Lets say you have an array like this: String[] theWords = {"hello", "good bye", "tomorrow"}. I want to remove/ignore all the strings in the array that have the letter 'e'. How would I go about doing that? My thinking is to go:
for (int arrPos = 0; arrPos < theWords.length; arrPos++) { //Go through the array
for (int charPos = 0; charPos < theWords[arrPos].length(); charPos++) { //Go through the strings in the array
if (!((theWords[arrPos].charAt(charPos) == 'e')) { //Finds 'e' in the strings
//Put the words that don't have any 'e' into a new array;
//This is where I'm stuck
}
}
}
I'm not sure if my logic works and if I'm even on the right track. Any responses would be helpful. Many thanks.
One easy way to filter an array is to populate an ArrayList with if in a for-each loop:
List<String> noEs = new ArrayList<>();
for (String word : theWords) {
if (!word.contains("e")) {
noEs.add(word);
}
}
Another way in Java 8 is to use Collection#removeIf:
List<String> noEs = new ArrayList<>(Arrays.asList(theWords));
noEs.removeIf(word -> word.contains("e"));
Or use Stream#filter:
String[] noEs = Arrays.stream(theWords)
.filter(word -> !word.contains("e"))
.toArray(String[]::new);
You can directly use contains() method of String class to check if "e" is present in your string. That will save your extra for loop.
It would be simple if you use ArrayList.
importing import java.util.ArrayList;
ArrayList<String> theWords = new ArrayList<String>();
ArrayList<String> yourNewArray = new ArrayList<String>;//Initializing you new array
theWords.add("hello");
theWords.add("good bye");
theWords.add("tommorow");
for (int arrPos = 0; arrPos < theWords.size(); arrPos++) { //Go through the array
if(!theWords.get(arrPos).contains("e")){
yourNewArray.add(theWords.get(arrPos));// Adding non-e containing string into your new array
}
}
The problem you have is that you need to declare and instantiate the String array before you even know how many elements are going to be in it (since you wouldn't know how many strings would not contain 'e' before going through the loop).
Instead, if you use an ArrayList you do not need to know the required size beforehand. Here is my code from start to end.
String[] theWords = { "hello", "good bye", "tomorrow" };
//creating a new ArrayList object
ArrayList<String> myList = new ArrayList<String>();
//adding the corresponding array contents to the list.
//myList and theWords point to different locations in the memory.
for(String str : theWords) {
myList.add(str);
}
//create a new list containing the items you want to remove
ArrayList<String> removeFromList = new ArrayList<>();
for(String str : myList) {
if(str.contains("e")) {
removeFromList.add(str);
}
}
//now remove those items from the list
myList.removeAll(removeFromList);
//create a new Array based on the size of the list when the strings containing e is removed
//theWords now refers to this new Array.
theWords = new String[myList.size()];
//convert the list to the array
myList.toArray(theWords);
//now theWords array contains only the string(s) not containing 'e'
System.out.println(Arrays.toString(theWords));
Related
I originally have an arraylist of strings but I want to save it as an arraylist of those strings.toCharArray() instead. Is it possible to make an arraylist that stores char arrays? Here is how I tried to implement it.
String[] words = new String[]{"peter","month","tweet", "pete", "twee", "pet", "et"};
HashMap<Integer,ArrayList<Character[]>> ordered = new HashMap<>();
int length = 0;
int max = 0; //max Length of words left
for(String word: words){
if(ordered.containsKey(length) == false){ //if int length key doesnt exist yet
ordered.put(length, new ArrayList<Character[]>()); //put key in hashmap with value of arraylist with the one value
ordered.get(length).add(word.toCharArray());
}
}
Note that toCharArray() returns an array of primitives (char[]), and not an array of the boxing class (Character[] as you currently have). Additionally, you're only adding the given array to the map if the length of the array isn't in the map, which probably isn't the behavior you wanted (i.e., you should move the line ordered.get(length).add(word.toCharArray()); outside the if statement).
Also, note that Java 8's streams can do a lot of the heavy lifting for you:
String[] words = new String[]{"peter","month","tweet", "pete", "twee", "pet", "et"};
Map<Integer, List<char[]>> ordered =
Arrays.stream(word)
.map(String::toCharArray)
.collect(Collectors.groupingBy(x -> x.length));
EDIT:
As per the question in the comment, this is also entirely possible in Java 7 without streams:
String[] words = new String[]{"peter","month","tweet", "pete", "twee", "pet", "et"};
Map<Integer, List<char[]>> ordered = new HashMap<>();
for (String word: words) {
int length = words.length();
// if int length key doesnt exist in the map already
List<char[]> list = orderd.get(length);
if (list == null) {
list = new ArrayList<>();
orderd.put(length, list);
}
list.add(word);
}
I am having issue to store all values of ArrayList<ArrayList<String>> into ArrayList<String>. Here stylistIDArray and durationArray are array of array. I want to store all their values in stylistId and duration respectively. The stylistid and duration are array of string.
Here's my attempt, but it stores only the last item of each array of array.
ArrayList<ArrayList<String>> stylistIDArray;
ArrayList<ArrayList<String>> durationArray;
stylistIDArray = differentGenderServicesAdapter.getSelectedStylistIdArray();
durationArray = differentGenderServicesAdapter.getSelectedDurArray();
ArrayList<String>stylistId = new ArrayList<>();
ArrayList<String>duration = new ArrayList<>();
for(int i=0; i<stylistIDArray.size(); i++) {
stylistId = stylistIDArray.get(i);
duration = durationArray.get(i);
}
Note : I have already tried this, but doesn't work for me.
To be generic, First let be an list of list of objects
List<List<Object>> listOfList;
That you want to put into a list of object
List<Object> result;
Note the result list will contain every object contain is the input list. This transformation will loose the information of which object was in which list.
You have to loop through the listOfList. At each loop you obtain a list of object (List<Object> listOfObject). Then loop through these lists to obtain every object (Object o). Then add these object to the result list (result.add(o)).
for(List<Object> listOfObject : listOfList) {
for(Object o : listOfObject) {
result.add(o);
}
}
In your case, the problem is that you use affectation instead of add(). At every loop this replaces the value by the new one. So at the end you have stored only the last item of each list.
stylistId=stylistIDArray.get(i); //This replace the existing stylistId
Instead try something like
ArrayList<ArrayList<String>> stylistIDArray;
ArrayList<ArrayList<String>> durationArray;
stylistIDArray = differentGenderServicesAdapter.getSelectedStylistIdArray();
durationArray = differentGenderServicesAdapter.getSelectedDurArray();
ArrayList<String> stylistId = new ArrayList<>();
ArrayList<String> duration = new ArrayList<>();
for(ArrayList<String> l : stylistIDArray) {
for(String s : l) {
stylistId.add(s);
}
}
for(ArrayList<String> l : durationArray ) {
for(String s : l) {
duration.add(s);
}
}
You doing wrong operation with arraylist, in loop you are getting data from stylistIDArray and assign to aryalist, not inserting in list, have look this
stylistIDArray=differentGenderServicesAdapter.getSelectedStylistIdArray();
durationArray=differentGenderServicesAdapter.getSelectedDurArray();
ArrayList<String>stylistId=new ArrayList<>();
ArrayList<String>duration=new ArrayList<>();
for(int i=0; i<stylistIDArray.size(); i++) {
stylistId.add(stylistIDArray.get(i));
duration.add(durationArray.get(i));
}
Hope it will help you!
I have one arraylist that contain two list
like this
[[asd, asswwde, efef rgg], [asd2223, asswwd2323e, efef343 rgg]]
My Code is
ArrayList<String> create = new ArrayList<String>();
ArrayList<String> inner = new ArrayList<String>();
ArrayList<String> inner1 = new ArrayList<String>();
inner.add("asd");
inner.add("asswwde");
inner.add("efef rgg");
inner1.add("asd2223");
inner1.add("asswwd2323e");
inner1.add("efef343 rgg");
create.add(inner.toString());
create.add(inner1.toString());
i have to get all value one by one of every index of that arraylist
So what is the best way to get these all value one by one.
I am using JAVA with Eclipse Mars.
Just use two nested loops:
List<List<Object>> list = ...;
for (List<Object> subList : list) {
for (Object o : subList) {
//work with o here
}
}
You may also want to consider replacing the inner lists by proper objects.
You want to loop through the outside ArrayList and then loop through each ArrayList within this ArrayList, you can do this by using the following:
for (int i = 0; i < outerArrayList.size(); i++)
{
for (int j = 0; j < outerArrayList.get(i).size(); j++)
{
String element = outerArrayList.get(i).get(j);
}
}
Here is another verison you may find easier to understand, but is essentially the same:
for (int i = 0; i < outerArrayList.size(); i++)
{
ArrayList<String>() innerArrayList = outerArrayList.get(i)
for (int j = 0; j < innerArrayList.size(); j++)
{
String element = innerArrayList.get(j);
}
}
or alternatively again using a foreach loop:
for (ArrayList<String> innerArrayList : outerArrayList)
{
for (String element : innerArrayList)
{
String theElement = element;
}
}
It might be worth noting that your ArrayList appears to contain different types of elements - is this definitely what you wanted to do? Also, make sure you surround your strings with "" unless they are variable names - which it doesn't appear so.
EDIT: Updated elements to type String as per your update.
I would also recommend you change the type of your create ArrayList, like below, as you know it will be storing multiple elements of type ArrayList:
ArrayList<ArrayList> create = new ArrayList<ArrayList>();
Try to use for loop nested in foreach loop like this:
for(List list : arrayListOfList)
{
for(int i= 0; i < list.size();i++){
System.out.println(list.get(i));
}
}
I'm not sure if the data structures are part of the requirements, but it would be better constructed if your outer ArrayList used ArrayList as the generic type.
ArrayList<ArrayList<String>> create = new ArrayList<ArrayList<String>>();
ArrayList<String> inner = new ArrayList<String>();
ArrayList<String> inner1 = new ArrayList<String>();
...
create.add(inner);
create.add(inner1);
Then you could print them out like this:
for(List list : create) {
for (String val : list) {
System.out.println(val);
}
}
Othewise, if you stick with your original code, when you add to the outer list you are using the toString() method on an ArrayList. This will produce a comma delimited string of values surrounded by brackets (ex. [val1, val2]). If you want to actually print out the individual values without the brackets, etc, you will have to convert the string back to an array (or list) doing something like this:
for (String valList : create) {
String[] vals = valList.substring(1, val.length() - 1).split(",");
for (String val : vals) {
System.out.println(val.trim());
}
}
I have a list of words ["home", "shop", "salmon", "time"] and I have a scrambled String "ahlowemr". I want to check if each word in the list has characters from this scrambled String and remove the word from list if it doesn't contain all the characters.
In this example, less "home", the remaining 3 Strings should be removed. I tried to loop as follows but it doesn't allow me to check characters. And I am nesting loops which I think is not a good idea. Is there any way around this?
ArrayList<String> myList = new ArrayList<String>();
myList.add("home");
myList.add("shop");
myList.add("salmon");
myList.add("time");
String scrambled = "ahlowemr";
for(String s : myList){
for(char c : scrambled.toCharArray()){
if(!s.contains(c)){ //doesn't allow character c
myList.remove(s);
}
}
}
If you want to remove items from a list while you iterate it, you should use an Iterator, also, the contains(...) method expects a String, not a char.
Here is what you can do:
for(Iterator<String> it = myList.iterator(); it.hasNext();){
String s = it.next();
for(char c : scrambled.toCharArray()){
if(!s.contains(String.valueOf(c))){
it.remove();
break;
}
}
}
ArrayList<String> myList = new ArrayList<String>();
myList.add("home");
myList.add("shop");
myList.add("salmon");
myList.add("time");
String scrambled = "ahlowemr";
for(int i = 0; i < myList.size(); i++) {
for(char c : scrambled.toCharArray()){
if(!myList.get(i).contains(c.toString())){ //doesn't allow character in that position
// There is a simple way using a regex or maybe a hashtable
myList.remove(s);
break; // break will jump into the next list value
}
}
}
java-8 solution for completeness:
ArrayList<String> myList = new ArrayList<>();
myList.add("home");
myList.add("shop");
myList.add("salmon");
myList.add("time");
String scrambled = "ahlowemr";
myList = myList.stream()
.filter(s -> scrambled.chars()
.allMatch(c -> s.contains(String.valueOf((char) c))))
.collect(Collectors.toCollection(ArrayList<String>::new));
This is what I have
ArrayList <String> cdList = new ArrayList();
Collections.addAll(cdList, "ExampleA\n"+"ExampleB\n"+"ExampleC\n"+"ExampleD");
Collections.sort(cdList, String.CASE_INSENSITIVE_ORDER);
System.out.println(cdList);
bigBox.setText("Original Order\n**************\n");
for (int i = 0; i < cdList.size(); i++) {
bigBox.setText(bigBox.getText()+""+cdList.get(i)+"\n");
}
bigBox.setText(bigBox.getText()+"\n\nSorted Order\n************\n");
Collections.sort(cdList);
for (int j = 0; j < cdList.size(); j++) {
bigBox.setText(bigBox.getText()+""+);
}
I want the 4 examples outputted in their original order, and in alphabetical order. What am I doing wrong?
You are adding only one element (String) to the list, a concatenated string.
Change this
ArrayList <String> cdList = new ArrayList();
Collections.addAll(cdList, "ExampleA\n"+"ExampleB\n"+"ExampleC\n"+"ExampleD");
to
List <String> cdList = new ArrayList<String>();
Collections.addAll(cdList, "ExampleA","ExampleB","ExampleC","ExampleD");
Read more Collections#addAll
And for showing you should use append rather than setText.
Example:
bigBox.append("Original Order\n**************\n");
for (String s : cdList) {
bigBox.append(s);
bigBox.append("\n");
}
I assume your elements are meant to be the strings "ExampleA", "ExampleB", "ExampleC", and "ExampleD". If the is the case, what you are currently doing in your call to Collections.addAll() is adding them to cdList as one long string. the + operator, when used on strings, appends them. What you probably want it to separate them with commas, so that instead of having:
Collections.addAll(cdList, "ExampleA\n"+"ExampleB\n"+"ExampleC\n"+"ExampleD");
you have:
Collections.addAll(cdList, "ExampleA\n", "ExampleB\n", "ExampleC\n", "ExampleD");