This question already has answers here:
Retrieving the first digit of a number [duplicate]
(9 answers)
Closed 6 years ago.
Here is my code:
if(Rs.getInt("Number") == 100){
//Do something
}
Rs is a PreparedStatement.
Instead of defining the exact number, I want to look for numbers
which start with 1. Maybe there are '110' or '120' ... what should i write in the loop
instead of the operator == ?
This guy here seems to have the right idea.
Retrieving the first digit of a number
if ("1".equals(Integer.parseInt(Rs.getInt(number).substring(0, 1)))){
//do stuff
}
Related
This question already has answers here:
What is the Java ?: operator called and what does it do?
(17 answers)
Closed 4 years ago.
I am confused by this statement. Please help me explain this statement:
return third == Long.MIN_VALUE ? (int)first : (int)third;
Considering your top tags in SO is Python, let's explain this statement with Python:
return first if third == sys.maxint else third
Of course the Long.MIN_VALUE is not necessarily equal to sys.maxint in Python.
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Why does non-equality check of one variable against many values always return true?
(3 answers)
Closed 6 years ago.
I'm trying to make a user validation for multiple choices using a while loop and If the user doesn't match the choices then the program has to terminate. This is what I got so far
while(input!="air" || input!="water" || input!="steel"){
System.exit(0);
}
Unfortunately, it doesn't work.
I would prefer to do exceptions, but my professor is strictly against using it for this assignment. I really want to grow as a programmer so any advice, tips and tricks are welcomed, thank you all for trying to help me out.
Change it as
while(!input.equals("air") && !input.equals("water") && !input.equals("steel")){
System.exit(0);
}
Or
while(!(input.equals("air") || input.equals("water") || input.equals("steel"))){
System.exit(0);
}
This question already has answers here:
How to evaluate a math expression given in string form?
(26 answers)
Closed 6 years ago.
I want to do calculator that do sums but just in one index like this:
args[0] = "2+2"
and the output should be 4.
I won't do your homework for you, but I'll split it in few steps:
You should get String before the "+" and after the "+":
Have a look at String.indexOf and String.substring for that. Make sure you check for -1 for indexOf.
Parse String to int:
int foo = Integer.parseInt(String s);
Now you can add two ints.
Good luck!
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 7 years ago.
String TypedMaxNumber = MaxValue.getText();
if(TypedMaxNumber == "100")
System.out.println(TypedMaxNumber+" = 100");
I think it is a silly problem, but when I am running to run this program and I type 100 in the text Field it is not going inside the loop. What could be the reason.
I am running to run this program and I type 100 in the text Field it
is not going inside the loop.
Its
if(TypedMaxNumber.equals("100"))
Since TypedMaxNumber is of type String. equals() check for value equality
This question already has an answer here:
Inbuilt Permutation Generator
(1 answer)
Closed 8 years ago.
hi im beginner in android and need a void that get numbers in array and give these numbers randomly mix.i try to make this something like these code but this is have bugs when it arrive to near of end.any body have solution for mix randomly numbers in array,like numbers between 1 to 20?
rand1=randomBox();
do {rand2=randomBox();
}while (rand1==rand2);
do {rand3=randomBox();
}while (rand1==rand3 || rand2==rand3 );
do {rand4=randomBox();
}while (rand1==rand4 || rand2==rand4 ||rand3==rand4);
.
.
.
Use Collections.shuffle(Arrays.asList(yourArray)) as explained in an other StackOverflow question: Inbuilt Permutation Generator