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How to access SOAP message elements?

So i am trying to replace the values of username and password in the XML file containing a SOAP message. Here are the elements:
<o:Security s:mustUnderstand="1" xmlns:o="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<o:UsernameToken u:Id="uuid-68f84594-d592-470b-9bbc-b29f58b4756f-1">
<o:Username></o:Username>
<o:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText"></o:Password>
</o:UsernameToken>
</o:Security>
Basically, i want to take the username and password values from my config file, and place them in the username and password fields within the XML file containing the soap message. This is my attempt, and it throws a NPE at the docElement.getElementsByTagName lines:
public void updateUserDetails() {
final Properties configProperties = new Properties();
try {
configProperties.load(new FileInputStream(PROPERTIES));
final Document requestDoc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new FileInputStream(SOAP_REQUEST));
final Element docElement = requestDoc.getDocumentElement();
docElement.getElementsByTagName("Username").item(0).setTextContent(configProperties.getProperty("username"));
docElement.getElementsByTagName("Password").item(0).setTextContent(configProperties.getProperty("password"));
} catch(IOException | ParserConfigurationException | SAXException exception) {
LOGGER.error("There was an error loading the properties file", exception);
}
}
Any help will be appreciated!

It seems to be related to a namespace problem.
Try specifying the namespace for your tag:
String namespace = "http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true);
final Document requestDoc = factory.newDocumentBuilder().parse(new FileInputStream(SOAP_REQUEST));
docElement.getElementsByTagNameNS(namespace, "Username").item(0).setTextContent(configProperties.getProperty("username"));
docElement.getElementsByTagNameNS(namespace, "Password").item(0).setTextContent(configProperties.getProperty("password"));
Also, don't forget in the end to write the result back to file:
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource domSource = new DOMSource(requestDoc);
StreamResult streamResult = new StreamResult(new File(SOAP_REQUEST));
transformer.transform(domSource, streamResult);

Catching exceptions with Xalan xslt

I have the folowwing XSLT based on Xalan:
TransformerFactory factory = TransformerFactory.newInstance();
XalanErrorListener listener = new XalanErrorListener();
factory.setErrorListener(listener);
// Create transformer
StreamSource config = new StreamSource(xslPath);
Transformer transformer = factory.newTransformer(config);
// Create input / ouput
StreamSource source = new StreamSource(inputPath);
StreamResult result = new StreamResult(outputPath);
// Transform
transformer.transform(source, result);
My XalanErrorListener simply overrides error, fatalError and warning methods from the javax.xml.transform.ErrorListener class and logs the exception:
public final class XalanErrorListener implements ErrorListener {
static final Logger LOGGER = LoggerFactory.getLogger(XalanErrorListener.class);
#Override
public void error(TransformerException exception) throws TransformerException {
LOGGER.error(exception);
}
#Override
public void fatalError(TransformerException exception) throws TransformerException {
LOGGER.error(exception);
}
#Override
public void warning(TransformerException exception) throws TransformerException {
LOGGER.warn(exception);
}
}
Yet, when executing on a badly encoded file, I get the following message in the console:
(Location of error unknown)
com.sun.org.apache.xerces.internal.impl.io.MalformedByteSequenceException:
Invalid byte 2 of 2-byte UTF-8 sequence.
The program executes normally: no exception is thrown or logged and the generated file is empty!
How can I catch the exception to handle it the way I want?

The ErrorListener you supply to Xalan catches transformation errors, but it does not catch XML parsing errors. For that you need to supply an ErrorHandler to the Xerces parser.

The problem came from the fact that the ErrorListener needed to be set to the Transformer and not the TransformerFactory:
Transformer transformer = factory.newTransformer(config);
transformer.setErrorListener(listener);

XML with namespace Validation with XSD throws exception

I have a xml file which is a response from Webservice.It has got various namespaces involved with it. When I try to validate it with appropriate XSD its throwing "org.xml.sax.SAXParseException: cvc-elt.1: Cannot find the declaration of element 'SOAP-ENV:Envelope'." The namespace declaration for all the namespaces are declared in the response.
Following is my code
try {
DocumentBuilderFactory xmlFact = DocumentBuilderFactory.newInstance();
SchemaFactory schemaFactory = SchemaFactory
.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
SAXSource mainInputStream = new SAXSource(new InputSource(new FileInputStream(new File("FIXEDINCOME_v3_0.xsd"))));
SAXSource importInputStream1 =new SAXSource(new InputSource(new FileInputStream(new File("Rating.xsd"))));
SAXSource importInputStream2 = new SAXSource(new InputSource(new FileInputStream(new File("Datatypes.xsd"))));
Source[] sourceSchema = new SAXSource[]{mainInputStream , importInputStream1, importInputStream2};
Schema schema = schemaFactory.newSchema(sourceSchema);
xmlFact.setNamespaceAware(true);
xmlFact.setSchema(schema);
DocumentBuilder builder = xmlFact.newDocumentBuilder();
xmlDOC = builder.parse(new InputSource(new StringReader(inputXML)));
NamespaceContext ctx = new NamespaceContext() {
public String getNamespaceURI(String prefix) {
String uri;
if (prefix.equals("ns0"))
uri = "http://namespace.worldnet.ml.com/EDS/Standards/Common/Service_v1_0/";
else if (prefix.equals("ns1"))
uri = "http://namespace.worldnet.ml.com/EDS/Product/Services/Get_Product_Data_Svc_v3_0/";
else if (prefix.equals("ns2"))
uri = "http://namespace.worldnet.ml.com/DataSOA/Product/Objects/FixedIncome/FixedIncome_v3_0/";
else if (prefix.equals("ns3")) {
uri = "http://namespace.worldnet.ml.com/DataSOA/Product/Objects/Rating/Rating_v2_0/";
} else if (prefix.equals("SOAP-ENV")) {
uri = "http://schemas.xmlsoap.org/soap-envelope/";
} else
uri = null;
return uri;
}
// Dummy implementation - not used!
public Iterator getPrefixes(String val) {
return null;
}
// Dummy implemenation - not used!
public String getPrefix(String uri) {
return null;
}
};
XPathFactory xpathFact = XPathFactory.newInstance();
xPath = xpathFact.newXPath();
xPath.setNamespaceContext(ctx);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

I don't think the problem is with detecting the namespace definition for the SOAP-ENV prefix. The validator needs the XSD file that defines elements used in that namespace in order to validate the SOAP-ENV:Envelope element, so you need to tell the validator where that schema is located.
I think the solution is either to add the following to your XML reponse:
<SOAP-ENV:Envelope
xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsi="http://schemas.xmlsoap.org/soap/envelope/"
xsi:schemaLocation="http://schemas.xmlsoap.org/soap/envelope/
http://schemas.xmlsoap.org/soap/envelope/">
Or, go download that schema off the web, save it to your local filesystem as an XSD file, and add it to your sourceSchema array. The first method should be preferred as it leads to more portable code (and XML).

Have you tried using the following URI for the SOAP-ENV?
http://schemas.xmlsoap.org/soap/envelope/

The set of schemas you are providing for validation does not include the soap schema. you can either include the soap schema in the schema collection, or, if you don't care about validating the soap wrapper, just grab the actual body content element and run your validation from there.

How to transform XML to HTML using XSLT in ANDROID?

I am working on a android(2.2) project which needs xsl transformation. The below code works perfectly in a regular non-android java project
public static String transform() throws TransformerException {
Source xmlInput = new StreamSource(new File("samplexml.xml"));
Source xslInput = new StreamSource(new File("samplexslt.xslt"));
TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer(xslInput);
OutputStream baos = new ByteArrayOutputStream();
Result result = new StreamResult(baos);
transformer.transform(xmlInput, result);
return baos.toString();
}
I need similar functionality on android. For this I created 2 files under resources/raw:
samplexml.xml
samplexslt.xslt
(contents of these files come from here.
I tried the below code & it does not work (note the StreamSource constructor arg):
public static String transform() throws TransformerException {
TransformerFactory factory = TransformerFactory.newInstance();
Source xmlInput = new StreamSource(this.getResources().openRawResource(R.raw.samplexml));
Source xslInput = new StreamSource(this.getResources().openRawResource(R.raw.samplexslt));
Transformer transformer = factory.newTransformer(xslInput);//NullPointerException here
OutputStream baos = new ByteArrayOutputStream();
Result result = new StreamResult(baos);
transformer.transform(xmlInput, result);
}
I saw the spec & believe I need to set a systemId. But I couldn't get the above code to work.
So, in an android project, how to handle xslt transformations? Please provide your thoughts.

As we know that we Cannot usethisin a static context and you are doing this in your static method transform(). You can do it like this_
public class YourLoadXSLClass extends Activity {
static Resources res;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
res = getResources();
String strHTML = transform();
// Other code.....
}
/*
* Your method that Transform CSLT.
*/
public static String transform() throws TransformerException {
TransformerFactory factory = TransformerFactory.newInstance();
// Now your raw files are accessible here.
Source xmlInput = new StreamSource(
LoadXSLTinWebview.res.openRawResource(R.raw.samplexml));
Source xslInput = new StreamSource(
LoadXSLTinWebview.res.openRawResource(R.raw.samplexslt));
Transformer transformer = factory.newTransformer(xslInput);
OutputStream baos = new ByteArrayOutputStream();
Result result = new StreamResult(baos);
transformer.transform(xmlInput, result);
return baos.toString();
}
}
Here is the complete class code that do the needful. I hope this will help you & all!

I've never done anything with XSLT but, looking at your code, logically there are only two things that could cause an NPE on that line. The first would be that factory might be null but that doesn't make sense.
That leaves xslInput as being the culprit which suggests openRawResource(R.raw.samplexslt) is failing to return a valid InputStream for the StreamSource constructor to use. Try putting a log statement in such as...
if (xslInput != null {
Transformer transformer = factory.newTransformer(xslInput);
...
}
else
Log.d("SomeTAG", "xslInput is null!!!");
If it turns out that xslInput is actually null then it suggests openRawResource(...) can't find/process the .xslt file properly. In that case I'd suggest using AssetManagerto open the .xslt file by name...
AssetManager am = this.getAssets();
Source xslInput = new StreamSource(am.open("samplexslt.xslt"));

How to skip well-formed for java DOM parser

I know this has been asked multiple times here, but I've a different issue dealing with it. In my case, the app receives a non well-formed dom structure passed as a string. Here's a sample :
<div class='video yt'><div class='yt_url'>http://www.youtube.com/watch?v=U_QLu_Twd0g&feature=abcde_gdata</div></div>
As you can see, the content is not well-formed. Now, if I try to parse using a normal SAX or DOM parse it'll throw an exception which is understood.
org.xml.sax.SAXParseException: The reference to entity "feature" must end with the ';' delimiter.
As per the requirement, I need to read this document,add few additional div tags and send the content back as a string. This works great by using a DOM parser as I can read through the input structure and add additional tags at their required position.
I tried using tools like JTidy to do a pre-processing and then parse, but that results in converting the document to a fully-blown html, which I don't want. Here's a sample code :
StringWriter writer = new StringWriter();
Tidy tidy = new Tidy(); // obtain a new Tidy instance
tidy.setXHTML(true);
tidy.parse(new ByteArrayInputStream(content.getBytes()), writer);
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new ByteArrayInputStream(writer.toString().getBytes()));
// Traverse thru the content and add new tags
....
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
StreamResult result = new StreamResult(new StringWriter());
DOMSource source = new DOMSource(doc);
transformer.transform(source, result);
This completely converts the input to a well-formed html document. It then becomes hard to remove html tags manually. The other option I tried was to use SAX2DOM, which too creates a HTML doc. Here's a sample code .
ByteArrayInputStream is = new ByteArrayInputStream(content.getBytes());
Parser p = new Parser();
p.setFeature(IContentExtractionConstant.SAX_NAMESPACE,true);
SAX2DOM sax2dom = new SAX2DOM();
p.setContentHandler(sax2dom);
p.parse(new InputSource(is));
Document doc = (Document)sax2dom.getDOM();
I'll appreciate if someone can share their ideas.
Thanks

The simplest way is replacing xml reserved characters with the corresponding xml entities. You can do this manually:
content.replaceAll("&", "&");
If you don't want to modify your string before parsing it, I could propose you another way using SaxParser, but this solution is more complicated. Basically you have to:
write a LexicalHandler in
combination with ContentHandler
tell the parser to continue its
execution after fatal error (the
ErrorHandler isn't enough)
treat undeclared entities as simple
text
UPDATE
According to your comment, I'm going to add some details regarding the second solution. I've writed a class which extends DefaulHandler (default implementation of EntityResolver, DTDHandler, ContentHandler and ErrorHandler) and implements LexicalHandler. I've extended ErrorHandler's fatalError method (my implementations does nothing instead of throwing the exception) and ContentHandler's characters method which works in combination with startEntity method of LexicalHandler.
public class MyHandler extends DefaultHandler implements LexicalHandler {
private String currentEntity = null;
#Override
public void fatalError(SAXParseException e) throws SAXException {
}
#Override
public void characters(char[] ch, int start, int length)
throws SAXException {
String content = new String(ch, start, length);
if (currentEntity != null) {
content = "&" + currentEntity + content;
currentEntity = null;
}
System.out.print(content);
}
#Override
public void startEntity(String name) throws SAXException {
currentEntity = name;
}
#Override
public void endEntity(String name) throws SAXException {
}
#Override
public void startDTD(String name, String publicId, String systemId)
throws SAXException {
}
#Override
public void endDTD() throws SAXException {
}
#Override
public void startCDATA() throws SAXException {
}
#Override
public void endCDATA() throws SAXException {
}
#Override
public void comment(char[] ch, int start, int length) throws SAXException {
}
}
This is my main which parses your xml not well formed. It's very important the setFeature, because without it the parser throws the SaxParseException despite of the ErrorHandler empty implementation.
public static void main(String[] args) throws ParserConfigurationException,
SAXException, IOException {
String xml = "<div class='video yt'><div class='yt_url'>http://www.youtube.com/watch?v=U_QLu_Twd0g&feature=abcde_gdata</div></div>";
SAXParser saxParser = SAXParserFactory.newInstance().newSAXParser();
XMLReader xmlReader = saxParser.getXMLReader();
MyHandler myHandler = new MyHandler();
xmlReader.setContentHandler(myHandler);
xmlReader.setErrorHandler(myHandler);
xmlReader.setProperty("http://xml.org/sax/properties/lexical-handler",
myHandler);
xmlReader.setFeature(
"http://apache.org/xml/features/continue-after-fatal-error",
true);
xmlReader.parse(new InputSource(new StringReader(xml)));
}
This main prints out the content of your div element which contains the error:
http://www.youtube.com/watch?v=U_QLu_Twd0g&feature=abcde_gdata
Keep in mind that this is an example which works with your input, maybe you'll have to complete it...for instance if you have some characters correctly escaped you should add some lines of code to handle this situation etc.
Hope this helps.