I tried to switch to popup alert and click on OK button, but i got an error saying that xpath (for OK button) is not found.
But this is working for me sometimes using the same code. Could anyone help me out on this. I tried all possible ways that is available in blogs. But i couldn't make it
you need to move control to your pop-up window first before doing any operation on pop-up window:-
below code is to move selenium control on pop-up window
driver.switchTo().alert();
by writing below line
alert.accept();
alert will get close
Based on the original question and the subsequent comments, I suspect what you're dealing with is a browser pop up window and not an alert. So this won't work
driver.switchTo().alert().accept();
You need to use window handles
Set<String> handles = driver.getWindowHandles();
Iterator<String> windows = handles.iterator();
String parent = windows.next();
String child = windows.next();
driver.switchTo().window(child);
driver.findElement(By.xpath("insert xpath to OK button")).click();
driver.switchTo().window(parent);
//continue with steps on parent window
Note: ensure that you add the required synchronization to the code snippet above
Related
i have issues with click(); function using selenium webdriver.
here's the outputHtml :
<button type="button" class="k-button k-primary" tabindex="0" style="width: 50%;">Valider< /button>
i used the findEelement using various xpath like :
- "//button[#class = 'k-button k-primary' and #type = 'button']"
- "//*[contains(#class, 'k-button k-primary') and text()='Valider']"
and still got the error Unable to locate the element
here's the screenshot of the pop-up's Button that i need to click on (button Valider)
Button : Valider
Have you tried actually copying and pasting the selector?
If you are on a Windows machine:
In Google Chrome if you press F12 to open the developer window.
Find the node you are looking for within the DOM and right click on it.
Then go to "Copy" and "Copy XPath" or you can "Copy JS Path"
Then you can paste the path into your code and try it that way.
I prefer to select dom nodes using the JS Path when I am developing with selenium.
The "Copy Full XPath" option is useful during development if you are having problems like you are because it copies the full path all the from the root node.
This feature is available in all major browsers but I am most familiar with developing with Google Chrome.
Are you sure the Element has loaded when you are searching for it? Try a break point before and verify it is available.
In order to handle alerts/pop-ups you need to switch to it
//switch to alert
Alert alert = driver.switchTo().alert();
//accept it
alert.accept();
// or accept it by your code
driver.findElement(By.XPATH("//button[#class = 'k-button k-primary' and #type = 'button']").click();
//dismiss alert
alert.dismiss();
//or dismiss with you code
driver.findElement(YOUR_LOCATOR).click();
//get text
String alertText = alert.getText()
Please check if the pop up is within some frame. If it is then you have to switch to the frame like this
driver.switchTo.frame(iframe locator)
I am on a page. After clicking on a link, a new window is opening. The window does not have any URL or title. So, while switching to the new window, aftre I am inspecting element, &, creating Xpath, Selenium code can't focus on the new window, and is not executing anything after that. Can you please resolve my query?
Note: After I inspect, the console window title is showing the URL of the parent window.
You can switch between different open windows you have opened:
String storeCurrentWindowHandler = driver.getWindowHandle();
Then perform the click operation that opens a new window
Make a switch to the new window that has opened
for(String winHandle : driver.getWindowHandles()){
driver.switchTo().window(winHandle);
}
Do whatever the test needs within the selected window
Then close the new window, if it is no longer required
driver.close();
And switch back to the first window that had been opened
driver.switchTo().window(storeCurrentWindowHandler);
Hopefully this will help you to solve your issue.
I want to automate a scenario.
When the browser lands on the website, there is a warning pop-up that requires a response to the prompt: Do you want to proceed?
There are two options Leave and Continue.
I am trying to switch the control with the following functions but its not working.
Alert alert=driver.switchTo().alert();
driver.switchTo().alert();
alert.accept();
If its JavaScript alert, then driver.switchTo().alert().accept(); should work by accepting the default.
Is this pop-up or modal window?
Did you try to switch to window and click on the button?
Also, which browser are you using? JavaScript alert might needs to handled differently based on the browser.
If its modal or window, then getWindowHandle() should work fine.
String newWindow = driver.getWindowHandle();
driver.switchTo().window(newWindow);
//Switching to new window
driver.findElement(By.id("buttonId"));
//Switching back to default/main window
driver.switchTo().defaultContent();
My scenario
i am working on page 1
i have to switch to page 2
but the pop up is coming, with text
you might lose the data, are you sure you want to continue?,
with two options:
Leave the page
Stay on page
i have to choose "leave the page" option
but how to handle this pop up,
(note :-i) this is not an alert, so switch to alert is not working
ii) even (( JavascriptExecutor ) webDriver).executeScript( "window.close()" ); is not working )
then only i can switch to page 2
can someone please help on this
Although It doesn't seems as an alert because alert.accept() or alert.dismiss() doesn't works.(as you haven't shared html) Just try the following code -
First switch on that alert -
Alert alert = driver.switchTo().alert();
and then change focus to leave if your default focus is on Stay
alert.sendKeys(Keys.chord(Keys.TAB)); //By pressing TAB key in this way
and then click the button
alert.dismiss();
Below code should work:
//Save the current window to switch back to it after clicking on Leave Page
String currentWindowHandle = driver.getWindowHandle();
//Switch to the latest window (a.k.a your pop up)
for(String windowHandle : driver.getWindowHandles())
{
driver.switchTo().window(windowHandle);
}
//Click on leave page
//If the window closes automatically, you can remove the below line
driver.close();
//Finally, switch back to the main window so you can keep doing stuff there.
driver.switchTo().window(currentWindowHandle);
The way I see it, it's a browser alert which you are receiving so you can use following code based on your requirement :
Alert alert = driver.switchTo().alert();
System.out.println(alert.getText());
If you want to stay on the page, use:
alert.dismiss();
If you want to leave the page, use:
alert.accept();
I need to read the text displayed on the popup window in Web driver using Java. I am able to handle the popup window for closing. I don't know how to read the text displayed on Popup window and print it in Console.
I am not able to provide any HTML code for this because its a Modal Popup window.
Please help me on this. Help will be appreciated.
Given your screenshot, it looks like the "modal popup" you're trying to automate is generated by the JavaScript alert() function. If this is the case, the following code or something similar to it, should work.
// WARNING! Untested code written from memory without
// benefit of an IDE! May not be exactly correct!
// Switch the driver context to the alert
Alert alertDialog = driver.switchTo().alert();
// Get the alert text
String alertText = alertDialog.getText();
// Click the OK button on the alert.
alertDialog.accept();
Have you used the WebDriverWait object before? To expand on the previous answer, you may be able to do something similar to this, but I have not tested:
WebDriverWait wait = new WebDriverWait(5, TimeUnit.Seconds);
element.click();
// Wait for the dialog to show
wait.until(ExpectedConditions.alertIsPresent());
// Switch the driver context to the alert
Alert alertDialog = driver.switchTo().alert();
// Get the alert text
String alertText = alertDialog.getText();
// Click the OK button on the alert.
alertDialog.accept();
Also, you may have to switch back to the alert after getting the text. Hope this helps.