBytes("Content-Disposition: form-data;" + "name=\"Filedata\"; filename=\"");
ds.write(NewName.getBytes("UTF-8"));
ds.writeBytes("\"" + end);
ds.writeBytes(end);
FileInputStream fStream = new FileInputStream(uploadFile);
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int length = -1;
while((length = fStream.read(buffer)) != -1) {
ds.write(buffer, 0, length);
}
ds.writeBytes(end);
ds.writeBytes(twoHyphens + boundary + twoHyphens + end);
fStream.close();
ds.flush();
InputStream is = con.getInputStream();
int ch;
StringBuffer b = new StringBuffer();
while((ch = is.read()) != -1) {
b.append((char)ch);
}
System.out.println("UPLOAD" + "SUCCESS");
ds.close();
}
catch(Exception e) {
e.printStackTrace();
}
}
I found the line InputStream is = con.getInputStream(); spend most time.
But how to get the progress of it send?
Or how to modify my method to upload file "by parts"?

You can try following code,
First display a Progress Dialog Before calling your upload method,
progDailog = ProgressDialog.show(loginAct,"Process ", "please wait....",true,true);
new Thread ( new Runnable()
{
public void run()
{
// your uploading code goes here
}
}).start();
Handler progressHandler = new Handler()
{
public void handleMessage(Message msg1)
{
progDailog.dismiss();
}
}