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Cant find the issue here, help please [closed]

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Multiple markers at this line - Syntax error, insert ";" to complete Statement - The left-hand side of an assignment must be a variable - Syntax error, insert "AssignmentOperator Expression" to complete Assignment - Syntax error on token "else", invalid (
import java.util.Scanner;
public class NGG {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int x1, x2;
System.out.println("");
System.out.println("\n Guess X from 10 - 0: ");
x1 = scan.nextInt();
System.out.println("");
x2 = ((int)(Math.random()*10));
System.out.println(x2);
if (x2 == x1) {
System.out.println("Victory");
} else if(x2 > x1 && x2 < x1) {
System.out.println("Lose");
}
}
}

I made some changes to it.
nice game :)
public class NGG {
public static void main(String[] args) {
NGG ngg = new NGG();
ngg.game();
}
private void game(){
Scanner scan = new Scanner(System.in);
int enteredNumber, guessedNumber;
System.out.println("\n Guess number between 0 - 10: ");
enteredNumber = scan.nextInt();
guessedNumber = ((int)(Math.random()*10));
System.out.println(guessedNumber);
if (guessedNumber == enteredNumber) {
System.out.println("Victory");
} else {
System.out.println("Lost: number was " + guessedNumber);
}
}
}
did some minor refactoring and updated the logic to check if the guessed number/random number is same as the entered number then you get "victory" otherwise you Lose and shows you what the guessed/random number was.

Can do-while loops only run with boolean variables? Java [closed]

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Closed 2 years ago.
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I am having some trouble with this small segment. Can do-while loops only run using boolean variables? I am trying to ask the "user" to enter "0" or "1" so that the program will either loop or end.
Error message:
Chapter4Practice.java:23: error: incompatible types: int cannot be
converted to boolean
} while (choice = 1);
^ 1 error
My code:
import java.util.Scanner;
public class Chapter4Practice
{
public static void main(String[] args)
{
int choice, num1, num2;
String input;
Scanner sc = new Scanner(System.in);
do {
System.out.print("Enter a number: ");
num1 = sc.nextInt();
System.out.print("Enter another number: ");
num2 = sc.nextInt();
System.out.println("The sum is " + (num1 + num2));
System.out.println("Do you want to do this again?");
System.out.println("(1 = yes, 0 = no)");
sc.nextLine();
choice = sc.nextInt();
} while (choice = 1);
} //End Main
} //End Class

Short answer: Yes, you can have simple or complex statements inside your do-while but at the end it will have to evaluate to either true or false
Also your statement should be == ( single = means assign, where == is evaluate)

Getting an integer to go to a different line [closed]

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Closed 4 years ago.
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This is my code for reversing the digits of an integer,
but the result gives each digit reversed but in a new line,
like if you give 341 to it , it gives you:
1
4
3
But I want to make it all come to the same line , is there a way to do it without changing the main code?
public static void main(String[] args)
{
Scanner scan=new Scanner(System.in);
System.out.println("Enter your number to reverse it ...");
int a=scan.nextInt();
while(a>0) {
i=a%10;
a/=10;
l++;
System.out.println(i);
}
System.out.println("Number of digits: "+l);
}

You could use print instead of println:
System.out.print(i);

Answer :
public static void main(String[] args)
{
Scanner scan=new Scanner(System.in);
System.out.println("Enter your number to reverse it ...");
int a=scan.nextInt();
while(a>0) {
i=a%10;
a/=10;
l++;
System.out.print(i);
}
System.out.println("Number of digits: "+l);
}

I think your code has few errors. It should be
int i = 0;
while(a>0) {
i=a%10;
a/=10;
System.out.print(i+" ");
i++;
}

In your code you are just picking digits and printing it in reversed order instead of really reversing it.
public static void main(String[] args)
{
int i,l=0,num=0;
Scanner scan=new Scanner(System.in);
System.out.println("Enter your number to reverse it ...");
int a=scan.nextInt();
while(a>0)
{
i=a%10;
a/=10;
num=(num*10)+i;
l++;
}
System.out.println("Number of digits: "+l);
System.out.println("Reversed Number: "+num);
}
Try this code instead.....

My program shows an error, It says that a semicolon missing [closed]

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Closed 5 years ago.
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import java.util.*;
public class Fact
program to find factorial numbers
{
Scanner sc=new Scanner(System.in);
int n;
Fact()
an empty constructor
{
}
void accept()
{
System.out.println("Enter the number");
n=sc.nextInt();
System.out.println(pact(n));
}
**int pact(int n)**
here is where my program says that it is missing a semicolon
(
if(n==1)
return 1;
else
return n*fact(n-1);
}
public static void main()
{
Fact obj=new Fact();
obj.accept();
}
}

Apart from the fact that
int pact(int n)
(
should be
int pact(int n)
{
You have String args[] missing as the arguments in the main method.
public static void main(String[] args){

After return statement you used closed curly, and no open curly is there .
You started with open parenthesis and closed with curly.
Just change that.

Try this. Removed invalid language constructs.
import java.util.Scanner;
public class Fact {
Scanner sc = new Scanner(System.in);
int n;
Fact() {
}
void accept() {
System.out.println("Enter the number");
n = sc.nextInt();
System.out.println(fact(n));
}
int fact(int n) {
if (n == 1)
return 1;
else
return n * fact(n - 1);
}
public static void main(String[] args) {
Fact obj = new Fact();
obj.accept();
}
}

If you copied the code correctly, you need to use a { instead of ( in this part of the code.
(
if(n==1)
return 1;
else
return n*fact(n-1);
}
so it should be
{
if(n==1)
return 1;
else
return n*fact(n-1);
}

Odd/even using subtraction or addition operation [closed]

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Anybody know how to identify a given number is odd/even using addition or subtraction operator? I am new to coding and don't have an idea how to do this?

using subtraction.
int inputNumber = 12;
while(inputNumber>2)
{
inputNumber-=2;
}
if(inputNumber==1)
System.out.println("Odd Number");
else
System.out.println("Even Number");

using addition
int inputNumber = 12;
int absInputNumber = Math.abs(inputNumber)
int i = 0;
while(i < absInputNumber) {
i += 2
}
if(inputNumber==i)
System.out.println("Even Number");
else
System.out.println("Odd Number");

Java answer (without reference to Math class):
package odd.even.tester;
public class OddEvenTester {
public boolean isEven(int number) {
int evaluatedValue = number;
if (evaluatedValue < 0) {
evaluatedValue *= (-1);
}
while (evaluatedValue > 0) {
evaluatedValue -= 2;
}
return evaluatedValue == 0;
}
}
short test:
package odd.even.tester;
import org.junit.Test;
import static org.junit.Assert.assertTrue;
import static org.junit.Assert.assertFalse;
public class OddEvenTesterTest {
#Test
public void testIsEven() {
OddEvenTester tester = new OddEvenTester();
assertTrue(tester.isEven(-10));
assertTrue(tester.isEven(-8));
assertTrue(tester.isEven(-6));
assertTrue(tester.isEven(-4));
assertTrue(tester.isEven(-2));
assertTrue(tester.isEven(0));
assertTrue(tester.isEven(2));
assertTrue(tester.isEven(4));
assertTrue(tester.isEven(6));
assertTrue(tester.isEven(8));
assertTrue(tester.isEven(10));
assertFalse(tester.isEven(-9));
assertFalse(tester.isEven(-7));
assertFalse(tester.isEven(-5));
assertFalse(tester.isEven(-3));
assertFalse(tester.isEven(-1));
assertFalse(tester.isEven(1));
assertFalse(tester.isEven(3));
assertFalse(tester.isEven(5));
assertFalse(tester.isEven(7));
assertFalse(tester.isEven(9));
}
}

There is another way to do it using "mod" which is the '%' symbol. If you have a number and use % 2, then if the answer is 0 it is even, if it is 1 it is odd.
Example:
int test = 12
if (test % 2 == 0)
System.out.print("Even.");
else
System.out.print("Odd.");
You can incorporate this in the addition and subtraction operators.