Servlet not opening the welcome page [duplicate] - java

I have a confusion regarding the structure of the web.xml for the servlet mapping, I don't have any problem by executing it but I am trying to figure it how why we have such a pattern in the deployment descriptor.
<web-app>
<servlet>
<servlet-name>Servlet1</servlet-name>
<servlet-path>foo.Servlet</servlet-path>
</servlet>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/enroll</url-pattern>
</servlet-mapping>
</web-app>
Now as far as my understanding whenever a request is comes for url-pattern "/enroll", servlet container is going to match the servlet-name with the url-pattern and will try to find the corresponding servlet-path and will forward the control to foo.Servlet. so basically there would be two passes one for finding servlet-name and another for servlet-path, my question is if container is designed to work in the following way
<web-app>
<servlet>
<servlet-name>foo.Servlet</servlet-path>
<url-pattern>/enroll</url-pattern>
</servlet>
</web-app>
what would be the drawback if we use the following approach. Wouldn't that be more efficient and the response time would be fast.

It allows servlets to have multiple servlet mappings:
<servlet>
<servlet-name>Servlet1</servlet-name>
<servlet-path>foo.Servlet</servlet-path>
</servlet>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/enroll</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/pay</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/bill</url-pattern>
</servlet-mapping>
It allows filters to be mapped on the particular servlet:
<filter-mapping>
<filter-name>Filter1</filter-name>
<servlet-name>Servlet1</servlet-name>
</filter-mapping>
Your proposal would support neither of them. Note that the web.xml is read and parsed only once during application's startup, not on every HTTP request as you seem to think.
Since Servlet 3.0, there's the #WebServlet annotation which minimizes this boilerplate:
#WebServlet("/enroll")
public class Servlet1 extends HttpServlet {
See also:
How do servlets work? Instantiation, sessions, shared variables and multithreading
Difference between each instance of servlet and each thread of servlet in servlets?
Our Servlets wiki page

Related

Jersey JAX-RS: Specifying /* as base URL pattern

I have a Dynamic Web application, and because of the requirements, I am specifying two types of servlet mappings in the web.xml file; Faces Servlet & Jersey(JAX-RS implementation).
My problem is, that if I try to use '/' as the base url-pattern in the Jersey configuration, then the resources of Faces Servlets stop working, i.e., nothing happens if I make REST call to those resources, otherwise everything works fine if I place something like'/rest/' in the Jersey Configuration. My web.xml file looks like this:
<!-- Jersey -->
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.saf.web.v2.beans</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<!-- Faces Servlet -->
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>100</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
Is there a way to specify the Jersey mapping so there is nothing in the url-pattern but '/*' and Faces Servlet resources also work fine at the same time.
Thanks!
If you define that Jersey should serve all requests (this is what /* means) the Faces Servlet doesn't have a chance any more. So in general: There is no such way.
Maybe you could work around this be mapping Jersey to /rest and writing an own Servlet mapped to /* which dispatches to one of the other servlets. I would not recommend that.
I had the same problem but I fixed it by using
/rest/*
for jersey's servlet
and other part of application can have any other url-pattern, as in your case it is *.xhtml for JSF's servlet.

Web.xml - not redirecting specific file or url to servlet

I want to redirect all connections (/*) to a specific servlet, except a specific file (someFile.xml).
I have the following section in web.xml:
<servlet-mapping>
<servlet-name>someServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
How can I modify it so that /someFile.xml will not be mapped to this servlet.
If I cannot do it using web.xml, is there some other way?
You can create a Servlet and map it to receive /someFile.xml.
<servlet-mapping>
<servlet-name>someServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>SomeFileServlet</servlet-name>
<url-pattern>/someFile.xml</url-pattern>
</servlet-mapping>
In this way all request except /someFile.xml will go to someServlet and request for /someFile.xml will go to SomeFileServlet.
**/* mapping in web.xml it answers all requests except other path mappings.**

Servlet Mapping using web.xml

I have a confusion regarding the structure of the web.xml for the servlet mapping, I don't have any problem by executing it but I am trying to figure it how why we have such a pattern in the deployment descriptor.
<web-app>
<servlet>
<servlet-name>Servlet1</servlet-name>
<servlet-path>foo.Servlet</servlet-path>
</servlet>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/enroll</url-pattern>
</servlet-mapping>
</web-app>
Now as far as my understanding whenever a request is comes for url-pattern "/enroll", servlet container is going to match the servlet-name with the url-pattern and will try to find the corresponding servlet-path and will forward the control to foo.Servlet. so basically there would be two passes one for finding servlet-name and another for servlet-path, my question is if container is designed to work in the following way
<web-app>
<servlet>
<servlet-name>foo.Servlet</servlet-path>
<url-pattern>/enroll</url-pattern>
</servlet>
</web-app>
what would be the drawback if we use the following approach. Wouldn't that be more efficient and the response time would be fast.
It allows servlets to have multiple servlet mappings:
<servlet>
<servlet-name>Servlet1</servlet-name>
<servlet-path>foo.Servlet</servlet-path>
</servlet>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/enroll</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/pay</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Servlet1</servlet-name>
<url-pattern>/bill</url-pattern>
</servlet-mapping>
It allows filters to be mapped on the particular servlet:
<filter-mapping>
<filter-name>Filter1</filter-name>
<servlet-name>Servlet1</servlet-name>
</filter-mapping>
Your proposal would support neither of them. Note that the web.xml is read and parsed only once during application's startup, not on every HTTP request as you seem to think.
Since Servlet 3.0, there's the #WebServlet annotation which minimizes this boilerplate:
#WebServlet("/enroll")
public class Servlet1 extends HttpServlet {
See also:
How do servlets work? Instantiation, sessions, shared variables and multithreading
Difference between each instance of servlet and each thread of servlet in servlets?
Our Servlets wiki page

Multiple SpringDispatcherServlet to handle different url

Is it ok to have more than 1 DispatcherServlet in web.xml to handle different URL ?
What's the downside?
<servlet>
<servlet-name>servlet1</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet>
<servlet-name>servlet2</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>servlet1</servlet-name>
<url-pattern>/url2/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>servlet2</servlet-name>
<url-pattern>/url1/*</url-pattern>
</servlet-mapping>
Yes, it is absolutely OK. Depending on app complexity and architecture, it actually may become very useful. You can use it to structure the application on dispatcher level (rather than on controllers). Or when you want certain URL classes to have different dispatcher configuration (view resolvers, locale resolvers, etc.)
You don't necessarily need multiple instances of the same servlet, unless you'd like to give them each different init-param values. I'd rather just assign different mappings to the same servlet like so:
<servlet>
<servlet-name>springDispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springDispatcherServlet</servlet-name>
<url-pattern>/url1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>springDispatcherServlet</servlet-name>
<url-pattern>/url2/*</url-pattern>
</servlet-mapping>
That's also perfectly valid for the case you didn't knew that.
Yeah, that's fine. The only downside is that the application contexts for each of the servlets won't be able to talk to each other, but it's a perfectly valid approach.
I would suggest, though, that it's generally better to have just the one DispatcherServlet, and handle all request routing within that. It's one less thing to go wrong.
Depends on your needs of course, but in most cases better to have one servlet.
So you can simplify you config to:
<servlet>
<servlet-name>servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>servlet</servlet-name>
<url-pattern>/url2/*</url-pattern>
<url-pattern>/url1/*</url-pattern>
</servlet-mapping>

Accessing a servlet's mapping from Tomcat?

The following code accesses a servlet's name: servletConfig.getServletName().
Can I access a servlet's URL pattern in a similar way?
An excerpt from web.xml:
<servlet-mapping>
<servlet-name>This is the servlet's name</servlet-name>
<url-pattern>/this-is-its-url-pattern/*</url-pattern>
</servlet-mapping>
In Servlet 3.0 (or Java EE 6) spec exist something:
http://docs.oracle.com/javaee/6/api/javax/servlet/ServletRegistration.html
You can get a ServletRegistration using ServletContext.html#getServletRegistration.
Nothing is available in the Servlet API. Either parse the web.xml yourself, or duplicate it as an <init-param> of the servlet wherein you'd like to access it.
<servlet>
<servlet-name>servlet</servlet-name>
<servlet-class>com.example.Servlet</servlet-class>
<init-param>
<param-name>url-pattern</param-name>
<param-value>/servlet</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>servlet</servlet-name>
<url-pattern>/servlet</url-pattern>
</servlet-mapping>
This way it's available by servletConfig.getInitParameter("url-pattern").

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