XML parsing to Java - getting root attribute value - java

I'm having a slight problem with XML parsing.
I'm creating a function where the parameter is a certain "element" from the XML file.
When found, I want to return the value of the root attribute.
Here's my code:
FileInputStream file = new FileInputStream(new File("C:\\Users\\Grizzly\\Java\\Projet_16_17-20161214\\bdd.xml"));
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(file);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("type");
for (int temp = 0; temp < nList.getLength(); temp++)
{
Node nNode = nList.item(temp);
if(nNode.toString().equalsIgnoreCase(element))
{
Element eElement = (Element) nNode;
System.out.println("Taxe= "+ eElement.getAttribute("taxe"));
}
}
}
Any idea on how to do this?
Here's my XML file:
<?xml version="1.0"?>
-<types>
-<type id="Nourriture" taxe="0.1">
<element>pomme</element>
<element>fraise</element>
<element>fromage</element>
<element>viande rouge </element>
</type>
-<type id="Matiere Premiere" taxe="0.2">
<element>fer</element>
<element>polypropylene</element>
</type>
-<type id="Element Solide" taxe="0.3">
<element>voiture</element>
<element>planche surf</element>
<element>pistolet</element>
</type>
</types>
In my code, I tried to get the elements of a certain node from the nodelist and then compare it to the the string "element" which is the input of the user, and if they match it will check the attribute value of taxe linked to it.
Thanks in advance.
EDIT: I'm getting closer to what I need:
NodeList nList = doc.getElementsByTagName("type");
for (int temp = 0; temp < nList.getLength(); temp++)
{
Node nNode = nList.item(temp);
NodeList nChildren = nNode.getChildNodes();
Element eElement = (Element) nNode;
for(int i = 0; i < nChildren.getLength(); i++)
{
String onElement = eElement.getElementsByTagName("element").item(i).getTextContent();
if(onElement.equalsIgnoreCase(element))
{
System.out.println("id : " + eElement.getAttribute("id"));
System.out.println("taxe : " + eElement.getAttribute("taxe"));
break;
}
}
}
But it's only reading the first element... and item(i) isn't working.
Any idea?

If I understand you correctly, you are trying to fetch specific attributes (id and taxe) of all the document nodes having at least one child element with specific name (element).
Although the problem can be solved by iterating the DOM and keeping the states, I would rather delegate this task to XPath. A code with XPath will look cleaner and be more maintainable. For example, in order to fetch all elements having attributes id and taxe and a child element element you can use an XPath expression like //*[#id and #taxe element]. The matching nodes are fetched in a single line. You can simply iterate the nodes and collect the attributes as shown in the following example.
Example
public static void main(String args[]) {
String element = args.length > 0 ? args[0] : "element";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
FileInputStream file = new FileInputStream(new File("/some/file.xml"));
Document doc = builder.parse(file);
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "//*[#id and #taxe and " + element + "]";
NodeList nodeList = (NodeList) xPath.compile(expression)
.evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
NamedNodeMap attributes = node.getAttributes();
for (int j = 0; j < attributes.getLength(); j++) {
Node aNode = attributes.item(j);
System.out.printf(
"%s: %s\n",
aNode.getNodeName(),
aNode.getNodeValue()
);
}
}
} catch (Exception e) {
System.err.println(e.getMessage());
System.exit(1);
}
}
Sample Output
id: Nourriture
taxe: 0.1
id: Matiere Premiere
taxe: 0.2
id: Element Solide
taxe: 0.3
Note, the sample above prints all attributes of the parent element. If you want to print only specific ones, you can, obviously, add a trivial check like this:
String aName = aNode.getNodeName();
if (aName.equals("taxe")) { // ...
But you can actually filter out the attributes with XPath:
String expression = "//*[ " + element + "]/#*[name() = 'id' or name() = 'taxe']";
NodeList nodeList = (NodeList) xPath.compile(expression)
.evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
System.out.printf("%s: %s\n", node.getNodeName(), node.getNodeValue());
}
The XPath expression above fetches all attribute nodes having names equal to whether id, or taxe. If you want all attributes, simply remove the last condition:
String expression = "//*[ " + element + "]/#*";

Related

Maintaining count of XML elements using Xpath

I am a beginner in using Java programming particularly using Xpath to parse an XML file.
I am trying to develop a system that routes flights according to their weightings. I want to:
Maintain a count of flights for each location;
The system should accept a location and return the number and country to route a flight to. For every 4 flights to Japan, route the next 2 flights to China then route the next 2 flights to India and loop and to return count, continent, location name, country and weight.
I would appreciate any assistance please.
I can pass the XML data of and retrieve the different element nodes using Xpath. I attempted using SAX and STAX but prefered this method as it was clear and concise when constructing the expressions.
XML File Example:
<continent>
<location name = "asia">
<country>Japan</country>
<code>0000011111</code>
<weight>10</weight>
</location>
<location name = "asia">
<country>China</country>
<code>0000022222</code>
<weight>1</weight>
</location>
</continent>
Java Sample Code:
public static void main(String[] args) {
try {
FileInputStream file = new FileInputStream(new File("c:/continents.xml"));
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document xmlDocument = builder.parse(file);
XPath xPath = XPathFactory.newInstance().newXPath();
System.out.println("*************************");
String expression = "/continent/location";
System.out.println(expression);
String name = xPath.compile(expression).evaluate(xmlDocument);
System.out.println(name);
System.out.println("**********Parse XML File***************");
expression = "/continent/location/country|//number|//weight";
System.out.println(expression);
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
System.out.println(nodeList.item(i).getFirstChild().getNodeValue());
}
System.out.println("*************************");
expression = "/continent/location[#name='asia']/number";
System.out.println(expression);
nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
System.out.println(nodeList.item(i).getFirstChild().getNodeValue());
}
System.out.println("*************************");
expression = "//location[country='China']";
System.out.println(expression);
Node node = (Node) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODE);
if(null != node) {
nodeList = node.getChildNodes();
for (int i = 0;null!=nodeList && i < nodeList.getLength(); i++) {
Node nod = nodeList.item(i);
if(nod.getNodeType() == Node.ELEMENT_NODE)
System.out.println(nodeList.item(i).getNodeName() + " : " + nod.getFirstChild().getNodeValue());
}
}
}
I’m not sure I understand your goal, but if you just want to count how many flights are to a particular country, you can count the matching elements:
NodeList matches = (NodeList) xPath.evaluate(
"//country[text()='" + country + "']",
xmlDocument,
XPathConstants.NODESET);
int matchCount = matches.getLength();

XML parsing. How can I get child's child?

I'm trying to parse this XML in Java:
<entities>
<entity name="product_section" id="1">
<product_type>3</product_type>
<section_type>1</section_type>
<name>Empresa</name>
<description>d</description>
<position>1</position>
<align>left</align>
<files section_id="1">
<ico id="ico_1" type="normal" src="sections/1/icons/ico.png"></ico>
<ico id="ico_2" type="hover" src="sections/1/icons/ico.png"></ico>
<ico id="ico_3" type="active" src="sections/1/icons/ico.png"></ico>
<img id="img_1" type="normal" src="sections/1/img/pestanya.png"></img>
<img id="img_2" type="hover" src="sections/1/img/pestanya-hover.png"></img>
<img id="img_3" type="active" src="sections/1/img/pestanya-active.png"></img>
<background id="background_1" type="background" position="1" src="sections/1/background/bg1.png"></background>
<background id="background_2" type="background" position="2" src="sections/1/background/bg2.png"></background>
<background id="background_3" type="background" position="3" src="sections/1/background/bg3.png"></background>
</files>
</entity>
But I just achieved to loop through Entities, getting all Entity and each <product_type>, <section_type>, etc.
But I want to loop through files too.
This is my implementation so far:
try {
File contingut = new File("xmlfile.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(contingut);
doc.getDocumentElement().normalize();
System.out.println("root of xml file " + doc.getDocumentElement().getNodeName());
//loop a cada entity
NodeList nodes = doc.getElementsByTagName("entity");
for (int i = 0; i < nodes.getLength(); i++) {
Node node = nodes.item(i);
Element element = (Element) node;
System.out.println("product_type: " + getValue("product_type", element));
System.out.println("section_type: " + getValue("section_type", element));
System.out.println("name: " + getValue("name", element));
System.out.println("description: " + getValue("description", element));
System.out.println("position: " + getValue("position", element));
System.out.println("align: " + getValue("align", element));
}
} catch (Exception e){
e.printStackTrace();
}
getValue function is:
private static String getValue(String tag, Element element) {
NodeList nodes = element.getElementsByTagName(tag).item(0).getChildNodes();
Node node = (Node) nodes.item(0);
return node.getNodeValue();
}
I've done lot of google search, and all I find are "simple" examples, with a parent, and a child, but not child's child.
Any help would be appreciated.
At first one suggestion:
check element type after this Element element = (Element) node;
use this code or something like this :
if (element.getNodeType() == Element.ELEMENT_NODE) { // do smth}
and answer to your question:
You can simply rewrite you code. after you create element you can get all it's child elements by using element.getChildNodes();
it gives you all child tags. After that you write simple for loop where you get each node element from node list like this :
NodeList nodes = element.getChildNodes();
for(int i =0; i < nodes.getLength(); i++){
Element child = (Element) nodes.item(i);
if(child.getNodeType() == Element.ELEMENT_NODE){
String tagName = child.getTagName();
if(!tagName.equals("files")){
System.out.println(tagName + " : " + child.getTextContent());
}else{
NodeList filesChilds = child.getChildNodes();
for(int j = 0; j < filesChilds.getLength(); j++){
//and like above
}
}
}
}

Fill an array with objects from XML [closed]

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Closed 10 years ago.
I have a XML file that I am trying to read and transform into objects. I want to transform and put all the locations in a array filled with Location objects wich are defined by a film id, a date and a amount.
Here is my XML file :
Here is my code to scan the location XML section :
public void findLocations() throws ParseException {
NodeList nList = document.getElementsByTagName("location");
Location[] locations = new Location[nList.getLength()];
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
locations[temp] = new Location(getTagValue("filmid", eElement), dateChanger(getTagValue("date", eElement)), getTagValue("amount", eElement));
System.out.println(locations[temp].getAmount()); //Outputs the good values.
}
}
System.out.println(locations[0].getAmount()); //Output : 5$
System.out.println(locations[1].getAmount()); //Output : 5$
System.out.println(locations[2].getAmount()); //Output : 5$
}
private static String getTagValue(String sTag, Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
Node nValue = (Node) nlList.item(0);
return nValue.getNodeValue();
}
The problem seems that my array is getting filled 3 times with the same location and ends up filled 3 time with the last location. The objects otherwise are well formed, so I imagine I got that part right.
You could use XPath instead...
public class TestXML03 {
public static void main(String[] args) {
try {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(false);
DocumentBuilder builder = factory.newDocumentBuilder();
Document xmlDoc = builder.parse(new File("Test.xml"));
Node root = xmlDoc.getDocumentElement();
XPathFactory xFactory = XPathFactory.newInstance();
XPath xPath = xFactory.newXPath();
XPathExpression xExpress = xPath.compile("/file/location");
NodeList nodes = (NodeList) xExpress.evaluate(root, XPathConstants.NODESET);
System.out.println("Found " + nodes.getLength() + " location nodes");
System.out.println("");
for (int index = 0; index < nodes.getLength(); index++) {
Node node = nodes.item(index);
xExpress = xPath.compile("filmid");
Node filmIDNode = (Node) xExpress.evaluate(node, XPathConstants.NODE);
System.out.println(filmIDNode.getNodeName() + " = " + filmIDNode.getTextContent());
xExpress = xPath.compile("date");
Node dateNode = (Node) xExpress.evaluate(node, XPathConstants.NODE);
System.out.println(dateNode.getNodeName() + " = " + dateNode.getTextContent());
xExpress = xPath.compile("amount");
Node amountNode = (Node) xExpress.evaluate(node, XPathConstants.NODE);
System.out.println(amountNode.getNodeName() + " = " + amountNode.getTextContent());
System.out.println("");
}
} catch (Exception exp) {
exp.printStackTrace();
}
}
}
Which outputs...
Found 3 location nodes
filmid = 100
date = 2013-01-11
amount = 4.00$
filmid = 200
date = 2013-01-13
amount = 9.00$
filmid = 334
date = 2013-01-23
amount = 5.00$
Updated After Feed-back
The Location class is maintaining a static reference to it's class fields, this means that changing the value for the field will change it for all instances of that class.
Remove the static references and it should solve the problem.
Your source is working perfectly. Simply modifying your source to output tags as below.
public static void findLocations(Document document) throws ParseException {
NodeList nList = document.getElementsByTagName("location");
Location[] locations = new Location[nList.getLength()];
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println(getTagValue("filmid", eElement));
System.out.println(getTagValue("date", eElement));
System.out.println(getTagValue("amount", eElement));
System.out.println();
}
}
}
I got the proper output
100
2013-01-11
4.00$
200
2013-01-13
9.00$
334
2013-01-23
5.00$
Check if your XML input is proper.

How to read alternative tags in xml using java?

I have xml file
<A>
<A1>
<A2>Hi</A2>
</A1>
<A>
<B>
<B1></B1>
<B2>100</B2>
</B>
<A>
<A1>
<A2>Hello</A2>
</A1>
<A>
<B>
<B1>1000</B1>
<B2></B2>
</B>
likewise this goes more than 10 blocks. Now my java code able to read one by one that is first reads all after that reads tag.
Code:
public class XMLParse {
static Document doc;
public static void main(String argv[]) {
try {
File file = new File("/home/dev042/Desktop/xxx.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
doc = db.parse(file);
doc.getDocumentElement().normalize();
System.out.println("Root element " + doc.getDocumentElement().getNodeName());
NodeList nodeLst = doc.getElementsByTagName("A");
System.out.println("Information of all Balence Sheet");
int count = nodeLst.getLength();
String name;
for (int s = 0; s < nodeLst.getLength(); s++) {
Node fstNode = nodeLst.item(s);
if (fstNode.getNodeType() == Node.ELEMENT_NODE) {
Element fstElmnt = (Element) fstNode;
NodeList fstNmElmntLst = fstElmnt.getElementsByTagName("A1");
for(int i =0; i < fstNmElmntLst.getLength(); i++ )
{
Node lst = fstNmElmntLst.item(i);
if(lst.getNodeType() == Node.ELEMENT_NODE)
{
Element fsttravel = (Element) lst;
NodeList secNmElt = fsttravel.getElementsByTagName("*");
name = secNmElt.item(0).getTextContent();
System.out.println("Name : " + name);
}
}
}
}
}
catch (Exception e) {
e.printStackTrace();
}
String amt;
double amount;
NodeList nodeLst = doc.getElementsByTagName("B");
int coun = nodeLst.getLength();
for (int s = 0; s < nodeLst.getLength(); s++) {
Node secNode = nodeLst.item(s);
if (secNode.getNodeType() == Node.ELEMENT_NODE) {
try
{
Element amtval = (Element) secNode;
NodeList secval = amtval.getElementsByTagName("B1");
amt = secval.item(0).getTextContent();
//amount = Double.parseDouble(amt);
System.out.println("SubAmt :" + amt);
NodeList lstNmElmntLst = amtval.getElementsByTagName("B2");
amt = lstNmElmntLst.item(0).getTextContent();
System.out.println("MainAmt : " +amt);
}
catch(Exception ex){
ex.printStackTrace();
}
}
}
}
}
current output:
Hi
Hello
100
1000
I want to read the tags alternatively. then only i can able map the values. How can i read these tags alternatively. output should be like this
Hi 100
Hello 1000
Kindly help me out of it.
Thanks in advance..
I think you need to filter only tags so that your parser will fetch only tags.For this you can use XPath.This is an examples here:
http://www.roseindia.net/tutorials/xPath/java-xpath.shtml

Parsing attribute in XML with DOM parser

I am currently parsing XML, but im not quite sure how to parse the "status" attribute of "message":
<message status="test"> <text>sometext</text> <msisdn>stuff</msisdn> </message>
Here is the code, i have cut off everything unnecessary:
NodeList nodeLst = doc.getElementsByTagName("message");
for (int s = 0; s < nodeLst.getLength(); s++) {
Node fstNode = nodeLst.item(s);
if (fstNode.getNodeType() == Node.ELEMENT_NODE) {
Element fstElmnt = (Element) fstNode;
NodeList numberNmElmntLst = fstElmnt
.getElementsByTagName("msisdn");
Element numberNmElmnt = (Element) numberNmElmntLst.item(0);
NodeList numberNm = numberNmElmnt.getChildNodes();
String phoneNumber = ((Node) numberNm.item(0))
.getNodeValue().substring(2);
NodeList txtNmElmntLst = fstElmnt
.getElementsByTagName("text");
Element txtNmElmnt = (Element) txtNmElmntLst.item(0);
NodeList txtNm = txtNmElmnt.getChildNodes();
String text = ((Node) txtNm.item(0)).getNodeValue();
NodeList rcvNmElmntLst = fstElmnt
.getElementsByTagName("received");
Element rcvNmElmnt = (Element) rcvNmElmntLst.item(0);
NodeList rcvNm = rcvNmElmnt.getChildNodes();
String recievedDate = ((Node) rcvNm.item(0)).getNodeValue();
}
}
Can anyone guide me how this is done?
Thanks in advance.
Node.getAttributes()
NamedNodeMap attributes = fstElmnt.getAttributes();
for (int a = 0; a < attributes.getLength(); a++)
{
Node theAttribute = attributes.item(a);
System.out.println(theAttribute.getNodeName() + "=" + theAttribute.getNodeValue());
}
You could avoid traversing if you use XPATH to retrieve the data. Read this tutorial.
I have been playing with Apache Xerces for parsing DOM. But it was horrible tasks. If you could, take a look at jsoup.
So, if your question has an answer in Jsoup, it would be:
node.attr("status")

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