Because of the project requirement, I have to use com.fasterxml.jackson.databind library to parse JSON data cannot use other JSON libraries available.
I am new to JSON parsing, so not sure if there are better options here?
I would like to know how can I update a string value in an Array node in the JSON file.
Following is a sample JSON. Please note this is not the entire file content, it's a simplified version.
{
"call": "SimpleAnswer",
"environment": "prod",
"question": {
"assertions": [
{
"assertionType": "regex",
"expectedString": "(.*)world cup(.*)"
}
],
"questionVariations": [
{
"questionList": [
"when is the next world cup"
]
}
]
}
}
Following is the code to read JSON into java object.
byte[] jsonData = Files.readAllBytes(Paths.get(PATH_TO_JSON));
JsonNode jsonNodeFromFile = mapper.readValue(jsonData, JsonNode.class);
To update a root level node value e.g. environment in the JSON file , I found following approach on some SO threads.
ObjectNode objectNode = (ObjectNode)jsonNodeFromFile;
objectNode.remove("environment");
objectNode.put("environment", "test");
jsonNodeFromFile = (JsonNode)objectNode;
FileWriter file = new FileWriter(PATH_TO_JSON);
file.write(jsonNodeFromFile.toString());
file.flush();
file.close();
QUESTION 1: Is this the only way to update a value in JSON file and is it the best way possible? I'm concerned on double casting and file I/O here.
QUESTION 2: I could not find a way to update the value for a nested Array node e.g. questionList. Update the question from when is the next world cup to when is the next soccer world cup
You can use ObjectMapper to parse that JSON, it is very easy to parse and update JSON using pojo class.
use link to convert your json to java class, just paste your json here n download class structure.
You can access or update nested json field by using . (dot) operator
ObjectMapper mapper = new ObjectMapper();
String jsonString="{\"call\":\"SimpleAnswer\",\"environment\":\"prod\",\"question\":{\"assertions\":[{\"assertionType\":\"regex\",\"expectedString\":\"(.*)world cup(.*)\"}],\"questionVariations\":[{\"questionList\":[\"when is the next world cup\"]}]}}";
TestClass sc=mapper.readValue(jsonString,TestClass.class);
// to update environment
sc.setEnvironment("new Environment");
System.out.println(sc);
//to update assertionType
Question que=sc.getQuestion();
List assertions=que.getAssertions();
for (int i = 0; i < assertions.size(); i++) {
Assertion ass= (Assertion) assertions.get(i);
ass.setAssertionType("New Type");
}
Related
I want to convert XML to JSON using either Java or Scala. Below is the working code, but here I am not able to see any identifier for XML attributes in Json to differentiate it with elements.
I need help to get XML attributes with identifier(#) in Json output.
Input XML :
<Test>
<AttrTest Code="199" Pro="Intel" Version="9.106">
<Info>FD2F</Info>
</AttrTest>
</Test>
Code :
import org.json.XML
def xmlToJson(xml: String) = {
var PRETTY_PRINT_INDENT_FACTOR = 4
try {
val xmlJSONObj = XML.toJSONObject(xml)
val jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR)
jsonPrettyPrintString
} catch {
case ex: Exception =>
println(ex.toString)
}
}
val xmlStr = "<Test>\n\t\t<AttrTest Code=\"199\" Pro=\"Intel\" Version=\"9.106\">\n\t\t<Info>FD2F</Info>\n</AttrTest>\n</Test>\n\t"
println(xmlToJson(xmlStr))
Output :
{"Test": {"AttrTest": {
"Version": 9.106,
"Pro": "Intel",
"Info": "FD2F",
"Code": 199
}}}
Expected Output :
{"Test": {"AttrTest": {
"#Version": 9.106,
"#Pro": "Intel",
"Info": "FD2F",
"#Code": 199
}}}
Please help.
I am afraid it is not possible with the library you are using. Here's from their docs:
Some information may be lost in this transformation because JSON is a data format and XML is a document format. XML uses elements, attributes, and content text, while JSON uses unordered collections of name/value pairs and arrays of values. JSON does not does not like to distinguish between elements and attributes.
You may try looking into other XML->JSON libraries or implement a pre-conversion step that would, say, append a "#" prefix to each node's attribute.
I have a malformed json array string which I get from an API call as follows:
[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Processed successfully\"}]\"}]
There is a double quote before open square bracket in the value of Response Msg property.
Is there a way to convert this into Java object ?
What I have tried so far:
I have used Jackson to parse it as follows but it gives error
ObjectMapper mapper = new ObjectMapper();
mapper.setPropertyNamingStrategy(new ResponseNameStrategy());
Response[] response = mapper.readValue(strOutput1, Response[].class);
Error: Can not deserialize instance of java.util.ArrayList out of VALUE_STRING token
I have also tried using Gson to parse it but it also gives error
Gson gson = new GsonBuilder()
.setFieldNamingPolicy(FieldNamingPolicy.UPPER_CAMEL_CASE)
.create();
Response[] response = gson.fromJson(strOutput1, Response[].class);
Error: Expected BEGIN_ARRAY but was STRING at line 1 column 35 path $[0].ResponseMsg
I have gone through the following links on StackOverflow but none of them has addressed my issue:
How to Convert String Array JSON in a Java Object
Convert a JSON string to object in Java ME?
JSON Array to Java objects
Convert json String to array of Objects
converting 'malformed' java json object to javascript
I think the answer is in the comments, you appear to be trying to solve the issue on the wrong place.
You are receiving json which you wish to parse into java objects, unfortunately the json is malformed so will not parse.
As a general rule you should never be trying to solve the symptom, but should look for the root cause and fix that, it may sound trivial but fixing symptoms leads to messy, unpredictable, and unmaintainable systems.
So the answer is fix the json where it is being broken. If this is something or of your control, while you wait for the fix, you could put a hack in to fix the json before you parse it.
This way you won't compromise your parsing, and only have a small piece of string replacement to remove when the third party has fixed the issue. But do not go live with the hack, it should only be used during development.
As i mentioned in the comment, you should prepare your service response in order to parse it.
I implemented an example:
public class JsonTest {
public static void main(String args[]) throws JsonProcessingException, IOException{
String rawJson =
"[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Processed successfully\"}]\"}]";
String goodJson = "{"+rawJson.split("[{{.}]")[2]+"}";
ObjectMapper mapper = new ObjectMapper();
final ObjectNode node = mapper.readValue(goodJson, ObjectNode.class);
System.out.println("Pretty Print: " + mapper.writerWithDefaultPrettyPrinter().writeValueAsString(node));
System.out.println("Just code: " + node.get("Code"));
}
}
Which returns:
This is how I finally solved my issue:
String inputJsonStr = "[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Claim has been added successfully.\"}"
+ "]\"}]";
int indexOfRes = inputJsonStr.indexOf("ResponseMsg");
if(inputJsonStr.substring(indexOfRes+13,indexOfRes+14).equals("\""))
{
inputJsonStr = inputJsonStr.substring(0,indexOfRes+13) + inputJsonStr.substring(indexOfRes+14);
}
int indexOfFirstClosingSquare = inputJsonStr.indexOf("]");
if(inputJsonStr.substring(indexOfFirstClosingSquare+1, indexOfFirstClosingSquare+2).equals("\"")) {
inputJsonStr = inputJsonStr.substring(0, indexOfFirstClosingSquare+1)+inputJsonStr.substring(indexOfFirstClosingSquare+2);
}
Now inputJsonStr contains a valid json array which can be parsed into Java custom object array easily with gson as given in this SO link:
Convert json String to array of Objects
I have JSON as a string and a JSONPath as a string. I'd like to query the JSON with the JSON path, getting the resulting JSON as a string.
I gather that Jayway's json-path is the standard. The online API, however, doesn't have have much relation to the actual library you get from Maven. GrepCode's version roughly matches up though.
It seems like I ought to be able to do:
String originalJson; //these are initialized to actual data
String jsonPath;
String queriedJson = JsonPath.<String>read(originalJson, jsonPath);
The problem is that read returns whatever it feels most appropriate based on what the JSONPath actually finds (e.g. a List<Object>, String, double, etc.), thus my code throws an exception for certain queries. It seems pretty reasonable to assume that there'd be some way to query JSON and get JSON back; any suggestions?
Java JsonPath API found at jayway JsonPath might have changed a little since all the above answers/comments. Documentation too. Just follow the above link and read that README.md, it contains some very clear usage documentation IMO.
Basically, as of current latest version 2.2.0 of the library, there are a few different ways of achieving what's been requested here, such as:
Pattern:
--------
String json = "{...your JSON here...}";
String jsonPathExpression = "$...your jsonPath expression here...";
J requestedClass = JsonPath.parse(json).read(jsonPathExpression, YouRequestedClass.class);
Example:
--------
// For better readability: {"store": { "books": [ {"author": "Stephen King", "title": "IT"}, {"author": "Agatha Christie", "title": "The ABC Murders"} ] } }
String json = "{\"store\": { \"books\": [ {\"author\": \"Stephen King\", \"title\": \"IT\"}, {\"author\": \"Agatha Christie\", \"title\": \"The ABC Murders\"} ] } }";
String jsonPathExpression = "$.store.books[?(#.title=='IT')]";
JsonNode jsonNode = JsonPath.parse(json).read(jsonPathExpression, JsonNode.class);
And for reference, calling 'JsonPath.parse(..)' will return an object of class 'JsonContent' implementing some interfaces such as 'ReadContext', which contains several different 'read(..)' operations, such as the one demonstrated above:
/**
* Reads the given path from this context
*
* #param path path to apply
* #param type expected return type (will try to map)
* #param <T>
* #return result
*/
<T> T read(JsonPath path, Class<T> type);
Hope this help anyone.
There definitely exists a way to query Json and get Json back using JsonPath.
See example below:
String jsonString = "{\"delivery_codes\": [{\"postal_code\": {\"district\": \"Ghaziabad\", \"pin\": 201001, \"pre_paid\": \"Y\", \"cash\": \"Y\", \"pickup\": \"Y\", \"repl\": \"N\", \"cod\": \"Y\", \"is_oda\": \"N\", \"sort_code\": \"GB\", \"state_code\": \"UP\"}}]}";
String jsonExp = "$.delivery_codes";
JsonNode pincodes = JsonPath.read(jsonExp, jsonString, JsonNode.class);
System.out.println("pincodesJson : "+pincodes);
The output of the above will be inner Json.
[{"postal_code":{"district":"Ghaziabad","pin":201001,"pre_paid":"Y","cash":"Y","pickup":"Y","repl":"N","cod":"Y","is_oda":"N","sort_code":"GB","state_code":"UP"}}]
Now each individual name/value pairs can be parsed by iterating the List (JsonNode) we got above.
for(int i = 0; i< pincodes.size();i++){
JsonNode node = pincodes.get(i);
String pin = JsonPath.read("$.postal_code.pin", node, String.class);
String district = JsonPath.read("$.postal_code.district", node, String.class);
System.out.println("pin :: " + pin + " district :: " + district );
}
The output will be:
pin :: 201001 district :: Ghaziabad
Depending upon the Json you are trying to parse, you can decide whether to fetch a List or just a single String/Long value.
Hope it helps in solving your problem.
For those of you wondering why some of these years-old answers aren't working, you can learn a lot from the test cases.
As of September 2018, here's how you can get Jackson JsonNode results:
Configuration jacksonConfig = Configuration.builder()
.mappingProvider( new JacksonMappingProvider() )
.jsonProvider( new JacksonJsonProvider() )
.build();
JsonNode node = JsonPath.using( jacksonConfig ).parse(jsonString);
//If you have a json object already no need to initiate the jsonObject
JSONObject jsonObject = new JSONObject();
String jsonString = jsonObject.toString();
String path = "$.rootObject.childObject"
//Only returning the child object
JSONObject j = JsonPath.read(jsonString, path);
//Returning the array of string type from the child object. E.g
//{"root": "child":[x, y, z]}
List<String> values = sonPath.read(jsonString, path);
Check out the jpath API. It's xpath equivalent for JSON Data. You can read data by providing the jpath which will traverse the JSON data and return the requested value.
This Java class is the implementation as well as it has example codes on how to call the APIs.
https://github.com/satyapaul/jpath/blob/master/JSONDataReader.java
Readme -
https://github.com/satyapaul/jpath/blob/master/README.md
I am storing a json string into a text field in mysql.
After the insertion, i want to update my json string and add the mysql line id into it with jackson json.
I have a java String which is in Json format
{
"thing":"val"
}
I'm looking to add another K/V without writing lines of codes.
to finally have this :
{
"thing":"val"
"mysqlId":10
}
I can convert my String to a JsonNode :
ObjectMapper mapper = new ObjectMapper();
JsonNode json = mapper.readTree( jsonStr);
Looking to do something like this
json.put("mysqlId",10);
json.toString();
then update in my text field with new json string in mysql
I can't make it.
I don't want use many class is there a simple way to do so with jackson?
Try casting your JsonNode to an com.fasterxml.jackson.databind.node.ObjectNode and then calling put set (or replace) on it.
I'm using XStream and JETTISON's Stax JSON serializer to send/receive messages to/from JSON javascripts clients and Java web applications.
I want to be able to create a list of objects to send to the server and be properly marshalled into Java but the format that XStream and JSON expect it in is very non-intuitive and requires our javascript libraries to jump through hoops.
[EDIT Update issues using GSON library]
I attempted to use the GSON library but it cannot deserialize concrete objects when I only have it expect generic super classes (XStream and Jettison handles this because type information is baked into the serialization).
GSON FAQ states Collection Limitation:
Collections Limitations
Can serialize collection of arbitrary objects but can not deserialize from it
Because there is no way for the user to indicate the type of the resulting object
While deserializing, Collection must be of a specific generic type
Maybe I'm using bad java practices but how would I go about building a JSON to Java messaging framework that sent/received various concrete Message objects in JSON format?
For example this fails:
public static void main(String[] args) {
Gson gson = new Gson();
MockMessage mock1 = new MockMessage();
MockMessage mock2 = new MockMessage();
MockMessageOther mock3 = new MockMessageOther();
List<MockMessage> messages = new ArrayList<MockMessage>();
messages.add(mock1);
messages.add(mock2);
messages.add(mock3);
String jsonString = gson.toJson(messages);
//JSON list format is non-intuitive single element array with class name fields
System.out.println(jsonString);
List gsonJSONUnmarshalledMessages = (List)gson.fromJson(jsonString, List.class);
//This will print 3 messages unmarshalled
System.out.println("XStream format JSON Number of messages unmarshalled: " + gsonJSONUnmarshalledMessages.size());
}
[{"val":1},{"val":1},{"otherVal":1,"val":1}]
Exception in thread "main" com.google.gson.JsonParseException: The JsonDeserializer com.google.gson.DefaultTypeAdapters$CollectionTypeAdapter#638bd7f1 failed to deserialized json object [{"val":1},{"val":1},{"otherVal":1,"val":1}] given the type interface java.util.List
Here's an example, I want to send a list of 3 Message objects, 2 are of the same type and the 3rd is a different type.
import java.util.ArrayList;
import java.util.List;
import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.io.json.JettisonMappedXmlDriver;
class MockMessage {
int val = 1;
}
class MockMessageOther {
int otherVal = 1;
}
public class TestJSONXStream {
public static void main(String[] args) {
JettisonMappedXmlDriver xmlDriver = new JettisonMappedXmlDriver();
XStream xstream = new XStream(xmlDriver);
MockMessage mock1 = new MockMessage();
MockMessage mock2 = new MockMessage();
MockMessageOther mock3 = new MockMessageOther();
List messages = new ArrayList();
messages.add(mock1);
messages.add(mock2);
messages.add(mock3);
String jsonString = xstream.toXML(messages);
//JSON list format is non-intuitive single element array with class name fields
System.out.println(jsonString);
List xstreamJSONUnmarshalledMessages = (List)xstream.fromXML(jsonString);
//This will print 3 messages unmarshalled
System.out.println("XStream format JSON Number of messages unmarshalled: " + xstreamJSONUnmarshalledMessages.size());
//Attempt to deserialize a reasonable looking JSON string
String jsonTest =
"{"+
"\"list\" : ["+
"{"+
"\"MockMessage\" : {"+
"\"val\" : 1"+
"}"+
"}, {"+
"\"MockMessage\" : {"+
"\"val\" : 1"+
"}"+
"}, {"+
"\"MockMessageOther\" : {"+
"\"otherVal\" : 1"+
"}"+
"} ]"+
"};";
List unmarshalledMessages = (List)xstream.fromXML(jsonTest);
//We expect 3 messages but XStream only deserializes one
System.out.println("Normal format JSON Number of messages unmarshalled: " + unmarshalledMessages.size());
}
}
Intuitively I expect the XStream JSON to be serialized (and able to deserialize correctly) from the following format:
{
"list" : [
{
"MockMessage" : {
"val" : 1
}
}, {
"MockMessage" : {
"val" : 1
}
}, {
"MockMessageOther" : {
"otherVal" : 1
}
} ]
}
Instead XStream creates a single element list with fields that are named the classnames and nested arrays of Objects of the same type.
{
"list" : [ {
"MockMessage" : [ {
"val" : 1
}, {
"val" : 1
} ],
"MockMessageOther" : {
"otherVal" : 1
}
} ]
}
The trouble may be caused by it using the XStream XML CollectionConverter?
Does anyone have a suggestion for a good JSON Java object serialization that allows you to read/write arbitrary Java objects. I looked at the Jackson Java JSON Processor but when you were reading in objects from a stream you had to specify what type of object it was unlike XStream where it will read in any object (because the serialized XStream JSON contains class name information).
I agree with other poster in that XStream is not a good fit -- it's an OXM (Object/Xml Mapper), and JSON is handled as a secondary output format using XML processing path. This is why a "convention" (of how to convert hierarchich xml model into object-graph model of json and vice versa) is needed; and your choice boils down to using whatever is least intrusive of sub-optimal choices.
That works ok if XML is your primary data format, and you just need some rudimentary JSON(-like) support.
To get good JSON-support, I would consider using a JSON processing library that does real OJM mapping (I assume Svenson does too, but additionally), such as:
Jackson
Google-gson
Also: even if you do need to support both XML and JSON, you are IMO better off using separate libraries for these tasks -- objects (beans) to use on server-side need not be different, just serialization libs that convert to/from xml and json.
I realize this is off-topic, but I'd like to present a solution in svenson JSON.
Do you really need public fields in your domain classes? Apart from having to use properties, svenson can handle cases like this with a more simple JSON output with a discriminator property
class Message
{
// .. your properties with getters and setters ..
// special property "type" acts a signal for conversion
}
class MessageOther
{
...
}
List list = new ArrayList();
list.add(new Message());
list.add(new MessageOther());
list.add(new Message());
String jsonDataSet = JSON.defaultJSON().forValue(list);
would output JSON like
[
{"type":"message", ... },
{"type":"message_other", ... },
{"type":"message", ... }
]
which could be parsed again with code like this
// configure reusable parse instance
JSONParser parser = new JSONParser();
// type mapper to map to your types
PropertyValueBasedTypeMapper mapper = new PropertyValueBasedTypeMapper();
mapper.setParsePathInfo("[]");
mapper.addFieldValueMapping("message", Message.class);
mapper.addFieldValueMapping("message_other", MessageOther.class);
parser.setTypeMapper(mapper);
List list = parser.parse(List.class, jsonDataset);
A svenson type mapper based on the full class name would look something like this
public class ClassNameBasedTypeMapper extends PropertyValueBasedTypeMapper
{
protected Class getTypeHintFromTypeProperty(String value) throws IllegalStateException
{
try
{
return Class.forName(value);
}
catch (ClassNotFoundException e)
{
throw new IllegalStateException(value + " is no valid class", e);
}
}
}
which is not an ideal implementation as it inherits the configuration of PropertyValueBasedTypeMapper without really needing. (should include a cleaner version in svenson)
The setup is very much like above
JSONParser parser = new JSONParser();
ClassNameBasedTypeMapper mapper = new ClassNameBasedTypeMapper();
mapper.setParsePathInfo("[]");
parser.setTypeMapper(mapper);
List foos = parser
.parse( List.class, "[{\"type\":\"package.Foo\"},{\"type\":\"package.Bar\"}]");