First of all I'm sorry if this question has been asked before or if there is documentation about the topic but i didn't found anything.
I want to make a windows app that open windows file explorer and you can browse for and then select a mp3 file, so you can play it (and replay it) in this program. I know how to open file explorer, this is my code :
import java.awt.Desktop;
import java.io.File;
import java.io.IOException;
public class Main
{
public static void main(String[] args) throws IOException {
Desktop desktop = Desktop.getDesktop();
File dirToOpen = null;
try {
dirToOpen = new File("c:\\");
desktop.open(dirToOpen);
} catch (IllegalArgumentException iae) {
System.out.println("File Not Found");
}
}
}
But i don't know how to select an mp3 file and then get the path of the file, so i can play it later.
I don't think you are approaching this right. You should use something like a FileDialog to choose a file:
FileDialog fd = new FileDialog(new JFrame());
fd.setVisible(true);
File[] f = fd.getFiles();
if(f.length > 0){
System.out.println(fd.getFiles()[0].getAbsolutePath());
}
Since you are only getting 1 MP3 file, you only need the first index of the File array returned from the getFiles() method. Since it is a modal dialog, the rest of your application will wait until after you choose a file. If you want to get multiple files at once, just loop through this aforementioned Files array.
See the documentation here: https://docs.oracle.com/javase/7/docs/api/java/awt/FileDialog.html
Related
I currently want to try to create a .jar file that pinpoints to a .bat file to start a gaming server,
the Forge Modloader for the current version switched from a server startup via jar file to .bat file, and my server provider currently has no solution for it. -Small disclaimer, I haven't touched java for 6 years, which is why I may not see the obvious
For this, I found some code from Pavan.
Though, there are two problems, where I hope you may have a solution or some other workaround.
First of all, while in Intellij, "everything" works fine. main() is running, and the "Hallo World" Test .bat is opening. After compiling it to a jar, nothing happens, even with a set File Path.
Second Problem. I've tried several spots, but System.exit(0) does not work, after
int returnCode = CommandLineUtils.executeCommandLine(commandLine, systemOut, systemErr);
The code basically stops, and the process stays inactive, which could end up bad for a gaming server where I have 0 access to the needed tools to clean this up by myself... and I don't want to explain to Customer Support why there are 1000 instances of java running in the background ;)
But regardless, Thanks for your time and hopefully help as well
import java.io.File;
import java.io.OutputStreamWriter;
import org.codehaus.plexus.util.cli.CommandLineException;
import org.codehaus.plexus.util.cli.CommandLineUtils;
import org.codehaus.plexus.util.cli.Commandline;
import org.codehaus.plexus.util.cli.WriterStreamConsumer;
public class BatRunner {
public BatRunner() {
String batfile = "run.bat";
String directory = "C:\\Users\\User\\IdeaProjects";
try {
runProcess(batfile, directory);
} catch (CommandLineException e) {
e.printStackTrace();
}
}
public void runProcess(String batfile, String directory) throws CommandLineException {
Commandline commandLine = new Commandline();
File executable = new File(directory + "/" +batfile);
commandLine.setExecutable(executable.getAbsolutePath());
WriterStreamConsumer systemOut = new WriterStreamConsumer(
new OutputStreamWriter(System.out));
WriterStreamConsumer systemErr = new WriterStreamConsumer(
new OutputStreamWriter(System.out));
int returnCode = CommandLineUtils.executeCommandLine(commandLine, systemOut, systemErr);
System.exit(0);
if (returnCode != 0) {
System.out.println("Something Bad Happened!");
} else {
System.out.println("Taaa!! ddaaaaa!!");
}
}
public static void main(String[] args) {
new BatRunner();
}
}
Source: https://www.opencodez.com/java/how-to-execute-bat-file-from-java.htm/
I've been browsing the site since yesterday and I can't see to find anything that answers my question, so I decided to just ask.
I'm making a pretty basic java GUI, it's designed to be run alongside files that wont be included in the actual java package for compatibility and easier customization of those files, I doubt they could be included either way as they have their own .jars and other things.
So, the problem I'm having is that the GUI application is in the main folder and I need it to locate and open txt files a couple sub-folders deep, in notepad without requiring a full file path as I'll be giving this project out to some people when it's done.
Currently I've been using this to open the files, but will only work for files in the main folder and trying to edit in any file paths did not work.
private void jButton4ActionPerformed(java.awt.event.ActionEvent evt) {
Runtime rt=Runtime.getRuntime();
String file;
file = "READTHIS.txt";
try {
Process p=rt.exec("notepad " +file);
} catch (IOException ex) {
Logger.getLogger(NumberAdditionUI.class.getName()).log(Level.SEVERE, null, ex);
}
}
if someone knows a way to do this, that'd be great.
On another note, I'd like to include the file shown above (READTHIS.txt) inside the actual java package, where would I put the file and how should I direct java towards it?
I've been away from java for a long time so I've forgotten pretty much anything, so simpler explanations are greatly appreciated.
Thanks to anyone reading this and any help would be awesome.
Update 2
So I added to the ConfigBox.java source code and made jButton1 open home\doc\READTHIS.txt in Notepad. I created an executable jar and the execution of the jar, via java -jar Racercraft.jar, is shown in the image below. Just take the example of what I did in ConfigBox.java and apply it to NumberAdditionUI.java for each of its JButtons, making sure to change the filePath variable to the corresponding file name that you would like to open.
Note: The contents of the JTextArea in the image below were changed during testing, my code below does not change the contents of the JTextArea.
Directory structure:
\home
Rasercraft.jar
\docs
READTHIS.txt
Code:
// imports and other code left out
public class ConfigBox extends javax.swing.JFrame {
// curDir will hold the absolute path to 'home\'
String curDir; // add this line
/**
* Creates new form ConfigBox
*/
public ConfigBox()
{
// this is where curDir gets set to the absolute path of 'home/'
curDir = new File("").getAbsolutePath(); // add this line
initComponents();
}
/*
* irrelevant code
*/
private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {//GEN-FIRST:event_jButton1ActionPerformed
Runtime rt = Runtime.getRuntime();
// filePath is set to 'home\docs\READTHIS.txt'
String filePath = curDir + "\\docs\\READTHIS.txt"; // add this line
try {
Process p = rt.exec("notepad " + filePath); // add filePath
} catch (IOException ex) {
Logger.getLogger(NumberAdditionUI.class.getName()).log(Level.SEVERE, null, ex);
}
// TODO add your handling code here:
}//GEN-LAST:event_jButton1ActionPerformed
/*
* irrelevant code
*/
Update
This is the quick and dirty approach, if you would like me to add a more elegant solution just let me know. Notice that the file names and their relative paths are hard-coded as an array of strings.
Image of the folder hierarchy:
Code:
Note - This will only work on Windows.
import java.io.File;
import java.io.IOException;
public class Driver {
public static void main(String[] args) {
final String[] FILE_NAMES = {"\\files\\READTHIS.txt",
"\\files\\sub-files\\Help.txt",
"\\files\\sub-files\\Config.txt"
};
Runtime rt = Runtime.getRuntime();
// get the absolute path of the directory
File cwd = new File(new File("").getAbsolutePath());
// iterate over the hard-coded file names opening each in notepad
for(String file : FILE_NAMES) {
try {
Process p = rt.exec("notepad " + cwd.getAbsolutePath() + file);
} catch (IOException ex) {
// Logger.getLogger(NumberAdditionUI.class.getName())
// .log(Level.SEVERE, null, ex);
}
}
}
}
Alternative Approach
You could use the javax.swing.JFileChooser class to open a dialog that allows the user to select the location of the file they would like to open in Notepad.
I just coded this quick example using the relevant pieces from your code:
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.File;
import java.io.IOException;
import javax.swing.JButton;
import javax.swing.JFileChooser;
import javax.swing.JFrame;
import javax.swing.SwingUtilities;
public class Driver extends JFrame implements ActionListener {
JFileChooser fileChooser; // the file chooser
JButton openButton; // button used to open the file chooser
File file; // used to get the absolute path of the file
public Driver() {
this.fileChooser = new JFileChooser();
this.openButton = new JButton("Open");
this.openButton.addActionListener(this);
// add openButton to the JFrame
this.add(openButton);
// pack and display the JFrame
this.pack();
this.setVisible(true);
}
public void actionPerformed(ActionEvent e) {
// handle open button action.
if (e.getSource() == openButton) {
int returnVal = fileChooser.showOpenDialog(Driver.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
// from your code
Runtime rt = Runtime.getRuntime();
try {
File file = fileChooser.getSelectedFile();
String fileAbsPath = file.getAbsolutePath();
Process p = rt.exec("notepad " + fileAbsPath);
} catch (IOException ex) {
// Logger.getLogger(NumberAdditionUI.class.getName())
// .log(Level.SEVERE, null, ex);
}
} else {
System.exit(1);
}
}
}
public static void main(String args[]) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
Driver driver = new Driver();
}
});
}
}
I've also included a link to some helpful information about the FileChooser API, provided by Oracle: How to use File Choosers. If you need any help figuring out the code just let me know, via a comment, and I'll try my best to help.
As for including READTHIS.txt inside the actual java package, take a gander at these other StackOverflow questions:
Getting file from same package?
Reading a text file from a specific package?
How to include text files with executable jar?
Creating runnable jar with external files included?
Including a text file inside a jar file and reading it?
I did this small Java project that in it's turn opens different MP3 files. For that I downloaded the JLayer 1.0.1 library and added it to my project. I also added the MP3 files to a package on my project -as well as some JPG images- so as to obtain them from there, and I'm using a hashmap (mapa) and this method to get them:
public static String consiguePath (int i) {
return AppUtils.class.getClass().getResource("/Movimiento/" + mapa.get(i)).getPath();
}
so as to avoid absolute paths.
When I open an MP3 file I do this:
try {
File archivo = new File(AppUtils.consiguePath(12));
FileInputStream fis = new FileInputStream(archivo);
BufferedInputStream bis = new BufferedInputStream(fis);
try {
Player player = new Player(bis);
player.play();
} catch (JavaLayerException jle) {
}
} catch (IOException e) {
}
The whole thing runs perfectly in NetBeans, but when I build a .jar file and execute it it runs well but it won't open the MP3 files. What called my attention is that it doesn't have trouble in opening the JPG files that are on the same package.
After generating the .jar I checked the MyProject/build/classes/Movimiento folder and all of the MP3 files were actually there, so I don't know what may be happening.
I've seen others had this problem before but I haven't seen any satisfactory answer yet.
Thanks!
Change the consiguePath to return the resulting URL from getResource
public static URL consiguePath(int i) {
return AppUtils.class.getClass().getResource("/Movimiento/" + mapa.get(i));
}
And then use it's InputStream to pass to the Player
try {
URL url = AppUtils.consiguePath(12);
Player player = new Player(url.openStream());
player.play();
} catch (JavaLayerException | IOException e) {
e.printStackTrace();
}
Equally, you could just use Class#getResourceAsStream
Resources are packaged into your Jar file and can no longer be treated as Files
I've write a Java programm and packaged it the usual way in a jar-File - unfortunately is needs to read in a txt-File. Thats way the programm failed to start on other computer machines because it could not find the txt-file.
At the same time Im using many images in my programm but here there is no such problem: I "copy" the images to the eclipse home directory, so that they are packaged in the jar-File and usable through following command:
BufferedImage buffImage=ImageIO.read(ClassName.class.getClassLoader()
.getResourceAsStream("your/class/pathName/));
There is something similar for simple textfiles which then can be use as a normal new File()?
Edit
Ive try to solve my problem with this solution:
package footballQuestioner;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import javax.security.auth.login.Configuration;
public class attempter {
public static void main(String[] args) {
example ex = new example();
}
}
class example {
public example() {
String line = null;
BufferedReader buff = new BufferedReader(new InputStreamReader(
Configuration.class
.getResourceAsStream("footballQuestioner/BackUpFile")));
do {
try {
line = buff.readLine();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} while (line != null);
}
}
But it gives always an NullPointerException...do I have forgotten something?
Here is as required my file structure of my jar-File:
You can load the file from the ClassPath by doing something like this:
ClassLoader cl = getClass().getClassLoader()
cl.getResourceAsStream("TextFile.txt");
this should also work:
getClass().getResourceAsStream(fileName);
File always points to a file in the filesystem, so I think you will have to deal with a stream.
There are no "files" in a jar but you can get your text file as a resource (URL) or as an InputStream. An InputStream can be passed into a Scanner which can help you read your file.
You state:
But it gives always an NullPointerException...do I have forgotten something?
It means that likely your resource path, "footballQuestioner/BackUpFile" is wrong. You need to start looking for the resource relative to your class files. You need to make sure to spell your file name and its extension correctly. Are you missing a .txt extension here?
Edit
What if you try simply:
BufferedReader buff = new BufferedReader(new InputStreamReader(
Configuration.class.getResourceAsStream("BackUpFile")));
I have made a button, but I don't now how to make it open a specific directory like %appdata% when the button is clicked on.
Here is the code ->
//---- button4 ----
button4.setText("Texture Packs");
button4.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e)
{
JFileChooser fileChooser=new JFileChooser("%appdata%");
int status = fileChooser.showOpenDialog(this);
fileChooser.setMultiSelectionEnabled(false);
if(status == JFileChooser.APPROVE_OPTION) {
File file = fileChooser.getSelectedFile();
// do something on the selected file.
}
}
And I want to make something like this ->
private void button4MouseClicked(MouseEvent e) throws IOException {
open folder %appdata%
// Open the folder in the file explorer not in Java.
// When I click on the button, the folder is viewed with the file explorer on the screen
}
import java.awt.Desktop;
import java.io.File;
public class OpenAppData {
public static void main(String[] args) throws Exception {
// Horribly platform specific.
String appData = System.getenv("APPDATA");
File appDataDir = new File(appData);
// Get a sub-directory named 'texture'
File textureDir = new File(appDataDir, "texture");
Desktop.getDesktop().open(textureDir);
}
}
Execute a command using Runtime.exec(..). However, not every OS has the same file explorer, so you need to handle the OS.
Windows: Explorer /select, file
Mac: open -R file
Linux: xdg-open file
I wrote a FileExplorer class for the purpose of revealing files in the native file explorer, but you'll need to edit it to detect operating system.
http://textu.be/6
NOTE: This is if you wish to reveal individual files. To reveal directories, Desktop#open(File) is far simpler, as posted by Andrew Thompson.
If you are using Windows Vista and higher, System.getenv("APPDATA"); will return you C:\Users\(username}\AppData\Roaming, so you should go one time up, and use this path for filechooser,
Just a simple modified Andrew's example,
String appData = System.getenv("APPDATA");
File appDataDir = new File(appData); // TODO: this path should be changed!
JFileChooser fileChooser = new JFileChooser(appData);
fileChooser.showOpenDialog(new JFrame());
More about windows xp, and windows vista/7/8