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How to read the TypedArray data in Android?

I'm new to Android and still following some tutorials. One tut is about TypedArray for storing the image information.
MainActivity.java
package com.example.materialme;
import androidx.appcompat.app.AppCompatActivity;
import android.content.res.TypedArray;
import android.os.Bundle;
import android.util.Log;
import java.util.ArrayList;
import java.util.Arrays;
public class MainActivity extends AppCompatActivity {
private static final String TAG = MainActivity.class.getSimpleName();
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
TypedArray sportsImageResources = getResources().obtainTypedArray(R.array.sports_images);
Log.d(TAG, "sportImageResources: " + sportsImageResources);
sportsImageResources.recycle();
}
}
strings.xml
<resources>
<array name="sports_images">
<item>#drawable/img_baseball</item>
<item>#drawable/img_badminton</item>
<item>#drawable/img_basketball</item>
<item>#drawable/img_bowling</item>
<item>#drawable/img_cycling</item>
<item>#drawable/img_golf</item>
<item>#drawable/img_running</item>
<item>#drawable/img_soccer</item>
<item>#drawable/img_swimming</item>
<item>#drawable/img_tabletennis</item>
<item>#drawable/img_tennis</item>
</array>
</resources>
When I see in logcat, the values of TypedArray sportsImageResources are
[3, 179, 6, 2131165272, 0, 0, 3, 178, 6, 2131165271, 0, 0, 3, 180, 6, 2131165273, 0, 0, 3, 181, 6, 2131165274, 0, 0, 3, 182, 6, 2131165275, 0, 0, 3, 183, 6, 2131165276, 0, 0, 3, 184, 6, 2131165277, 0, 0, 3, 185, 6, 2131165278, 0, 0, 3, 186, 6, 2131165279, 0, 0, 3, 187, 6, 2131165280, 0, 0, 3, 188, 6, 2131165281, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 17, 512, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 16, 250, 1, 0, 1073742848, 0, 16, 400, 1, 0, 1073742848, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 1, 2131558747, 6, 2131558747, 1073742848, 0, 1, 2131558746, 6, 2131558746, 1073742848, 0, 28, -1, 1, 17170443, 1073742848, 0, 3, 193, 6, 2131165294, 1073742848, 0, 3, 27, 6, 0, 1073742848, 0, 18, -1, 6, 0, 1073742848, 0, 18, 0, 6, 0, 1073742848, 0, 18, 0, 6, 0, 1073742848, 0, 0, 0, -1, 0, 1073742848, 0, 0, 0, -1, 0, 1073742848, 0, 0, 0, -1, 0, 1073742848, 0, 0, 0, -1, 0, 1073742848, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, 18, 0, 6, 0, 1073742848, 0]
How to read this data?

May be this example will help you.
TypedArray sportsimgs = getResources().obtainTypedArray(R.array.random_imgs);
// get resource ID by index
sportsimgs .getResourceId(i, -1)
// or set you ImageView's resource to the id
mImgView1.setImageResource(sportsimgs .getResourceId(i, -1));
// recycle the array
sportsimgs .recycle();

For Loop Map Overwrites Previous Value

Essentially I am making a board game using sockets. Each client connected is stored in a map .
When the user makes a move to a coordinate in the 2D Array i.e. "move 2,3", it should put the connectionID in that position.
Currently my issue is, because I have a for loop; when i use the move command, the connection ID is replaced with the last value in the loop.
public void move(int x, int y) {
for (int value : gs.returnClients().values()) {
storeArray[x][y] = value;
}
}
i.e. If i have 2 clients connected: {62029=1, 62032=2} and my board
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 1, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 2, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
Let's say I want to have client 1 move to 0, 3 it should be:
[[0, 0, 0, 1, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 1, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 2, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
But instead I get:
[[0, 0, 0, 2, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 1, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 2, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
Since it's overwriting the last value of the map in the for loop.
How would I make it move dependent on its client "id" from the map?
Edit
In my server i have clients.put(socket.getPort(), connectionID); and methods to return the map and id. I have a class GameService that executes command which is
switch (request.type) {
case MOVE:
int clientID = Integer.parseInt(request.params[0]);
int getX = Integer.parseInt(request.params[1]);
int getY = Integer.parseInt(request.params[2]);
game.move(clientID,getX, getY);
return game.returnBoard();
In a file Request
String[] items = line.trim().split("\\s+");
switch (items[0].toUpperCase()) {
case "MOVE":
return new Request(RequestType.MOVE, items[1], items[2], items[3]);

As far as I understand your code, you need to do your move the following way:
public void move(int client, int x, int y) {
storeArray[x][y] = client;
}
where client is one (!) of the numbers within the gs.returnClients().values()-list. If you need to take it out of that map, you need to deliver the appropriate key for that, e.g.:
public void move(int clientId, int x, int y) {
storeArray[x][y] = gs.returnClients().get(clientId);
}

Dijkstra's Algorithm and trouble with A* algorithm

So I have been searching these two algorithms on the Internet and was able to, after days of working on it, get Dijkstra's Algorithm working. From what I have read the two Algorithms are not that different. So I am going to post what I did for Dijkstra's and I was hoping that you can show me or point me into the direction on how to modify it to the A* algorithm.
public Integer processGraph(int graph[][], int algorithm, int s, int d) {
if(algorithm == 1) {
// shortestDist[index] will hold the distance from s to the index
int shortestDist[] = new int[graph.length];
// added[i] is true if vertex index is included / the shortest distance from the source to the index is finalized
boolean added[] = new boolean[graph.length];
// establish all distances as Integer.Max_Value and added[] as false
for (int vertexIndex = 0; vertexIndex < graph.length; vertexIndex++) {
shortestDist[vertexIndex] = Integer.MAX_VALUE;
added[vertexIndex] = false;
}
// Distance of the source from itself is always 0
shortestDist[s] = 0;
// Parent array to store shortest the shortest path -- example: [num, num, num]
int[] parents = new int[graph.length];
// Find shortest path for all vertices
for (int i = 1; i < graph.length; i++) {
// Pick the minimum distance vertex
// from the set of vertices not yet
// processed. nearestVertex is
// always equal to the source in
// first iteration.
int u = minDistance(shortestDist, added);
added[u] = true;
for (int vertexIndex = 0; vertexIndex < graph.length; vertexIndex++) {
if (!added[vertexIndex] && graph[u][vertexIndex] != 0 && shortestDist[u] != Integer.MAX_VALUE && shortestDist[u] + graph[u][vertexIndex] < shortestDist[vertexIndex]) {
shortestDist[vertexIndex] = shortestDist[u] + graph[u][vertexIndex];
parents[vertexIndex] = u;
}
}
}
if(shortestDist[d] == Integer.MAX_VALUE) {
System.out.println(" ");
System.out.println("ERROR MESSAGE -- No path present from " + s + " to " + d);
System.out.println("ERROR MESSAGE --no path present from " + s + " to " + d);
System.out.println(" ");
return null;
}
//pathPrint(s, shortestDist, d); this only works for the first test
return shortestDist[d];
} // end algorithm 1
TO add more context to this, I have a driver class in which with several graphs upon which this finds the shortest path.
Example of graph[][]:
int regValid[][] = {{0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0}};
Again, how can I modify what I have to work with the A* algorithm instead of Dijkstras. Thank you and hopefully this makes sense.

You have full information about all nodes, edges and destination node, so Dijkstra is the best solution for your problem. A* would be useful if you hadn't known complete graph (most often for huge node space) and were forced to prioritize decisions according to some heuristics.
If you really want to simulate A* on your graph, you have to think out some artificial criterion (heuristics) which describes the estimated distance between given node and target node (in other words, pretend you don't know the path). Since your data set doesn't contain such additional information (and thinking out any satisfying admissibility condition is not trivial), your question doesn't make much sense to me.

Read string from USB HID RFID Reader with Java

I'm trying to read a String from a via USB connected RFID-Reader. The Reader is recognized correctly inside my appliaction. But I do not know how to read the transferred characters into a String.
If I do not detach the device, the String is printed like by a Keyboard (as you would expect from a HID). What I want is to catch that String inside my Java application only. This is the reason why I detach the USB device.
For example my application prints '"''#$&' to the console (see code below) or something like this
[0, 0, 39, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 34, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 39, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 39, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 35, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 36, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 38, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 39, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
But what I wanted to read is 05006790.
I think that there is a stupid false in my attempt. I hope that someone can help me to figure out how I have to read the Bytes into a String correctly.
Thank you very much.
CODE FOLLOWS HERE
Context context = new Context();
int result = LibUsb.init(context);
DeviceList list = new DeviceList();
result = LibUsb.getDeviceList(context, list);
for (Device device: list)
{
int address = LibUsb.getDeviceAddress(device);
int busNumber = LibUsb.getBusNumber(device);
DeviceDescriptor descriptor = new DeviceDescriptor();
DeviceHandle handle = new DeviceHandle();
int resultOpen = LibUsb.open(device, handle);
// if (resultOpen < 0) // handle = null;
int resultDescriptor = LibUsb.getDeviceDescriptor(device, descriptor);
// if (resultDescriptor< 0) // handle = null;
if(descriptor.idVendor() == 0x8ff && descriptor.idProduct() == 0x0009)
{
System.out.println("found");
LibUsb.detachKernelDriver(handle, 0);
}
}
UsbServices services = UsbHostManager.getUsbServices();
UsbDevice deviceHigh = findDevice(services.getRootUsbHub(), (short) 0x8ff, (short) 0x0009);
if(deviceHigh != null)
{
System.out.println("found high");
UsbConfiguration configuration = deviceHigh.getActiveUsbConfiguration();
UsbInterface iface = configuration.getUsbInterface((byte) 0x00);
iface.claim();
UsbEndpoint endpoint = iface.getUsbEndpoint((byte) 0x81);
UsbPipe pipe = endpoint.getUsbPipe();
pipe.open();
byte[] buffer = new byte[128];
int rx = 0;
rx = pipe.syncSubmit(buffer);
System.out.printf("%d bytes received\n", rx);
System.out.println(Arrays.toString(buffer));
iface.release();
}

Multidimensional arrays: Java. How does this code work?

I've been following a tutorial about creating a basic tile-based tower defense game in Java and have encountered a piece of code I cannot wrap my brain around and would like some help. (My main question is at the bottom after the code)
At this point we are iterating through a multidimensional array of 0's and 1's that we pass to a constructor which has a method that assigns a grass tile for 0's and stone tile for 1's and then another method to draw them to the screen creating our game screen. Simple enough, right?
Here is the class:
package data;
import static helpers.Artist.*;
public class TileGrid {
public Tile[][] map;
public TileGrid(int[][] newMap){
map = new Tile[20][15];
for(int i = 0; i < map.length; i++){
for(int j = 0; j <map[i].length; j++){
switch(newMap[j][i]){
case 0:
map[i][j] = new Tile(row * 64, col * 64, 64, 64, TileType.GRASS);
break;
case 1:
map[i][j] = new Tile(row * 64, col * 64, 64, 64, TileType.STONE);
break;
case 2:
map[i][j] = new Tile(row * 64, col * 64, 64, 64, TileType.WATER);
break;
}
}
}
}
public void Draw(){
for(int i = 0; i < map.length; i++){
for(int j = 0; j < map[i].length; j++){
Tile t = map[i][j];
DrawQuadTex(t.getTexture(), t.getX(), t.getY(), t.getWidth(), t.getHeight());
}
}
}
}
And here is the array we are passing in:
int[][] map = { //20 tiles wide, 15 tiles high
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0},
{0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 0, 1, 0, 0, 0, 0, 0, 2, 2, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0},
};
So my main question has to do with the switch statement in the constructor for the TileGrid.
Why do the i and the j get switched newMap[j][i] when checking what it equals? I get that this code works, well, because it does and I understand nested for loops to iterate through a multidimensional array.
But why wouldn't newMap[i][j] work?
As well at the very beginning of that same constructor why do we create an array (of type Tile) with the dimension of map = new Tile[20][15] when we are passing in an array with the dimensions of map[15][20]?
I have tried to figure this out and study this on my own and will continue to do so until I understand it but any help would be soooo appreciated!

You are passing to the TileGrid constructor a 2D array of 15 rows and 20 columns, but inside the constructor you create a 2D array of 20 rows and 15 columns. That's why map[i][j] corresponds with newMap[j][i].
If the input int[][] map was also of 20 rows and 15 columns, you wouldn't have to switch the order of the indices inside the constructor.

This would give an index out of bounds error if it was really switched. However, there is a col variable in the second for loop that is not defined anywhere so it's hard to tell what's going on. This code will not compile.
If it is some code pulled off a a tutorial on some web page, I would just assume that it was a typo and continue on with that in mind. OR better yet, contact the author.