I have a web application that read an argument from tomcat -D option and decide which property file should be used. So, How can I set below property in hibernate xml? Here What I want to do:
run tomcat with -Doption=xOption
Singleton Config class load xOption.properties
<hibernate-configuration>
<property name="hibernate.connection.url">Config.getinstance().getValue("dbUrl")</property>
</hibernate-configuration>
I get used to do it with using hibernate java config. Is there anyway to do it in xml file?
Related
I have this structure in my Jboss 6.4, and I need to access outside of the war to another folder to take the configuration for Hibernate:
/usr/webapps/MYAPP/deployments/MYAPP.war
/usr/webapps/MYAPP/appconfig/hibernate.properties
I have to use this pattern, and I'm using Hibernate 4.2, in my case I need to take the content of the properties file to use it in my hibernate.cfg.xml like here:
<property name="connection.driver_class">${db.driver}</property>
<property name="hibernate.dialect">${db.dialect}</property>
<property name="hibernate.connection.url">${db.url}</property>
<property name="hibernate.connection.username">${db.username}</property>
<property name="hibernate.connection.password">${db.password}</property>
hibernate.properties:
db.username=usernameTest
db.password=passwordTest
db.driver=driverTest
db.url=urlTest
db.dialect=dialectTest
What should be the best practice to do this, I was watching some cases with Spring here, but in my case it's only with JEE
I want to read an external properties file when launching Jboss 4.2 . I want to add it to the classpath to read it from a WAR file . I have seen different solutions with Jboss 6 using modules, but I haven't seen anything related to JBoss 4.2.
I have included inside 'jboss-service.xml' the following code :
<!-- Bean for reading properties -->
<mbean code="org.jboss.varia.property.SystemPropertiesService"
name="jboss.util:type=Service,name=SystemProperties">
<!-- Load properties from each of the given comma separated URLs -->
<attribute name="URLList">
./conf/path.tmview.properties
</attribute>
</mbean>
In this file I have defined the property :
property-placeholder filepath=/var/tmview_props/tmview/tmview.properties
This property is used in the following bean definition
<bean id="tmviewConfigurerLocation" class="org.springframework.core.io.FileSystemResource">
<constructor-arg value="${property-placeholder-filepath}" />
</bean>
inside an applicationContext.xml . When I launch jboss, the file of properties is read
15:45:29,939 INFO [SystemPropertiesService] Loaded system properties
from: file:/D:/devel/projects/tmview/deployment/jboss-
...ver/tmview/conf/path.tmview.properties
So, the property is read, but I kept obtaining the following exception
2015-03-24 15:45:39,219 ERROR
[org.springframework.web.context.ContextLoader] Context
initialization failed
org.springframework.beans.factory.BeanInitializationException: Could
not load properties; nested exception is
java.io.FileNotFoundException: ${property-placeholder-filepath} (The
system cannot find the file specified)
at
org.springframework.beans.factory.config.PropertyResourceConfigurer.
postProcessBeanFactory(PropertyResourceConfigurer.java:78)
Is there any special way to read the property inside the spring bean ?
In jboss 4 you was able to drop property files in the <jboss_home>/server/<instance>/conf directory and they would be available from the classpath.
Another possibility is add your custom directory to the classpath, to do this see Adding second conf folder to JBoss 5.1.0
Ok . At the end , I solved the problem . It seems the problem was located in reading from application-context.xml .
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>file:${tmview.conf.variables}</value>
</property>
</bean>
I had to add a property placeholder reader . Regarding to jboss, you can read the parameter file either from conf/jboss-service.xml or deploy/properties-receive.xml, but it seems more appropiate to do the reading from the second one .
I am trying to use Hibernate 3.2.5 with Play framework 1.2.5
In Hibernate I am having two files:
1) cfg.xml file (containing the db config details along with some additional properties
2) hbm.xml file (containing the mapping between the java bean and the db table
For getting connected to the oracle 10g db, I am providing the db details in the application.config files like this and the connection is successful also when I start the server:
db.url=jdbc:oracle:thin:#localhost:1521/orcl
db.driver=oracle.jdbc.OracleDriver
db.user=system
db.pass=tiger
I want to know Where will I place the hbm.xml file (for mapping details) and the cfg.xml file for the remaining properties other than db connecion details?
Please let me know about this.
Regards,
Starting from the root directory of your application:
the hibernate.cfg.xml must be placed inside the app directory
the mapping files (the hbm files) where your models classes are defined, usually inside the app/models/ directory
Inside your hibernate.cfg.xml the mapping attributes should be something like:
<mapping class="models.yourHmbFile1"/>
<mapping class="models.yourHmbFile2"/>
Btw, I find easy to use the hibernate annotations instead of the hbm - xml mapping. Easier to write and to mantain.
If you prefer to annotate your model classes, you can delete the hbm files and directly map your annotated classes in your hibernate.cfg.xml.
In the application.conf you've to specify the data you have already added:
db.url=jdbc:oracle:thin:#localhost:1521/orcl
db.driver=oracle.jdbc.OracleDriver
db.user=system
db.pass=tiger
Also in the hibernate.cfg.xml you need to specify the connection data:
<property name="hibernate.dialect">...</property>
<property name="hibernate.connection.driver_class">...</property>
<property name="hibernate.connection.url">...</property>
<property name="hibernate.connection.username">...</property>
<property name="hibernate.connection.password">...</property>
I'm working in a Java Web Project.
I need to change the folder of the files "jdbc.properties" and "log4j.properties" depending of the environment, because testing, demo and release have diferent values for those files.
I have this folders and subfolders:
c:\myProject\conf\dev
c:\myProject\conf\test
c:\myProject\conf\demo
I need to put diferent jdbc.properties and log4j.properties files in each of those folders
c:\myProject\conf\dev\log4j.properties
c:\myProject\conf\dev\jdbc.properties
c:\myProject\conf\test\log4j.properties
c:\myProject\conf\test\jdbc.properties
c:\myProject\conf\demo\log4j.properties
c:\myProject\conf\demo\jdbc.properties
The three project are in the same Server and in the same Apache (It is a Web Project)
First i made some changes to use a windows system variable to get the parent folder (c:\myProject). To do that, i made this on Spring appContext file:
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>file:${PARENT_FOLDER}/conf/dev/jdbc.properties</value>
</property>
</bean>
"PARENT_FOLDER" is defined on Windows environment variables/system variable
Those changes works OK.
But, as you can see, I always loking for file on "/conf/dev"
I need to make dynamic the "dev" part of the path.
I Can't use Windows environment variables/system variable because the 3 environments are deployed on the same Server.
I'm trying to use a "property" (using ) on web.xml, but I don't know how to find the property in my Spring appContext file.
I definy the property like this:
<env-entry>
<env-entry-name>ENVIRONMENT</env-entry-name>
<env-entry-type>java.lang.String</env-entry-type>
<env-entry-value>Dev</env-entry-value>
</env-entry>
But I don't know how to access "ENVIRONMENT" property on Spring
I don't know what to do. I a little desperate
Can someone help me?
Thanks and sorry for my poor english
Have you considered using JNDI?
With JNDI you will define the db connection properties inside tomcat itself. This way your spring configuration is independent of the environment and you can deploy the same war on all environments. See also this.
If you need to run it locally that you can always use the 'new' spring environment profiles feature.
Other option (if JNDI is not an option and assuming you use maven) is the maven replacer plugin where you will generate the db.properties at build time.
Most or all the core hibernate configuration properties can be specified in a startup properties file, as an alternative to specifying mappings in hibernate.cfg.xml.
Is there an easy way to specify mappings of annotated classes in a properties file?
You can map annotated classes like this in the hibernate.cfg.xml configuration:
<session-factory>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
...
<mapping class="com.annotated.classes.EntityOne"/>
</session-factory>
Similar configuration can be written using a properties file i.e. hibernate.properties
hibernate.connection.driver_class = com.mysql.jdbc.Driver
hibernate.mapping = ???
What I haven't figured out is how to specify the mapping of annotated classes (entities) using the properties configuration, if this is possible.
I don't think there is any way to specify entities in the properties file.
I suppose you could create your own custom initialization code using Configuration to accomplish what you are looking for. The problem with using a properties file, though, is that you cannot specify a property with a list of values unless you identify a way to split the value into a list. You would then need to write code that parses the value accordingly.