Validating the Date format using selenium Webdriver - java

I have a tab with name 'Preferences' where user can set the Date format in any format like DD/MM/YYYY, DD.MM.YYYY, MM/DD/YYYY etc and is applicable through out the web application
I have chosen a Date format DD.MM.YYYY and saved it
Now I need to validate a text field some where in my application where I give input say 01012001 and it should automatically take the input and convert to the preferred Date format 01.01.2001 where I have been saved in 'Preferences' tab
Could any one help me out how can I validate this in java?

In your case What I understand is you need to write function which will return you formatted date according to selected format.Below function will do the work and return you formatted string.
public String parseDate(StringBuilder dateString, String formatString) {
String separator = "";
String slashSeperator = "/";
if (formatString.contains(slashSeperator)) {
separator = slashSeperator;
} else {
String dotSeparator = ".";
if (formatString.contains(dotSeparator)) {
separator = dotSeparator;
}
}
if (dateString.length() == 8) {
dateString.insert(2, separator);
dateString.insert(5, separator);
} else {
return "False Date Entered";
}
return dateString.toString();
}

If you are using Java 8 you can check new Date library and its DateTimeFormatter. Use this formatter to parse date using Date.parse. Examples are included within docs.

Related

regex to select after and upto specific character at same time

Is there any way I could select specific text after specific text and keep selecting until that word is selected. And once selected then leave the remaining.
Here is the example
ABCDEF
JHJHJNJN<098978686
<jjg>
HGHJFGV XXXX
10-10-2018
JHKGHKGHG
JKHJHHJM
10-10-2019 JGHHGHGVH
HBVJHBHBB
Just want to select this date 10-10-2018 in whole content which always comes after XXX with couple of spaces. I can't use just regex with specific value(10-10-2018) because date can be changed and possible that date pattern somewhere is also present like in example in last line.
Please share your thoughts..!
Thanks
Assuming the example is correct, then the following regex will extract just the date using find() and ensure that DOTALL is set.
"XXXX.*?[\\s]+([\\d]{1,2}-[\\d]{1,2}-[\\d]{4})"
Basically, search for XXX followed by spaces/newline then find the date. It will be placed into a group and can then be extracted.
You can see the operation at this location, though be sure to select "DOTALL".
public String getDate(String input)
{
String date = "";
Pattern dte = Pattern.compile("XXXX.*?[\\s]+([\\d]{1,2}-[\\d]{1,2}-[\\d]{4})", Pattern.DOTALL);
Matcher m = dte.matcher(input);
if (m.find() && m.groupCount() > 0) {
date = m.group(1);
}
return date;
}
Test case
#Test
public void testData() throws Exception
{
RegEx_52879334 re = new RegEx_52879334();
String input = re.getInputData();
String date = re.getDate(input);
assertEquals("10-10-2018", date);
System.out.println("Found: " + date);
}
Output:
Found: 10-10-2018

Reading GEDCOM files: How to substring the corresponding birth day, month, and year, into an Integer variable from an input file to an output file

I have an input GEDCOM file with tons of individual/family records. The purpose is to format their data into this form:
name(p6, 'Harry Buis').
birth(p6, date(1927,11,17)).
death(p6, date(2001,08,21)).
famc(p6, f3).
fams(p6, f2).
I have been able to pull out the person number and their name and print it to an output file, however I am having trouble parsing the birth/death dates. I want to be able to use substring to assign the birthDay, birthMonth, and BirthYear as Integers so I can print it to the output file. It must be Integers so I can sort by date. Here is a sample of one client's data from the input file.
0 #P6# INDI
1 BIRT
2 DATE 17 Nov 1924
1 NAME Harry /Buis/
1 DEAT Age: 76
2 DATE 21 Aug 2001
1 SEX M
1 FAMC #F3#
1 FAMS #F2#
And here is my source code of what I have so far:
public class Main {
static Scanner scan;
static BufferedWriter outFile;
static int birthYear = 0;
static int birthMonth = 0;
static String birthDay = "";
static int deathYear = 0;
static int deathMonth = 0;
static int deathDay = 0;
static String name = "";
static String person = "";
static String sex = "";
static String famC = "";
static String famS = "";
static String man = "";
static String woman = "";
static String child = "";
public static void parse() throws IOException {
scan = new Scanner(new FileReader("pbuis.ged"));
outFile = new BufferedWriter(new FileWriter("output.txt"));
String reader = scan.nextLine();
int count = 0;
while (scan.hasNextLine()) {
if (reader.contains("NAME") && count < 1) {
reader = reader.substring(1).replace("/", "");
count++;
System.out.println(reader);
name = reader.replace("NAME", "");
}
if (reader.startsWith("0")) {
person = reader.trim().substring(2, 7).replace("#", "")
.replace("I", "").trim().toLowerCase();
System.out.print(person);
count = 0;
}
if (reader.contains("BIRT")) {
scan.nextLine();
birthDay = Integerreader.substring(6, 9).trim();
}
if (reader.equalsIgnoreCase("") || reader.equalsIgnoreCase(" ")) {
outFile.write("name(" + person + ", " + "'" + name.trim() + "'"
+ ")." + "\n" + birthDay);
}
reader = scan.nextLine();
}
}
public static void main(String[] args) throws IOException {
parse();
}
}
Without the if statement (contains "BIRT"), and "birthDay" not in the outFile.write() method, my output looks like this:
name(p1, 'Paul Edward Buis').
name(p2, 'Thomas Edward Buis').
name(p3, 'Jennifer Joy Buis').
name(p4, 'Daniel Paul Buis').
name(p5, 'Barbara Joy VanderWall').
name(p6, 'Harry Buis').
which is a good start.
But when I have that if statement, I get an error like this, and nothing prints:
p1Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 9
at java.lang.String.substring(Unknown Source)
at Main.parse(Main.java:50)
at Main.main(Main.java:64)
Now, I have tried every combination of substringing index values, and nothing seems to work. Any idea on how I fix this?
Thanks in advance.
I suggest you use a Date function. Date functions can be sorted easier than year/month/date. If you really want, store them as the milliseconds since the epoch.
To parse the date, use a SimpleDateFormatter. I believe something like this would work:
SimpleDateFormatter dateFormat=new SimpleDateFormat("dd mmm yyyy")
Date birth=date.parse("17 jul 1984",0);
One you get it in to the Date format, you can do a lot of neat things, like these:
Date date1, date2;
date1.after(date2);
date1.compareTo(date2)
You could even get the minutes or seconds, but I don't recommend that. Note the 0 refers to the index starting the string, so you could just specify the index where the format starts, and you're good. Overall, I think this is a lot cleaner.
Date parsing from GEDCOM files is tricky. You can use a SimpleDateFormatter for any dates that are in dd MMM yyyy format (like 26 SEP 2015) but GEDCOM supports a lot of weird variations, including imprecise dates where you only have the month and year, or just the year. It also allows prefixes like "ABT" to indicate that something occurred around a specific date, allows for ranges ("BET date1 AND date2") and ("FROM date1 TO date2"), and a lot of other complex behavior (French Republican or Hebrew calendars, anyone?)
I would recommend using gedcom4j (http://gedcom4j.org), which is a java library you can link into your program to load your data into Java objects and then do what you need. The DateParser class in that library can interpret your string values and turn them into java.util.Date values so you can do what you're describing.

Apply a date pattern a piece os expression

I have an expression working inside a Report (jasperReport), the language to work with expressions i groovy. the expression is
= Util.textoComun("OCURRENCIA")+ " "+Util.aFecha($F{fecha}).
Everything in the same box, but i just want to apply a date pattern at the second part of expression (Util.aFecha(xx)), is this possible?
I don't wanna to separate in two boxes.
Util is a java class.
afecha does:
public static Date aFecha(String s)
{
try
{
SimpleDateFormat formatter = new SimpleDateFormat("yyyyMMdd");
formatter.setLenient(false);
return formatter.parse(s);
} catch (Exception ex) {
System.out.println("Error convertint la data: " + ex);
}
return null;
}
Right, so from the edit, it appears that $F{fecha} is returning you a String which you parse into a Date with Util.aFecha. In that case (and assuming this is Groovy), you should be able to do:
Util.textoComun("OCURRENCIA")+ " "+Util.aFecha($F{fecha}).format( 'EEE, d MMM yyyy' )

Convert String to appropriate DataType

I have a String that could be in many different formats. I need to be able to recognize the actual type of the value at runtime and then transform the value to that type.
For example. If I have a String Fri Feb 08 07:30:00 GMT 2013 this is actually a Date and a the String should be transformed into a date object and returned as such.
My current solution to this problem is to 'try' to convert it to a data type, if the conversion succeeds then all is good, if the conversion fails then move on to the next conversion attempt. This works, but is ugly and un-maintainable and I'm sure a better solution already exists out there.
Thanks.
You may use separate regular expression for each data type like this:
private final static Pattern DATE_PATTERN =
Pattern.compile (
"(?:Sun|Mon|Tue|Wed|Thu|Fri|Sat) " +
"(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec) " +
"\\d\\d \\d\\d:\\d\\d:\\d\\d \\S+ \\d\\d\\d\\d");
private final static Pattern DOUBLE_PATTERN =
Pattern.compile (
"[\\+\\-]?\\d+\\.\\d+(?:[eE][\\+\\-]?\\d+)?");
private final static Pattern INTEGER_PATTERN =
Pattern.compile (
"[\\+\\-]?\\d+");
public static Object stringToObject (String string)
{
if (DATE_PATTERN.matcher (string).matches ())
return stringToDate (string);
else if (DOUBLE_PATTERN.matcher (string).matches ())
return Double.valueOf (string);
else if (INTEGER_PATTERN.matcher (string).matches ())
return Integer.valueOf (string);
else return string;
}
public static void main(String[] args) {
String s = "Fri Feb 08 07:30:00 GMT 2013";
SimpleDateFormat FT = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy");
Date d;
try {
d = FT.parse(s);
System.out.println(d);
} catch (ParseException ex) {
Logger.getLogger(Test.class.getName()).log(Level.SEVERE, null, ex);
}
}
Try regular expression :
You can write a pattern for each data type you have, then match that pattern with each actual string you can associate a conversion for each match.
Here is a simple example (in pseudo Java):
String name = "Mike"; // This is an English name
String nameRegEx ="[A-Z][a-z]+"; //this patterns matches an english name
Matcher nameMatcher = new Matcher(regEx);
if (match.matches(name)){// I use the matches() method to verify the format of the string
Name nameObject = Converter.getNameObjectFromString(name);//I make the conversion
}
Checkout the java documentation for more details on matchers and regular expressions :
http://docs.oracle.com/javase/tutorial/essential/regex/
Your approach is fine, if the strings passed to you are out of your control. Just one more suggestion: You should apply every possible conversion and check for ambiguous strings. If multiple conversions succeed then the string is ambiguous and you should do some error handling, probably throwing an exception.

How to delete all the characters after one character in the String?

I have a String which contains a date, for example "01-01-2012", then an space and then the time "01:01:01". The complete string is: "01-01-2012 01:01:01"
I would like to extract only the date from this string so at the end I would have "01-01-2012" but don't know how to do this.
Four options (last two added to make this one answer include the options given by others):
Parse the whole thing as a date/time and then just take the date part (Joda Time or SimpleDateFormat)
Find the first space using indexOf and get the leading substring using substring:
int spaceIndex = text.indexOf(" ");
if (spaceIndex != -1)
{
text = text.substring(0, spaceIndex);
}
Trust that it's valid in the specified format, and that the first space will always be at index 10:
text = text.substring(0, 10);
Split the string by spaces and then take the first result (seems needlessly inefficient to me, but it'll work...)
text = text.split(" ")[0];
You should consider what you want to happen if there isn't a space, too. Does that mean the data was invalid to start with? Should you just continue with the whole string? It will depend on your situation.
Personally I would probably go with the first option - do you really want to parse "01-01-2012 wibble-wobble bad data" as if it were a valid date/time?
String input = "01-01-2012 01:01:01";
String date = d.split(" ")[0];
Try this:
String date = s.substring(0, s.indexOf(" "));
Or even (because the length is fixed):
String date = s.substring(0, 10);
Or use StringUtils.substringBefore():
String date = StringUtils.substringBefore(s, " ");
Lots of ways to do this, a very simple method is to split the String at the space and use the first part (which will be the date):
String dateTime = "01-01-2012 01:01:01";
String date = dateTime.split(" ")[0];
You can use String.split() and take only the relevant String in your resultng String[] [in your example, it will be myString.split(" ")[0]
In that case where only one space is in the string, you can use String.split(" "). But this is a bad practice. You should parse the date with a DateFormat
.
You can use substring to extract the date only:
String thedatetime = "01-01-2012 01:01:01";
String thedateonly = thedate.substring(0, 10);
You should really read through the javadoc for String so you are aware of the available functions.
If you know in advance this is the format of the string, I'd do this:
public String getDateOnly(String fullDate){
String[] spl = fullDate.split(" ");
return spl[0];
}
You can do it either using string manipulation API:
String datetime = "01-01-2012 01:01:01";
int spacePos = datetime.indexOf(" ");
if (spacePos > 0) {
String date = datetime.substring(0, spacePos - 1);
}
or using regular expression:
Pattern p = Pattern.compile("(\\d{2}-\\d{2}-\\d{4})");
String datetime = "01-01-2012 01:01:01";
Matcher m = p.matcher(datetime);
if(m.find()) {
String date = m.group(1);
}
or using SimpleDateFormat
DateFormat fmt = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
Date date = fmt.parse(datetime);
Calendar c = Calendar.getInstance();
c.setTime(date);
String date = c.getDayOfMonth() + "-" + c.getMonth() + "-" + c.getYear();
Use String.substring(int, int). If you are interested in the value of the date and time, then use SimpleDateFormatter to parse your string.
myString.substring(0,10);
If your string is always in that format (2 digits, minus, 2 digits, minus, 4 digits, space etc...) then you can use substring(int beginIndex, int endIndex) method of string to get what you want.
Note that second parameter is the index of character after returning substring.
If you want to explode the complete date from the string use this method.
/**
* #param dateTime format string
* #param type type of return value : "date" or "time"
* #return String value
*/
private String getFullDate(String dateTime, String type) {
String[] array = dateTime.split(" ");
if (type == "time") {
System.out.println("getDate: TIME: " + array[1]);
return array[1];
} else if (type == "date") {
System.out.println("getDate: DATE: " + array[0]);
return array[0];
} else {
System.out.println("NULL.");
return null;
}
}
Otherwise if you want only the date for explample 01-01-2012
use this:
/**
* #param datetime format string
* #return
*/
private String getOnlyDate(String datetime) {
String array[] = datetime.split("-");
System.out.println("getDate: DATE: " + array[0]);
return array[0];
}
I hope my answer will help you.

Categories