I have set up a HashMap which populates with customers details as values (name, postcode, item) and the keys being say Customer1, Customer2 etc.
I want a method to delete just value "item" from each key, my code at the moment is as per below but when i run it the "item" value from argument isn't deleted.
public void deleteThisValue(String value)
{
if (this.customer.containsValue(value))
{
this.customer.remove(value);
}
}
Now in my head this works but it obviously doesn't, can anyone shed any light on this matter?
Thanks
You can simply iterate over the values...then invoking the get method of the map will return the reference of the value, on that reference you can invoke a setter.
myMap.get(x).setItem("newItem");
//or
myMap.get(x).setItem(-1);
it depends what is Item for a type....
example:
Map<String, Pojo> myMap = new HashMap<>();
myMap.put("A", new Customer2());
myMap.put("B", new Customer2());
myMap.put("C", new Customer2());
for (String x : myMap.keySet()) {
myMap.get(x).setItem("newItem");
//or
myMap.get(x).setItem(-1);
}
System.out.println(myMap);
Edit:
since java8 is offering streams, you can use those nice features doing:
myMap.values().stream().forEach(x -> x.setItem("none"));
remove method works with key only,
If you want to remove value only, then you can set value as null for that key.
e.g:
this.customer.put(key,null);
But if you want to set a particular value (say item) of value then you can do this something like that:
this.customer.get(key).setItem(null);
Related
I'm trying to remove an element from a set that is in a map but I'm unsure how to do it.
The code I have so far is:
public void deleteToValue(String aLocation, String aEquipment)
{
locationMap.remove(aLocation, aEquipment);
}
The map key is the location and the the set is called equipment.
Assume the location is London and I want to remove a bike from the set.
The key and set will always be present so there's no need to check for nulls at this point.
This requires 2 steps:
Set<String> equipment = locationMap.get(aLocation) => returns the set
equipment.remove(aEquipment) ==> removes equipment from set.
If I understood you correctly, you have a map -> Map<String, Set<String>> and you want to remove equipment for some location.
Please, consider this code:
public void deleteToValue(String aLocation, String aEquipment)
{
Set<String> equip = locationMap.get(aLocation);
if (equip != null) {
equip.remove(aEquipment);
}
}
When calling map .get(..key..) method, it returns a value associated with a provided key, in your case, your value is Set<>.
So, to remove something from the set, firtly you need to read it from the map by key -> Set<String> equip = locationMap.get(aLocation); and then remove the required item from the Set -> equip.remove(aEquipment);
So I'm going crazy with this one. This is for an assignment and can't seem to get this to work at all!!
I have the following HashMap:
HashMap<String, ArrayList<Team>> teams;
(Team being another class to obtain the details of the teams)
What I need to be able to do is get the List of teams for the Key(String) from the above HashMap, and assign the List to a local variable I have declared:
List<Team> results = teams.get(division);
But this is where I get stuck. I have no idea how I'm suppose to complete this task.
As a further note "division" is the Key used in the HashMap. The ArrayList is a list of teams that belong to the division.
I have tried the below, which does not compile at all. Really not sure how I can get this to work!!
public void recordResult(String division, String teamA, String teamB, int teamAScore, int teamBScore)
{
List<Team> results = teams.get(division);
for (String i : teams.keySet())
{
results = new ArrayList<Team>();
results.add();
}
}
**You can ignore the arguments after the "String division". These will be used later.
Iterate over the entrySet() of the Map. Now you can fetch each List for that specific key and proceed further. Something like:
for (Entry<String, ArrayList<Team>> entry : teams.entrySet()) {
// extract the value from the key using `teams.get(entry.getKey())`
// proceed further with the value obtained
}
Is there a way to add a key to a HashMap without also adding a value? I know it seems strange, but I have a HashMap<String, ArrayList<Object>> amd I want to first be able to create keys as needed and then check if a certain key exists and, if so, put the appropriate value, namely the ArrayList<Object>
Was that confusing enough?
Since you're using a Map<String, List<Object>>, you're really looking for a multimap. I highly recommend using a third-party library such as Google Guava for this - see Guava's Multimaps.
Multimap<String, Object> myMultimap = ArrayListMultimap.create();
// fill it
myMultimap.put("hello", "hola");
myMultimap.put("hello", "buongiorno");
myMultimap.put("hello", "สวัสดี");
// retrieve
List<String> greetings = myMultimap.get("hello");
// ["hola", "buongiorno", "สวัสดี"]
Java 8 update: I'm no longer convinced that every Map<K, SomeCollection<V>> should be rewritten as a multimap. These days it's quite easy to get what you need without Guava, thanks to Map#computeIfAbsent().
Map<String, List<Object>> myMap = new HashMap<>();
// fill it
myMap.computeIfAbsent("hello", ignored -> new ArrayList<>())
.addAll(Arrays.asList("hola", "buongiorno", "สวัสดี");
// retrieve
List<String> greetings = myMap.get("hello");
// ["hola", "buongiorno", "สวัสดี"]
I'm not sure you want to do this. You can store null as a value for a key, but if you do how will be able to tell, when you do a .get("key") whether the key exists or if it does exist but with a null value? Anyway, see the docs.
You can put null values. It is allowed by HashMap
You can also use a Set initially, and check it for the key, and then fill the map.
Yes, it was confusing enough ;) I don't get why you want to store keys without values instead just putting empty arraylists instead of null.
Adding null may be a problem, because if you call
map.get("somekey");
and receive a null, then you do not know, if the key is not found or if it is present but maps to null...
//This program should answer your questions
import java.util.*;
public class attemptAddingtoHashMap { //Start of program
//MAIN METHOD #################################################
public static void main(String args[]) { //main begins
Map<String, ArrayList<Object>> hmTrial = new HashMap<String, ArrayList<Object>>();
ArrayList alTrial = new ArrayList();//No values now
if (hmTrial.containsKey("first")) {
hmTrial.put("first", alTrial); }
else {hmTrial.put("first",alTrial);}
//in either case, alTrial, an ArrayList was mapped to the string "first"
//if you choose to, you can also add objects to alTrial later
System.out.println("hmTrial is " + hmTrial); //empty now
alTrial.add("h");
alTrial.add("e");
alTrial.add("l");
alTrial.add("l");
alTrial.add("o");
System.out.println("hmTrial is " + hmTrial);//populated now
} //end of main
//#############################################################################################################
} //end of class
//Note - removing objects from alTrial will remove the from the hashmap
//You can copy, paste and run this code on https://ide.geeksforgeeks.org/
I have a hashmap that is 101 keys in size, but I know for sure about 6 of those have no data inside, and there may be more without data as well. What exactly is inside the empty indexes? Is it null? or is there a Hash(index).isEmpty() method that I can use to see if its empty?
I realize there is a isEmpty method inside hashmap, but I thought that only checked if the entire map was empty not just a single index.
I realize there is a isEmpty method
inside hashmap, but I thought that
only checked if the entire map was
empty not just a single index.
I think what you're looking for is the containsKey(Object) method. According to the documentation:
Returns true if this map contains a
mapping for the specified key. More
formally, returns true if and only if
this map contains a mapping for a key
k such that (key==null ? k==null :
key.equals(k)). (There can be at most
one such mapping.)
Parameters:
key - key whose presence in this map is to be tested
Returns:
true if this map contains a mapping for the specified key
Well, for the keys to arrive there with no data, you have to put them there.
If you did map.put(key, null) then yes the data for that key is null. You always have to give the second parameter to the method, you can't just map.put(key).
If you know for sure that a certain key should have no data you could try going into debug mode and putting a watch for myMap.get(myEmptyKey) and see what you get (in case that no data is an empty object or something else, you should be able to see that).
Edit: Some code would be useful to help you, but if I understand correctly you do something like this:
for (Object obj : list) {
if (matchesCriteriaX(obj)) {
map.put("X", obj);
else if (matchesCriteriaY(obj)) {
map.put("Y", obj);
}
}
Well, if you do that and try to do map.get("X"), but you never actually put anything for that key (becaus no object matched criteria X), you will most definitely get back a null.
On the other hand, if you did something like
Map<String, List<Object>> map = new HashMap<String, List<Object>>();
map.add("X", new ArrayList<Object>());
map.add("Y", new ArrayList<Object>());
for (Object obj : list) {
if (matchesCriteriaX(obj)) {
List<Object> list = map.get("X");
list.add(obj);
else if (matchesCriteriaY(obj)) {
List<Object> list = map.get("Y");
list.add(obj);
}
}
then you could check if a category is empty by doing map.get("x").isEmpty() since List has that method (and it would be empty if no object matched the key criteria).
Judging from what you said, I'm suspecting something like this:
Map<SomeKey, List<SomeValue>> yourMap;
If this is the case, what you can do is
if( yourMap.contains(someKey) ){
List<SomeValue> someList = yourMap.get(someKey);
if(someList.size() == 0){
// it's empty, do something?
}
}
If I pass the same key multiple times to HashMap’s put method, what happens to the original value? And what if even the value repeats? I didn’t find any documentation on this.
Case 1: Overwritten values for a key
Map mymap = new HashMap();
mymap.put("1","one");
mymap.put("1","not one");
mymap.put("1","surely not one");
System.out.println(mymap.get("1"));
We get surely not one.
Case 2: Duplicate value
Map mymap = new HashMap();
mymap.put("1","one");
mymap.put("1","not one");
mymap.put("1","surely not one");
// The following line was added:
mymap.put("1","one");
System.out.println(mymap.get("1"));
We get one.
But what happens to the other values? I was teaching basics to a student and I was asked this. Is the Map like a bucket where the last value is referenced (but in memory)?
By definition, the put command replaces the previous value associated with the given key in the map (conceptually like an array indexing operation for primitive types).
The map simply drops its reference to the value. If nothing else holds a reference to the object, that object becomes eligible for garbage collection. Additionally, Java returns any previous value associated with the given key (or null if none present), so you can determine what was there and maintain a reference if necessary.
More information here: HashMap Doc
You may find your answer in the javadoc of Map#put(K, V) (which actually returns something):
public V put(K key,
V value)
Associates the specified value with the specified key in this map
(optional operation). If the map
previously contained a mapping for
this key, the old value is replaced by
the specified value. (A map m is said
to contain a mapping for a key k if
and only if m.containsKey(k) would
return true.)
Parameters:
key - key with which the specified value is to be associated.
value - value to be associated with the specified key.
Returns:
previous value associated with specified key, or null if there was no
mapping for key. (A null return can also indicate that the map previously associated null with the specified key, if the implementation supports null values.)
So if you don't assign the returned value when calling mymap.put("1", "a string"), it just becomes unreferenced and thus eligible for garbage collection.
it's Key/Value feature and you could not to have duplicate key for several values because when you want to get the actual value which one of values is belong to entered keyin your example when you want to get value of "1" which one is it ?!that's reasons to have unique key for every value but you could to have a trick by java standard lib :
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Map;
public class DuplicateMap<K, V> {
private Map<K, ArrayList<V>> m = new HashMap<>();
public void put(K k, V v) {
if (m.containsKey(k)) {
m.get(k).add(v);
} else {
ArrayList<V> arr = new ArrayList<>();
arr.add(v);
m.put(k, arr);
}
}
public ArrayList<V> get(K k) {
return m.get(k);
}
public V get(K k, int index) {
return m.get(k).size()-1 < index ? null : m.get(k).get(index);
}
}
and you could to use it in this way:
public static void main(String[] args) {
DuplicateMap<String,String> dm=new DuplicateMap<>();
dm.put("1", "one");
dm.put("1", "not one");
dm.put("1", "surely not one");
System.out.println(dm.get("1"));
System.out.println(dm.get("1",1));
System.out.println(dm.get("1", 5));
}
and result of prints are :
[one, not one, surely not one]
not one
null
It replaces the existing value in the map for the respective key. And if no key exists with the same name then it creates a key with the value provided.
eg:
Map mymap = new HashMap();
mymap.put("1","one");
mymap.put("1","two");
OUTPUT
key = "1", value = "two"
So, the previous value gets overwritten.
The prior value for the key is dropped and replaced with the new one.
If you'd like to keep all the values a key is given, you might consider implementing something like this:
import org.apache.commons.collections.MultiHashMap;
import java.util.Set;
import java.util.Map;
import java.util.Iterator;
import java.util.List;
public class MultiMapExample {
public static void main(String[] args) {
MultiHashMap mp=new MultiHashMap();
mp.put("a", 10);
mp.put("a", 11);
mp.put("a", 12);
mp.put("b", 13);
mp.put("c", 14);
mp.put("e", 15);
List list = null;
Set set = mp.entrySet();
Iterator i = set.iterator();
while(i.hasNext()) {
Map.Entry me = (Map.Entry)i.next();
list=(List)mp.get(me.getKey());
for(int j=0;j<list.size();j++)
{
System.out.println(me.getKey()+": value :"+list.get(j));
}
}
}
}
Associates the specified value with the specified key in this map. If the map previously contained a mapping for the key, the old value is replaced.
To your question whether the map was like a bucket: no.
It's like a list with name=value pairs whereas name doesn't need to be a String (it can, though).
To get an element, you pass your key to the get()-method which gives you the assigned object in return.
And a Hashmap means that if you're trying to retrieve your object using the get-method, it won't compare the real object to the one you provided, because it would need to iterate through its list and compare() the key you provided with the current element.
This would be inefficient. Instead, no matter what your object consists of, it calculates a so called hashcode from both objects and compares those. It's easier to compare two ints instead of two entire (possibly deeply complex) objects. You can imagine the hashcode like a summary having a predefined length (int), therefore it's not unique and has collisions. You find the rules for the hashcode in the documentation to which I've inserted the link.
If you want to know more about this, you might wanna take a look at articles on javapractices.com and technofundo.com
regards
Maps from JDK are not meant for storing data under duplicated keys.
At best new value will override the previous ones.
Worse scenario is exception (e.g when you try to collect it as a stream):
No duplicates:
Stream.of("one").collect(Collectors.toMap(x -> x, x -> x))
Ok. You will get: $2 ==> {one=one}
Duplicated stream:
Stream.of("one", "not one", "surely not one").collect(Collectors.toMap(x -> 1, x -> x))
Exception java.lang.IllegalStateException: Duplicate key 1 (attempted merging values one and not one)
| at Collectors.duplicateKeyException (Collectors.java:133)
| at Collectors.lambda$uniqKeysMapAccumulator$1 (Collectors.java:180)
| at ReduceOps$3ReducingSink.accept (ReduceOps.java:169)
| at Spliterators$ArraySpliterator.forEachRemaining (Spliterators.java:948)
| at AbstractPipeline.copyInto (AbstractPipeline.java:484)
| at AbstractPipeline.wrapAndCopyInto (AbstractPipeline.java:474)
| at ReduceOps$ReduceOp.evaluateSequential (ReduceOps.java:913)
| at AbstractPipeline.evaluate (AbstractPipeline.java:234)
| at ReferencePipeline.collect (ReferencePipeline.java:578)
| at (#4:1)
To deal with duplicated keys - use other package, e.g:
https://google.github.io/guava/releases/19.0/api/docs/com/google/common/collect/Multimap.html
There is a lot of other implementations dealing with duplicated keys.
Those are needed for web (e.g. duplicated cookie keys, Http headers can have same fields, ...)
Good luck! :)
I always used:
HashMap<String, ArrayList<String>> hashy = new HashMap<String, ArrayList<String>>();
if I wanted to apply multiple things to one identifying key.
public void MultiHash(){
HashMap<String, ArrayList<String>> hashy = new HashMap<String, ArrayList<String>>();
String key = "Your key";
ArrayList<String> yourarraylist = hashy.get(key);
for(String valuessaved2key : yourarraylist){
System.out.println(valuessaved2key);
}
}
you could always do something like this and create yourself a maze!
public void LOOK_AT_ALL_THESE_HASHMAPS(){
HashMap<String, HashMap<String, HashMap<String, HashMap<String, String>>>> theultimatehashmap = new HashMap <String, HashMap<String, HashMap<String, HashMap<String, String>>>>();
String ballsdeep_into_the_hashmap = theultimatehashmap.get("firststring").get("secondstring").get("thirdstring").get("forthstring");
}
BTW, if you want some semantics such as only put if this key is not exist. you can use concurrentHashMap with putIfAbsent() function.
Check this out:
https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/ConcurrentHashMap.html#put(K,%20V)
concurrentHashMap is thread safe with high performance since it uses "lock striping" mechanism to improve the throughput.
Yes, this means all the 1 keys with value are overwriten with the last added value and here you add "surely not one" so it will display only "surely not one".
Even if you are trying to display with a loop, it will also only display one key and value which have same key.
HashMap<Emp, Emp> empHashMap = new HashMap<Emp, Emp>();
empHashMap.put(new Emp(1), new Emp(1));
empHashMap.put(new Emp(1), new Emp(1));
empHashMap.put(new Emp(1), new Emp());
empHashMap.put(new Emp(1), new Emp());
System.out.println(empHashMap.size());
}
}
class Emp{
public Emp(){
}
public Emp(int id){
this.id = id;
}
public int id;
#Override
public boolean equals(Object obj) {
return this.id == ((Emp)obj).id;
}
#Override
public int hashCode() {
return id;
}
}
OUTPUT : is 1
Means hash map wont allow duplicates, if you have properly overridden equals and hashCode() methods.
HashSet also uses HashMap internally, see the source doc
public class HashSet{
public HashSet() {
map = new HashMap<>();
}
}