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Splitting a string that has numbers and characters into an int and String

I have a String that goes "Peyton Manning; 49". Is there a way to have the computer read the left side of the String and make it equal to a new String "Peyton Manning" and take the right side of the String and make it equal to an int with a value of 49?

A number of ways spring to mind: you can tokenize or you can use regexs. You didn't specify about white space padding. Also, you didn't specify if the string segments around the delimiter can be invalid integers, mixtures strings digits etc. If this helped you, please mark accordingly.
public class Test {
public static void main(String[] args) {
String s="Blah; 99";
StringTokenizer st = new StringTokenizer(s, ";");
String name = st.nextToken();
Integer number = Integer.parseInt(st.nextToken().trim());
System.out.println(name.trim() + "---" + number);
number = Integer.parseInt(s.replaceAll("[^0-9]", ""));
name = s.replaceAll("[^A-Za-z]", "");
System.out.println(name + "---" + number);
int split = s.indexOf(";");
name = s.substring(0, split);
number = Integer.parseInt(s.substring(split+2, s.length()));
System.out.println(name + "---" + number);
}
}

The simplest way is:
String text = input.replaceAll(" *\\d*", "");
int number = Integer.parseInt(input.replaceAll("\\D", ""));
See KISS principle.

Simple java program that finds the number of words in a sentence

public static String number(String words) {
int length = words.length;
int total = 0;
while(int index < length) {
total = total + 1;
index = index + 1;
}
}
String output;
output = total + " word";
return output;
}
Example output for this would be:
numberOfWords("Hello whats up?")
3 word
This would work for all proper sentences but I have to account for bad input for example:
"Hi my name is bob"
, this would be like thirty plus words. Also
" "
, should be 0 words. Is there any simple way to make the first example to "hi my name is bob" ?

you can do something like this :
String trimmed = text.trim();
int words = trimmed.isEmpty() ? 0 : trimmed.split("\\s+").length;
or (simplest way):
use str.replaceAll("\\s+"," ");

Simplest will work in every case
String word = "Hi my name is bob";
word = word.replaceAll("\\s+", " ");
String count [] = word.split(" ");
System.out.println(count.length);

getting a number from a user and making changes and turning it into a string

I am making a math program that guesses the birthday of the user.
The user enters a number lets say : 75622 and i subtract a number from it to get the birthday, in this case 42682 -- 04/26/82
i want to be able to turn that integer into a string and then add the forward slash between the month, day and year.. and also add a 0 if it is only 5 digits and not 6 ( because of the month being 1-9).
I know how to use Integer.toString(int) to turn it into a string, but i do not know how to insert the forward slashes and the zero.
thank you kindly!

If you just want to convert the int to a String (with a leading 0) you can use String.format like
int num = 42682;
String s = String.format("%06d", num);
You might then use another String.format and String.substring to build your desired output, like
String output = String.format("%s/%s/%s", s.substring(0, 2),
s.substring(2, 4), s.substring(4));
System.out.println(output);
Which outputs (as requested)
04/26/82

Please find answer below:
public class CreateDateFromNumber {
public static void main(String[] args) {
int number = 42682;
System.out.println(getDate(number));
}
public static String getDate(int number) {
String numberStr = Integer.toString(number);
String outputStr = "";
if (numberStr.length() != 5 && numberStr.length() != 6) {
throw new IllegalArgumentException(
"Number should be length of 5 or 6");
}
if (numberStr.length() == 5) {
numberStr = "0" + numberStr;
}
int var0 = 0;
while (var0 < numberStr.length()) {
String var1 = numberStr.substring(var0, var0 + 2);
outputStr = outputStr + var1;
if (var0 + 2 < numberStr.length()) {
outputStr = outputStr + "/";
}
var0 = var0 + 2;
}
return outputStr;
}
}

Recursive method print string and counts down by 1 and deletes 1 letter for each recursion

I'm working on a recursive method that will return and print in my main method a String that will count down by 1 for N. Deleting one letter for each recursion for the string. Until N becomes 1 or until the string has 1 letter. (N being a int on the commandline)
For example if my command lines aruments are: 5 valentine
It should output too:
5 valentine, 4 alentine, 3 lentine, 2 entine, 1 ntine,
So far I managed to count down the number inputted on the commandline argument. I just don't know how to go about deleting one letter from the string? :o
My code so far:
public static void main(String[] args){
int number = Integer.parseInt(args[0]);
String word = new String("");
word = args[1];
String method = recursive.method1(number);
System.out.println(method);
}
public static String method1(int number){
if (number < 0){
return "";
}
else{
return number + ", " + method1(number - 1);
}
}

You can read through subString() documentation to understand how to go about taking the portions of a String.
Change your method definition to include the word
Add the word to your return statement: return number + " " + word +...
Call substring of the original word from the 1st index
Check for <=0 rather than <0
Code:
public static void main(String[] args){
int number = 5;
String word = new String("");
word = "Valentine";
String method = Recurcive.method1(number, word);
System.out.println(method);
}
public static String method1(int number, String word){
if (number <= 0){
return "";
}
else{
return number + " " + word + ", " + method1(number - 1, word.substring(1));
}
}
Gives,
5 Valentine, 4 alentine, 3 lentine, 2 entine, 1 ntine,

Java not showing last letter of string correctly?

So I have this little program and all it needs to do is check if the last letter of the last name is an "s". And if it is an "s" itll change the last name to plural.
Ex.
Smith = Smith's
Smiths = Smiths'
Changes the last name to plural. Simple right? Seems so, but my if statement isnt detecting if the last letter is an "s"
Here's some code
import javax.swing.JOptionPane;
public class Lastname {
public static void main(String[] args) {
String messageText = null;
String title = null;
int messageType = 0;
String lastName = "";
String pluralLastName = "";
Input input;
input = new Input();
messageText = "Please enter a last name. I'll make it plural.";
title = "Plural Last Names";
messageType = 3;
lastName = input.getString(messageText,title,messageType);
int intLength = lastName.length();
String lastLetter = lastName.substring(intLength- 1);
System.out.println("The last letter is: " + lastLetter);
if (lastLetter.equals('s'))
JOptionPane.showMessageDialog(null, "The last name entered as plural is " + lastName + "'" );
else
JOptionPane.showMessageDialog(null, "The last name entered as plural is " + lastName + "'s" );
}}
The if statement always just adds an "'s" to everything.

You need to use double quotes to represent a String literal.
if (lastLetter.equals("s"))
Otherwise you are comparing a String with a Character which will always return false.

Instead of comparing Strings, you can compare chars:
char lastLetter = lastName.charAt(intLength- 1);
System.out.println("The last letter is: " + lastLetter);
if (lastLetter == 's')
Right now, you are comparing Strings to chars.