UUID got lost in translation? - java

I have a MySQL table with UUID as id. When I select (in MySQL Workbench), I get:
269ecb9e-b7fe-11e6-a630-657416131b50
667d6caa-b800-11e6-a630-657416131b50
6f94b93c-b734-11e6-8618-ba2ba7c3db03
ab8478b8-b7fe-11e6-a630-657416131b50
ddb6b7d8-b80d-11e6-a630-657416131b50
fc031a90-b805-11e6-a630-657416131b50
Then I query in Java using Hibernate, and I get:
32363965-6362-3965-2d62-3766652d3131
36363764-3663-6161-2d62-3830302d3131
36663934-6239-3363-2d62-3733342d3131
61623834-3738-6238-2d62-3766652d3131
64646236-6237-6438-2d62-3830642d3131
66633033-3161-3930-2d62-3830352d3131
As you can see, I really don't get the same result.
My database schema uses a char(36) and is as:
CREATE TABLE `table` (
`id` char(36) NOT NULL COMMENT 'Unique identifier as a UUID.',
`fragment` text COMMENT 'Generic field. '
PRIMARY KEY (`id`),
UNIQUE KEY `id_UNIQUE` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
My Hibernate POJO is:
package net.jgp.map.pojo;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
import java.util.UUID;
#Entity
#Table(name = "table", catalog = "z_map")
public class ExternalMapping {
private String id;
private String fragment;
#Id
#Column(name = "id", unique = true, nullable = false)
public UUID getId() {
return java.util.UUID.fromString(this.id);
}
public void setId(UUID id) {
this.id = id.toString();
}
#Column(name = "fragment")
public String getFragment() {
return this.fragment;
}
public void setFragment(String fragment) {
this.fragment = fragment;
}
}
The rest is classic Hibernate code (happy to share if helpful).
My first attempt was without the toString() stuff and using UUID natively in the POJO code, but the result was the same.

Related

Spring Boot org.hibernate.exception.ConstraintViolationException

I am getting .ConstraintViolationException when I try to persist data using the POST REST API.
Caused by: org.postgresql.util.PSQLException: ERROR: null value in column "id" violates not-null constraint
Detail: Failing row contains (null, John Doe, How are you?, I am fine).
I am using #GeneratedValue(strategy = GenerationType.IDENTITY) to auto generate "id" from Hibernate and I am not sure If I am missing any configuration in application.properties. I am using Postgres db.
I tried using GenerationType.AUTO and I was getting hibernate_sequence missing error from postgres.
Thanks!
POST REST API input using Postman
{
"personName": "John Doe",
"question": "How are you?",
"response": "I am fine"
}
questionnaries.sql
CREATE TABLE questionnaries(
id BIGINT PRIMARY KEY,
personName VARCHAR(255) NOT NULL,
question VARCHAR(255) NOT NULL,
response VARCHAR(255) NOT NULL
);
Questionnarie.java #
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
#Entity
#Table(name = "questionnaries")
public class Questionnarie {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "personname")
#NotNull
private String personname;
#Column(name = "question")
#NotNull
private String question;
#Column(name = "response")
#NotNull
private String response;
public Questionnarie() {}
public Questionnarie(#NotNull String personname, #NotNull String question, #NotNull String response) {
super();
this.personname = personname;
this.question = question;
this.response = response;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getPersonname() {
return personname;
}
public void setPersonname(String personname) {
this.personname = personname;
}
public String getQuestion() {
return question;
}
public void setQuestion(String question) {
this.question = question;
}
public String getResponse() {
return response;
}
public void setResponse(String response) {
this.response = response;
}}
application.properties
# ===============================
# = DATA SOURCE
# ===============================
# Set here configurations for the database connection
spring.datasource.jndi-name=java:jboss/datasources/test_data_source
# ===============================
# = JPA / HIBERNATE
# ===============================
# Show or not log for each sql query
spring.jpa.show-sql=true
# Allows Hibernate to generate SQL optimized for a particular DBMS
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect
That means your database supports sequences for primary key values. So in your case, you will have to create a Database sequence and then use #GeneratedValue(strategy=GenerationType.AUTO) or #GeneratedValue(strategy=GenerationType.SEQUENCE, generator="seq")
#SequenceGenerator(name="seq", sequenceName = "db_seq_name") to generate values for primary key fields.
Also make sure that you add SERIAL to your SQL, so that it looks like: id SERIAL PRIMARY KEY
See the PostgreSQL documentation for the serial data types.
Change your script to:
CREATE TABLE questionnaries(
id BIGINT PRIMARY KEY GENERATED BY DEFAULT AS IDENTITY,
personName VARCHAR(255) NOT NULL,
question VARCHAR(255) NOT NULL,
response VARCHAR(255) NOT NULL
);

How to configure a polymorphic Map relationship with EBean?

I have seen examples of setting up Map association with EBean. Examples I've seen typically support a schema as below.
With such a schema, the JPA mapping of Video would have a property public List<VideoMetadata> metadata;.
How can I change this so that metadata is a Map instead of a List, for instance public Map<String, String> metadata;?
CREATE TABLE video (
id UUID PRIMARY KEY,
title VARCHAR(255) NOT NULL
);
CREATE TABLE metadata (
id BIGSERIAL PRIMARY KEY,
video_id UUID NOT NULL, -- this relationship is not polymorphic
key VARCHAR(255) NOT NULL,
value VARCHAR(255) NOT NULL
);
I have defined a polymorphic relationship between Metadata and Video (and Photo, and on...). A Video can have multiple metadata, as can a Photo.
The polymorphic relationship is configured with InheritanceType.SINGLE_TABLE and the "describable" is identified via a combination of describable_type and describable_id.
The database schema looks like this.
CREATE TABLE video (
id UUID PRIMARY KEY,
title VARCHAR(255) NOT NULL
);
CREATE TABLE metadata (
id BIGSERIAL PRIMARY KEY,
describable_id UUID NOT NULL, -- now we have polymorphism
describable_type VARCHAR(255) NOT NULL, -- now we have polymorphism
key VARCHAR(255) NOT NULL,
value VARCHAR(255) NOT NULL
);
And the models (in case it's relevant, I'm using Ebean)...
package models;
import io.ebean.Model;
import javax.persistence.Id;
import java.util.UUID;
import play.data.validation.Constraints;
import javax.persistence.*;
import java.util.List;
#Entity
public class Video extends Model {
#Id
public UUID id;
#Constraints.Required
public String title;
#ElementCollection(fetch = FetchType.EAGER)
#OneToMany(mappedBy = "describable", cascade = CascadeType.ALL)
public List<VideoMetadata> metadata;
}
package models;
import io.ebean.Model;
import play.data.validation.Constraints;
import javax.persistence.*;
#Entity
#Inheritance(strategy = InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(
name = "describable_type",
discriminatorType = DiscriminatorType.STRING
)
public abstract class Metadata extends Model {
#Id
#GeneratedValue
public Long id;
#Constraints.Required
public String key;
#Constraints.Required
public String value;
}
package models;
import javax.persistence.DiscriminatorValue;
import javax.persistence.Entity;
import javax.persistence.ManyToOne;
#Entity
#DiscriminatorValue("video")
public class VideoMetadata extends Metadata {
#ManyToOne(optional = false)
public Video describable;
}
package models;
import javax.persistence.DiscriminatorValue;
import javax.persistence.Entity;
import javax.persistence.ManyToOne;
#Entity
#DiscriminatorValue("photo")
public class ImageMetadata extends Metadata {
#ManyToOne(optional = false)
public Photo describable;
}

org.h2.jdbc.JdbcSQLException: Column "Id" not found during testing with H2 Database

I have a class that uses a Hibernate session to call a stored procedure via a JPA #NamedNativeQuery using an in memory H2 database for testing (the actual database is MySQL). The stored procedure inserts a record into a database table and then returns that row.
However during testing, on converting to the JPA #Entity, I am seeing an H2 database error: org.h2.jdbc.JdbcSQLException: Column "Id" not found.
I've documented a cut down version of the code below.
As far as I can tell I think it has something to do with the H2 interpretation of the #Id annotation, but don't understand why, so any help would be gratefully appreciated...
NB - I have searched Stack overflow fairly extensively, including the issue relating to the use of double quotes for column specification, but don't think that this relates to my situation...
Table
CREATE TABLE History.Status_Report (
Id INT NOT NULL AUTO_INCREMENT,
Unique_Users INT NOT NULL,
PRIMARY KEY (Id)
);
Stored Procedure
CREATE PROCEDURE History.Status_Reporting(reporting_date DATE)
BEGIN
INSERT INTO history.status_report (Unique_Users) VALUES (10);
SELECT *
 FROM History.Status_Report WHERE Id = LAST_INSERT_ID();
END;
Entity
package com.test;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.NamedNativeQuery;
import javax.persistence.Table;
import java.io.Serializable;
#NamedNativeQuery(name = "callStatusReporting", query = "CALL Status_Reporting(:reporting_date)", resultClass = StatusReportEntity.class)
#Entity
#Table(name = "Status_Report", catalog = "History")
public class StatusReportEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue
#Column(name = "Id")
protected Integer id;
#Column(name = "Unique_Users")
protected int uniqueUsers;
public Integer getId() {
return this.id;
}
public int getUniqueUsers() {
return this.uniqueUsers;
}
}
Class under test
package com.test;
import org.hibernate.Query;
import org.hibernate.Session;
public class MyListener {
public StatusReportEntity doRequest(Date reportDate) {
Session session = HibernateUtil.openSession(); // returns a MySQL session or H2 if testing…
try {
Query query = session.getNamedQuery("callStatusReporting").setParameter("reporting_date", reportDate);;
StatusReportEntity statusReportEntity = (StatusReportEntity) query.uniqueResult();
return statusReportEntity;
} catch (Exception e) {
System.err.println(e);
} finally {
session.close();
return null;
}
}
H2 Aliases
To enable testing using H2, There is also a file to specify the necessary aliases:
CREATE SCHEMA IF NOT EXISTS History;
CREATE ALIAS IF NOT EXISTS Status_Reporting FOR "com.test.StoredProcs.statusReporting";
Test Class to be used by Alias
And a test class to return a default result from the SP call:
package com.test;
import com.test.StatusReportEntity;
public class StoredProcs {
public static StatusReportEntity statusReporting(Date reportingDate) {
StatusReportEntity statusReportEntity = StatusReportEntity.builder().withId(1).withUniqueUsers(10).build();
return statusReportEntity;
}
}
Test Class
package com.test;
import com.test.MyListener;
import java.util.Calendar;
import org.junit.Test;
import static org.junit.Assert.*;
public class MyListenerTest {
private MyListener listener;
#Test
public void listenerReturnsLatestData() throws Exception {
MyListener myListener = new MyListener();
assertNotNull(myListener.statusReporting(Calendar.getInstance().getTime()));
}
}
CREATE TABLE PERSON(
PERSON_ID IDENTITY PRIMARY KEY,
GIVEN_NAME VARCHAR(20),
FIRST_NAME VARCHAR(20),MIDDLE_NAME VARCHAR(20),
LAST_NAME VARCHAR(20),TITLE VARCHAR(20),NAME_SUFFIX VARCHAR(20));
The entity class must use any Generation strategy.
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name ="PERSON_ID")
private int personId;

Unexpected Generated Evolution Script for Ebean Model with Enum Field Type

I still learning about Ebean ORM with Play Framework. have problem with unexpected evolution script that generated by Play!Framework. I'm using Play!Framework 2.1.1 with JDK 1.7 update 5 64-bit. Sorry, for long code snippet in this question.
I have two Ebean Model looks like following:
Course.java
package models;
import play.data.validation.Constraints;
import play.db.ebean.Model;
import javax.persistence.*;
#Entity
#Table(name = "castillo_courses")
public class Course extends Model {
public enum CourseType {
COMPULSORY(1), BASIC_INTEREST(2), ADVANCED_INTEREST(3), THESIS(4);
private int value;
CourseType(int value) {
this.value = value;
}
public int getValue() {
return value;
}
}
#Id
private String code;
#Constraints.Required
private String course_name;
#Constraints.Required
private String credits;
#Constraints.Required
private CourseType course_type;
// Ebean finder and Other getter and setter method
......
}
CourseInterest.java
package models;
import play.data.validation.Constraints;
import play.db.ebean.Model;
import javax.persistence.*;
#Entity
#Table(name = "castillo_course_interest")
public class CourseInterest extends Model {
public enum InterestType {
ARCHITECTURAL_INFRA(1), SOFTWARE_TECH(2), INFORMATION_PROCESSING(3), ENTERPRISE_SYSTEM(4), COMP_INTELLIGENCE(5);
private int value;
InterestType(int value) {
this.value = value;
}
public int getValue() {
return value;
}
}
#Id
#ManyToOne
#JoinColumn(name = "course_code", referencedColumnName = "code")
private Course course;
#Id
#Constraints.Required
private InterestType interest_type;
// Ebean finder and Other getter and setter method
......
}
This is generated evolution script from the models above:
# --- Created by Ebean DDL
# To stop Ebean DDL generation, remove this comment and start using Evolutions
# --- !Ups
create table castillo_courses (
code varchar(255) not null,
course_name varchar(255),
credits varchar(255),
course_type integer,
constraint ck_castillo_courses_course_type check (course_type in (0,1,2,3)),
constraint pk_castillo_courses primary key (code))
;
create table castillo_course_interest (
course_name varchar(255),
credits varchar(255),
course_type integer,
interest_type integer not null,
constraint ck_castillo_course_interest_course_type check (course_type in (0,1,2,3)),
constraint ck_castillo_course_interest_interest_type check (interest_type in (0,1,2,3,4)))
;
create sequence castillo_courses_seq;
create sequence castillo_course_interest_seq;
# ..... !DOWNS code not shown
What I expected with the generated evolution script is:
In castillo_courses CREATE TABLE script, ck_castillo_courses_course_type constraint should check in (1,2,3,4) as defined by CourseType.value attribute, not to check in (0,1,2,3). I suspect evolution generated this check by using ORDINAL value of my Enums.
In castillo_course_interest CREATE TABLE script, it define again all castillo_courses fields except code. I expect the script is only define course_code column as defined by #JoinColumn annotation. There is another problem here. It has no script to generate primary key constraint too, because I have defined two #Id defined in model.
I appreciate to anyone that can explain, give advice, or help me with this problem.. :)
Kindly regards.
user the #EnumValue("1")
sample.
If all the values are parsable as Integers then Ebean will persist and fetch them as integers rather than strings.
public enum InterestType {
#EnumValue("1")
ARCHITECTURAL_INFRA(1),
#EnumValue("2")
SOFTWARE_TECH(2),
#EnumValue("3")
INFORMATION_PROCESSING(3),
#EnumValue("4")
ENTERPRISE_SYSTEM(4),
#EnumValue("5")
COMP_INTELLIGENCE(5);
private int value;
InterestType(int value) {
this.value = value;
}
public int getValue() {
return value;
}
}
For question number 1, I used suggestion from #publiclass1.
For question number 2, I learn about Compound Primary Key. On CourseInterest model, I used the Compound Primary Key because I want it to have 2 type of primary key, one is the foreign key (course_code) and the other is a common field (interest_type). So, I tried like following.
This is sample of CourseInterest model :
#EmbeddedId // using compound primarykey
public CourseInterestPK key;
#MapsId("courseCode") // map embedded key
#ManyToOne
#JoinColumn(name = "course_code", referencedColumnName = "code")
public Course course;
#MapsId("interestType") // map embedded key
#Constraints.Required
public InterestType interest_type;
This is sample of CourseInterestPK (Compound Primary Key definition) class:
#Embeddable
public class CourseInterest15541120PK {
#Column(name = "course_code")
public String courseCode;
#Column(name = "interest_type")
public CourseInterest.InterestType interestType;
#Override
public boolean equals(Object obj) {
... // MUST to override this method
}
#Override
public int hashCode() {
... // MUST to override this method
}
}
So, with these technique, I get the evolution script that I want to. ;)

Hibernate: "Field 'id' doesn't have a default value"

I'm facing what I think is a simple problem with Hibernate, but can't solve it (Hibernate forums being unreachable certainly doesn't help).
I have a simple class I'd like to persist, but keep getting:
SEVERE: Field 'id' doesn't have a default value
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [hibtest.model.Mensagem]
at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103)
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91)
[ a bunch more ]
Caused by: java.sql.SQLException: Field 'id' doesn't have a default value
[ a bunch more ]
The relevant code for the persisted class is:
package hibtest.model;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Inheritance;
import javax.persistence.InheritanceType;
#Entity
#Inheritance(strategy = InheritanceType.JOINED)
public class Mensagem {
protected Long id;
protected Mensagem() { }
#Id
#GeneratedValue
public Long getId() {
return id;
}
public Mensagem setId(Long id) {
this.id = id;
return this;
}
}
And the actual running code is just plain:
SessionFactory factory = new AnnotationConfiguration()
.configure()
.buildSessionFactory();
{
Session session = factory.openSession();
Transaction tx = session.beginTransaction();
Mensagem msg = new Mensagem("YARR!");
session.save(msg);
tx.commit();
session.close();
}
I tried some "strategies" within the GeneratedValue annotation but it just doesn't seem to work. Initializing id doesn't help either! (eg Long id = 20L).
Could anyone shed some light?
EDIT 2: confirmed: messing with#GeneratedValue(strategy = GenerationType.XXX) doesn't solve it
SOLVED: recreating the database solved the problem
Sometimes changes made to the model or to the ORM may not reflect accurately on the database even after an execution of SchemaUpdate.
If the error actually seems to lack a sensible explanation, try recreating the database (or at least creating a new one) and scaffolding it with SchemaExport.
If you want MySQL to automatically produce primary keys then you have to tell it when creating the table. You don't have to do this in Oracle.
On the Primary Key you have to include AUTO_INCREMENT. See the example below.
CREATE TABLE `supplier`
(
`ID` int(11) NOT NULL **AUTO_INCREMENT**,
`FIRSTNAME` varchar(60) NOT NULL,
`SECONDNAME` varchar(100) NOT NULL,
`PROPERTYNUM` varchar(50) DEFAULT NULL,
`STREETNAME` varchar(50) DEFAULT NULL,
`CITY` varchar(50) DEFAULT NULL,
`COUNTY` varchar(50) DEFAULT NULL,
`COUNTRY` varchar(50) DEFAULT NULL,
`POSTCODE` varchar(50) DEFAULT NULL,
`HomePHONENUM` bigint(20) DEFAULT NULL,
`WorkPHONENUM` bigint(20) DEFAULT NULL,
`MobilePHONENUM` bigint(20) DEFAULT NULL,
`EMAIL` varchar(100) DEFAULT NULL,
PRIMARY KEY (`ID`)
)
ENGINE=InnoDB DEFAULT CHARSET=latin1;
Here's the Entity
package com.keyes.jpa;
import java.io.Serializable;
import javax.persistence.*;
import java.math.BigInteger;
/**
* The persistent class for the parkingsupplier database table.
*
*/
#Entity
#Table(name = "supplier")
public class supplier implements Serializable
{
private static final long serialVersionUID = 1L;
#Id
**#GeneratedValue(strategy = GenerationType.IDENTITY)**
#Column(name = "ID")
private long id;
#Column(name = "CITY")
private String city;
#Column(name = "COUNTRY")
private String country;
#Column(name = "COUNTY")
private String county;
#Column(name = "EMAIL")
private String email;
#Column(name = "FIRSTNAME")
private String firstname;
#Column(name = "HomePHONENUM")
private BigInteger homePHONENUM;
#Column(name = "MobilePHONENUM")
private BigInteger mobilePHONENUM;
#Column(name = "POSTCODE")
private String postcode;
#Column(name = "PROPERTYNUM")
private String propertynum;
#Column(name = "SECONDNAME")
private String secondname;
#Column(name = "STREETNAME")
private String streetname;
#Column(name = "WorkPHONENUM")
private BigInteger workPHONENUM;
public supplier()
{
}
public long getId()
{
return this.id;
}
public void setId(long id)
{
this.id = id;
}
public String getCity()
{
return this.city;
}
public void setCity(String city)
{
this.city = city;
}
public String getCountry()
{
return this.country;
}
public void setCountry(String country)
{
this.country = country;
}
public String getCounty()
{
return this.county;
}
public void setCounty(String county)
{
this.county = county;
}
public String getEmail()
{
return this.email;
}
public void setEmail(String email)
{
this.email = email;
}
public String getFirstname()
{
return this.firstname;
}
public void setFirstname(String firstname)
{
this.firstname = firstname;
}
public BigInteger getHomePHONENUM()
{
return this.homePHONENUM;
}
public void setHomePHONENUM(BigInteger homePHONENUM)
{
this.homePHONENUM = homePHONENUM;
}
public BigInteger getMobilePHONENUM()
{
return this.mobilePHONENUM;
}
public void setMobilePHONENUM(BigInteger mobilePHONENUM)
{
this.mobilePHONENUM = mobilePHONENUM;
}
public String getPostcode()
{
return this.postcode;
}
public void setPostcode(String postcode)
{
this.postcode = postcode;
}
public String getPropertynum()
{
return this.propertynum;
}
public void setPropertynum(String propertynum)
{
this.propertynum = propertynum;
}
public String getSecondname()
{
return this.secondname;
}
public void setSecondname(String secondname)
{
this.secondname = secondname;
}
public String getStreetname()
{
return this.streetname;
}
public void setStreetname(String streetname)
{
this.streetname = streetname;
}
public BigInteger getWorkPHONENUM()
{
return this.workPHONENUM;
}
public void setWorkPHONENUM(BigInteger workPHONENUM)
{
this.workPHONENUM = workPHONENUM;
}
}
Take a look at GeneratedValue's strategy. It typically looks something like:
#GeneratedValue(strategy=GenerationType.IDENTITY)
you must be using update in your hbm2ddl property. make the changes and update it to Create so that it can create the table.
<property name="hbm2ddl.auto">create</property>
It worked for me.
Dropping the table from the database manually and then re-running the application worked for me. In my case table was not created properly(with constraints) I guess.
I had this issue. My mistake was i had set the insertable and updatable fileds as false and was trying to set the field in the request. This field is set as NON NULL in DB.
#ManyToOne
#JoinColumn(name="roles_id", referencedColumnName = "id", insertable = false, updatable = false, nullable=false)
#JsonBackReference
private Role role;
Later I changed it to - insertable = true, updatable = true
#ManyToOne
#JoinColumn(name="roles_id", referencedColumnName = "id", insertable = true, updatable = true, nullable=false)
#JsonBackReference
//#JsonIgnore
private Role role;
It worked perfectly later.
I came here because of the error message, turns out I had two tables with the same name.
I had the same problem. I found the tutorial Hibernate One-To-One Mapping Example using Foreign key Annotation and followed it step by step like below:
Create database table with this script:
create table ADDRESS (
id INT(11) NOT NULL AUTO_INCREMENT,
street VARCHAR(250) NOT NULL,
city VARCHAR(100) NOT NULL,
country VARCHAR(100) NOT NULL,
PRIMARY KEY (id)
);
create table STUDENT (
id INT(11) NOT NULL AUTO_INCREMENT,
name VARCHAR(100) NOT NULL,
entering_date DATE NOT NULL,
nationality TEXT NOT NULL,
code VARCHAR(30) NOT NULL,
address_id INT(11) NOT NULL,
PRIMARY KEY (id),
CONSTRAINT student_address FOREIGN KEY (address_id) REFERENCES ADDRESS (id)
);
Here is the entities with the above tables
#Entity
#Table(name = "STUDENT")
public class Student implements Serializable {
private static final long serialVersionUID = 6832006422622219737L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
}
#Entity
#Table(name = "ADDRESS")
public class Address {
#Id #GeneratedValue
#Column(name = "ID")
private long id;
}
The problem was resolved.
Notice: The primary key must be set to AUTO_INCREMENT
Another suggestion is to check that you use a valid type for the auto-generated field. Remember that it doesn't work with String, but it works with Long:
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
public Long id;
#Constraints.Required
public String contents;
The above syntax worked for generating tables in MySQL using Hibernate as a JPA 2.0 provider.
Just add not-null constraint
I had the same problem. I just added not-null constraint in xml mapping. It worked
<set name="phone" cascade="all" lazy="false" >
<key column="id" not-null="true" />
<one-to-many class="com.practice.phone"/>
</set>
Maybe that is the problem with the table schema. drop the table and rerun the application.
In addition to what is mentioned above, do not forget while creating sql table to make the AUTO INCREMENT as in this example
CREATE TABLE MY_SQL_TABLE (
USER_ID INTEGER NOT NULL AUTO_INCREMENT PRIMARY KEY,
FNAME VARCHAR(50) NOT NULL,
LNAME VARCHAR(20) NOT NULL,
EMAIL VARCHAR(50) NOT NULL
);
When your field is not nullable it requires a default value to be specified on table creation. Recreate a table with AUTO_INCREMENT properly initialized so DB will not require default value since it will generate it by itself and never put NULL there.
CREATE TABLE Persons (
Personid int NOT NULL AUTO_INCREMENT,
LastName varchar(255) NOT NULL,
FirstName varchar(255),
Age int,
PRIMARY KEY (Personid)
);
https://www.w3schools.com/sql/sql_autoincrement.asp
I solved it changuing #GeneratedValue(strategy = GenerationType.IDENTITY) by #GeneratedValue(strategy = GenerationType.AUTO)
By the way i didn't need to put it to create, just:
spring.jpa.hibernate.ddl-auto: update
Please check whether the Default value for the column id in particular table.if not make it as default
I had the same problem. I was using a join table and all I had with a row id field and two foreign keys. I don't know the exact caused but I did the following
Upgraded MySQL to community 5.5.13
Rename the class and table
Make sure I had hashcode and equals methods
#Entity
#Table(name = "USERGROUP")
public class UserGroupBean implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
#Column(name = "USERGROUP_ID")
private Long usergroup_id;
#Column(name = "USER_ID")
private Long user_id;
#Column(name = "GROUP_ID")
private Long group_id;
The same exception was thrown if a DB table had an old unremoved column.
For example:
attribute_id NOT NULL BIGINT(20), and attributeId NOT NULL BIGINT(20),
After removing the not used attribute, in my case contractId, the problem was resolved.
This happened to me with a #ManyToMany relationship. I had annotated one of the fields in the relationship with #JoinTable, I removed that and used the mappedBy attribute on #ManyToMany instead.
I tried the code and in my case the code below solve the issue. I had not settled the schema properly
#Entity
#Table(name="table"
,catalog="databasename"
)
Please try to add ,catalog="databasename" the same as I did.
,catalog="databasename"
In my case,
I altered that offending tables and the field "id" in question I made it AUTO_INCREMENT, I still need to figure out why on deployment time it was not making it "AUTO_INCREMENT" so that I have to do it by myself!
What about this:
<set name="fieldName" cascade="all">
<key column="id" not-null="true" />
<one-to-many class="com.yourClass"/>
</set>
I hope it helps you.
Try to change Long object type to long primitive type (if using primitives is ok for you).
I had the same problem and changing type helped me.
I had this issue, by mistake I had placed #Transient annotation above that particular attribute. In my case this error make sense.
"Field 'id' doesn't have a default value" because you didn't declare GenerationType.IDENTITY in GeneratedValue Annotation.
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
This issue is because sometimes you need to again update/create the database or sometimes if you have added the field in db table but not not entity class then it can not insert any null value or zero so this error came.
So check both side.Db and Entity class.
i have got such error in GCP cloud sql when model field didn't match correct table field in db.
Example:
when in model field is fieldName
table in db should have field field_name
Fixing table field name helped me.
I solved similar problem, when I altered the database column type , and did not add auto_increment. After adding back auto_increment in the alter table command (as in my original table creation) it worked
In my case I have not added the below property in my application.properties file:
spring.jpa.database-platform = org.hibernate.dialect.MySQL5InnoDBDialect
And added the following annotation to my entity class's Id column:
#GeneratedValue(strategy = GenerationType.IDENTITY)
And after adding this I have also drop my table manually from datatbase and run my project again that creates a new table with all default constraints for the table.
To delete just delete your schema is a really bad suggestion. There is a problem and it's best to find and fix it.
In my case I was using Envers this creates an Audit table for when entries are updated. But this audit table does not get updated itself it seems when the schema updates (At least not ID and it's relationships)
I just eddited the audit tables offending property and done. Everything back to normal.
To find what the issue is turn the following properties on in application.properties file
spring.jpa.show-sql=true
spring.jpa.properties.hibernate.format_sql=true
logging.level.org.hibernate.SQL=DEBUG
logging.level.org.hibernate.type.descriptor.sql.BasicBinder=TRACE
This will show you what SQL it is trying to executing and hopefully it will provide clarity on real issue.
Add a method hashCode() to your Entity Bean Class and retry it

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