How to get redirected url from RestTemplate? - java

I would like to call RestTemplate with http GET and retrieve status code and redirected url (if there was one).
How to achieve that?

Using Spring and overriding prepareConnection() in SimpleClientHttpRequestFactory...
RestTemplate restTemplate = new RestTemplate( new SimpleClientHttpRequestFactory(){
#Override
protected void prepareConnection( HttpURLConnection connection, String httpMethod ) {
connection.setInstanceFollowRedirects(false);
}
} );
ResponseEntity<Object> response = restTemplate.exchange( "url", HttpMethod.GET, null, Object.class );
int statusCode = response.getStatusCodeValue();
String location = response.getHeaders().getLocation() == null ? "" : response.getHeaders().getLocation().toString();

Create Apache HttpClient with custom RedirectStrategy where you can intercept intermediate response(s) when redirect occurred.
Replace default request factory with HttpComponentsClientHttpRequestFactory and new Apache HttpClient.
Have a look at org.apache.http.client.RedirectStrategy for more information. Or reuse DefaultRedirectStrategy as in the following example:
CloseableHttpClient httpClient = HttpClientBuilder
.create()
.setRedirectStrategy( new DefaultRedirectStrategy() {
#Override
public boolean isRedirected(HttpRequest request, HttpResponse response,
HttpContext context) throws ProtocolException {
System.out.println(response);
// If redirect intercept intermediate response.
if (super.isRedirected(request, response, context)){
int statusCode = response.getStatusLine().getStatusCode();
String redirectURL = response.getFirstHeader("Location").getValue();
System.out.println("redirectURL: " + redirectURL);
return true;
}
return false;
}
})
.build();
HttpComponentsClientHttpRequestFactory factory = new HttpComponentsClientHttpRequestFactory(httpClient);
RestTemplate restTemplate = new RestTemplate(factory);
.......

var responseEntity = restTemplate.exchange("someurl", HttpMethod.GET, null, Object.class);
HttpHeaders headers = responseEntity.getHeaders();
URI location = headers.getLocation();
location.toString();

Related

Apache HttpClient 4.5 redirect POST request to GET request

Am traying to hit a post endpoint but It is giving error 302, When I tried another get Url on the same server it gives me 200. Then I redirected the post request using LaxRedirectStrategy() The post request is redirecting to the get request(same endpoint only method name is GET and POST) it is not getting response from the post method. Can anyone tell me how to redirect post request to post request using apahce httpClient 4.5
HttpClient client= HttpClientBuilder.create()
.setRedirectStrategy(new LaxRedirectStrategy()).build();
HttpPost post = new HttpPost("url");
post.addHeader("content-type", " application/json");
HttpResponse response = client.execute(post);
I had the same issue I solved it by using using LaxRedirectStrategy with overridden getRedirect method.
Apparently the default behaviour for POST requests is to make the redirected call as a GET request when the initial redirect response is different than 307 or 308.
See:
DefaultRedirectStrategy which LaxRedirectStrategy inherits from.
In my case the redirect response code was a 302.
So if you want something different, you can just override the getRedirect method and provide your own implementation.
Something like:
new LaxRedirectStrategy() {
#Override
public HttpUriRequest getRedirect(HttpRequest request, HttpResponse response, HttpContext context) throws ProtocolException {
final URI uri = getLocationURI(request, response, context);
final String method = request.getRequestLine().getMethod();
if (method.equalsIgnoreCase(HttpHead.METHOD_NAME)) {
return new HttpHead(uri);
} else if (method.equalsIgnoreCase(HttpGet.METHOD_NAME)) {
return new HttpGet(uri);
} else {
final int status = response.getStatusLine().getStatusCode();
if (status == HttpStatus.SC_TEMPORARY_REDIRECT || status == HttpStatus.SC_MOVED_TEMPORARILY) { //HttpStatus.SC_MOVED_TEMPORARILY == 302
return RequestBuilder.copy(request).setUri(uri).build();
} else {
return new HttpGet(uri);
}
}
}
}
HttpClient httpClient =
HttpClients.custom().setRedirectStrategy(new LaxRedirectStrategy() {
/*
* (non-Javadoc)
*
* #see org.apache.http.impl.client.DefaultRedirectStrategy#
* getRedirect(org.apache.http.HttpRequest,
* org.apache.http.HttpResponse,
* org.apache.http.protocol.HttpContext)
*/
#Override
public HttpUriRequest getRedirect(
HttpRequest request, HttpResponse response,
HttpContext context) throws ProtocolException
{
final URI uri = getLocationURI(request, response, context);
final String method = request.getRequestLine().getMethod();
if (method.equalsIgnoreCase(HttpPost.METHOD_NAME)) {
HttpPost post = new HttpPost(uri);
post.setEntity(entity);
return post;
} else if (method.equalsIgnoreCase(HttpHead.METHOD_NAME)) {
return new HttpHead(uri);
} else if (method.equalsIgnoreCase(HttpGet.METHOD_NAME)) {
return new HttpGet(uri);
} else {
final int status =
response.getStatusLine().getStatusCode();
return status == HttpStatus.SC_TEMPORARY_REDIRECT
? RequestBuilder.copy(request).setUri(uri).build()
: new HttpGet(uri);
}
}
})

Retrofit: Making Web Requests to Internal APIs

I want to make a request to my organisation api's. The request contains Headers, UserName, Password, & Cookie for session management.
Below is the actual code (in HttpClient) which I want to rewrite using Retrofit. I have heard that HttpClient libraries have been deprecated or someting so have opted Retrofit. I expect the response with 200 status code.
public static CookieStore cookingStore = new BasicCookieStore();
public static HttpContext context = new BasicHttpContext();
public String getAuth(String login,String password) {
String resp = null;
try {
String url = DOMAIN+"myxyzapi/myanything";
context.setAttribute(HttpClientContext.COOKIE_STORE, cookingStore);
HttpClient client = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(url);
String log = URLEncoder.encode(login, "UTF-8");
String pass = URLEncoder.encode(password, "UTF-8");
String json = "username="+log+"&password="+pass+"&maintain=true&finish=Go";
StringEntity entity = new StringEntity(json);
post.setEntity(entity);
post.addHeader("Content-Type", "application/x-www-form-urlencoded");
HttpResponse response = client.execute(post,context);
resp = EntityUtils.toString(response.getEntity());
accountPoller();
} catch(Exception a) {
log.info("Exception in authentication api:"+a.getMessage().toString());
}
return resp;
}
Below is my code where I can't figure out how to pass the context with request. HttpResponse response = client.execute(post,**context**); using retrofit.
I don't even know if I have made my retrofit request right.
try {
String log = URLEncoder.encode(login, "UTF-8");
String pass = URLEncoder.encode(password, "UTF-8");
RequestBody formBody = new FormBody.Builder()
.add("username=", xyz)
.add("password=", mypass)
.add("&maintain=", "true")
.add("finish=", "Go")
.build();
String url = www.xyz.com+"myxyzapi/myanything";
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder().url(url).post(formBody).addHeader("Content-Type", "application/x-www-form-urlencoded").build();
client.newCall(request).enqueue(new Callback() {
#Override
public void onFailure(Call call, IOException e) {
e.printStackTrace();
}
#Override
public void onResponse(Call call, Response response) throws IOException {
if(response.isSuccessful()){
final String myresp = response.body().string();
}
}
});
} catch(Exception a) {
a.getMessage();
}
You have to catch exception and use this class.
retrofit2.HttpException
retrofit2
Class HttpException
int
code()
HTTP status code.
String
message()
HTTP status message.
Response
response()
The full HTTP response.

Why is my Session gone when using RestTemplate to access Spring MVC?

I am trying to access a Spring MVC app. That uses a CSRF Token. I do an initial GET to receive the Token. Then add it to my POST with my JSESSIONID. However, during debug the Server app doesn't find my JSESSIONID. And therefore, doesn't authenticate my token, and gives me 403.
I can't tell but it looks like my GET JSESSIONID doesn't get saved in the server HTTP Session repository.
Is there a way, to validate:
The session is in the server context?
Am I sending the correct header data?
Here's my code:
public String testLogin() {
ResponseEntity<String> response =
restTemplate.getForEntity(LOGIN_RESOURCE_URL, String.class);
List<String> cookies = new ArrayList<String>();
cookies = response.getHeaders().get("Set-Cookie");
String[] firstString = cookies.get(0).split("=|;");
String jsessionPart = firstString[1];
String[] secondString = cookies.get(1).split("=|;");
String tokenPart = secondString[1];
BasicCookieStore cookieStore = new BasicCookieStore();
BasicClientCookie cookie = new BasicClientCookie("JSESSIONID",
jsessionPart);
cookie.setDomain(".mydomain.com");
cookie.setPath("/");
cookieStore.addCookie(cookie);
BasicClientCookie cookie2 = new BasicClientCookie("X-XSRF-TOKEN",
tokenPart);
cookie2.setDomain(".mydomain.com");
cookie2.setPath("/");
cookieStore.addCookie(cookie2);
HttpClient client = HttpClientBuilder
.create()
.setDefaultCookieStore(cookieStore)
.disableRedirectHandling()
.build();
HttpComponentsClientHttpRequestFactory factory = new
HttpComponentsClientHttpRequestFactory();
factory.setHttpClient(client);
RestTemplate postTemplate = new RestTemplate(factory);
HttpEntity<?> requestEntity = new HttpEntity<Object>(body, headers);
ResponseEntity<String> response = postTemplate.exchange(loginUserUrl,
HttpMethod.POST, requestEntity,String.class);
To your code sample I added user name and password plus changed the content type. The 403 still happens whether i sent content type or not:
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
// if you need to pass form parameters in request with headers.
MultiValueMap<String, String> map = new LinkedMultiValueMap<>();
try {
map.add( URLEncoder.encode("username", "UTF-8"),
URLEncoder.encode("userdev", "UTF-8") );
map.add(URLEncoder.encode("password", "UTF-8"),
URLEncoder.encode("devpwd","UTF-8") );
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
HttpEntity<MultiValueMap<String, String>> requestEntity = new HttpEntity<>
(map, headers);
ResponseEntity<String> response =
this.restTemplate(builder).exchange(RESOURCE_URL, HttpMethod.POST,
requestEntity, String.class);
Instead of messing around with cookies yourself let the framework, Apache HttpClient, handle this for you. Configure the RestTemplate to work with a properly configured HttpClient.
Something like this should do the trick
#Bean
public RestTemplate restTemplate(RestTemplateBuilder builder) {
return builder.requestFactory(this::requestFactory)
.build();
}
#Bean
public HttpComponentsClientHttpRequestFactory requestFactory() {
RequestConfig defaultRequestConfig = RequestConfig.custom()
.setCookieSpec(CookieSpecs.DEFAULT)
.setExpectContinueEnabled(true)
.build();
CloseableHttpClient httpClient = HttpClientBuilder.create()
.setDefaultCookieStore(new BasicCookieStore())
.setDefaultRequestConfig(defaultRequestConfig).build();
HttpComponentsClientHttpRequestFactory requestFactory = new HttpComponentsClientHttpRequestFactory();
requestFactory.setHttpClient(httpClient);
return requestFactory;
}
This will configure the RestTemplate to use a HttpClient that stores cookies in a CookieStore in between requests. Reuse the configured RestTemplate and don't create a new one because you might need it.

Spring RestTemplate gives 401 Unauthorized error when sending with Authorization Header

I am trying to hit one Microsoft Flow POST URL in my Spring Rest application using following code but it is giving me 401 error.
My Code:
#RequestMapping(value = "/hookslistner", method = RequestMethod.POST)
public ResponseEntity<Void> recieveWebhook(#RequestBody InventorySystemModel inventory,
#RequestHeader("event") String event,
#RequestHeader("Authorization") String authorization) {
// authorization = "Basic <Base64 encoded value of username:pwd>"
RestTemplate restTemplate = new RestTemplate();
org.springframework.http.HttpHeaders httpHeaders = new org.springframework.http.HttpHeaders();
String url = "https://prod-01.centralindia.logic.azure.com/workflows/835348<hiding rest of part>";
String headerName = "Authorization";
httpHeaders.add(headerName, authorization);
httpHeaders.add("Content-Type", "application/json");
HttpEntity<String> requestEntity = new HttpEntity<>("Headers", httpHeaders);
System.out.println(">>>>>>>" + restTemplate.exchange(url, HttpMethod.POST, requestEntity, String.class).getBody());
}
Error:
SEVERE: Servlet.service() for servlet [webhooks] in context with path [/inventoryhooks] threw exception [Request processing failed; nested exception is org.springframework.web.client.HttpClientErrorException: 401 Unauthorized] with root cause
org.springframework.web.client.HttpClientErrorException: 401 Unauthorized
at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:91)
.
.
.
Is it because my target url is https and my localhost is http?
Can anyone point me what is going wrong?
Two points for you to check for this problem:
if the target server is a http server, then you shouldn't use https in the url.
make sure the authorization value is base64 encoded.
Update:
Since the target server is a https server, the problem is that you haven't configured ssl info into the RestTempalte. You can refer to the following code snippet to get a ssl restTemplate:
#Configuration
public class RestClientConfig {
#Bean
public RestOperations restOperations(ClientHttpRequestFactory clientHttpRequestFactory) throws Exception {
return new RestTemplate(clientHttpRequestFactory);
}
#Bean
public HttpComponentsClientHttpRequestFactory clientHttpRequestFactory(HttpClient httpClient) {
return new HttpComponentsClientHttpRequestFactory(httpClient);
}
#Bean
public HttpClient httpClient(#Value("${keystore.file}") String file, #Value("${keystore.pass}") String password) throws Exception {
KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
FileInputStream inStream = new FileInputStream(file);
try {
trustStore.load(inStream, password.toCharArray());
} finally {
inStream.close();
}
SSLContext sslcontext =
SSLContexts.custom().loadTrustMaterial(trustStore, new TrustSelfSignedStrategy()).build();
SSLConnectionSocketFactory sslsf =
new SSLConnectionSocketFactory(sslcontext, new String[]{"TLSv1.2"}, null,
null);
return HttpClients.custom().setSSLSocketFactory(sslsf).build();
}
#Bean
public static PropertySourcesPlaceholderConfigurer propertySourcesPlaceholderConfigurer() {
return new PropertySourcesPlaceholderConfigurer();
}
}
The test case:
#RunWith(SpringRunner.class)
#ContextConfiguration(classes = RestClientConfig.class)
public class RestClientTest {
#Autowired
private RestOperations rest;
private HttpHeaders getHeaders(){
String plainCredentials="admin:admin";
String base64Credentials = Base64.getEncoder().encodeToString(plainCredentials.getBytes());
HttpHeaders headers = new HttpHeaders();
headers.add("Authorization", "Basic " + base64Credentials);
return headers;
}
#Test
public void test() {
HttpEntity<String> request = new HttpEntity<String>(getHeaders());
ResponseEntity<String> response = rest.exchange(url, HttpMethod.GET, request, String.class);
System.out.println(response.getBody());
}
}

Invalid HTTP method: PATCH

After trying other solutions from HttpURLConnection Invalid HTTP method: PATCH
I am getting Invalid HTTP Method: PATCH Exception with JAVA 7.
Updating JAVA is not in option so i have to stick to the workarounds.
I am using Invocation to invoke the request like this
Invocation invoke = reqBuilder.build(getHTTPVerb(), Entity.entity(requestJSON, MediaType.APPLICATION_JSON));
getWebTarget().request(MediaType.APPLICATION_JSON).header("Authorization", getAuthorization()).accept(MediaType.APPLICATION_JSON);
getHTTPVerb() returns String "POST" or "PATCH".
With PATCH method I am having problem.
In the mentioned question, i have not tried one solution with:
conn.setRequestProperty("X-HTTP-Method-Override", "PATCH");
conn.setRequestMethod("POST");
conn is HttpURLConnection instance.
But I am not sure how I can get HttpURLConnection from Invocation class or any property.
Any pointers or help would be highly appreciated.
An example of PATCH method with apache http client:
try {
//This is just to avoid ssl hostname verification and to trust all, you can use simple Http client also
CloseableHttpClient httpClient = HttpClientBuilder.create().setSSLContext(new SSLContextBuilder().loadTrustMaterial(null, TrustAllStrategy.INSTANCE).build())
.setSSLHostnameVerifier(NoopHostnameVerifier.INSTANCE).build();
HttpPatch request = new HttpPatch(REST_SERVICE_URL);
StringEntity params = new StringEntity(JSON.toJSONString(payload), ContentType.APPLICATION_JSON);
request.setEntity(params);
request.addHeader(org.apache.http.HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_JSON_VALUE);
request.addHeader(HttpHeaders.ACCEPT, MediaType.APPLICATION_JSON_VALUE);
request.addHeader(HttpHeaders.AUTHORIZATION, OAuth2AccessToken.BEARER_TYPE + " " + accessToken);
HttpResponse response = httpClient.execute(request);
String statusCode = response.getStatusLine().getStatusCode();
} catch (Exception ex) {
// handle exception here
}
Equivalent example with RestTemplate:
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
headers.add("Authorization", OAuth2AccessToken.BEARER_TYPE + " " + accessToken);
final HttpEntity<String> entity = new HttpEntity<String>(JSON.toJSONString(payload), headers);
RestTemplate restTemplate = new RestTemplate();
try {
ResponseEntity<String> response = restTemplate.exchange(REST_SERVICE_URL, HttpMethod.PATCH, entity, String.class);
String statusCode = response.getStatusCode();
} catch (HttpClientErrorException e) {
// handle exception here
}

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