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I am trying to retrieve blob image from MySQL using array list into a table column [duplicate]

How can I retrieve and display images from a database in a JSP page?

Let's see in steps what should happen:
JSP is basically a view technology which is supposed to generate HTML output.
To display an image in HTML, you need the HTML <img> element.
To let it locate an image, you need to specify its src attribute.
The src attribute needs to point to a valid http:// URL and thus not a local disk file system path file:// as that would never work when the server and client run at physically different machines.
The image URL needs to have the image identifier in either the request path (e.g. http://example.com/context/images/foo.png) or as request parameter (e.g. http://example.com/context/images?id=1).
In JSP/Servlet world, you can let a Servlet listen on a certain URL pattern like /images/*, so that you can just execute some Java code on specific URL's.
Images are binary data and are to be obtained as either a byte[] or InputStream from the DB, the JDBC API offers the ResultSet#getBytes() and ResultSet#getBinaryStream() for this, and JPA API offers #Lob for this.
In the Servlet you can just write this byte[] or InputStream to the OutputStream of the response the usual Java IO way.
The client side needs to be instructed that the data should be handled as an image, thus at least the Content-Type response header needs to be set as well. You can obtain the right one via ServletContext#getMimeType() based on image file extension which you can extend and/or override via <mime-mapping> in web.xml.
That should be it. It almost writes code itself. Let's start with HTML (in JSP):
<img src="${pageContext.request.contextPath}/images/foo.png">
<img src="${pageContext.request.contextPath}/images/bar.png">
<img src="${pageContext.request.contextPath}/images/baz.png">
You can if necessary also dynamically set src with EL while iterating using JSTL:
<c:forEach items="${imagenames}" var="imagename">
<img src="${pageContext.request.contextPath}/images/${imagename}">
</c:forEach>
Then define/create a servlet which listens on GET requests on URL pattern of /images/*, the below example uses plain vanilla JDBC for the job:
#WebServlet("/images/*")
public class ImageServlet extends HttpServlet {
// content=blob, name=varchar(255) UNIQUE.
private static final String SQL_FIND = "SELECT content FROM Image WHERE name = ?";
#Resource(name="jdbc/yourDB") // For Tomcat, define as <Resource> in context.xml and declare as <resource-ref> in web.xml.
private DataSource dataSource;
#Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String imageName = request.getPathInfo().substring(1); // Returns "foo.png".
try (Connection connection = dataSource.getConnection(); PreparedStatement statement = connection.prepareStatement(SQL_FIND)) {
statement.setString(1, imageName);
try (ResultSet resultSet = statement.executeQuery()) {
if (resultSet.next()) {
byte[] content = resultSet.getBytes("content");
response.setContentType(getServletContext().getMimeType(imageName));
response.setContentLength(content.length);
response.getOutputStream().write(content);
} else {
response.sendError(HttpServletResponse.SC_NOT_FOUND); // 404.
}
}
} catch (SQLException e) {
throw new ServletException("Something failed at SQL/DB level.", e);
}
}
}
That's it. In case you worry about HEAD and caching headers and properly responding on those requests, use this abstract template for static resource servlet.
See also:
How should I connect to JDBC database / datasource in a servlet based application?
How to upload an image and save it in database?
Simplest way to serve static data from outside the application server in a Java web application

I suggest you address that as two problems. There are several questions and answer related to both.
How to load blob from MySQL
See for instance Retrieve image stored as blob
How to display image dynamically
See for instance Show thumbnail dynamically

I've written and configured the code in JSP using Oracle database.
Hope it will help.
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.http.HttpSession;
import javax.servlet.ServletException;
import javax.servlet.ServletOutputStream;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class displayfetchimage
*/
#WebServlet("/displayfetchimage")
public class displayfetchimage extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* #see HttpServlet#HttpServlet()
*/
public displayfetchimage() {
super();
// TODO Auto-generated constructor stub
}
/**
* #see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);// Since my data was in first column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
// response.getWriter().append("Served at: ").append(request.getContextPath());
/**
* #see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
}

Try to flush and close the output stream if it does not display.
Blob image = rs.getBlob(ImageColName);
InputStream in = image.getBinaryStream();
// Output the blob to the HttpServletResponse
response.setContentType("image/jpeg");
BufferedOutputStream o = new BufferedOutputStream(response.getOutputStream());
byte by[] = new byte[32768];
int index = in.read(by, 0, 32768);
while (index != -1) {
o.write(by, 0, index);
index = in.read(by, 0, 32768);
}
o.flush();
o.close();

I used SQL SERVER database and so the answer's code is in accordance. All you have to do is include an <img> tag in your jsp page and call a servlet from its src attribute like this
<img width="200" height="180" src="DisplayImage?ID=1">
Here 1 is unique id of image in database and ID is a variable. We receive value of this variable in servlet. In servlet code we take the binary stream input from correct column in table. That is your image is stored in which column. In my code I used third column because my images are stored as binary data in third column. After retrieving input stream data from table we read its content in an output stream so it can be written on screen. Here is it
import java.io.*;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.*;
import javax.servlet.http.*;
import model.ConnectionManager;
public class DisplayImage extends HttpServlet {
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws IOException
{
Statement stmt=null;
String sql=null;
BufferedInputStream bin=null;
BufferedOutputStream bout=null;
InputStream in =null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = ConnectionManager.getConnection();
int ID = Integer.parseInt(request.getParameter("ID"));
try {
stmt = conn.createStatement();
sql = "SELECT * FROM IMAGETABLE WHERE ID="+ID+"";
ResultSet result = stmt.executeQuery(sql);
if(result.next()){
in=result.getBinaryStream(3);//Since my data was in third column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch=0;
while((ch=bin.read())!=-1)
{
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(DisplayImage.class.getName()).log(Level.SEVERE, null, ex);
}finally{
try{
if(bin!=null)bin.close();
if(in!=null)in.close();
if(bout!=null)bout.close();
if(out!=null)out.close();
if(conn!=null)conn.close();
}catch(IOException | SQLException ex){
System.out.println("Error : "+ex.getMessage());
}
}
}
}
After the execution of your jsp or html file you will see the image on screen.

You can also create custom tag for displaying image.
1) create custom tag java class and tld file.
2) write logic to display image like conversion of byte[] to string by Base64.
so it is used for every image whether you are displaying only one image or multiple images in single jsp page.

Java JSP show Image Icon from Controller in JSP [duplicate]

How can I retrieve and display images from a database in a JSP page?

Let's see in steps what should happen:
JSP is basically a view technology which is supposed to generate HTML output.
To display an image in HTML, you need the HTML <img> element.
To let it locate an image, you need to specify its src attribute.
The src attribute needs to point to a valid http:// URL and thus not a local disk file system path file:// as that would never work when the server and client run at physically different machines.
The image URL needs to have the image identifier in either the request path (e.g. http://example.com/context/images/foo.png) or as request parameter (e.g. http://example.com/context/images?id=1).
In JSP/Servlet world, you can let a Servlet listen on a certain URL pattern like /images/*, so that you can just execute some Java code on specific URL's.
Images are binary data and are to be obtained as either a byte[] or InputStream from the DB, the JDBC API offers the ResultSet#getBytes() and ResultSet#getBinaryStream() for this, and JPA API offers #Lob for this.
In the Servlet you can just write this byte[] or InputStream to the OutputStream of the response the usual Java IO way.
The client side needs to be instructed that the data should be handled as an image, thus at least the Content-Type response header needs to be set as well. You can obtain the right one via ServletContext#getMimeType() based on image file extension which you can extend and/or override via <mime-mapping> in web.xml.
That should be it. It almost writes code itself. Let's start with HTML (in JSP):
<img src="${pageContext.request.contextPath}/images/foo.png">
<img src="${pageContext.request.contextPath}/images/bar.png">
<img src="${pageContext.request.contextPath}/images/baz.png">
You can if necessary also dynamically set src with EL while iterating using JSTL:
<c:forEach items="${imagenames}" var="imagename">
<img src="${pageContext.request.contextPath}/images/${imagename}">
</c:forEach>
Then define/create a servlet which listens on GET requests on URL pattern of /images/*, the below example uses plain vanilla JDBC for the job:
#WebServlet("/images/*")
public class ImageServlet extends HttpServlet {
// content=blob, name=varchar(255) UNIQUE.
private static final String SQL_FIND = "SELECT content FROM Image WHERE name = ?";
#Resource(name="jdbc/yourDB") // For Tomcat, define as <Resource> in context.xml and declare as <resource-ref> in web.xml.
private DataSource dataSource;
#Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String imageName = request.getPathInfo().substring(1); // Returns "foo.png".
try (Connection connection = dataSource.getConnection(); PreparedStatement statement = connection.prepareStatement(SQL_FIND)) {
statement.setString(1, imageName);
try (ResultSet resultSet = statement.executeQuery()) {
if (resultSet.next()) {
byte[] content = resultSet.getBytes("content");
response.setContentType(getServletContext().getMimeType(imageName));
response.setContentLength(content.length);
response.getOutputStream().write(content);
} else {
response.sendError(HttpServletResponse.SC_NOT_FOUND); // 404.
}
}
} catch (SQLException e) {
throw new ServletException("Something failed at SQL/DB level.", e);
}
}
}
That's it. In case you worry about HEAD and caching headers and properly responding on those requests, use this abstract template for static resource servlet.
See also:
How should I connect to JDBC database / datasource in a servlet based application?
How to upload an image and save it in database?
Simplest way to serve static data from outside the application server in a Java web application

I suggest you address that as two problems. There are several questions and answer related to both.
How to load blob from MySQL
See for instance Retrieve image stored as blob
How to display image dynamically
See for instance Show thumbnail dynamically

I've written and configured the code in JSP using Oracle database.
Hope it will help.
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.http.HttpSession;
import javax.servlet.ServletException;
import javax.servlet.ServletOutputStream;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class displayfetchimage
*/
#WebServlet("/displayfetchimage")
public class displayfetchimage extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* #see HttpServlet#HttpServlet()
*/
public displayfetchimage() {
super();
// TODO Auto-generated constructor stub
}
/**
* #see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);// Since my data was in first column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
// response.getWriter().append("Served at: ").append(request.getContextPath());
/**
* #see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
}

Try to flush and close the output stream if it does not display.
Blob image = rs.getBlob(ImageColName);
InputStream in = image.getBinaryStream();
// Output the blob to the HttpServletResponse
response.setContentType("image/jpeg");
BufferedOutputStream o = new BufferedOutputStream(response.getOutputStream());
byte by[] = new byte[32768];
int index = in.read(by, 0, 32768);
while (index != -1) {
o.write(by, 0, index);
index = in.read(by, 0, 32768);
}
o.flush();
o.close();

I used SQL SERVER database and so the answer's code is in accordance. All you have to do is include an <img> tag in your jsp page and call a servlet from its src attribute like this
<img width="200" height="180" src="DisplayImage?ID=1">
Here 1 is unique id of image in database and ID is a variable. We receive value of this variable in servlet. In servlet code we take the binary stream input from correct column in table. That is your image is stored in which column. In my code I used third column because my images are stored as binary data in third column. After retrieving input stream data from table we read its content in an output stream so it can be written on screen. Here is it
import java.io.*;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.*;
import javax.servlet.http.*;
import model.ConnectionManager;
public class DisplayImage extends HttpServlet {
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws IOException
{
Statement stmt=null;
String sql=null;
BufferedInputStream bin=null;
BufferedOutputStream bout=null;
InputStream in =null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = ConnectionManager.getConnection();
int ID = Integer.parseInt(request.getParameter("ID"));
try {
stmt = conn.createStatement();
sql = "SELECT * FROM IMAGETABLE WHERE ID="+ID+"";
ResultSet result = stmt.executeQuery(sql);
if(result.next()){
in=result.getBinaryStream(3);//Since my data was in third column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch=0;
while((ch=bin.read())!=-1)
{
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(DisplayImage.class.getName()).log(Level.SEVERE, null, ex);
}finally{
try{
if(bin!=null)bin.close();
if(in!=null)in.close();
if(bout!=null)bout.close();
if(out!=null)out.close();
if(conn!=null)conn.close();
}catch(IOException | SQLException ex){
System.out.println("Error : "+ex.getMessage());
}
}
}
}
After the execution of your jsp or html file you will see the image on screen.

You can also create custom tag for displaying image.
1) create custom tag java class and tld file.
2) write logic to display image like conversion of byte[] to string by Base64.
so it is used for every image whether you are displaying only one image or multiple images in single jsp page.

how to store and retrieve a jpg image in oracle database using BLOB datatype in java

I've tried the following code to retrieve an image stored in the oracle database with BLOB datatype. Upon running it in apace tomcat7 server i could only see an image icon(may be a broken image) but not an image. When I tried to open the image icon it got downloaded. I opened the downloaded image using picasa but it displayed "invalid image".
PLEASE try solving my problem....!!
public class RetrieveInkblot extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException {
Blob photo = null;
Connection conn = null;
Statement stmt = null;
ResultSet rs = null;
String query = "select img from inkblots where bid = 23";
ServletOutputStream out = response.getOutputStream();
try {
Class.forName("oracle.jdbc.driver.OracleDriver");
conn = DriverManager.getConnection("jdbc:oracle:thin:#localhost:1521:XE", "system", "manager");
out.println("Connection");
stmt = conn.createStatement();
rs = stmt.executeQuery(query);
if (rs == null) {
out.print("null except");
} else if (rs.next()) {
photo = rs.getBlob(1);
} else {
response.setContentType("text/html");
out.println("<html><head><title>Person Photo</title></head>");
out.println("<body><h1>No photo found for id= 001 </h1></body></html>");
return;
}
byte[] imgData = photo.getBytes(1, (int) photo.length());
response.setContentType("image/jpg");
OutputStream o = response.getOutputStream();
o.write(imgData);
o.flush();
o.close();
} catch (Exception e) {
response.setContentType("text/html");
out.println("<html><head><title>Error: Person Photo</title></head>");
out.println("<body><h1>Error=" + e.getMessage() + "</h1></body></html>");
return;
}
}
}

Your error is in this line:
byte[] imgData = photo.getBytes(1,(int)photo.length());
Note that java starts counting by 0, so change it to this line:
byte[] imgData = photo.getBytes(0,(int)photo.length());
If this gives you a IndexOutOfBoundsException, you also need to decrement photo.length():
byte[] imgData = photo.getBytes(0,(int)photo.length()-1);
By the way I wouldn't save the picture in the database, I would either write the image into your server and write the url into database, or encode the image with base64 witch is easier to read back.

Problems when sending XML data from HTTP Java client to a servlet with HttpURLConnection

I have standalone java client sending xml data to http servlet using httpURLconnection class.but data appearing in non printable character format.
For simulation i have been trying to send simple string but still it was appearing in non printable format.
I have written the following client code to communicate with servlet,
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.ProtocolException;
import java.net.URL;
public class HttpClient implements IClient {
private static IClient client = null;
private HttpURLConnection httpConn = null;
private OutputStream output = null;
private InputStream input = null;
private OutputStreamWriter out = null;
private HttpClient() {
}
public static IClient getHttpClient() {
if (client == null) {
client = new HttpClient();
}
return client;
}
#Override
public void connect(String urlString) throws IOException {
URL url = new URL(urlString);
httpConn = (HttpURLConnection) url.openConnection();
initConnection();
httpConn.connect();
output = httpConn.getOutputStream();
input = httpConn.getInputStream();
System.out.println("Connection Response:" + httpConn.getResponseCode());
}
#Override
public void sendFile(File file) throws IOException {
// BufferedOutputStream bos = new BufferedOutputStream(output);
// InputStream fis = new FileInputStream(file);
// int bytesRead = 0;
// byte[] buffer = new byte[8192];
// while ((bytesRead = fis.read(buffer, 0, 8192)) != -1) {
// bos.write(buffer, 0, bytesRead);
// System.out.println("write:"+buffer);
// }
// bos.close();
// fis.close();
OutputStreamWriter out = new OutputStreamWriter(output, "UTF-16");
out.write("test me");
}
#Override
public boolean isConnected() {
return httpConn != null ? true : false;
}
#Override
public void close() {
httpConn.disconnect();
}
private void initConnection() throws ProtocolException {
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
httpConn.setRequestMethod("POST");
httpConn.setUseCaches(false);
httpConn.setRequestProperty("Content-Type",
"text/xml; charset=\"UTF-16\"");
httpConn.setRequestProperty("Connection", "Keep-Alive");
}
private static byte[] getBytesFromFile(File file) throws IOException {
InputStream is = new FileInputStream(file);
System.out.println("\nDEBUG: FileInputStream is " + file);
// Get the size of the file
long length = file.length();
System.out.println("DEBUG: Length of " + file + " is " + length + "\n");
/*
* You cannot create an array using a long type. It needs to be an int
* type. Before converting to an int type, check to ensure that file is
* not loarger than Integer.MAX_VALUE;
*/
if (length > Integer.MAX_VALUE) {
System.out.println("File is too large to process");
return null;
}
// Create the byte array to hold the data
byte[] bytes = new byte[(int) length];
// Read in the bytes
int offset = 0;
int numRead = 0;
while ((offset < bytes.length)
&& ((numRead = is.read(bytes, offset, bytes.length - offset)) >= 0)) {
offset += numRead;
}
// Ensure all the bytes have been read in
if (offset < bytes.length) {
throw new IOException("Could not completely read file "
+ file.getName());
}
return bytes;
}
}
and servlet code is given below,
import java.io.BufferedInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class XMLServlet extends HttpServlet {
#Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
doPost(req, resp);
}
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
System.out.println("=========inside doPost=========");
// BufferedInputStream bis = new BufferedInputStream(req.getInputStream());
// OutputStream fos = new FileOutputStream("test.xml");
// int bytesRead = 0;
// byte[] buffer = new byte[8192];
// while ((bytesRead = bis.read(buffer, 0, 8192)) != -1) {
// System.out.println("read:"+buffer);
// fos.write(buffer, 0, bytesRead);
// }
// fos.close();
// bis.close();
//
req.setCharacterEncoding("UTF-16");
InputStreamReader isr = new InputStreamReader(req.getInputStream(),"UTF-16");
char[] data = new char[10];
isr.read(data);
System.out.println(data);
for (char c : data) {
System.out.println(c);
}
}
}
Please any help me to get out of this problem.

I think you are overcomplicating it. I JUST wrote something similar that takes any file and transfers it through HTTP to a servlet. Just remember: All data is binary (including a text file)-- period. It's up to the given application to interpret that binary data. For example, notepad.exe simply reads a binary set of data and attempts to format it using ASCII standard. So knowing that, simply read a file using a raw stream, set the mime-type of the connection to application/octet-stream and send it via "PUT" method. The servlet code should be reading the file using the raw InputStream from the request and creating the corresponding file in its space.
From the client code:
URL url = new URL(urlString);
HttpURLConnection cnx = (HttpURLConnection)url.openConnection();
cnx.setRequestMethod("PUT");
cnx.setRequestProperty("Content-Type", "application/octet-stream");
// optional request property
cnx.setRequestProperty("filename", filename);
cnx.setDoOutput(true);
cnx.connect();
BufferedInputStream fileIn =
new BufferedInputStream(new FileInputStream(fileName), BUFFER_SIZE);
BufferedOutputStream out =
new BufferedOutputStream(cnx.getOutputStream(), BUFFER_SIZE);
byte[] bytes = new byte[BUFFER_SIZE];
int bytesRead;
while((bytesRead = fileIn.read(bytes)) != -1){
out.write(bytes, 0, bytesRead);
}
That's it.
Now the servlet code....
public void doPut(HttpServletRequest request, HttpServletResponse response){
String filename = (String)request.getHeader("filename");
StringBuilder fullPath = new StringBuilder(100);
ServletContext ctxt = getServletContext();
fullPath.append(ctxt.getRealPath(""))
.append("uploads\\").append(filename);
File f = new File(fullPath.toString());
f.createNewFile();
InputStream in = request.getInputStream();
BufferedOutputStream fileOut =
new BufferedOutputStream(new FileOutputStream(f));
byte[] bytes = new byte[BUFFER_SIZE];
int bytesRead;
while((bytesRead = in.read(bytes)) != -1){
fileOut.write(bytes, 0, bytesRead);
}
fileOut.flush();
fileOut.close();
response.setStatus(HttpServletResponse.SC_CREATED);
}

There are two major ways to upload a file on to server using http methods:
Upload a file using PUT method. This allow you to put one file at a time on to server. PUT method is easy to implement but you cannot upload a file from a html form (e.g. uploading form in your web browser) using PUT method.
Upload files using POST method. This is more complicated but most web site uses this to upload files on to server. You can do multiple file uploading per request. This is what I am going to talk about.
Note: GET is not used for file uploading unless you encode it somehow.
Uploading files using URLConnection is not straight forwards and requires you to prepare your data in "multipart form". Of course, you shouldn't do it yourself. There are a number of libraries to deal with this for you, e.g. HttpClient. If you really want to use URLConnection, I shall refer to previous question on "How to use java.net.URLConnection to fire and handle HTTP requests"
Below is the code for uploading your file using HttpClient. It is simplified from HttpClient example code.
import java.io.File;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.methods.PostMethod;
import org.apache.commons.httpclient.methods.multipart.FilePart;
import org.apache.commons.httpclient.methods.multipart.MultipartRequestEntity;
import org.apache.commons.httpclient.methods.multipart.Part;
import org.apache.commons.httpclient.params.HttpMethodParams;
public class MultipartFileUploadApp {
public static void main(String[] args) {
String targetURL = "http://localhost:8080/yourserver/upload";
File targetFile = new File("/path/to/your/file.txt");
PostMethod filePost = new PostMethod(targetURL);
filePost.getParams().setBooleanParameter(HttpMethodParams.USE_EXPECT_CONTINUE, false);
try {
System.out.println("Uploading " + targetFile.getName() + " to " + targetURL);
// add more parts you want to upload multiple files.
Part[] parts = {new FilePart(targetFile.getName(), targetFile)};
filePost.setRequestEntity(new MultipartRequestEntity(parts, filePost.getParams()));
HttpClient client = new HttpClient();
client.getHttpConnectionManager().getParams().setConnectionTimeout(5000);
int status = client.executeMethod(filePost);
if (status == HttpStatus.SC_OK) {
System.out.println("Upload complete, response=" + filePost.getResponseBodyAsString());
} else {
System.out.println("Upload failed, response=" + HttpStatus.getStatusText(status));
}
} catch (Exception ex) {
System.out.println("Error: " + ex.getMessage());
ex.printStackTrace();
} finally {
filePost.releaseConnection();
}
}
}
For the server side, you have to parse multipart form request. Of course, there exists libraries to do that for you. Here is the snipplet I am using
import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Iterator;
import java.util.List;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
public class CommonsFileUploadServlet extends HttpServlet {
private static final String TMP_DIR_PATH = "c:\\tmp";
private File tmpDir;
private static final String DESTINATION_DIR_PATH = "c:\\tmp\\files";
private File destinationDir;
public void init(ServletConfig config) throws ServletException {
super.init(config);
tmpDir = new File(TMP_DIR_PATH);
if (!tmpDir.isDirectory()) {
throw new ServletException(TMP_DIR_PATH + " is not a directory");
}
//String realPath = getServletContext().getRealPath(DESTINATION_DIR_PATH);
destinationDir = new File(DESTINATION_DIR_PATH);
if (!destinationDir.isDirectory()) {
throw new ServletException(DESTINATION_DIR_PATH + " is not a directory");
}
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
response.setContentType("text/plain");
out.println("<h1>Servlet File Upload Example using Commons File Upload</h1>");
out.println();
DiskFileItemFactory fileItemFactory = new DiskFileItemFactory();
/*
*Set the size threshold, above which content will be stored on disk.
*/
fileItemFactory.setSizeThreshold(1 * 1024 * 1024); //1 MB
/*
* Set the temporary directory to store the uploaded files of size above threshold.
*/
fileItemFactory.setRepository(tmpDir);
ServletFileUpload uploadHandler = new ServletFileUpload(fileItemFactory);
try {
/*
* Parse the request
*/
List items = uploadHandler.parseRequest(request);
out.println("Count : " + items.size());
Iterator itr = items.iterator();
while (itr.hasNext()) {
FileItem item = (FileItem) itr.next();
/*
* Handle Form Fields.
*/
if (item.isFormField()) {
out.println("Field = " + item.getFieldName() + ", Value = " + item.getString());
} else {
//Handle Uploaded files.
out.println("Field Name = " + item.getFieldName()
+ ", File Name = " + item.getName()
+ ", Content type = " + item.getContentType()
+ ", File Size = " + item.getSize());
/*
* Write file to the ultimate location.
*/
File file = new File(destinationDir, item.getName());
item.write(file);
}
}
out.close();
} catch (FileUploadException ex) {
log("Error encountered while parsing the request", ex);
} catch (Exception ex) {
log("Error encountered while uploading file", ex);
}
}
}

I have standalone java client sending xml data to http servlet using httpURLconnection class.but data appearing in non printable character format.
I can understand that. You're sending the data as UTF-16, but the XML file itself is likely not saved in UTF-16. You need to use the same character encoding as the XML file is saved in. That's usually UTF-8.
For simulation i have been trying to send simple string but still it was appearing in non printable format.
I don't understand that. It should work fine the way as you have in the code. Probably you didn't test it properly.

How to retrieve and display images from a database in a JSP page?

How can I retrieve and display images from a database in a JSP page?

Let's see in steps what should happen:
JSP is basically a view technology which is supposed to generate HTML output.
To display an image in HTML, you need the HTML <img> element.
To let it locate an image, you need to specify its src attribute.
The src attribute needs to point to a valid http:// URL and thus not a local disk file system path file:// as that would never work when the server and client run at physically different machines.
The image URL needs to have the image identifier in either the request path (e.g. http://example.com/context/images/foo.png) or as request parameter (e.g. http://example.com/context/images?id=1).
In JSP/Servlet world, you can let a Servlet listen on a certain URL pattern like /images/*, so that you can just execute some Java code on specific URL's.
Images are binary data and are to be obtained as either a byte[] or InputStream from the DB, the JDBC API offers the ResultSet#getBytes() and ResultSet#getBinaryStream() for this, and JPA API offers #Lob for this.
In the Servlet you can just write this byte[] or InputStream to the OutputStream of the response the usual Java IO way.
The client side needs to be instructed that the data should be handled as an image, thus at least the Content-Type response header needs to be set as well. You can obtain the right one via ServletContext#getMimeType() based on image file extension which you can extend and/or override via <mime-mapping> in web.xml.
That should be it. It almost writes code itself. Let's start with HTML (in JSP):
<img src="${pageContext.request.contextPath}/images/foo.png">
<img src="${pageContext.request.contextPath}/images/bar.png">
<img src="${pageContext.request.contextPath}/images/baz.png">
You can if necessary also dynamically set src with EL while iterating using JSTL:
<c:forEach items="${imagenames}" var="imagename">
<img src="${pageContext.request.contextPath}/images/${imagename}">
</c:forEach>
Then define/create a servlet which listens on GET requests on URL pattern of /images/*, the below example uses plain vanilla JDBC for the job:
#WebServlet("/images/*")
public class ImageServlet extends HttpServlet {
// content=blob, name=varchar(255) UNIQUE.
private static final String SQL_FIND = "SELECT content FROM Image WHERE name = ?";
#Resource(name="jdbc/yourDB") // For Tomcat, define as <Resource> in context.xml and declare as <resource-ref> in web.xml.
private DataSource dataSource;
#Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String imageName = request.getPathInfo().substring(1); // Returns "foo.png".
try (Connection connection = dataSource.getConnection(); PreparedStatement statement = connection.prepareStatement(SQL_FIND)) {
statement.setString(1, imageName);
try (ResultSet resultSet = statement.executeQuery()) {
if (resultSet.next()) {
byte[] content = resultSet.getBytes("content");
response.setContentType(getServletContext().getMimeType(imageName));
response.setContentLength(content.length);
response.getOutputStream().write(content);
} else {
response.sendError(HttpServletResponse.SC_NOT_FOUND); // 404.
}
}
} catch (SQLException e) {
throw new ServletException("Something failed at SQL/DB level.", e);
}
}
}
That's it. In case you worry about HEAD and caching headers and properly responding on those requests, use this abstract template for static resource servlet.
See also:
How should I connect to JDBC database / datasource in a servlet based application?
How to upload an image and save it in database?
Simplest way to serve static data from outside the application server in a Java web application

I suggest you address that as two problems. There are several questions and answer related to both.
How to load blob from MySQL
See for instance Retrieve image stored as blob
How to display image dynamically
See for instance Show thumbnail dynamically

I've written and configured the code in JSP using Oracle database.
Hope it will help.
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.http.HttpSession;
import javax.servlet.ServletException;
import javax.servlet.ServletOutputStream;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class displayfetchimage
*/
#WebServlet("/displayfetchimage")
public class displayfetchimage extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* #see HttpServlet#HttpServlet()
*/
public displayfetchimage() {
super();
// TODO Auto-generated constructor stub
}
/**
* #see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);// Since my data was in first column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
// response.getWriter().append("Served at: ").append(request.getContextPath());
/**
* #see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
Statement stmt = null;
String sql = null;
BufferedInputStream bin = null;
BufferedOutputStream bout = null;
InputStream in = null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = employee.DbConnection.getDatabaseConnection();
HttpSession session = (HttpSession) request.getSession();
String ID = session.getAttribute("userId").toString().toLowerCase();
try {
stmt = conn.createStatement();
sql = "select user_image from employee_data WHERE username='" + ID + "' and rownum<=1";
ResultSet result = stmt.executeQuery(sql);
if (result.next()) {
in = result.getBinaryStream(1);
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch = 0;
while ((ch = bin.read()) != -1) {
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(displayfetchimage.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
if (bin != null)
bin.close();
if (in != null)
in.close();
if (bout != null)
bout.close();
if (out != null)
out.close();
if (conn != null)
conn.close();
} catch (IOException | SQLException ex) {
System.out.println("Error : " + ex.getMessage());
}
}
}
}

Try to flush and close the output stream if it does not display.
Blob image = rs.getBlob(ImageColName);
InputStream in = image.getBinaryStream();
// Output the blob to the HttpServletResponse
response.setContentType("image/jpeg");
BufferedOutputStream o = new BufferedOutputStream(response.getOutputStream());
byte by[] = new byte[32768];
int index = in.read(by, 0, 32768);
while (index != -1) {
o.write(by, 0, index);
index = in.read(by, 0, 32768);
}
o.flush();
o.close();

I used SQL SERVER database and so the answer's code is in accordance. All you have to do is include an <img> tag in your jsp page and call a servlet from its src attribute like this
<img width="200" height="180" src="DisplayImage?ID=1">
Here 1 is unique id of image in database and ID is a variable. We receive value of this variable in servlet. In servlet code we take the binary stream input from correct column in table. That is your image is stored in which column. In my code I used third column because my images are stored as binary data in third column. After retrieving input stream data from table we read its content in an output stream so it can be written on screen. Here is it
import java.io.*;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.*;
import javax.servlet.http.*;
import model.ConnectionManager;
public class DisplayImage extends HttpServlet {
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws IOException
{
Statement stmt=null;
String sql=null;
BufferedInputStream bin=null;
BufferedOutputStream bout=null;
InputStream in =null;
response.setContentType("image/jpeg");
ServletOutputStream out;
out = response.getOutputStream();
Connection conn = ConnectionManager.getConnection();
int ID = Integer.parseInt(request.getParameter("ID"));
try {
stmt = conn.createStatement();
sql = "SELECT * FROM IMAGETABLE WHERE ID="+ID+"";
ResultSet result = stmt.executeQuery(sql);
if(result.next()){
in=result.getBinaryStream(3);//Since my data was in third column of table.
}
bin = new BufferedInputStream(in);
bout = new BufferedOutputStream(out);
int ch=0;
while((ch=bin.read())!=-1)
{
bout.write(ch);
}
} catch (SQLException ex) {
Logger.getLogger(DisplayImage.class.getName()).log(Level.SEVERE, null, ex);
}finally{
try{
if(bin!=null)bin.close();
if(in!=null)in.close();
if(bout!=null)bout.close();
if(out!=null)out.close();
if(conn!=null)conn.close();
}catch(IOException | SQLException ex){
System.out.println("Error : "+ex.getMessage());
}
}
}
}
After the execution of your jsp or html file you will see the image on screen.

You can also create custom tag for displaying image.
1) create custom tag java class and tld file.
2) write logic to display image like conversion of byte[] to string by Base64.
so it is used for every image whether you are displaying only one image or multiple images in single jsp page.