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How to specify a Java file path for both Mac and Ubuntu

I'm using IntelliJ and Spring and Java to locally develop an app on a Mac, and then deploy to a tomcat server on AWS, using Ubuntu 16.04.3 LTS (GNU/Linux 4.4.0-1048-aws x86_64).
I'm having trouble specifying the file path so that it works in both environments.
My code is
InputStream fileStream = new FileInputStream("src/main/resources/static/web/data/ReportDates.json");
JsonReader reader = Json.createReader(fileStream);
JsonObject reportDates = reader.readObject();
reader.close();
When I run locally, the file is read in correctly. It is located in:
src/main/resources/static/web/data/ReportDates.json
But when I deploy, that code results in the error message:
java.io.FileNotFoundException: src/main/resources/static/web/data/ReportDates.json (No such file or directory)
The actual location of the file on that machine turns out to be:
/opt/tomcat/webapps/automentor/WEB-INF/classes/static/web/data/ReportDates.json
How can I specify the file path so that it works correctly in both environments?

I have given up on using a single path. #Nicholas Pesa got me thinking -- since I use IDEA, I don't have a fixed WEB-INF folder, so it's easier for me to change the path that should be used than to move the file to a fixed location.
My code now uses:
String filepath = (new File("src/main/resources/static/web/data/ReportDates.json").exists()) ? "src/main/resources/static/web/data/ReportDates.json" : "/opt/tomcat/webapps/automentor/WEB-INF/classes/static/web/data/ReportDates.json";

How to give local system path in ssh?

I'm trying to insert records from local directory path in SSH but it shows "file not found" because it does not recognize the path. But if I give sft directory then it recognise the path.
This is the code:
Local directory path:
./putmsgE1E2.ksh LPDWA123 ABC.GD.SENDCORRESPONDENCE.BATCH.INPUT XPRESSION.TEST /Users/admin/Desktop/important.txt;
and I tried using c:/Users/admin/Desktop/important.txt
SFT Directory:
./putmsgE1E2.ksh LPDWA123 ABC.GD.SENDCORRESPONDENCE.BATCH.INPUT XPRESSION.TEST /abchome/abc123/1.txt;
I have inputs in the txt file in my local directory; I want to poll that files to the server. Hope someone finds a solution. Thanks.

Use the below command on Linux systems:
scp /path/to/your/local/file remoteUser#some_address:/home/remoteUser/Documents

IOException when creating a temporary file?

I'm creating a task plugin for Atlassian Bamboo. At some moment of task executing, I would like to create a temporary file:
File temp = File.createTempFile(fileName.toString(), null, dir);
temp.deleteOnExit();
, where:
fileName.toString() = e.g. "C:\Atlassian\bamboo-home\xml-data\build-dir\CMPT-CMPTP-JOB1\test.java"
dir = new File("temp");
When testing this locally, everything works fine - the file is created properly. However, after I deploy plugin on server and try to execute above code, I've got an IOException:
java.io.IOException: The filename, directory name, or volume label syntax is incorrect
at java.io.WinNTFileSystem.createFileExclusively(Native Method)
at java.io.File.createTempFile(File.java:1879)
What could be the reason?
Additional info: I'm pretty sure that dir.exists() .

A file name of
"C:\Atlassian\bamboo-home\xml-data\build-dir\CMPT-CMPTP-JOB1\test.java"
is valid on Windows but is invalid on Unix operating systems. You won't be able to create a (temp) file like that, either as specified as the absolute name/path or the file nor just relative to another folder.
If your OS is Windows, you still can't use a full path (starting with drive specification like "C:") to be created as a child of another folder.

You could have spaces in the beginning or the ending of your path, print your file.getAbsolutePath() in order to see the current path where java is reading.

The dir variable must be set with the full (or relative) path to the directory temp. The first arg of File.createTempFile should be the prefix of the temp file (at least three letter long. for exeample "test"). This will create a "test.tmp" in the given directory (specified by the variable dir).
Check the javadoc
You can check existence of the directory dir with dir.exists()

Why an extra "/.\" in linux path?

Windows Scenario :-
I have a small piece of code which gets me the location of a specific folder in the directory. The code is as given below:
browserPath = this.EnginePath + "\\Chrome_Selenium\\" + "chromedriver.exe";
This gets me the exact path : D:\Engine\Test
I am trying to use the same logic to get the path in linux machine.
The path where the Engine and Chrome Driver is stored in my linux machine (VM) is
/root/Engine/Chrome_Selenium
Now the linux part :-
I am using the following piece of code to get that
browserPath = this.EnginePath + "/Chrome_Selenium/" + "chromedriver";
The path this piece of code fetches is
/root/Engine/.\Chrome_Selenium\chromedriver
Can you please help me understand why the "/.\" is appearing in the path?

I am guessing the reason why ./ is added is because in linux in order to execute a script in the present working directory you need to address it this way: ./script instead of script. Somehow it is attached even in cases where it is not needed (execution in other folder)
As for the main part as Alfe mentioned it does not make any different at the first place.

Deployment in tomcat

i am getting a problem
i have deployed a war file, when i run localy through tomcat it works fine but when i run on another system by giveing my system ip and then project folder e.g
http:\192.168.0.145\DllTest it loads the applet but when i click on a button to load the functionality it is throwing an exception
Exception in thread "AWT-EventQueue-3" java.lang.UnsatisfiedLinkError: Expecting an absolute path of the library: http:\192.168.0.145:8080\DllTest\lib\jinvoke.dll
while it is working fine localy but not in another system. Please tell me what is the problem.
Is it a rights issue or something else.

You cannot load a DLL on an external host. It has to be an absolute disk file system -as the exception message already hints. Your best bet is to download it manually, create a temp file and load it instead.
File dllFile = File.createTempFile("jinvoke", ".dll");
InputStream input = new URL(getCodeBase(), "lib/jinvoke.dll").openStream();
OuptutStream output = new FileOutputStream(dllFile);
// Write input to output and close streams the usual Java IO way.
// Then load it using absolute disk file system path.
System.loadLibrary(dllFile.getAbsolutePath());
dllFile.deleteOnExit();