I am using JPA to query an OracleSQL database.
However, I am getting the error:
Request processing failed; nested exception is java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: CLIENT_ID of: com.fdmgroup.pojo.File [SELECT c FROM com.fdmgroup.pojo.File c WHERE c.CLIENT_ID = :clientId]
When I write the following query
String sqlQuery = "SELECT c FROM XD_FILES c WHERE c.CLIENT_ID = :clientId";
TypedQuery<File> query = em.createQuery(sqlQuery, File.class);
query = query.setParameter("clientId", clientId);
ArrayList<File> clientFiles = (ArrayList<File>) query.getResultList();
File has this column
#ManyToOne(targetEntity = Client.class)
#JoinColumn(name = "CLIENT_ID")
private Client client;
I am unsure why as it appears to have the field "client" linked to "CLIEND_ID".
You will need to mention the property name in the query and not the column name.
So the query should look like the following:
String sqlQuery = "SELECT c FROM XD_FILES c WHERE c.clientId = :clientId";
Your query seems native query and not a JPQL, you can solve this in two ways.
1) change em.createQuery(sqlQuery, File.class); to em.createNativeQuery(sqlQuery, File.class);
2) Change your query from native query to JPQL, your query should be like
select c from File c where c.client.clientID=:clientId
(Assuming clientID is primary key column name in Client class)
Related
JPA repository throwing Error for custom query method:
org.h2.jdbc.JdbcSQLException: Table "NBMRBANKDTLSENTITY" not found; SQL statement:
select NBMRBankDtlsEntity from NBMRBankDtlsEntity where NBMRBankDtlsEntity.ipphId = ? [42102-191]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:345)
Class :
#Repository
public interface NBMRBankDtlsRepository extends JpaRepository<NBMRBankDtlsEntity, Long> {
#Query(value ="select n from NBMRBankDtlsEntity n where n.ipphId = :ipphId",nativeQuery = true)
Optional<NBMRBankDtlsEntity> findByIPPHId(#Param("ipphId") Long ipphId);
}
The error message tells you: Table "NBMRBANKDTLSENTITY" not found. Therefore it probably doesn't exist. To fix this you'll have to create the table, manually through a script or through hibernates schema creation feature.
I am already creating a table also inserting the record, After that only i am calling this custom query method.
I have found the issue as i am using nativeQuery = true so it is expecting normal sql query to query DB directly not the java query which is creating issue. Now after changing below it works fine ,
#Query(value = "SELECT * from NB_MR_BANK_DTLS WHERE IPPH_ID = :ipphId",nativeQuery = true)
For java query we can use directly as it internally converts to SQL while querying the DB,
#Query(value = "select p from NBMRBankDtlsEntity p WHERE p.ipphId = :ipphId")
Let say there is the below definition:
#Entity
#NamedQueries({
#NamedQuery(name = "name1", query = "SELECT n FROM SomeEntity n where n.name= :name"),
#NamedQuery(name = "name2", query = "SELECT n FROM SomeEntity n where n.name <> :name")
})
public class SomeEntity ......
How to programmatically get a definition of the named query ?
For example the bellow code snippet should print a definition of name1 query, I don't know how to get this definition in code:
String queryString = ????????.getSqlOfNamedQuery("name1");
// the below line should print: SELECT n FROM SomeEntity n where n.name= :name
System.out.println( queryString );
You can use the unwrap method and provide it with a vendor specific class. I saw this in an old DZone article. I've tested the EclipseLink version and it works for me:
Query query = entityManager.createQuery("....");
For EclipseLink:
String sqlString = query.unwrap(JpaQuery.class).getDatabaseQuery().getSQLString();
For Hibernate:
String sqlString = query.unwrap(org.hibernate.Query.class).getQueryString();
You could also check your database logs (i.e. /var/log/postgres/postgres.log) but you might have other requirements that necessitate a programmatic approach.
I tried to run native sql query with resulttransformer (AliasToBeanResultTransformer), it gives error like below.
Exception in thread "AWT-EventQueue-0" java.lang.ClassCastException: com.ozpas.ozentegre.entity.EntDevirlog cannot be cast to java.util.Map
at org.hibernate.property.access.internal.PropertyAccessMapImpl$SetterImpl.set(PropertyAccessMapImpl.java:102)
at org.hibernate.transform.AliasToBeanResultTransformer.transformTuple(AliasToBeanResultTransformer.java:78)
By the way, my native sql query does not include all fields in the entity ( EntDevirlog ), there are only some fields in that entity. shall the query include all fields in the entity ?
as i understood, hibernate transforms result into a map object instead EntDevirlog entity. It uses PropertyAccessMapImpl. how can i solve this problem to get the result as a list ( arraylist ) ? thanks.
Session session = HibernateUtilMikro.getSessionFactory().openSession();
List<EntDevirlog> results = new ArrayList<EntDevirlog>();
Transaction tx = null;
String sql = "mynativequery";
SQLQuery query = session.createSQLQuery(sql);
query.setParameter("tarih", tarih);
query.setParameter("srmkodu", srmkodu);
query.setParameter("s1", EnumPanoislemtipleri.islem1.getValue());
query.setParameter("s2", EnumPanoislemtipleri.islem2.getValue());
query.setResultTransformer(new AliasToBeanResultTransformer(EntDevirlog.class));
results = query.list();
tx.commit();
Just use the quotes for the aliases
"select firstName as \"firstName\",
lastName as \"lastName\" from Employee"
Read for a more deeply explanation here:
mapping Hibernate query results to custom class?
The project that I'm working on has the following setup: JPA 2.0 (Hibernate 4 implementation) and SQL Server 2008 R2.
I need to select some data from an SQL view. In order to do this I use a native query, but I ran into some problems with the NVARCHAR fields. Basically, when using this piece of code:
String sql = "SELECT v.text_field as address FROM SOME_CUSTOM_VIEW v
Query q = entityManager.createNativeQuery(sql,"ItemDetailsMapping");
List<Object[]> result = q.getResultList();
The ItemDetailsMapping is declared like:
#SqlResultSetMapping(name = "ItemDetailsMapping", columns = { #ColumnResult(name = "address") })
I get an exception saying:
org.springframework.orm.hibernate3.HibernateSystemException: No Dialect mapping for JDBC type: -9; nested exception is org.hibernate.MappingException: No Dialect mapping for JDBC type: -9
Type -9 is actually the NVARCHAR type, which we are extensively using throughout the application and it works perfectly when we are using non-native queries. Why is it not working with native queries? I even used a custom dialect and registered the type, but it's still not working.
Thanks a lot for your help
You have to associate the data type NVARCHAR to String.When using Hibernate via Session interface, you can explcitly set a type of result with addScalar() instead (also accessible via unwrap() in JPA 2.0):
So modify your code as below,
String sql = "SELECT v.text_field as address FROM SOME_CUSTOM_VIEW v"
Query q = entityManager.createNativeQuery(sql,"ItemDetailsMapping");
q.unwrap(SQLQuery.class).addScalar("address ", StringType.INSTANCE);
List<Object[]> result = q.getResultList();
Read here for more information.
(Edit 7/1/15 -- Added quotation mark for clarity)
You can do it like this:
String myquery = "select cast(t2.name as varchar) column_name from sys.objects t1 inner join sys.columns t2 on t2.object_id = t1.object_id"+
" left join sys.indexes t3 on t3.object_id = t1.object_id and t3.is_unique = 1 left join sys.index_columns t4 on t4.object_id = t1.object_id and t4.index_id = t3.index_id and t4.column_id = t2.column_id where (upper(t1.type) = 'U' or upper(t1.type) = 'V') and upper(schema_name(t1.schema_id)) = 'dbo' and upper(t1.name) = 'TEST'";
When I try to execute the following HQL query:
Query query = getSession().createQuery("update XYZ set status = 10");
query.executeUpdate();
I get this exception:
Exception in thread "main" org.hibernate.QueryException: query must begin with SELECT or FROM: update
EDIT:
I also tried following .But it doennot work either.
org.hibernate.Query query = getSession().createQuery("update XYZ t set t.status = 10");
EDIT2:
Making changes in hinbernate.cfg.xml solved my problem
Earlier i was using
setting hibernate.query.factory_class" = org.hibernate.hql.classic.ClassicQueryTranslatorFactor
Now am using following property
<property name="hibernate.query.factory_class">org.hibernate.hql.ast.ASTQueryTranslatorFactory</property>
Thats not an HQL query.
You want to import javax.persistence.Query which allows normal sql,
not org.hibernate.Query which works on entity objects.
If you want to use simple sql, you could also use PreparedStatement
However, if you really want to use hibernate, without taking advantage of entityobjects (totally defeating the point of using hibernate in the first place, imho) you could do it like this (reference docs):
String myUpdate = "update XYZ myAlias set myAlias.status = :newStatus";
// or String noAliasMyUpdate = "update XYZ set status = :newStatus";
int updatedEntities = getSession().createQuery(myUpdate) //or noAliasMyUpdate
.setInt( "newStatus", 10 )
.executeUpdate();
The question is thinking in SQL, when you should be thinking in objects:
XYZ xyz = new XYZ();
xyz.setStatus(10);
getSession().merge(xyz);
Try:
Query query = getSession().createQuery("update XYZ o set o.status = 10");
query.executeUpdate();
Take a look at this also.
Session sesssion = getSession(); //getter for session
For HQL :
String hql = "update Activity " +
"set startedOn = :taskStartedOn " +
"where id = :taskId";
Query query = session.createQuery(hql);
query.setDate("taskStartedOn",new Date());
query.setLong("taskId",1)
int rowCount = query.executeUpdate();
Here Activity is POJO.
Use
hibernate.query.factory_class = org.hibernate.hql.ast.ASTQueryTranslatorFactory
in hibernate.cfg.xml file to resolve exception:
org.hibernate.QueryException: query must begin with SELECT or FROM: update.....