Photo picker intent:
Intent photoPickerIntent = new Intent(Intent.ACTION_PICK);
photoPickerIntent.setType("image/*");
startActivityForResult(photoPickerIntent, SELECT_PHOTO);
The text, shown below, currently says "Complete action using Photos". Is there a way to change this to something custom?
It's simple. The answer is No. Also in won't always be "with Photos", it will depend on most used(or recent) app for this kind of Action.
Lil update
You can use some other way of doing this.
Intent.createChooser(yourIntent, "Open via ..." /*your text goes here*/)
This will look differently, but will have your text
Use like this
this.startActivity(Intent.createChooser(emailIntent, "Send mail via ..."));
Related
When I want to share basic plaintext in my app, the option to copy it in my clipboard does not show up in the chooserlist. Is there something wrong with my code? Or has my device a wrong setup?
String code = getXMLCode();
Intent sharingIntent = new Intent(android.content.Intent.ACTION_SEND);
sharingIntent.setType("text/plain");
sharingIntent.putExtra(android.content.Intent.EXTRA_TEXT, code);
startActivity(Intent.createChooser(sharingIntent, getString(R.string.shareXMLCode)));
public String getXMLCode(){...}
Android does not have a "copy to clipboard" option as part of ACTION_SEND. Certain apps, like Google Drive, might offer such a feature.
cketti recently wrote a blog post about how you can add your own "copy to clipboard" option to your own ACTION_SEND requests. In a nutshell, you use EXTRA_INITIAL_INTENTS to add another option to the chooser, one that points to your own activity that will offer "copy to clipboard".
I am trying to share a link from my app with direct share. The share dialog must be like the image below with the most used contacts from messaging apps, like WhatsApp contacts.
This is the Intent structure which I am using for share the link:
Intent shareIntent = ShareCompat.IntentBuilder
.from(getActivity())
.setType("text/plain")
.setText(sTitle+ "\n" + urlPost)
.getIntent();
if (shareIntent.resolveActivity(
getActivity().getPackageManager()) != null)
startActivity(shareIntent);
And this is what my app shows:
Any idea how to achieve that?
You should use .createChooserIntent() instead of .getIntent()
Like this code below, you can use Intent.createChooser
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
Uri screenshotUri = Uri.parse("file://" + filePath);
sharingIntent.setType("image/png");
sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
startActivity(Intent.createChooser(sharingIntent, "Share image using"));
You should use .createChooserIntent() instead of .getIntent()
Docs: This uses the ACTION_CHOOSER intent, which shows
an activity chooser, allowing the user to pick what they want to before proceeding. This can be used as an alternative to the standard activity picker that is displayed by the system when you try to start an activity with multiple possible matches, with these differences in behavior:
You can specify the title that will appear in the activity chooser.
The user does not have the option to make one of the matching activities a preferred activity, and all possible activities will
always be shown even if one of them is currently marked as the
preferred activity.
This action should be used when the user will naturally expect to
select an activity in order to proceed. An example if when not to use
it is when the user clicks on a "mailto:" link. They would naturally
expect to go directly to their mail app, so startActivity() should be
called directly: it will either launch the current preferred app, or
put up a dialog allowing the user to pick an app to use and optionally
marking that as preferred.
In contrast, if the user is selecting a menu item to send a picture
they are viewing to someone else, there are many different things they
may want to do at this point: send it through e-mail, upload it to a
web service, etc. In this case the CHOOSER action should be used, to
always present to the user a list of the things they can do, with a
nice title given by the caller such as "Send this photo with:".
I am trying to capture the result of Intent.createChooser to know which app a user selected for sharing.
I know there have been a lot of posts related to this:
How to know which application the user chose when using an intent chooser?
https://stackoverflow.com/questions/6137592/how-to-know-the-action-choosed-in-a-intent-createchooser?rq=1
How to get the user selection from startActivityForResult(Intent.createChooser(fileIntent, "Open file using..."), APP_PICKED);?
Capturing and intercepting ACTION_SEND intents on Android
but these posts are somewhat old, and I am hoping that there might be some new developments.
I am trying to implement a share action without having it be present in the menu. The closest solution to what I want is provided by ClickClickClack who suggest implementing a custom app chooser, but that seems heavy handed. Plus, it seems like there might be some Android hooks to get the chosen app, like the ActivityChooserModel.OnChooseActivityListener.
I have the following code in my MainActivity, but the onShareTargetSelected method is never getting called.
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, shareMessage());
sendIntent.setType("text/plain");
Intent intent = Intent.createChooser(sendIntent, getResources().getText(R.string.share_prompt));
ShareActionProvider sap = new ShareActionProvider(this);
sap.setShareIntent(sendIntent);
sap.setOnShareTargetSelectedListener(new ShareActionProvider.OnShareTargetSelectedListener() {
#Override
public boolean onShareTargetSelected(ShareActionProvider source, Intent intent) {
System.out.println("Success!!");
return false;
}
});
startActivityForResult(intent, 1);
As of API level 22 it is now actually possible. In Android 5.1 a method (createChooser (Intent target, CharSequence title, IntentSender sender)) was added that allows for receiving the results of the user's choice. When you provide an IntentSender to createChooser, the sender will be notified by the chooser dialog with the ComponentName chosen by the user. It will be supplied in the extra named EXTRA_CHOSEN_COMPONENT int the IntentSender that is notified.
I am trying to capture the result of Intent.createChooser to know which app a user selected for sharing.
That is not possible.
Other "choosing" solutions, like ShareActionProvider, may offer more. I have not examined the Intent handed to onShareTargetSelected() to see if it contains the ComponentName of the chosen target, though the docs suggest that it should.
And, if for some reason it does not, you are welcome to try to fork ShareActionProvider to add the hooks you want.
The reason why createChooser() cannot be handled this way is simply because the "choosing" is being done by a separate process from yours.
I have the following code in my MainActivity, but the onShareTargetSelected method is never getting called.
ShareActionProvider goes in the action bar. You cannot just create an instance, call a couple of setters, and expect something to happen.
OK,I'm new at this forum, so don't blame me for putting this in the wrong tags,not putting something in,eg.
I want to learn how to create a shortcut(I did that by Googling) and link it to an activity (In this case, com.android.mms.ui.ComposeMessageActivity)
I tried doing it, but it only showed me a toast saying "Application not installed" and I'm pretty sure it is.
It would be better if you can display a "complete action with another application" dialog.
If I assumed your question correctly, you mean a button or something within an activity that leads to another activity, that being -- "com.android.mms.ui.ComposeMessageActivity"
if your activity that you want to link to is in another application-- then
Intent intent = new Intent();
intent.setComponent(new ComponentName("com.mine", "com.android.mms.ui.ComposeMessageActivity"));
startActivity(intent);
if it is within the same application, then
Intent intent = new Intent(this, ComposeMessageActivity.class);
startActivity(intent);
//optional add this to your manifest to finish the current loading activity so
//as to not keep it in the activity stack
//<activity android:name="yourActivity" android:noHistory="true" ... />
EDIT If you mean a shortcut on a homescreen, then I would create a tiny application that only has one activity which uses the above method to link to a different application. Then I would drag that application to the home screen, and boom. If there's a better way, then please feel free to correct me
How to you make it so if a user does something, it asks them how they want to do it and it brings them to that application? Like if you go "Share" a photo or video it pops up a list with all apps that can do that for you like facebook or text or email , ect.? I am asking how to have my app use other apps, not them use mine.
You do this by targeting the intent filter that the other apps use.
For example, if I want to share a picture, I can do this:
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");
share.putExtra(Intent.EXTRA_STREAM, Uri.parse("/sdcard/test.jpg"));
startActivity(Intent.createChooser(share, "Share image"));
Then you will get a popup to choose the app to use for this action.