I have a maven web project in eclipse. I need to get the project's path, actually have to get list of files under src\main\resources\someFolder in project.
Tried String dataDir = "src\\main\\resources\\someFolder";, on running this directory structure is created inside eclipse folder like F:\softwares\eclipse\eclipse\src\main\resources\someFolder. Same when using / instead of \\.
Tried System.getProperty("user.dir")and new File(".").getAbsolutePath(), they return F:\softwares\eclipse\eclipse.
I need to access the project folder in my workspace F:\workspace\Project\src\main\resources\someFolder
But when created a core java app and used System.getProperty("user.dir")and new File(".").getAbsolutePath(), I am getting project path in workspace, F:\workspace\Project. This src\\main\\resources\\someFolder also works fine then.
Why this odd behavior from eclipse?
As mentioned here the directory user.dir is the place where the JVM is started. As web applications are mostly jar/war/ear packages placed somewhere within the folder of the server eclipse handles them in a different way because the behaviour of such a web application is different. You cannot expect to have file access from outside the jar/war/ear file. Within the jar/war/ear file everything from within src/main/resources will be available just by using getResourceAsStream as described in many other stackoverflow articles. This way you mustn't use src/main/resources/myfile.txt but myfile.txt.
Don't try to guess or use what the user.dir / JVM/server start folder is!
Related
In my Maven project I have a properties file that has a property for a location of keystore file file=filename.p12 (I think the file type doesn't really matter now).
The problem I have that when i built it with maven, I see that the file is inside the root of jar and when i run java -jar the-jar-file.jar I get the IO exception that the filename.p12 is not found.
Everything runs fine in Eclipse, it finds the file and the application runs. Not to confuse somebody, I keep a copy of that filename.p12 as well in src/main/resources folder so that the paths are resolved running in Eclipse and standalone. But this is going to be my other question.
What I can't do is to get the filename.p12 as a resource, because I have external jar that gets as argument my properties file and then handles that properties file itself where the row file=filename.p12 is. Why is the file not found inside the jar, even though I see it's there? My other property files that I have open with Spring's ClassPathResource run just fine.
In order to access internal/embedded resources you need to use Class#getResource or Class#getResourceAsStream depending on your needs
I have 2 Java projects, one is a Web Project in NetBeans and the other is a Java Project in Eclipse.
Just to know, the Java Project from Eclipse is used by the Web Project in NetBeans as a library (.jar)
Situation:
1. Java Project from Eclipse has the following structure:
And inside the src, there is a class that uses the file1, file2, etc in some method using global variables like this:
public static final String PATH_ONE = "./files/file1.xml";
public static final String PATH_TWO = "./files/file2.xml";
...
Finally, when I test the method in some main() class everything works good.
2. Web Project from NetBeans has a jar reference to the above library and If everything works good, then the web project will be able to execute the method that uses the global variables without problems from the library project.
Problem:
When I run the web project and I want to invoke the method from my library that uses the above xml files from it, for some reason, NetBeans or the project (I don't certainly know) looks for the path and fails in Exception because the path can not be found (It seems that tries to find the path in the web project and not in the library one).
How can I solve this issue? It sounds simple but I don't want to change my structure, load them as a resource or transfer files from one project to another and use external paths to make this work because I just make a recreation of the situation but I am working with lots of files with different folders and paths too.
If you unzip your jar you can't find your folder file because not is included in your classpath.
You can See .classpath file and the folder isn't. For these reason is FileNotFoudnException.
You can to add how source folder in Eclipse ID:
1. Right click in your project/Build Path/ New source folder
Create the source folder . Then you can add a new package with the name Folder.
Your project:
src
resources
folder
resource1.xml
resource2.xml
2. Modify your java project.
public static final String PATH ="/folder/resource1.xml";
Now, if you try to unzip the jar, you can see that the folder was added in the .classpath.
It works for me. I tried to paste image but i'm new user.
I have a Java project which uses a third party application. I have the license file (.lic format) stored in the resources folder. Upon running the Ant script, it will copy this file into the /lib/jar directory as it rolls up the project into a Jar file to use on the server. This is where I will need to access the file when running the system live. Here is how the folder structure looks
MyProject
src
package
AccessingClass.java
resources
File.lic
lib
jar
File.lic (upon copy from Ant)
I am not sure the best way to do this so any suggestions other than how I have been trying will probably be helpful. The 3rd party project has a method in a class like License.setLicense(), which can either take a String to the location or an InputStream of the file.
I have been playing around with feeding it an InputStream, but always get a null value when calling getClass().getResourceAsStream(). Here is everything I have tried:
getClass().getResourceAsStream("../../../lib/jar/File.lic");
getClass().getResourceAsStream("/File.lic");
And as a backup I also tried (for local builds I figure I would try the resource folder):
getClass().getResourceAsStream("../../../resources/File.lic");
getClass().getResourceAsStream("/File.lic");
Is there a better method to perform this action? Or would someone be able to tell me why what I am trying is failing? Thanks ahead of time.
Are you running this code standalone or in IDE env looks like classpath issue. If you are running at command prompt you have to set classpath to lib dir if in ide make sure you resources dir is in classpath.
First, you need to ensure that the JAR is added in your class path.
Below should work.
InputStream inputStream =
getClass().getClassLoader().getResourceAsStream("/resources/File.lic");
Assuming File.lic is placed in root folder of the jar.
I have tomcat installed at "C:\Program Files\apache-tomcat-7.0.27"
I have eclipse installed at "C:\Program Files\eclipse"
And I have the workspace located at "C:\workspace"
I'm using "Java perspective", created a "Java Project" with the default output folder as "helloWorld/web/WEB-INF/classes".
The structure of the project goes like this:
-helloWorld
---src
-----servlets
-------hello.java
-------world.java
---web
-----WEB-INF
-------jsp
---------hello.jsp
---------world.jsp
-------lib
-------web.xml
---helloWorld.xml
---record.txt
doPost() in hello.java generate a random number, and write it to a text file "record.txt".
doPost() in world.java open the text file "record.txt" and read a number.
The system is working, but what I originally put in the record.txt file in eclipse project never get changed, and I'm sure that what world.java read from the file is exactly what hello.java generated.
I checked "C:\Program Files\apache-tomcat-7.0.27\work\Catalina\localhost\helloWorld", and only jsp files are there.
I then tried restart tomcat and reload and even undelopy and deploy again, but the previous generated number is still there. I didn't try restart computer.
My question is where is the record.txt file? It is definitely not the one in the eclipse project.
If you use a relative file path in your Java code then it will not be relative to your webapp it will be relative to where the process running Tomcat was started. Therefore you might find your file in the Tomcat bin directory or somewhere similar.
If you want to create a file relative to your webapp then you need to obtain the path to your webapp, which you can do by calling getServletContext().getRealPath("") in your Servlet.
Eclipse deployed projects are run in temp folder. the path looks some thing like this... tmp0/conf/catalina/localhost/projectname.....context.xml of servers might help you in this..
i suggest u should go for an absolute path....i faced same problem while using eclipse...That time i had to even provide the link to the user...
Check your webapps folder for a folder with the same name as your project.
C:\Program Files\apache-tomcat-7.0.27\webapps
Here you will find the exact folder structure and your record.txt file as well.
Hope this helps!
My file is located under the src directory. However, when I try to call it using "src/readme.txt" the file is not found.
In fact, it states that java is looking for "C:\Documents and settings\john\My Documents\Downloads\eclipse-win32\eclipse\coolCarsProject\src\readme.txt".
How do I fix this? I do not want to put in the absolute path all the time.
Do I need to fix the classpath, buildpath, or change the project root, etc? It is not at all obvious from the roughly 1000 settings in Eclipse for a newbie.
First, you have to decide if you want to load the file from the file system, or if the file will in fact be bundled with your application code.
If the former, then you should really think about how your application will be launched when actually deployed, because using a relative file path means that the program should always be started from the same location: a relative path is relative to the location from where the program is started (the current directory). If this is really what you want, then edit your launch configuration in Eclipse, go to the Arguments tab, and set the working directory you want. But the src directory is not where you should put this file, since this will copy the file to the target directory, along with the classes, that will probably be put in a jar once you'll deploy the application.
If the latter, then you should not treat the file as a file, but as a resource that is loaded by the ClassLoader, using ClassLoader.getResourceAsStream() (or Class.getResourceAsStream()). Read the javadoc of those methods to understand the path to pass. If you put the file directly under src, it will be copied by Eclipse to the target directory, along with your classes, in the default package. And you should thus use SomeClass.class.getResourceAsStream("/readme.txt") to load it.
Using paths relative to the current working directory is not a good idea in general, as it's often quite hard to establish what your current working directory will be. In Eclipse, it will be your project folder (unless you set it to something different in your launch configuration), in webapps it will be the webapp's root directory, in a command line app it could be anything.
Try this one:
String filePath = ".\\userFiles\\data.json";
where «.\» is a root for the Eclipse project, «userFiles» is a folder with the user's files inside of Eclipse project. Since we are talking about Windows OS, we have to use «\» and not «/» like in Linux, but the «\» is the reserved symbol, so we have to type «\\» (double backslash) to get the desired result.