How to find max element in array using LMAX disruptor - java

Could you please provide an link on code example that implement parallel sort or parallel max finding using LMAX Disruptor pattern.

It's not really applicable. The disruptor is essentially behaving like a pipe with a handler visiting every item in isolation, but it's implemented very differently for avoiding locks and improving locality of references.
To find the max, this handler would have to "leak" information in a central place, thus colliding with other threads trying to produce their own value. To sort, I wouldn't even know where to begin... you want each handler to do some insertion sort into separate array somewhere else and merge later? That's just so not a good fit.
Besides, some thread has to put the data in the ring, which is pretty much the linear search you could have done in the first place. If the ring could be built directly over an existing array (to skip publishing), then what's the point of the disruptor? You would be better off with a bunch of threads given a sub range of the array.

Related

How to get an iterator from an akka streams Source?

I'm trying to create a flow that I can consume via something like an Iterator.
I'm implementing a library that exposes an iterator-like interface, so that would be the simplest thing for me to consume.
My graph designed so far is essentially a Source<Iterator<DataRow>>. One thing I see so far is to flatten it to Source<DataRow> and then use http://doc.akka.io/japi/akka/current/akka/stream/javadsl/StreamConverters.html#asJavaStream-- followed by https://docs.oracle.com/javase/8/docs/api/java/util/stream/BaseStream.html#iterator--
But given that there will be lots potentially many rows, I'm wondering whether it would make sense to avoid the flattening step (at least within the akka streams context, I'm assuming there's some minor per-element overhead when passed via stages), or if there's a more direct way.
Also, I'm curious how backpressure works in the created stream, especially the child Iterator; does it only buffer one element?
Flattening Step
Flattening a Source<Iterator<DataRow>> to a Source<DataRow> does add some amount of overhead since you'll have to use flatMapConcat which does eventually create a new GraphStage.
However, if you have "many" rows then this separate stage may come in handy since it will provide concurrency for the flattening step.
Backpressure
If you look at the code of StreamConverters.asJavaStream you'll see that there is a QueueSink that is spawning a Future to pull the next element from the akka stream and then doing an Await.result(nextElementFuture, Inf) to wait on the Future to complete so the next element can be forwarded to the java Stream.
Answering your question: yes the child Iterator only buffers one element, but the QueueSink has a Future which may also have the next DataRow. Therefore the javaStream & Iterator may have 2 elements buffered, on top of however much buffering is going on in your original akka Source.
Alternatively, you may implement an Iterator using prefixAndTail(1) under the hood for implementing hasNext and next.

Efficient multithreaded array building in Java

I have many threads adding result-like objects to an array, and would like to improve the performance of this area by removing synchronization.
To do this, I would like for each thread to instead post their results to a ThreadLocal array - then once processing is complete, I can combine the arrays for the following phase. Unfortunately, for this purpose ThreadLocal has a glaring issue: I cannot combine the collections at the end, as no thread has access the collection of another.
I can work around this by additionally adding each ThreadLocal array to a list next to the ThreadLocal as they are created, so I have all the lists available later on (this will require synchronization but only needs to happen once for each thread), however in order to avoid a memory leak I will have to somehow get all the threads to return at the end to clean up their ThreadLocal cache... I would much rather the simple process of adding a result be transparent, and not require any follow up work beyond simply adding the result.
Is there a programming pattern or existing ThreadLocal-like object which can solve this issue?
You're right, ThreadLocal objects are designed to be only accessible to the current thread. If you want to communicate across threads you cannot use ThreadLocal and should use a thread-safe data structure instead, such as ConcurrentHashMap or ConcurrentLinkedQueue.
For the use case you're describing it would be easy enough to share a ConcurrentLinkedQueue between your threads and have them all write to the queue as needed. Once they're all done (Thread.join() will wait for them to finish) you can read the queue into whatever other data structure you need.

Accessing one array with multiple threads but either only reading or only writing

I'm wondering if there could be any problems while accessing one array with multiple threads but either only reading or only writing.
When the threads write to the array it wouldn't matter in which order they write and even if they write to the same entry all threads would write the same value.
For example, if I want to find prime numbers via the Sieve of Eratosthenes:
I create an array of consecutive numbers and set all multiples of prime numbers to 0 using multiple threads.
It wouldn't matter if the thread which strikes off the multiples of two and the thread which strikes off the multiples of 5 set the entry of the number 20 to 0 at the same time or one before or after the other.
So it's not an question of the qualitiy or consistency of the data, but of the technical possibility to do it wihout facing any java errors.
I'm assuming you mean 'without synchronization controls'. The short answer is no.
Synchronization is used for 2 reasons:
Mutual exclusion of data
communication between threads
Your setup indicates that the first reason isn't really a problem in your case. The algorithm effectively separates the data out so that multiple worker threads won't be using the same data.
However, in order for changes done in one thread to become visible to another thread, you must use synchronization. Without synchronization, the JVM makes no guarantee as to the ordering of writes. Updates that one thread makes may be visible in another thread at any time later, or even never. See Effective Java Item #66, and maybe look at the Java Concurrency in Practice book.
I don't think it would work since eventually you need to read the variables (to output them, save to disk, etc.). And the read has to be synchronized in order to guarantee correct interthread operation ordering. Remember that without synchronization java only guarantees intrathread operation ordering.
Now, you can say that you don't want to read them at all in anyway, but if that is the case, java can just optimize throwing away the whole code.

Queue implementation with blocked 'take()' but with eviction policy

Is there an implementation with a blocking queue for take but bounded by a maximum size. When the size of the queue reaches a given max-size, instead of blocking 'put', it will remove the head element and insert it. So put is not blocked() but take() is.
One usage is that if I have a very slow consumer, the system will not crash ( runs out of memory ) rather these message will be removed but I do not want to block the producer.
An example of this would stock trading system. When you get a spike in stock trade/quote data, if you haven't consumed data, you want to automatically throw away old stock trade/quote.
There currently isnt in Java a thread-safe queue that will do what you are looking for. However, there is a BlockingDequeue (Double Ended Queue) that you can write a wrapper in which you can take from the head and and tail as you see freely.
This class, similar to a BlockingQueue, is thread safe.
Several strategies are provided in ThreadPoolExecutor. Search for "AbortPolicy" in this javadoc . You can also implement your own policy if you want. Perhaps Discard is similar to what you want. Personally I think CallerRuns is what you want in most cases.
I think using these is a better solution, but if you absolutely want to implement it at the queue, I'd probably do it by composition. Perhaps use a LinkedList or something and wrap it with synchronize keyword.
EDIT:(some clarifications..)
"Executor" is basically a thread pool combined with a blocking queue. It is the recommended way to implement a producer/consumer pattern in java. The authors of these libraries provides several strategies to cope with issues like you mentioned. If you are interested, here is another approach to specifically address the OOME issue (the source is framework specific and can't be used as is).

Java: Large collection and concurrent threads

I am facing this issue:
I have lots of threads (1024) who access one large collection - Vector.
Question:
is it possible to do something about it which would allow me to do concurrent actions on it without having to synchronize everything (since that takes time)? What I mean, is something like Mysql database works, you don't have to worry about synchronizing and thread-safe issues. Is there some collection alike that in Java? Thanks
Vector is a very old Java class - predates the Collections API. It synchronizes on every operation, so you're not going to have any luck trying to speed it up.
You should consider reworking your code to use something like ConcurrentHashMap or a LinkedBlockingQueue, which are highly optimized for concurrent access.
Failing that, you mention that you'd like performance and access semantics similar to a database - why not use a dedicated database or a message queue? They are likely to implement it better than you ever will, and it's less code for you to write!
[edit] Given your comment:
all what thread does is adding elements to vector
(only if num of elements in vector = 0) &
removing elements from vector. (if vector size > 0)
it sounds very much like you should be using something much more like a queue than a list! A bounded queue with size 1 will give you these semantics - although I'd question why you can't add elements if there is already something there. When you've got thousands of threads this seems like a very inefficient design.
Well first off, this design doesn't sound right. It sounds like you need to think about using a proper database rather than an simple data structure, even if this means just using something like an in-memory instance of HypersonicDB.
However, if you insist on doing things this way, then the java.util.concurrent package has a number of highly concurrent, non-locking data structures. One of them might suit your purpose (e.g. ConcurrentHashMap, if you can use a Map rather than a List)
Looks like you are implementing the producer consumer pattern, you should google "producer consumer java" or have a look at the BlockingQueue interface
I agree with skaffman about looking at java.util.concurrent.
ConcurrentHashMap is very scalable. However, the size() call on it returns only an approximation. So e.g. your app will occasionally be adding elements to it even if !(num of elements in vector = 0).
If you want to strictly enforce the condition you gave, there is no other way than to synchronize.
Instead of having tons of context switches, I guess you could let your users thread post a callable on a queue and have only one thread dealing with the mutation. This will eliminate the need for synchronization on the collection. The user threads can wait on Future.get().
Just an idea.
If you do not want to change your data structure and have only infrequent writes, you might also use one or many ReentrantReadWriteLock to synchronize access. Then many threads can read at the same time, but when a thread wants to write all reads are blocked until the write is done.
But you should check whether the used data structure is appropriate for the task, or whether another of the many java.util or java.util.concurrent classes is more appropriate. java.util.Vector is synchronized, by the way.

Categories