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Jar cannot find txt File in FileOutputStream

**I am trying to save and get Player objects from a Textfile and it works when using my IDE but when i create a Jar it can't find the text File. I tried with
this.getClas().getResources(path)
But still it didnt find the path to my text file.Can anybody Help?
public void setPlayer() throws FileNotFoundException {
ArrayList<Player> playerArrayList = new ArrayList<>();
playerArrayList = getPlayers();
Player player = new Player();
player.name = ViewManager.name;
player.score = Collision.points;
playerArrayList.add(player);
try{
FileOutputStream fileOut = new FileOutputStream("src/resources/highscore.txt");
ObjectOutputStream out = new ObjectOutputStream(fileOut);
for(Player player1 : playerArrayList){
out.writeObject(player1);
}
out.close();
fileOut.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
´´´´

Resource files are not physical Files, as they can be inside a jar. They are intended to be read-only, and the class loader may cache them. They are case sensitive, with / as path separator and there path starts at the class path's root, probably src/resources.
So use the resource file as fall back resource to copy, if some physical file does not exist.
Path appDir = Paths.get(System.getProperty("user.home") + ".myapp");
Files.createDirectories(appDir);
Path file = appDir.resolve("highscore.txt");
if (!Files.exists(file)) {
// Copy resource to file, either:
URL url = getClass().getResource("/highscore.txt");
Path templatePath = Paths.get(url.toURI());
Files.copy(templatePath, file);
// Or
InputStream templateIn = getClass().getResourceAsStream("/highscore.txt");
Files.copy(templateIn, file);
}
try (FileOutputStream out = Files.newOutputStream(file)) {
...
}
Path is the generalisation of File.

I don't know what IDE you're using, but you're writing the file to the source sub directory. That directory might not be included in the jar.

URI not hierarchical need to use File class for a method

I need to open a video file with my code, and it works perfectly fine in Eclipse but when I export into a runnable JAR, i get an error "URI not hierarchical".
I have seen people suggest using getResourceAsStream(), but i need to have a file object as i am using Desktop.getDesktop.open(File). Can anyone help me out?
Here is the code:
try {
URI path1 = getClass().getResource("/videos/tutorialVid1.mp4").toURI();
File f = new File(path1);
Desktop.getDesktop().open(f);
} catch (Exception e) {
e.printStackTrace();
}
if it helps my folder list is like
Src
videos
videoFile.mp4
EDIT:
I plan to run this on windows only, and use launch4j to create an exe.

You can copy the file from the jar to a temporary file and open that.
Here's a method to create a temporary file for a given jar resource:
public static File createTempFile(String path) {
String[] parts = path.split("/");
File f = File.createTempFile(parts[parts.length - 1], ".tmp");
f.deleteOnExit();
try (Inputstream in = getClass().getResourceAsStream(path)) {
Files.copy(in, f.toPath(), StandardCopyOption.REPLACE_EXISTING);
}
return f;
}
And here's an example of how you'd use it:
Desktop.getDesktop().open(createTempFile("/videos/tutorialVid1.mp4"));

File get save under some Unknown Path in Eclipse

I am using Eclipse and have the following folder structure:
Eclipse Folder Structure
In UserHelper.java i have the code
try {
File file = new File ("vikvik1.JSON");
if (!file.exists ()) {
System.out.println ("No file");
file.createNewFile ();
temp = true;
}
System.out.println (file.getAbsolutePath ());
} catch (IOException ioe) {
System.out.println ("Exception occurred:");
ioe.printStackTrace ();
}
But after creating the file, the output is C:\Users\a595649\Documents\Vikram Thakur\Soft\eclipse\vikvik1.JSON
This is the location where my Eclipse Exe file is stored.
How can I get this File saved under my project DBnov folder ?

You have to provide the path of your file while instantiating the File object, otherwise java select it per default.
See the javadoc for the constructor, you can initiate it different ways, for example with the path as String:
File file = new File ("your_path", "vikvik1.JSON");

One possible solution:
create a property file under your classpath, say foo.properties
put there a property like
basePath=/some/path/you/want/to/use
Read the property file
String basePath="";
final Properties properties = new Properties();
try (final InputStream stream =
this.getClass().getResourceAsStream("foo.properties")) {
properties.load(stream);
basePath=properties.getProperty("basePath");
}
Read your file
File file = new File ("basePath","vikvik1.JSON");

Read text file from resource folder and populate jTextArea (NetBeans Java)

StringBuilder result = new StringBuilder("");
ClassLoader classLoader = getClass().getClassLoader();
File file = new File(classLoader.getResource("DBase.dat").getFile());
try (Scanner scanner = new Scanner(file)) {
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
result.append(line).append("\n");
}
jTextArea1.setText(result.toString());
scanner.close();
} catch (FileNotFoundException ex) {
}
I am new to JAVA and netBeans I am using this code to read a text file from resources folder and then populate jTextArea from that file. But I am getting Errors. I want to read textfile line by line not all the text at once...
Please Help me what should I do.
I am pasting a picture too...
Project Picture

try something like that:
File file = new File(classLoader.getResource("DBase.dat").getPath());

Java, reading a file from current directory?

I want a java program that reads a user specified filename from the current directory (the same directory where the .class file is run).
In other words, if the user specifies the file name to be "myFile.txt", and that file is already in the current directory:
reader = new BufferedReader(new FileReader("myFile.txt"));
does not work. Why?
I'm running it in windows.

Try
System.getProperty("user.dir")
It returns the current working directory.

The current directory is not (necessarily) the directory the .class file is in. It's working directory of the process. (ie: the directory you were in when you started the JVM)
You can load files from the same directory* as the .class file with getResourceAsStream(). That'll give you an InputStream which you can convert to a Reader with InputStreamReader.
*Note that this "directory" may actually be a jar file, depending on where the class was loaded from.

None of the above answer works for me. Here is what works for me.
Let's say your class name is Foo.java, to access to the myFile.txt in the same folder as Foo.java, use this code:
URL path = Foo.class.getResource("myFile.txt");
File f = new File(path.getFile());
reader = new BufferedReader(new FileReader(f));

Files in your project are available to you relative to your src folder. if you know which package or folder myfile.txt will be in, say it is in
----src
--------package1
------------myfile.txt
------------Prog.java
you can specify its path as "src/package1/myfile.txt" from Prog.java

If you know your file will live where your classes are, that directory will be on your classpath. In that case, you can be sure that this solution will solve your problem:
URL path = ClassLoader.getSystemResource("myFile.txt");
if(path==null) {
//The file was not found, insert error handling here
}
File f = new File(path.toURI());
reader = new BufferedReader(new FileReader(f));

Thanks #Laurence Gonsalves your answer helped me a lot.
your current directory will working directory of proccess so you have to give full path start from your src directory like mentioned below:
public class Run {
public static void main(String[] args) {
File inputFile = new File("./src/main/java/input.txt");
try {
Scanner reader = new Scanner(inputFile);
while (reader.hasNextLine()) {
String data = reader.nextLine();
System.out.println(data);
}
reader.close();
} catch (FileNotFoundException e) {
System.out.println("scanner error");
e.printStackTrace();
}
}
}
While my input.txt file is in same directory.

Try this:
BufferedReader br = new BufferedReader(new FileReader("java_module_name/src/file_name.txt"));

try using "."
E.g.
File currentDirectory = new File(".");
This worked for me