I am currently creating a err... annoying program that repeatedly plays a ding sound, but there is a error whenever I run it. I have tried everything, and the file IS in the correct spot. Here is my current code:
public class PlaySound {
public static void main(String[] args) throws Exception {
while (true) {
String path = PlaySound.class.getProtectionDomain().getCodeSource().getLocation().getPath().replaceAll("%20", " ");;
InputStream in = new FileInputStream(path + "//src//ding.wav");
AudioStream audioStream = new AudioStream(in);
AudioPlayer.player.start(audioStream);
TimeUnit.SECONDS.sleep(1);
}
}
}
And yes, I have used other formats of the code like //src//ding.wav
Any help would be appreciated.
EDIT: also the error is
Exception in thread "main" java.io.FileNotFoundException: C:\Users\*** ******\Desktop\ding.jar\src\ding.wav (The system cannot find the path specified)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at net.lookatthis.PlaySound.main(PlaySound.java:19)
EDIT2: The error is older before I renamed the file. I changed the error to reflect the current filename
I think you're trying to read a resource in a jar file specifying the absolute path of your hard disk drive.
ding.jar\src\hit.wav
So there are two alternatives, or unzip your ding.jar file into a directory.
Or specify the relative path and access to the file using the classloader resource reader.
Using the resource reader you can find to the hit.wav file using
InputStream in = PlaySound.class.getResource("/ding.wav").openStream();
AudioStream audioStream = new AudioStream(in);
You probably need to unjar your ding.jar to expand its file structure. FileInputStream (probably?) can't access the jar'ed version of this file.
Related
For some reason (new to Java), when I'm trying to read an Excel file from my resources folder, it shows that it is there, but when I use FileInputStream to read it I get a FileNotFound Exception. Any ideas?
Code:
public static void openExcelSheet() throws IOException {
FileInputStream fileInputStream = null;
if(applicationSettings.class.getResourceAsStream("/files/Employees.xlsx") != null) {
System.out.println("File Found");
fileInputStream = new FileInputStream("/files/Employees.xlsx");
}else {
System.out.println("File Not Found");
}
XSSFWorkbook workbook = new XSSFWorkbook(fileInputStream);
//int numberOfSheets = workbook.getNumberOfSheets();
System.out.println(workbook.getAllNames());
workbook.close();
}
Here is the Output that I am receiving:
File Found
Exception in Application start method
java.lang.reflect.InvocationTargetException
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.base/java.lang.reflect.Method.invoke(Method.java:564)
at javafx.graphics/com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:473)
at javafx.graphics/com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:372)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.base/java.lang.reflect.Method.invoke(Method.java:564)
at java.base/sun.launcher.LauncherHelper$FXHelper.main(LauncherHelper.java:941)
Caused by: java.lang.RuntimeException: Exception in Application start method
at javafx.graphics/com.sun.javafx.application.LauncherImpl.launchApplication1(LauncherImpl.java:973)
at javafx.graphics/com.sun.javafx.application.LauncherImpl.lambda$launchApplication$2(LauncherImpl.java:198)
at java.base/java.lang.Thread.run(Thread.java:844)
Caused by: java.io.FileNotFoundException: /files/Employees.xlsx (No such file or directory)
at java.base/java.io.FileInputStream.open0(Native Method)
at java.base/java.io.FileInputStream.open(FileInputStream.java:220)
at java.base/java.io.FileInputStream.<init>(FileInputStream.java:158)
at java.base/java.io.FileInputStream.<init>(FileInputStream.java:113)
at applicationSettings.openExcelSheet(applicationSettings.java:32)
at loginScreen.start(loginScreen.java:70)
at javafx.graphics/com.sun.javafx.application.LauncherImpl.lambda$launchApplication1$9(LauncherImpl.java:919)
at javafx.graphics/com.sun.javafx.application.PlatformImpl.lambda$runAndWait$11(PlatformImpl.java:449)
at javafx.graphics/com.sun.javafx.application.PlatformImpl.lambda$runLater$9(PlatformImpl.java:418)
at java.base/java.security.AccessController.doPrivileged(Native Method)
at javafx.graphics/com.sun.javafx.application.PlatformImpl.lambda$runLater$10(PlatformImpl.java:417)
at javafx.graphics/com.sun.glass.ui.InvokeLaterDispatcher$Future.run(InvokeLaterDispatcher.java:96)
Exception running application loginScreen
The problem seems to be some incorrect assumptions in your code:
if (applicationSettings.class.getResourceAsStream("/files/Employees.xlsx") != null) {
System.out.println("File Found");
fileInputStream = new FileInputStream("/files/Employees.xlsx");
} else {
System.out.println("File Not Found");
}
So this is saying: "if I can find "Employees.xlsx" on the resource path, I can find it in the file system with the same path".
There are two incorrect assumptions here:
You are assuming that since you found "Employees.xlsx" on the resource path will be in the file system at all. This is not a valid assumption:
The resource could be (in fact, typically will be) a member of a JAR file or a similar file.
The resource or the resource's container could have been downloaded on the fly to a temporary file, or into memory.
The resource could have been created on the fly; e.g. by a clever class loader that decrypts or uncompresses something else.
You are assuming that "Employees.xlsx" will have the same resource path as file system path. This is pretty much guaranteed to not be the case. (It can only be the case if you put the root of the filesystem on the classpath ....)
I am not sure why you are trying to do this at all. Per #fabian's answer, POI allows you to open a spreadsheet from a InputStream. You should not need a FileInputStream here.
But in situations where you do need a FileInputStream for a resource on the resource path, the portable solution is to copy the resource to a temporary file, and then open a FileInputStream on the temporary file.
Resources are not necessarily files; They could be stored as entries in a .jar archive. Even if they are stored as files in a directory structure of the file system, the working directory may not match the current working directory. You should use the InputStream returned by getResourceAsStream directly instead of trying to open a new one:
InputStream inputStream = applicationSettings.class.getResourceAsStream("/files/Employees.xlsx");
if (inputStream != null) {
XSSFWorkbook workbook = new XSSFWorkbook(inputStream);
//int numberOfSheets = workbook.getNumberOfSheets();
System.out.println(workbook.getAllNames());
workbook.close();
} else {
System.out.println("Resource not found");
}
Provided that your file is residing inside the project folder, here is the problem remove the slash from the front of the name
fileInputStream = new FileInputStream("Employees.xlsx");
should work then. If it is inside the files folder inside the project folder then
fileInputStream = new FileInputStream("files/Employees.xlsx");
Or you can provide the complete path to the file and that should work
fileInputStream = new FileInputStream("/users/myfolder/files/Employees.xlsx");
I encountered the same issue today, which took me about two hours to partially figured it out. It was so annoying. Depending on how your class code is structured, Java does not allow you to read text file within the method definition. Try reading it in the main method, then take that FileInputStream object as input to your openExcelSheet() method. Let me know if it works :)
I am trying to get a JSON file form my resource folder in the main method using relative path. The code works using absolute path but this breaks once I build a jar file from my project which is want I want.
public static void main(String[] args) throws FileNotFoundException {
// Read in database
db = Database.read(Thread.currentThread().getContextClassLoader().getResource("JSON/inhabitants.json").toExternalForm());
names = db.getAllNames();
Read calls a method in Database which uses a inputstream to read the file.
public static Database read(String filename) throws FileNotFoundException {
InputStream is = new FileInputStream(filename);
Reader reader = new InputStreamReader(is);
return gson.fromJson(reader, Database.class);
}
The error I am getting is the following :
java.io.FileNotFoundException:
file:/Users/timpelser/IdeaProjects/TurfApp/target/classes/JSON/inhabitants.json
(No such file or directory) at java.io.FileInputStream.open0(Native
Method) at java.io.FileInputStream.open(FileInputStream.java:195) at
java.io.FileInputStream.(FileInputStream.java:138) at
java.io.FileInputStream.(FileInputStream.java:93) at
Core.Database.read(Database.java:22) at Main.main(Main.java:51) ...
11 more
The file in directory /Users/timpelser/IdeaProjects/TurfApp/target/classes/JSON/inhabitants.json
does exist however so I have no idea what is going wrong.
Here is my folder structure (Maven basic structure):
Is there a solution which will still able me to deploy it as a jar file ?
EDIT (25/09) : If I use getResourceAsStream instead of getResource, I am getting the following error :
Caused by: java.io.FileNotFoundException: java.io.BufferedInputStream#4f8e5cde (No such file or directory)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(FileInputStream.java:195)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at java.io.FileInputStream.<init>(FileInputStream.java:93)
at Core.Database.read(Database.java:22)
at Main.main(Main.java:51)
... 11 more
You have to use getResourceAsStream to read files from within the running jar (which contains the files within src\main\resources)!
Use This,
Resource resource = new classpathResource(json);
new ObjectMapper.readValue(resource.getInputStream(),Object.class);
I am getting an error when I try to read my file abc.txt in my D drive.
Even I tried format : "D:\EDU\java\abc.txt"
Here's my code :
package javapro;
import java.io.FileInputStream;
public class office {
public static void main (String[] args)throws Exception {
FileInputStream apple = new FileInputStream ("D:/EDU/java/abc.txt");
int din;
while ((din=apple.read())!=-1){
System.out.println((char)din);
}
apple.close();
}
}
My Error :
Exception in thread "main" java.io.FileNotFoundException: D:\EDU\java\abc.txt (The system cannot find the file specified)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at javapro.office.main(office.java:8)
Make sure the file is actually located in that directory. Right-click and click on Properties to check the path.
If you've done that, change all the \ to / or \\.
The error is self-explanatory. The file isn't where you have told the application it is. Check your path to make sure that it leads to the file.
1) Change the code as below
FileInputStream apple = new FileInputStream ("D:\\EDU\\java\\abc.txt");
or
InputStream is = getClass().getResourceAsStream("abc.txt");
//if abc.txt is present in classpath
From InputStream, you have to read the data.
EDIT: Resolve non static error
InputStream is = office.class.getClass().getResourceAsStream("abc.txt");
I'm making a simple game.
Eclipse reads a text file but when I export my project as runnable jar file it doesn't read it.
My resource folder looks like this: http://i.stack.imgur.com/LK2SF.png
The code:
BufferedReader br = new BufferedReader(
new FileReader("Resources/LevelManager/LevelManager.txt"));
When i run runnable jar file I get this error:
java.io.FileNotFoundException: Resources\LevelManager\LevelManager.txt (System cant find the path)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileReader.<init>(Unknown Source)
at LevelManager.Utils.getLevel(Utils.java:13)
at LevelManager.LevelManager.<init>(LevelManager.java:15)
at State.GameState.<init>(GameState.java:26)
at Main.Game.init(Game.java:54)
at Main.Game.run(Game.java:80)
at java.lang.Thread.run(Unknown Source)`
Thank you for your answers.
This is a classical error.
Your application will run in its own jar; which means its resources will be included in the jar and not available as File objects. You need to use a classloader.
I'm not sure how you intend to read from the resource but here is how to obtain a stream from a resource (and please note that slashes are used for separators, always:
#WillNotClose //this is a JSR 305 annotation
public static InputStream loadResource(final String resourcePath)
throws IOException
{
final URL url = EnclosingClass.class.getResource(resourcePath);
if (url == null)
throw new IOException(resourcePath + ": resource not found");
return url.openStream();
}
I'm trying to open a resource in my Java application by calling MainClass.class.getResource("/Resources/file.extension") and passing it to File's constructor with getPath(). Next, when I initialize a new FileInputStream with the File, I get a FileNotFoundException. The complete stack trace looks this.
java.io.FileNotFoundException: E:\user\Documents\NetBeansProjects\Project name\build\classes\Resources\file.csv (The system cannot find the path specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at my.secret.project.MainClass.main(MainClass.java:27)
Here's my code.
File file = new File(MainClass.class.getResource("/Resources/file.extension").getPath());
...
InputStream in = new FileInputStream(file);
Your whole code can be replaced with simple:
InputStream in = MainClass.class.getResourceAsStream("/Resources/file.extension");
No need to use File. In fact the file on your CLASSPATH might be pointing to some location inside JAR/WAR, which definitely won't work. Have a loot at Class.getResourceAsStream() for details.