Input date is 2016-01-01, but why output shows 2016/02/01?
String df = "2016-01-01";
String enddate="";
SimpleDateFormat DATE_FORMAT_QUERY = new SimpleDateFormat("yyyyMMdd'T'HHmmss'Z'");
Calendar cal=Calendar.getInstance();
String[] dateStr=df.split("-");
int year=Integer.parseInt(dateStr[0]);
int month=Integer.parseInt(dateStr[1]);
int day=Integer.parseInt(dateStr[2]);
cal.set(year,month,day,23, 59,59);
System.out.println(cal.getTime());
enddate=DATE_FORMAT_QUERY.format(cal.getTime());
System.out.println(enddate);
Output:
Mon Feb 01 23:59:59 EST 2016 20160201T235959Z
ANSWER TO YOUR QUESTION
Input date is 2016-01-01, but why output shows 2016/02/01?
Because Calendar::month is 0-based.
month - the value used to set the MONTH calendar field. Month value is 0-based. e.g., 0 for January.
You should use
int month=Integer.parseInt(dateStr[1] - 1);
CORRECT SOLUTION
NEVER parse manually a String containing a Date, better get date with SimpleDateFormat and use it to set Calendar time:
SimpleDateFormat dfo = new SimpleDateFormat("yyyy-MM-dd");
Calendar cal=Calendar.getInstance();
cal.setTime(dfo.parse("2016-01-01"));
OUTPUT:
Fri Jan 01 00:00:00 CET 2016
20160101T000000Z
Related
Using SimpleDateFormat:
DateFormat df = new SimpleDateFormat("dd-MMMM-YYYY kk:mm:ss.SSS");
Date extractedDate = df.parse(possibleDate);
Input given:
11-May-2017 21:45:33.614
Output data object:
Sun Jan 01 21:45:33 MST 2017
I have tried lots of iterations but it won't pull the month and day.
Use dd-MMM-yyyy kk:mm:ss.SSS as pattern
Example :
DateFormat df = new SimpleDateFormat("dd-MMM-yyyy kk:mm:ss.SSS");
Date extractedDate = df.parse("11-May-2017 21:45:33.614");
System.out.println(extractedDate);
Output :
Thu May 11 21:45:33 BDT 2017
Another thing If you use kk for hour, hour should be represent between 1 to 24. If the hour between 0 to 23 use HH instead of kk
From the below java code I'm getting a month First & last dateTimestamp, but here i need last dateTimestamp as - "Mon Aug 31 23:59:59 IST 2015" instead of - "Mon Aug 31 00:00:00 IST 2015"?
Calendar cal = Calendar.getInstance();
int year = 2015;
int month = 07;
cal.set(cal.DATE,1);
cal.set(cal.YEAR,year);
cal.set(cal.MONTH, month);
String firstDate = (cal.getActualMinimum(cal.DATE) + "/" + (month+1) + "/" +year);
System.out.println("firstDate-->"+"\t"+firstDate);
String lastDate = (cal.getActualMaximum(cal.DATE) + "/" + (month+1) + "/" +year);
System.out.println("lastDate-->"+"\t"+lastDate);
DateFormat firstFormat = new SimpleDateFormat("dd/MM/yyyy");
Date beginDate = firstFormat.parse(firstDate);
System.out.println("BeginDate Timestamp"+ "\t" + beginDate);
DateFormat secoundFormat = new SimpleDateFormat("dd/MM/yyyy");
Date endDate = secoundFormat.parse(lastDate);
System.out.println("endDate Timestamp"+ "\t" + endDate);
Output:->
firstDate--> 1/8/2015
lastDate--> 31/8/2015
BeginDate Timestamp Sat Aug 01 00:00:00 IST 2015
endDate Timestamp Mon Aug 31 00:00:00 IST 2015
Please help me if we have any solution.
If I understand your question, it looks as if you want to pass a year and month into a method, and get back the last day of the passed month.
I would suggest consider (in this order):
which jdk you use
configuration of calendar
configuration of timezone (maybe)
using jodatime
As of 1.8 many JodaTime-like features have been added to the jdk- e.g. see https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html (If you arent using 1.8 you can use the joda lib, assuming your organization allows it)
Calendar.getInstance() gives a default TimeZone and a default Locale, which means the definitions of the running JVM. You may or may not need to consider this and implement more than just getInstance(). See API javadoc.
Assuming a Gregeorian Calendar (hey, you could be Bahaian and have 19 months in the year ...) , here is one partial implementation using JDK 1.7, JodaTime jar 2.2, validation-1.0.0.GA jar:
#Test
public void testDate() {
final String dateStringOfFirstDay = "1.7.2015";
final Date lastDayOfMonth = getLastDayOfMonth(dateStringOfFirstDay);
Assert.assertNotNull(lastDayOfMonth);
//more assertions ...
}
private Date getLastDayOfMonth(#NotNull String dateStringOfFirstDay) {
//further validation here necessary according to required date format
DateTime dt = DateTime.parse(dateStringOfFirstDay);
return dt.dayOfMonth().withMaximumValue().toDate();
}
The defintion of DateFormat/DateTimeFormat and further result assertions is left up to you.
Best of luck!
Guys I got a solution for my question!!!
I think it will help u too...
Calendar calendar = Calendar.getInstance();
int year=2015;
int month=7;
int date=31;
int hourOfDay=23;
int minute=59;
int second=59;
int milliSecond=999;
calendar.set(year, month, date, hourOfDay, minute, second);
calendar.set(calendar.MILLISECOND, milliSecond);
System.out.println("Time from Calendar: "+calendar.getTime());
long timeInMilliSeconds=calendar.getTimeInMillis();
System.out.println("timeInMilliSeconds from calendar: "+timeInMilliSeconds);
Timestamp timestamp=new Timestamp(timeInMilliSeconds);
System.out.println(timestamp);
The above program gives the last date last timestamp in a selected month.
getTimeInMillis() takes the time from Jan 01, 1970 to current time in Milliseconds.
Using those milliseconds i'm getting the Timestamp.
Thank you for your help guys!!!
OutPut:->
Time from Calendar: Mon Aug 31 23:59:59 IST 2015
timeInMilliSeconds from calendar: 1441045799999
2015-08-31 23:59:59.999
I am new to java. I have a Date that is stored in the variable, pubDate = "2013-09-23"
When I'm executing this
SimpleDateFormat pubSimpleDateFormat = new SimpleDateFormat("yyyy-mm-dd");
Date publishDate = pubSimpleDateFormat.parse(pubDate);
I'm getting wrong value : Wed Jan 23 00:09:00 GMT+05:30 2013
Please help me why it so. and help me to solve this.
M is for Month in year while m is for Minute in hour
You should use SimpleDateFormat pubSimpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
String pubDate = "2013-09-23";
SimpleDateFormat pubSimpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
Date publishDate = pubSimpleDateFormat.parse(pubDate);
System.out.println(publishDate);
Output :
Mon Sep 23 00:00:00 GMT 2013
Read the section Date and Time Patterns.
DateFormat formatter = new SimpleDateFormat("yy-mm-dd");
formatter.setLenient(false);
String[] dateStr = { "2013-12-27", "2013-01-03"};
for (int i = 0; i <= 1; i++) {
Date date = formatter.parse(dateStr[i]);
System.out.println("date is "+date);
}
result :
Sun Jan 27 00:12:00 IST 2013
Thu Jan 03 00:01:00 IST 2013
i am parsing string date in to Date.but it is giving me date Starting with month Jan regardless of what month i am passing to formatter constructor.
The format for your date would be yy-MM-dd. Update your format and check.
mm for minutes
MM for month
Use: "yy-MM-dd"
See here
once Silly Mistake
DateFormat formatter = new SimpleDateFormat("yy-MM-dd");
Format this line in your code
Trying to compare some dates in java but can't get the formatting right, where am i going wrong?
DateFormat df = new SimpleDateFormat("dd/mm/yyyy");
Date date1 = null, date2 = null, today = new Date();
date1 = (Date) df.parse(scan.next());
System.out.println(date1);
System.out.println(today);
if(date1.compareTo(today) < 0){
date1 = null;
System.out.println(start + " is not a valid date.. please try again!");
}
Please enter a start date:
10/04/2011
Mon Jan 10 00:04:00 GMT 2011
Tue Apr 05 22:27:44 BST 2011
I think you need MM, not mm
From the doc:
M Month in year
m Minute in hour
Change line 1 to be:
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
mm in SimpleDateFormat is the minutes. MM is the month. So your input is actaully January 10 2011 at 00:10:00
Check out http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html for abbreviations and javadoc.