I am trying to do a HTTP post request to a web API and then parse the received HttpResponse and access the key value pairs in the body. My code is like this:
public class access {
// http://localhost:8080/RESTfulExample/json/product/post
public static void main(String[] args) {
HttpClient httpclient = HttpClients.createDefault();
HttpPost httppost = new HttpPost("https://XXXXXXX/RSAM_API/api/Logon");
// Request parameters and other properties.
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>(2);
urlParameters.add(new BasicNameValuePair("UserId", "XXXXX"));
urlParameters.add(new BasicNameValuePair("Password", "XXXXXX"));
try {
httppost.setEntity(new UrlEncodedFormEntity(urlParameters));
//Execute and get the response.
HttpResponse response = httpclient.execute(httppost);
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line;
while(null !=(line=rd.readLine())){
System.out.println(line);
}
System.out.println(response);
String resp = EntityUtils.toString(response.getEntity());
JSONObject obj = new JSONObject(resp);
}
catch (Exception e){
e.printStackTrace();
}
}
}
I am trying to access the body by converting it to a JSONObject with these 2 lines of code:
String resp = EntityUtils.toString(response.getEntity());
JSONObject obj = new JSONObject(resp);
But I get an error in the second line saying:
JSONObject
(java.util.Map)
in JSONObject cannot be applied
to
(java.lang.String)
Not sure if this is the correct approach. Is there a way to do what I am trying to do?
Any help would be appreciated, Thank you.
EDIT:
So when I try to print the response body using the following lines,
String resp = EntityUtils.toString(response.getEntity());
System.out.println(resp);
I get the result: {"APIKey":"xxxxxxxxxxxxxx","StatusCode":0,"StatusMessage":"You have been successfully logged in."}
I am looking for a way to parse this result and then access each element. Is there a way to do this?
According to JsonSimple's JsonObject documentation it takes map in the constructor but not a String. So the error you are getting what it says.
You should use JSONParser to parse the string first.
Its also better to provide the encoding as part of EntityUtils.toString say UTF-8 or 16 based off your scenario.
IOUtils.toString() from Apache Commons IO would be a better choice to use too.
Try the below line to parse the JSON:
JSONParser parser = new JSONParser();
JSONObject obj = (JSONObject) parser.parse(resp);
The above lines will vaildate the JSON and through exception if the JSON is invalid.
You don't need to read the response in the extra while loop. EntityUtils.toString(response.getEntity()); will do this for you. As you read the response stream before, the stream is already closed when comming to response.getEntity().
Related
I need to get specific data from this API http://countryapi.gear.host/v1/Country/getCountries?pName=Australia, convert it to String and write out on the console. I want to get data only for Australia. How can I get data in String format only for Name and Alpha2Code like this:
Australia, AU? I was trying to use EntityUtils.toString(response) but it doesn't work.
This is my code:
public class Client {
public static void main(String[] args) throws ClientProtocolException, IOException {
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://countryapi.gear.host/v1/Country/getCountries?pName=Australia");
request.addHeader("accept", "application/json");
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(stream));
String line = reader.readLine();
System.out.println(line);
}
}
The code actually return JSON for Australia, like this:
enter image description here
Try something like this:
Gson gson = new Gson();
JsonObject result = gson.fromJson(line, JsonObject.class);
JsonArray response = result.getAsJsonArray("Response");
Country country = gson.fromJson(response, Country.class);
You can use java api for json parsing. I am just writing a sample code. YOu can explore json parsing api more on below URL:
http://www.oracle.com/technetwork/articles/java/json-1973242.html
JsonObject obj = rdr.readObject();
JsonArray results = obj.getJsonArray("data");
for (JsonObject result : results.getValuesAs(JsonObject.class)) {
System.out.print(result.getJsonObject("name").getString("name"));
System.out.print(": ");
System.out.println(result.getString("message", ""));
System.out.println("-----------");
}
I have this code on my Android phone.
URI uri = new URI(url);
HttpPost post = new HttpPost(uri);
HttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(post);
I have a asp.net webform application that has in the page load this
Response.Output.Write("It worked");
I want to grab this Response from the HttpReponse and print it out. How do I do this?
I tried response.getEntity().toString() but it just seems to print out the address in memory.
Thanks
Use ResponseHandler. One line of code. See here and here for sample Android projects using it.
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/user");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
ResponseHandler<String> responseHandler=new BasicResponseHandler();
String responseBody = httpclient.execute(httppost, responseHandler);
JSONObject response=new JSONObject(responseBody);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
add combination of this post and complete HttpClient at - http://www.androidsnippets.org/snippets/36/
I would just do it the old way. It's a more bulletproof than ResponseHandler, in case you get different content types in the response.
ByteArrayOutputStream outstream = new ByteArrayOutputStream();
response.getEntity().writeTo(outstream);
byte [] responseBody = outstream.toByteArray();
I used the following code
BufferedReader r = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuilder total = new StringBuilder();
String line = null;
while ((line = r.readLine()) != null) {
total.append(line);
}
r.close();
return total.toString();
The simplest approach is probably using org.apache.http.util.EntityUtils:
String message = EntityUtils.toString(response.getEntity());
It reads the contents of an entity and returns it as a String. The content is converted using the character set from the entity (if any), failing that, "ISO-8859-1" is used.
If necessary, you can pass a default character set explicitly - e.g.
String message = EntityUtils.toString(response.getEntity(). "UTF-8");
It gets the entity content as a String, using the provided default character set if none is found in the entity. If the passed default character set is null, the default "ISO-8859-1" is used.
This code will return the entire response message in respond as a String, and status code in rsp, as an int.
respond = response.getStatusLine().getReasonPhrase();
rsp = response.getStatusLine().getStatusCode();`
I want json to be sent to GET request in query parameter to get the response for that json request.
If I use a link something like this :
www.url.com/search?query1=abc&filter={"or":[{"terms":{"vin":["1g1105sa2gu104086"]}}]}
Then the url part appears blue if I do it as sysout statement, something like this:
www.url.com/search?query1=abc&filter={"or":[{"terms":{"vin":["1g1105sa2gu104086"]}}]}
and the json appears as if it is not the part of the request.
To create a URL, I'm appending the manipulated JSON string to the URL and then sending the request. But it appears as two different strings.
Also I have used encoder to encode the JSON part
filter={"or":[{"terms":{"vin":["1g1105sa2gu104086"]}}]}
In that case the brackets and double quotes everything in that json is encoded, even the equalTo sign. Also the link appears blue but while sending request it throws exception of 400 Bad Request, since the equalTo is also converted to its encoding format.
I tried encoding only the JSON part leaving the filter= in the url itself, something like this :
www.url.com/search?query1=abc&filter={"or":[{"terms":{"vin":["1g1105sa2gu104086"]}}]}
The results that appear after the request is send is different from the results I want.
I'm using following code to create a JSON:
private String getVinFromInventoryRequest(String vin) throws JSONException {
JSONObject request = new JSONObject();
JSONArray orArray = new JSONArray();
for(String vin : vins) {
JSONObject termsObject = new JSONObject();
JSONObject vinsObject = new JSONObject();
JSONArray vinsArray = new JSONArray();
vinsArray.put(vin);
vinsObject.put("vin", vinsArray);
termsObject.put("terms", vinsObject);
orArray.put(termsObject);
}
request.put("or", orArray);
System.out.println("OfferMapper.getVinFromInventoryRequest " + request.toString());
return request.toString();
}
Also look what I found with a little googling :
JSONObject json = new JSONObject();
json.put("someKey", "someValue");
CloseableHttpClient httpClient = HttpClientBuilder.create().build();
try {
HttpPost request = new HttpPost("http://yoururl");
StringEntity params = new StringEntity(json.toString());
request.addHeader("content-type", "application/json");
request.setEntity(params);
httpClient.execute(request);
// handle response here...
} catch (Exception ex) {
// handle exception here
} finally {
httpClient.close();
}
For more info see : HTTP POST using JSON in Java
I want to extract the string returned from java web service in java client. The string returned from java web service is as follows:
{"Name":"Raj Johri","Email":"mailraj#server.com","status":true}
Which is a Json string format. I have written client code to extract this string as follows:
public static void main(String[] args) throws Exception{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost post = new HttpPost("http://localhost:8080/JsonWebService/services/JsonWebService/getData");
post.setHeader("Content-Type", "application/xml");
HttpResponse httpres = httpClient.execute(post);
HttpEntity entity = httpres.getEntity();
String json = EntityUtils.toString(entity).toString();
System.out.println("json:" + json);
}
I am getting following print on the console for json as:
json:<ns:getDataResponse xmlns:ns="http://ws.jsonweb.com"><ns:return>{"Name":"Raj Johri","Email":"mailraj#server.com","status":true}</ns:return></ns:getDataResponse>
Please tell me how to extract the string
{"Name":"Raj Johri","Email":"mailraj#server.com","status":true}
which is the actual message. Thanks in advance...
Well, The respons is as type of xml, and your json is in the <ns:return> node , so i suggest you to enter in depth of the xml result and simply get your json from the <ns:return> node.
Note:
I suggest you to try to specifying that you need the response as JSON type:
post.setHeader("Content-type", "application/json");
post.setHeader("Accept", "application/json");
There is a dirty way to do this (beside the xml parsing way)
if you are getting the same XML every time,
you can use split()
String parts[] = json.split("<ns:return>");
parts = parts[1].split("</ns:return>");
String jsonPart = parts[0];
now jsonPart should contain only {"Name":"Raj Johri","Email":"mailraj#server.com","status":true}
I am trying to send a http request to a website which is supposed to return a json response. The problem is that i am not getting the json data. But when i paste the url in a browser it displays the json output. Am a newbie. Kindly help.
Here is my code
HttpClient client = new DefaultHttpClient();
String url="http://directclientvendors.com/news24/api/get.php?type=news";
HttpGet request = new HttpGet(url);
HttpResponse response;
response = client.execute(request);
BufferedReader br =
new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line = "";
while(br.ready())
{
line+=br.readLine();
}
System.out.println("line "+line);
You should be executing a GET request and not a POST. Please change the request type to HttpGet. The browser executes a GET on the URL when you paste it on the address bar and hit enter.
Additionally use a Reader + StringBuilder / JsonReader / GSON to read from the URL's response content. String concatenation leads to the creation of additional objects unnecessarily.
[EDIT]
To my astonishment the API call works even when a POST call is made to get the resource. The problem must be in your parsing logic. Using a JsonReader works fine for me. This is just template code, but you can fill in the rest to get the other JSON elements. Regardless of whether POST works or not, you should still use GET for this call.
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://directclientvendors.com/news24/api/get.php?type=news");
HttpResponse response = client.execute(request);
InputStream content = response.getEntity().getContent();
JsonReader jsonReader = new JsonReader(new InputStreamReader(content, "UTF-8"));
jsonReader.beginObject();
if(jsonReader.hasNext())
{
System.out.println(jsonReader.nextName()); // prints 'news'
// BEGIN_ARRAY etc to parse the rest
}
// END_OBJECT and cleanup