How to use Java 8 `Files.find` method? - java

I am trying to write an app to use Files.find method in it.
Below program works perfectly :
package ehsan;
/* I have removed imports for code brevity */
public class Main {
public static void main(String[] args) throws IOException {
Path p = Paths.get("/home/ehsan");
final int maxDepth = 10;
Stream<Path> matches = Files.find(p,maxDepth,(path, basicFileAttributes) -> String.valueOf(path).endsWith(".txt"));
matches.map(path -> path.getFileName()).forEach(System.out::println);
}
}
This works fine and gives me a list of files ending with .txt ( aka text files ) :
hello.txt
...
But below program does not show anything :
package ehsan;
public class Main {
public static void main(String[] args) throws IOException {
Path p = Paths.get("/home/ehsan");
final int maxDepth = 10;
Stream<Path> matches = Files.find(p,maxDepth,(path, basicFileAttributes) -> path.getFileName().equals("workspace"));
matches.map(path -> path.getFileName()).forEach(System.out::println);
}
}
But it does not show anything :(
Here is my home folder hiearchy (ls result) :
blog Projects
Desktop Public
Documents Templates
Downloads The.Purge.Election.Year.2016.HC.1080p.HDrip.ShAaNiG.mkv
IdeaProjects The.Purge.Election.Year.2016.HC.1080p.HDrip.ShAaNiG.mkv.aria2
Music Videos
Pictures workspace
So whats going wrong with path.getFileName().equals("workspace")?

Path.getFilename() does not return a String, but a Path object, do this:
getFilename().toString().equals("workspace")

Use the following and look at the console. Maybe none of your files contains workspace in it
Files.find(p,maxDepth,(path, basicFileAttributes) -> {
if (String.valueOf(path).equals("workspace")) {
System.out.println("FOUND : " + path);
return true;
}
System.out.println("\tNOT VALID : " + path);
return false;
});

Related

How to list folders and files from different paths stored in a json file - Java

I want to list all the folders and files from different paths stored in a json file in order to delete them later with a filter. In the folowing code I list the folders using the FILE class and only one path.
public class Depurador {
public static void main(String[] args) {
File ruta = new File("C:\\Users\\erick\\Desktop\\prueba");
ImprimirFicheros1(ruta, 0);
}
public static void ImprimirFicheros1(File file, int nivelArbol){
for(int i = 0; i < nivelArbol; i++){
System.out.print("-");
}
System.out.println(file.getName());
if(file.isDirectory()){
File[] listaFicheros = file.listFiles();
for(File fichero : listaFicheros){
ImprimirFicheros1(fichero, nivelArbol + 2);
}
}
}
I would like to list all the folders and files from this json file and not only from one path.
{
"Directorios":[
{
"ruta": "C:\\Users\\erick\\Desktop\\prueba",
"periodo": 15,
"archivos":["yyyy-mm-dd_reportesdetalles_1.csv, yyyy-mm-dd_reportesdetalles_2.csv"]
},
{
"ruta": "C:\\Users\\erick\\Desktop\\test",
"periodo": 20,
"archivos":["yyyy-mm-dd_test_1.csv, yyyy-mm-dd_test_2.csv"]
}
]
}
You will need to deserialize the JSON string into object. You can use a library like jackson ObjectMapper
class Directory {
private String ruta;
private int periodo;
private List<String> archivos;
// getters and setters
}
or use a record (java 14+)
public record Directory(String ruta, int periodo, List<String> archivos) {}
public record Input(List<Directory> Directorios) {}
In your main function you can do this now.
// triple quote text block is java 13+
String jsonString = """
{
"Directorios":[
{
"ruta": "C:\\Users\\erick\\Desktop\\prueba",
"periodo": 15,
"archivos":["yyyy-mm-dd_reportesdetalles_1.csv, yyyy-mm-dd_reportesdetalles_2.csv"]
},
{
"ruta": "C:\\Users\\erick\\Desktop\\test",
"periodo": 20,
"archivos":["yyyy-mm-dd_test_1.csv, yyyy-mm-dd_test_2.csv"]
}
]
}
""";
List<Directory> directories = new com.fasterxml.jackson.databind.ObjectMapper().readValue(jsonString, Input.class).getDirectorios();
for (Directory d : directories) {
File ruta = new File(d.getRuta());
ImprimirFicheros1(ruta, 0);
}

JDT ASTParser: Cannot resolve to a type/variable

I'm new here and I'm currently working on a standalone source code parser with eclipse-jdt. I have currently an issue that I can't get any further with. The source code parser should write (in this case) a compiler message in a log file:
The following code is from a visitor:
for (IProblem problem : problems) {
if (problem.isError()) {
final String msg = "Problem count: " + problems.length + " in " + resource.getAbsolutePath()
+ "\n\tERROR: " + problem.getSourceLineNumber() + " > " + problem.getMessage();
logger.log(Level.INFO, msg);
continue; // do not count errors
}
// ...
logCompilerMessage(getFullQualifiedName(), mainAuthor, problem);
}
For an example, while parsing the method readData:
package testproj.pckg.billing;
//...
public class Bill {
private boolean readData(MODETYPE modeType) {
// MODETYPE is an enum in other class but in the same package
}
}
The program will "classified" the enum MODETYPE as a error which is in class Bill2.java:
package testproj.pckg.billing;
// ...
public class Bill2 {
// ...
}
enum MODETYPE {
// ...
}
The output will be looking like this:
Problem count: 8 in E:\ws\preview\project\src\testproj\pckg\billing\Bill.java
ERROR: 1925 > MODETYPE cannot be resolved to a type
And this is my parse method:
private void parse(ProjectInfo project, File resource) {
final ASTParser parser = ASTParser.newParser(AST.JLS11);
parser.setResolveBindings(true);
parser.setBindingsRecovery(true);
parser.setStatementsRecovery(true);
parser.setKind(ASTParser.K_COMPILATION_UNIT);
parser.setCompilerOptions(project.getCompilerOptions());
final Path sourcePath = Paths.get(resource.toURI());
final char[] source = sourceToChar(sourcePath);
if (source == null) {
return;
}
parser.setSource(source);
parser.setUnitName(resource.getName());
final String[] sources = project.getProjectRelatedSources();
final String[] classpaths = project.getProjectRelatedClasspaths();
final String[] encoders = listOfEncoders(sources);
parser.setEnvironment(classpaths, sources, encoders, true);
// accept visitor(s)
}
EDIT: I forgot to show you my getCompilerOptions method:
private Map<String, String> getCompilerOptions(ProjectInfo project) {
final Map<String, String> list = JavaCore.getOptions();
list.put(JavaCore.COMPILER_SOURCE, JavaCore.VERSION_11);
list.put(JavaCore.COMPILER_COMPLIANCE, JavaCore.VERSION_11);
list.put(JavaCore.COMPILER_CODEGEN_TARGET_PLATFORM, JavaCore.ENABLED);
list.put(JavaCore.COMPILER_DOC_COMMENT_SUPPORT, JavaCore.ENABLED);
final Config config = new Config(project.getProjectPath() + File.separator + ".settings",
"org.eclipse.jdt.core.prefs");
for (String key : config.keySet()) {
list.put(key, config.value(key));
}
return list;
}
Config is just a handler for property file which I used to initialize the program. In this case, I read the property file org.eclipse.jdt.core.prefs from the eclipse project and return it as a Map.
Everything is working and correctly detected on our IDE but somehow not on the standalone parser.
Can someone help me with it? Thank you in advice!
Best regards,
lftdbmr

Play Framework 2.3.x ByteChunks MP3 streaming has no playback, is not 'scrollable' in the browser

Using Play Framework (version 2.3.x) (Java style), I am trying to serve an .mp3 file to the browser. Since it is a 'large' file I have decided to go with Play's ByteChunks Object, as follows.
#With(MP3Headers.class)
public static Result test() {
Chunks<byte[]> chunks = new ByteChunks() {
public void onReady(Chunks.Out<byte[]> out) {
try {
byte[] song = Files.readAllBytes(Paths.get("public/mp3/song.mp3"));
out.write(song);
} catch(Exception e) {
e.printStackTrace();
} finally {
out.close();
}
}
};
return ok(chunks);
}
For clarification, my Mp3Headers file, which is responsable for setting the headers so that the browser knows what type the payload has:
public class MP3Headers extends Action.Simple {
public Promise<Result> call(Http.Context ctx) throws Throwable {
ctx.response().setContentType("audio/mpeg");
return delegate.call(ctx);
}
}
For completion, my routes file:
# Routes
# This file defines all application routes (Higher priority routes first)
# ~~~~
# Home page
GET / controllers.Application.index()
GET /test controllers.Application.test()
# Map static resources from the /public folder to the /assets URL path
GET /assets/*file controllers.Assets.at(path="/public", file)
As is to be expected, navigating to localhost:9000/test renders to a nice HTML5 audio player (see picture).
The problem I have is that 'scrolling' in the audio player does not work. If I do scroll, the music pauses, and when I let go (when I 'chose' a position in time), it continues where it first paused.
I hope that I make sense, and I hope that you guys know something more about this. Thanks in advance.
You will need to tell your browser that your server support range requests and implement the ranges responses (ie just provide the part of the music the browser needs). You can get an overview of the request/response cycle in this answer.
#With(MP3Headers.class)
public static Result test() {
final int begin, end;
final boolean isRangeReq;
response().setHeader("Accept-Ranges", "bytes");
if (request().hasHeader("RANGE")) {
isRangeReq = true;
String[] range = request().getHeader("RANGE").split("=")[1].split("-");
begin = Integer.parseInt(range[0]);
if (range.length > 1) {
end = Integer.parseInt(range[1]);
} else {
end = song.length-1;
}
response().setHeader("Content-Range", String.format("bytes %d-%d/%d", begin, end, song.length));
} else {
isRangeReq = false;
begin = 0;
end = song.length - 1;
}
Chunks<byte[]> chunks = new ByteChunks() {
public void onReady(Chunks.Out<byte[]> out) {
if(isRangeReq) {
out.write(Arrays.copyOfRange(song, begin, end));
} else {
out.write(song);
}
out.close();
}
};
response().setHeader("Content-Length", (end - begin + 1) + "");
if (isRangeReq) {
return status(206, chunks);
} else {
return status(200, chunks);
}
}
Note that in this code the song was already loaded in song. Also the parsing of the RANGE header is very dirty (you can get values like RANGE:)
I Found this code very easy implementation.
Put the below action and its private helper method in your controller.
Controller Action
public static Result file(Long id, String filename) throws IOException {
Item item = Item.fetch(id);
File file = item.getFile();
if(file== null || !file.exists()) {
Logger.error("File no longer exist item"+id+" filename:"+filename);
return notFound();
}
String rangeheader = request().getHeader(RANGE);
if(rangeheader != null) {
String[] split = rangeheader.substring("bytes=".length()).split("-");
if(Logger.isDebugEnabled()) { Logger.debug("Range header is:"+rangeheader); }
if(split.length == 1) {
long start = Long.parseLong(split[0]);
long length = file.length()-1l;
return stream(start, length, file);
} else {
long start = Long.parseLong(split[0]);
long length = Long.parseLong(split[1]);
return stream(start, length, file);
}
}
// if no streaming is required we simply return the file as a 200 OK
if(Play.isProd()) {
response().setHeader("Cache-Control", "max-age=3600, must-revalidate");
}
return ok(file);
}
Stream Helper method
private static Result stream(long start, long length, File file) throws IOException {
FileInputStream fis = new FileInputStream(file);
fis.skip(start);
response().setContentType(MimeTypes.forExtension("mp4").get());
response().setHeader(CONTENT_LENGTH, ((length - start) +1l)+"");
response().setHeader(CONTENT_RANGE, String.format("bytes %d-%d/%d", start, length,file.length()));
response().setHeader(ACCEPT_RANGES, "bytes");
response().setHeader(CONNECTION, "keep-alive");
return status(PARTIAL_CONTENT, fis);
}
Complete example link is here Byte range requests in Play 2 Java Controllers

Job failed Exception hadoop

I am using multi text output formate to create multiple files of a single file i.e each line on new file.
This is my code:
public class MOFExample extends Configured implements Tool {
private static double count = 0;
static class KeyBasedMultipleTextOutputFormat extends
MultipleTextOutputFormat<Text, Text> {
#Override
protected String generateFileNameForKeyValue(Text key, Text value,
String name) {
return count++ + "_";// + name;
}
}
/**
* The main job driver.
*/
public int run(final String[] args) throws Exception {
Path csvInputs = new Path(args[0]);
Path outputDir = new Path(args[1]);
JobConf jobConf = new JobConf(super.getConf());
jobConf.setJarByClass(MOFExample.class);
jobConf.setMapperClass(IdentityMapper.class);
jobConf.setInputFormat(KeyValueTextInputFormat.class);
jobConf.setOutputFormat(KeyBasedMultipleTextOutputFormat.class);
jobConf.setOutputValueClass(Text.class);
jobConf.setOutputKeyClass(Text.class);
FileInputFormat.setInputPaths(jobConf, csvInputs);
FileOutputFormat.setOutputPath(jobConf, outputDir);
//jobConf.setNumMapTasks(4);
jobConf.setNumReduceTasks(4);
return JobClient.runJob(jobConf).isSuccessful() ? 0 : 1;
}
public static void main(final String[] args) throws Exception {
int res = ToolRunner.run(new Configuration(), new MOFExample(), args);
System.exit(res);
}
}
This code runs fine on small text file but when the number of lines of input file are greater than 1900 which is yet not a large file it throws an exception:
Exception in thread "main" java.io.IOException: Job failed!
at org.apache.hadoop.mapred.JobClient.runJob(JobClient.java:836)
at MOFExample.run(MOFExample.java:57)
at org.apache.hadoop.util.ToolRunner.run(ToolRunner.java:70)
at MOFExample.main(MOFExample.java:61)
I also tried this tutorial but this one returns empty output directory without any exception when the input file is large however this one also worked fine with small input file.
Note: I am using Single-Node Cluster

How to list the files inside a JAR file?

I have this code which reads all the files from a directory.
File textFolder = new File("text_directory");
File [] texFiles = textFolder.listFiles( new FileFilter() {
public boolean accept( File file ) {
return file.getName().endsWith(".txt");
}
});
It works great. It fills the array with all the files that end with ".txt" from directory "text_directory".
How can I read the contents of a directory in a similar fashion within a JAR file?
So what I really want to do is, to list all the images inside my JAR file, so I can load them with:
ImageIO.read(this.getClass().getResource("CompanyLogo.png"));
(That one works because the "CompanyLogo" is "hardcoded" but the number of images inside the JAR file could be from 10 to 200 variable length.)
EDIT
So I guess my main problem would be: How to know the name of the JAR file where my main class lives?
Granted I could read it using java.util.Zip.
My Structure is like this:
They are like:
my.jar!/Main.class
my.jar!/Aux.class
my.jar!/Other.class
my.jar!/images/image01.png
my.jar!/images/image02a.png
my.jar!/images/imwge034.png
my.jar!/images/imagAe01q.png
my.jar!/META-INF/manifest
Right now I'm able to load for instance "images/image01.png" using:
ImageIO.read(this.getClass().getResource("images/image01.png));
But only because I know the file name, for the rest I have to load them dynamically.
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
if (src != null) {
URL jar = src.getLocation();
ZipInputStream zip = new ZipInputStream(jar.openStream());
while(true) {
ZipEntry e = zip.getNextEntry();
if (e == null)
break;
String name = e.getName();
if (name.startsWith("path/to/your/dir/")) {
/* Do something with this entry. */
...
}
}
}
else {
/* Fail... */
}
Note that in Java 7, you can create a FileSystem from the JAR (zip) file, and then use NIO's directory walking and filtering mechanisms to search through it. This would make it easier to write code that handles JARs and "exploded" directories.
Code that works for both IDE's and .jar files:
import java.io.*;
import java.net.*;
import java.nio.file.*;
import java.util.*;
import java.util.stream.*;
public class ResourceWalker {
public static void main(String[] args) throws URISyntaxException, IOException {
URI uri = ResourceWalker.class.getResource("/resources").toURI();
Path myPath;
if (uri.getScheme().equals("jar")) {
FileSystem fileSystem = FileSystems.newFileSystem(uri, Collections.<String, Object>emptyMap());
myPath = fileSystem.getPath("/resources");
} else {
myPath = Paths.get(uri);
}
Stream<Path> walk = Files.walk(myPath, 1);
for (Iterator<Path> it = walk.iterator(); it.hasNext();){
System.out.println(it.next());
}
}
}
erickson's answer worked perfectly:
Here's the working code.
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
List<String> list = new ArrayList<String>();
if( src != null ) {
URL jar = src.getLocation();
ZipInputStream zip = new ZipInputStream( jar.openStream());
ZipEntry ze = null;
while( ( ze = zip.getNextEntry() ) != null ) {
String entryName = ze.getName();
if( entryName.startsWith("images") && entryName.endsWith(".png") ) {
list.add( entryName );
}
}
}
webimages = list.toArray( new String[ list.size() ] );
And I have just modify my load method from this:
File[] webimages = ...
BufferedImage image = ImageIO.read(this.getClass().getResource(webimages[nextIndex].getName() ));
To this:
String [] webimages = ...
BufferedImage image = ImageIO.read(this.getClass().getResource(webimages[nextIndex]));
I would like to expand on acheron55's answer, since it is a very non-safe solution, for several reasons:
It doesn't close the FileSystem object.
It doesn't check if the FileSystem object already exists.
It isn't thread-safe.
This is somewhat a safer solution:
private static ConcurrentMap<String, Object> locks = new ConcurrentHashMap<>();
public void walk(String path) throws Exception {
URI uri = getClass().getResource(path).toURI();
if ("jar".equals(uri.getScheme()) {
safeWalkJar(path, uri);
} else {
Files.walk(Paths.get(path));
}
}
private void safeWalkJar(String path, URI uri) throws Exception {
synchronized (getLock(uri)) {
// this'll close the FileSystem object at the end
try (FileSystem fs = getFileSystem(uri)) {
Files.walk(fs.getPath(path));
}
}
}
private Object getLock(URI uri) {
String fileName = parseFileName(uri);
locks.computeIfAbsent(fileName, s -> new Object());
return locks.get(fileName);
}
private String parseFileName(URI uri) {
String schemeSpecificPart = uri.getSchemeSpecificPart();
return schemeSpecificPart.substring(0, schemeSpecificPart.indexOf("!"));
}
private FileSystem getFileSystem(URI uri) throws IOException {
try {
return FileSystems.getFileSystem(uri);
} catch (FileSystemNotFoundException e) {
return FileSystems.newFileSystem(uri, Collections.<String, String>emptyMap());
}
}
There's no real need to synchronize over the file name; one could simply synchronize on the same object every time (or make the method synchronized), it's purely an optimization.
I would say that this is still a problematic solution, since there might be other parts in the code that use the FileSystem interface over the same files, and it could interfere with them (even in a single threaded application).
Also, it doesn't check for nulls (for instance, on getClass().getResource().
This particular Java NIO interface is kind of horrible, since it introduces a global/singleton non thread-safe resource, and its documentation is extremely vague (a lot of unknowns due to provider specific implementations). Results may vary for other FileSystem providers (not JAR). Maybe there's a good reason for it being that way; I don't know, I haven't researched the implementations.
So I guess my main problem would be, how to know the name of the jar where my main class lives.
Assuming that your project is packed in a Jar (not necessarily true!), you can use ClassLoader.getResource() or findResource() with the class name (followed by .class) to get the jar that contains a given class. You'll have to parse the jar name from the URL that gets returned (not that tough), which I will leave as an exercise for the reader :-)
Be sure to test for the case where the class is not part of a jar.
I've ported acheron55's answer to Java 7 and closed the FileSystem object. This code works in IDE's, in jar files and in a jar inside a war on Tomcat 7; but note that it does not work in a jar inside a war on JBoss 7 (it gives FileSystemNotFoundException: Provider "vfs" not installed, see also this post). Furthermore, like the original code, it is not thread safe, as suggested by errr. For these reasons I have abandoned this solution; however, if you can accept these issues, here is my ready-made code:
import java.io.IOException;
import java.net.*;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.Collections;
public class ResourceWalker {
public static void main(String[] args) throws URISyntaxException, IOException {
URI uri = ResourceWalker.class.getResource("/resources").toURI();
System.out.println("Starting from: " + uri);
try (FileSystem fileSystem = (uri.getScheme().equals("jar") ? FileSystems.newFileSystem(uri, Collections.<String, Object>emptyMap()) : null)) {
Path myPath = Paths.get(uri);
Files.walkFileTree(myPath, new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
System.out.println(file);
return FileVisitResult.CONTINUE;
}
});
}
}
}
Here is an example of using Reflections library to recursively scan classpath by regex name pattern augmented with a couple of Guava perks to to fetch resources contents:
Reflections reflections = new Reflections("com.example.package", new ResourcesScanner());
Set<String> paths = reflections.getResources(Pattern.compile(".*\\.template$"));
Map<String, String> templates = new LinkedHashMap<>();
for (String path : paths) {
log.info("Found " + path);
String templateName = Files.getNameWithoutExtension(path);
URL resource = getClass().getClassLoader().getResource(path);
String text = Resources.toString(resource, StandardCharsets.UTF_8);
templates.put(templateName, text);
}
This works with both jars and exploded classes.
Here's a method I wrote for a "run all JUnits under a package". You should be able to adapt it to your needs.
private static void findClassesInJar(List<String> classFiles, String path) throws IOException {
final String[] parts = path.split("\\Q.jar\\\\E");
if (parts.length == 2) {
String jarFilename = parts[0] + ".jar";
String relativePath = parts[1].replace(File.separatorChar, '/');
JarFile jarFile = new JarFile(jarFilename);
final Enumeration<JarEntry> entries = jarFile.entries();
while (entries.hasMoreElements()) {
final JarEntry entry = entries.nextElement();
final String entryName = entry.getName();
if (entryName.startsWith(relativePath)) {
classFiles.add(entryName.replace('/', File.separatorChar));
}
}
}
}
Edit:
Ah, in that case, you might want this snippet as well (same use case :) )
private static File findClassesDir(Class<?> clazz) {
try {
String path = clazz.getProtectionDomain().getCodeSource().getLocation().getFile();
final String codeSourcePath = URLDecoder.decode(path, "UTF-8");
final String thisClassPath = new File(codeSourcePath, clazz.getPackage().getName().repalce('.', File.separatorChar));
} catch (UnsupportedEncodingException e) {
throw new AssertionError("impossible", e);
}
}
Just to mention that if you are already using Spring, you can take advantage of the PathMatchingResourcePatternResolver.
For instance to get all the PNG files from a images folder in resources
ClassLoader cl = this.getClass().getClassLoader();
ResourcePatternResolver resolver = new PathMatchingResourcePatternResolver(cl);
Resource[] resources = resolver.getResources("images/*.png");
for (Resource r: resources){
logger.info(r.getFilename());
// From your example
// ImageIO.read(cl.getResource("images/" + r.getFilename()));
}
A jar file is just a zip file with a structured manifest. You can open the jar file with the usual java zip tools and scan the file contents that way, inflate streams, etc. Then use that in a getResourceAsStream call, and it should be all hunky dory.
EDIT / after clarification
It took me a minute to remember all the bits and pieces and I'm sure there are cleaner ways to do it, but I wanted to see that I wasn't crazy. In my project image.jpg is a file in some part of the main jar file. I get the class loader of the main class (SomeClass is the entry point) and use it to discover the image.jpg resource. Then some stream magic to get it into this ImageInputStream thing and everything is fine.
InputStream inputStream = SomeClass.class.getClassLoader().getResourceAsStream("image.jpg");
JPEGImageReaderSpi imageReaderSpi = new JPEGImageReaderSpi();
ImageReader ir = imageReaderSpi.createReaderInstance();
ImageInputStream iis = new MemoryCacheImageInputStream(inputStream);
ir.setInput(iis);
....
ir.read(0); //will hand us a buffered image
Given an actual JAR file, you can list the contents using JarFile.entries(). You will need to know the location of the JAR file though - you can't just ask the classloader to list everything it could get at.
You should be able to work out the location of the JAR file based on the URL returned from ThisClassName.class.getResource("ThisClassName.class"), but it may be a tiny bit fiddly.
Some time ago I made a function that gets classess from inside JAR:
public static Class[] getClasses(String packageName)
throws ClassNotFoundException{
ArrayList<Class> classes = new ArrayList<Class> ();
packageName = packageName.replaceAll("\\." , "/");
File f = new File(jarName);
if(f.exists()){
try{
JarInputStream jarFile = new JarInputStream(
new FileInputStream (jarName));
JarEntry jarEntry;
while(true) {
jarEntry=jarFile.getNextJarEntry ();
if(jarEntry == null){
break;
}
if((jarEntry.getName ().startsWith (packageName)) &&
(jarEntry.getName ().endsWith (".class")) ) {
classes.add(Class.forName(jarEntry.getName().
replaceAll("/", "\\.").
substring(0, jarEntry.getName().length() - 6)));
}
}
}
catch( Exception e){
e.printStackTrace ();
}
Class[] classesA = new Class[classes.size()];
classes.toArray(classesA);
return classesA;
}else
return null;
}
public static ArrayList<String> listItems(String path) throws Exception{
InputStream in = ClassLoader.getSystemClassLoader().getResourceAsStream(path);
byte[] b = new byte[in.available()];
in.read(b);
String data = new String(b);
String[] s = data.split("\n");
List<String> a = Arrays.asList(s);
ArrayList<String> m = new ArrayList<>(a);
return m;
}
There are two very useful utilities both called JarScan:
www.inetfeedback.com/jarscan
jarscan.dev.java.net
See also this question: JarScan, scan all JAR files in all subfolders for specific class
The most robust mechanism for listing all resources in the classpath is currently to use this pattern with ClassGraph, because it handles the widest possible array of classpath specification mechanisms, including the new JPMS module system. (I am the author of ClassGraph.)
How to know the name of the JAR file where my main class lives?
URI mainClasspathElementURI;
try (ScanResult scanResult = new ClassGraph().whitelistPackages("x.y.z")
.enableClassInfo().scan()) {
mainClasspathElementURI =
scanResult.getClassInfo("x.y.z.MainClass").getClasspathElementURI();
}
How can I read the contents of a directory in a similar fashion within a JAR file?
List<String> classpathElementResourcePaths;
try (ScanResult scanResult = new ClassGraph().overrideClasspath(mainClasspathElementURI)
.scan()) {
classpathElementResourcePaths = scanResult.getAllResources().getPaths();
}
There are lots of other ways to deal with resources too.
One more for the road that's a bit more flexible for matching specific filenames because it uses wildcard globbing. In a functional style this could resemble:
import java.io.IOException;
import java.net.URISyntaxException;
import java.nio.file.FileSystem;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.function.Consumer;
import static java.nio.file.FileSystems.getDefault;
import static java.nio.file.FileSystems.newFileSystem;
import static java.util.Collections.emptyMap;
/**
* Responsible for finding file resources.
*/
public class ResourceWalker {
/**
* Globbing pattern to match font names.
*/
public static final String GLOB_FONTS = "**.{ttf,otf}";
/**
* #param directory The root directory to scan for files matching the glob.
* #param c The consumer function to call for each matching path
* found.
* #throws URISyntaxException Could not convert the resource to a URI.
* #throws IOException Could not walk the tree.
*/
public static void walk(
final String directory, final String glob, final Consumer<Path> c )
throws URISyntaxException, IOException {
final var resource = ResourceWalker.class.getResource( directory );
final var matcher = getDefault().getPathMatcher( "glob:" + glob );
if( resource != null ) {
final var uri = resource.toURI();
final Path path;
FileSystem fs = null;
if( "jar".equals( uri.getScheme() ) ) {
fs = newFileSystem( uri, emptyMap() );
path = fs.getPath( directory );
}
else {
path = Paths.get( uri );
}
try( final var walk = Files.walk( path, 10 ) ) {
for( final var it = walk.iterator(); it.hasNext(); ) {
final Path p = it.next();
if( matcher.matches( p ) ) {
c.accept( p );
}
}
} finally {
if( fs != null ) { fs.close(); }
}
}
}
}
Consider parameterizing the file extensions, left an exercise for the reader.
Be careful with Files.walk. According to the documentation:
This method must be used within a try-with-resources statement or similar control structure to ensure that the stream's open directories are closed promptly after the stream's operations have completed.
Likewise, newFileSystem must be closed, but not before the walker has had a chance to visit the file system paths.
Just a different way of listing/reading files from a jar URL and it does it recursively for nested jars
https://gist.github.com/trung/2cd90faab7f75b3bcbaa
URL urlResource = Thead.currentThread().getContextClassLoader().getResource("foo");
JarReader.read(urlResource, new InputStreamCallback() {
#Override
public void onFile(String name, InputStream is) throws IOException {
// got file name and content stream
}
});

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