I am trying to send a message from the server to the client using the following method:
final public void sendToClient(Object msg) throws IOException
{
if (clientSocket == null || output == null)
throw new SocketException("socket does not exist");
output.writeObject(msg);
this.output.flush();
}
and before the
output.writeObject;
everything seems fine, but right after, the socket along with the input/output streams all become null..
Any idea why?
Edit:
Here is a link to all server-client parts of the code-
https://drive.google.com/open?id=0B02W0JiTbQUXS1RCVk9ORER3YUU
And when I wrote that the variables become null, what I mean is that there is no exception thrown (tried surrounding it with try-catch) and when I debug, it just changes after said specific line..
Some ideas:
somewhere else in your program the fields are being set to null;
the fields are not becoming null, another set of fields, that were not initialized, is being checked/causing the problem (e.g. from wrong instance); or
the java virtual machine is broken or something else very strange is going on.
the msg object, which we don't known what it is, is messing up the socket in its writeObject method
Anyway the posted code doesn't seem to be the cause for the fields becoming null, hard to make better guesses without a Minimal, Complete, and Verifiable example.
Related
void appendFile() throws IOException{
FileWriter print = new FileWriter(f, true);
String info = GetData.getWord("Write desired info to File");
print.append(" "); //Write Data
print.append(info);
System.out.println("this executes");
print.flush();
print.close();
}
boolean fileExist(){
return f.exists();
}
try{
if (f.fileExist())
f.appendFile();
else {
throw new IOException();
}
}
catch(IOException e) {
e.printStackTrace();
}
I'm not sure if the ecxeption is well handeled? The FileWriter is not going to be created if there is a fileNotFoundException, therefore don't need to be closed. However, is it possible that this code throws another kind of IOException after the file was opened?, and in that case do I need a finally block to close the file.
No.
It doesn't safely close the resource
The general rule is, if you call a constructor of an object that represents a closable resource, or a method that returns one which documents that this counts as 'opening the resource', which often but not always includes new being part of the method name (examples: socket.getInputStream(), Files.newInputStream), then you are responsible for closing it.
The problem is, what if an exception occurs? So, you have to use try/finally, except that's a mouthful, so there's a convenient syntax for this.
The appendFile method should use it; it isn't, that makes it bad code. This is correct:
try (FileWriter print = new FileWriter(f, true)) {
String info = GetData.getWord("Write desired info to File");
print.append(" "); //Write Data
print.append(info);
System.out.println("this executes");
}
Not how it is not neccessary to flush before close (close implies flush), and in this case, not neccessary to close() - the try construct does it for you. It also does it for you if you get out of the {} of the try via a return statement, via control flow (break), or via an exception, or just by running to the } and exiting normally. No matter how - the resource is closed. As it should be.
It throws description-less exceptions
else throw new IOException(); is no good; add a description that explains why the exception happened. throw new IOException("File not found") is better, but throw new FileNotFoundException(f.toString()) is even better: The message should convey useful information and nothing more than that (in other words, throw new IOException("Something went wrong") is horrible, don't do that, that message adds no useful information), should not end in punctuation (throw new IOException("File not found!") is bad), and should throw a type that is most appropriate (if the file isn't there, FileNotFoundException, which is a subtype of IOException, is more appropriate, obviously).
It commits the capital offense
You should not ever write a catch block whose contents are just e.printStackTrace();. This is always wrong.
Here's what you do with a checked exception:
First, think of what the exception means and whether the nature of your method inherently implies that this exception can occur (vs. that it is an implementation detail). In this case, you didn't show us what the method containing that try/catch stuff even does. But let's say it is called appendFile, obviously a method that includes the text 'file' does I/O, and therefore, that method should be declared with throws IOException. It's not an implementation detail that a method named appendFile interacts with files. It is its nature.
This is somewhat in the eye of the beholder. Imagine a method named saveGame. That's less clear; perhaps the mechanism to save may involve a database instead, in which case SQLException would be normal. That's an example of a method where 'it interacts with the file system' is an implementation detail.
The problem that the exception signals is logical, but needs to be more abstract.
See the above: A save file system can obviously fail to save, but the exact nature of the error is abstract: If the save file system is DB-based, errors would show up in the form of an SQLException; if a file system, IOException, etcetera. However, the idea that saving may fail, and that the code that tried to save has a reasonable chance that it can somewhat recover from this, is obvious. If it's a game, there's a user interface; you should most absolutely TELL the player that saving failed, instead of shunting some stack trace into sysout which they probably never even look at! Telling the user that something failed is one way of handling things, not always the best, but here it applies).
In such cases, make your own exception type and throw that, using the wrapper constructor:
public class SaveException extends Exception {
public SaveException(Throwable cause) {
super(cause);
}
}
// and to use:
public void save() throws SaveException {
try {
try (OutputStream out = Files.newOutputStream(savePath)) {
game.saveTo(out);
}
} catch (IOException e) {
throw new SaveException(e);
}
}
If neither applies, then perhaps the exception is either essentially not handleable or not expectable or nearly always a bug. For example, writing to an outputstream that you know is a ByteArrayOutputStream (which can't throw), trying to load the UTF-8 charset (which is guaranteed by the JVM spec and therefore cannot possibly throw NoSuchCharsetException) - those are not expectable. Something like Pattern.compile("Some-regexp-here") can fail (not all strings are valid regexps), but as the vast majority of regexes in java are literals written by a programmer, any error in them is therefore neccessarily a bug. Those, too, are properly done as RuntimeExceptions (which are exceptions you don't have to catch or list in your throws line). Not handleables are mostly an application logic level thing. All fair game for runtimeexceptions. Make your own or use something that applies:
public void save(int saveSlot) {
if (saveSlot < 1 || saveSlot > 9) throw new IllegalArgumentException("Choose a saveslot from 1 to 9");
// ... rest of code.
}
This really feels like door number one: Whatever method this is in probably needs to be declared as throws IOException and do no catching or trying at all.
Minor nit: Uses old API
There's new API for file stuff in the java.nio.file package. It's 'better', in that the old API does a bunch of bad things, such as returning failure by way of a boolean flag instead of doing it right (by throwing an exception), and the new API has far more support for various bits and bobs of what file systems do, such as support for file links and creation timestamps.
This question already has answers here:
What is object serialization?
(15 answers)
Closed 2 years ago.
I'm trying to make a Client/Server chat application using java. I'm pretty new to using sockets to communicate between applications. I've decided to use ObjectInput/ObjectOutput streams to send objects between the client and server.
I'm trying to send user data to the server when the client connects to the socket. Here is the code.
Server:
private void startServer() {
try {
this.server = new ServerSocket(port);
this.socket = server.accept();
ChatUtils.log("Accepted a new connection!");
this.output = new ObjectOutputStream(socket.getOutputStream());
this.input = new ObjectInputStream(socket.getInputStream());
try {
User user = (User) input.readObject();
ChatUtils.log(user.getDisplayName() + " (" + user.getUsername() + ") has connected!");
} catch (ClassNotFoundException e) {
}
} catch (IOException e) {
e.printStackTrace();
}
}
Client:
public void connectToServer(int port) {
try {
server = new Socket("127.0.0.1", port);
this.port = port;
this.objectOutput = new ObjectOutputStream(server.getOutputStream());
System.out.println("Connected to a server on port " + port + "!");
objectOutput.writeObject(user);
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
Everything works fine, but I'm looking for some clarification as to how the methods ObjectOutputStream#writeObject() and ObjectInputStream#readObject() work.
When I write the line User user = (User) input.readObject();, it reads the object as a User object. Would this only attempt to convert "User" objects that are send from the client's ObjectOutputStream?
As this method is only called once, can I cast the input stream to other objects if I send those objects to the server from the output stream? Ex: String message = (String) input.readObject();.
What would happen if I sent multiple objects to the server from the output stream at once?
4)In example one, I try to read the "user" object. What happens if there are two or more objects waiting to be read? How do I determine which object is which? Ex:
// Client
public void connectToServer() {
String message = "Hello server!"
User user = new User("John Doe", "jdoe123");
output.writeObject(user);
output.writeObject(message);
}
If someone could answer these questions, that'd be great. Thanks so much!
Every time you call .writeObject, java will take the object you specified and will serialize it.
This process is a hacky, not-recommended strategy.
Java will first attempt to break down the object you passed into its constituent parts. It will do this, hopefully, with some assistance from the class definition (the class that the object is, i.e. the one returned by theObjectWritten.getClass(). any class def that implements Serializable claims to be designed for this and gets some additional help, but the mechanism will try with reflection hacks if you don't.
Then, the constituent parts are sent along the wire (that is, take the object, and any fields that are primitives can just be sent; ObjectOutputStream knows how to send an int intrinsically, for example. Any other types are sent by, in turn, asking THAT object's class to do so). For each object, java also sends the so called 'serial version uid', which is a calculated number and changes any time any so-called signature changes anywhere in the class. It's a combination of the class's package, name, which class it extends, which interfaces it implements, and every name and type of every field (and possibly every name, return type, param types, and exception types thrown for every method).
So, now we have a bundle, consisting of:
The name of the class (e.g. com.foo.elliott.User)
The serialversionUID of the class
the actual data in User. If User contained any non-primitive fields, apply this process recursively.
Then this is all sent across the wire.
Then on receipt, the receiving code will take all that and pack it back into a User object. This will fail, unless the receiving end actually has com.foo.elliott.User on the classpath, and that def has the same serial version UID.
In other words, if you ever update this class, the transport fails unless the 'other side' also updates.
You can manually massage this stuff by explicitly declaring the serialVersionUID, but note that e.g. any created fields just end up being blank, even if the constructor ordinarily would ensure they could never be.
You can also fully manually manage all this by overriding some specific 'voodoo' methods (a method with a specific name. Java is ordinarily not structurally typed, but these relics of 25 years in the past, such as psv main and these methods, are the only structurally typed things in all of java).
In addition, the binary format of this data is more or less 'closed', it is not obvious, not easy to decode, and few libraries exist.
So, the upshot is:
It is a finicky, error ridden process.
Updating anything you serialize is a pain in the behind.
You stand no chance of ever reading this wire protocol with any programming language except java.
The format is neither easy to read, nor easy to work with, nor particularly compact.
This leads to the inevitable conclusion: Don't use ObjectOutputStream.
Instead, use other serialization frameworks that weren't designed 25 years ago, such as JSON or XML marshallers like google's GSON or Jackson.
NB: In addition your code is broken. Whenever you make a resource, you must also close it, and as code may exit before you get there, the only solution is a special construct. This is how to do it:
try (OutputStream out = socket.getOutputStream()) { .. do stuff here .. }
note that no matter how code 'escapes' from the braces, be it normally (run to the end of it), or because you return/break/continue out of it, or an exception is thrown, the resource is closed.
This also means assigning resources (anything that implements AutoClosable, like Socket, InputStream, and OutputStream, does so) to fields is broken, unless you make the class itself an AutoClosable, and whomever makes it, does so in one of these try-with blocks.
Finally, don't catch exceptions unless you can actually handle them, and 'printStackTrace' doesn't count. If you have no idea how to handle it, throw it onwards; declare your methods to 'throws IOException'. main can (and should!) generally be declared as throws Exception. If truly you can't, the 'stand in', forget-about-it correct way to handle this, and update your IDE to generate this instead of the rather problematic e.printStackTrace(), is this:
catch (ThingICantHandleException e) {
throw new RuntimeException("unhandled", e);
}
Not doing so means your code continues whilst the process is in an error state, and you don't want that.
This question already has an answer here:
EOFexception in Java when reading objectinputstream
(1 answer)
Closed 2 years ago.
I basically have a similar problem as stated here: EOFexception in Java when reading objectinputstream, but I don't find an answer with clean code.
The answer states that the ObjectInputStream#readObject will throw the exception when the reader reachs the End Of File. After looking in the web for a solution, I haven't found a solution. Could be a good and clean solution for this case?
Note: I have tried this (but it looks ugly and is not clean code). I'm looking for a better solution:
ObjectInputStream ois = new ObjectInputStream(new FileInputStream(file));
try {
Object o;
while ((o = ois.readObject()) != null) {
if (o instanceof MyClass) {
MyClass m = (MyClass)o;
//use the object...
}
}
} catch (EOFException eofex) {
//do nothing
} catch (IOException ioex) {
throw ioex;
//I have another try/catch block outside to control the life of the ObjectInputStream
}
//later in the code...
ois.close();
That's what's supposed to happen. Your code is wrong. Check the Javadoc. readObject() only returns null if you wrote a null. It doesn't say anything about returning a null at EOF. Looping until readObject() returns null will only stop if you ever wrote a null via writeObject(), and if you didn't you will get an EOFException.
#EJP's answer has nailed it.
However if you are a paid-up member of the "exceptions should't be used for normal flow control" club* then you can avoid having to catch the exception if you can use some other means to determine when to stop; for example
You could start the stream with a count sent as an int or an Integer object.
You could mark the end the stream by sending a null.
You could mark the end the stream by sending a special object that means "this is the end". It does not need to be a MyClass instance.
You could send a List<MyClass> ... though that means that you can't "stream" the objects.
Note that this implies that you are able to change the sender-side code ...
* Membership of this club requires either the ability to assimilate circular arguments, or willingness to blindly accept dogma as truth. :-)
Rather than repeat the arguments ad nauseam, here are some links to some of my answers related to the "normal flow control" debate:
Cost of compound if/or versus try/catch in Java 6
What is an alternative to exceptions for flow control?
Regex or Exception Handling?
Check if a file exists before calling openFileInput
Which is faster, try catch or if-else in java (WRT performance)
If you read through them, you will see that I don't come down firmly on either side of the fence. Rather, my view is that you should understand the trade-offs, and make a decision about whether exceptions are appropriate or not on a case-by-case basis.
You could try this:
boolean check=true;
while (check) {
try{
System.out.println(ois.readObject());
} catch(EOFException ex){
check=false;
}
}
I encountered this error because I had forgot to close an ObjectOutputStream in the code that wrote the data. Once I wrote the data again with code that closed the output stream the data was able to be read in fine.
While readObject() doesn't return NULL when it hits the end of a file, if you control the file from it's inception you could always add NULL right before closing your output stream. It will get passed as an object, but you can then test for end of file as such:
Boolean complete = false;
ObjectInputStream in = <...>
while(complete != true) {
Object test = (Object)in.readObject();
if(test != null) { someArrayList.add(test); }
else { complete = true; }
}
Is the use of NullPointerException recommended in this case:
/**
* Drop the database referenced by the singleton.
*
* #throws NullPointerException
*/
public static void dropDatabase() throws NullPointerException {
if (store != null) {
store.dropDatabase(DATABASE);
} else {
throw new NullPointerException("No valid database connection.");
}
}
Well it's pretty pointless code in that you'd still get a NullPointerException if it unconditionally called store.dropDatabase. You wouldn't get the same message, but the stack trace would make it pretty clear.
In this case I would say it should be an IllegalStateException though:
Signals that a method has been invoked at an illegal or inappropriate time. In other words, the Java environment or Java application is not in an appropriate state for the requested operation.
Sounds exactly like the situation to me. I'd also do the check first, like this:
if (store == null)
{
throw new IllegalStateException("No valid database connection.");
}
store.dropDatabase(DATABASE);
That way you can get all the preconditions out of the way at the start of the method, and then focus on the main body.
With Guava, I'd just change this to:
Preconditions.checkState(store != null, "No valid database connection.");
store.dropDatabase(DATABASE);
It's OK. Ideally, you should not be needing to write if ... else, the dropDatabase method, if using store in any useful way, will throw NPE automatically.
I'm getting a NullPointerException in a Nokia S40.
I want to know what is causing this exception.
The device shows:
NullPointerException java/lang/NullPointerException
This error only occurs in the device, running in the emulator the application works fine.
I use microlog to debug my application. But the application works fine if the log is enabled.
Is there a way to get the stack trace when I get this NullPointerException? I don't need all details like the line number just which method cause this exception.
UPDATE: I installed the same application in another Nokia S40 and the same error didn't occur.
Nokia 2660 - error
Nokia 6131 - no error
UPDATE 2: Somehow I find what was causing the NullPointerException.
import javax.microedition.lcdui.Canvas;
import javax.microedition.lcdui.Graphics;
public class OuterClass extends Canvas {
private Config config;
public OuterClass() {
this.config = new Config();
}
public void paint(Graphics graphics) {
HelperClass helper = new HelperClass(this.config);
helper.doStuff();
}
public void dispose() {
this.config = null;
}
public class Config implements IConfig {
public int getSomething() {
// ...
}
}
}
public class HelperClass {
private IConfig config;
public HelperClass(IConfig) {
this.config = config;
}
public doStuff() {
config.getSomething(); // Here is thrown NullPointerException
}
}
In some situations a thread is started and call the OuterClass.dispose() before the helper.doStuff() causing the NPE. I think when I enabled the log it made the thread slower and helper.doStuff() was called when I expected it to be called.
You are not going to find any way to save a Throwable stack trace on a Nokia Series40 handset.
The usual brute force way of debugging JavaME application on Series40 is to modify your code to create a stack trace yourself in memory.
What I'm talking about is:
Each Thread that you can identify (including system callback threads) needs its own Stack object, containing strings. Obviously, this increases the memory footprint of your application somewhat but keeping it in memory should limit the impact on race conditions.
When your code enters a method, it adds the method signature to the current Thread Stack. When the method exits (and you better only have one exit point per method) it pops the top of the Stack.
You can add aditional debug info on the stack, like values of variables in different places of the code.
You don't necessarily need to add this to every single method in your code.
You can add try{}catch(Throwable){} to the entry point of every thread you identified and either dump the stack in a file or on the screen (in a Form).
Obviously, this is not the kind of change you want to manually add in a lot of places in a large existing codebase. You can however make it part of your organisation coding standards for the future and write a source code parsing script to automatically add it to existing code.
I had some trouble in the past trying to print the stack trace to somewhere else than the standard output. The standard exception class doesn't provide the printStackTrace method that receives the output stream, therefore it only prints to the standard output stream.
It's possible, at least in Java SE, to redirect the java output stream to somewhere else by simply saying that System.out = . The PrintStream class receives an OutputStream, which means that you could create your own ByteArrayOutputStream, initialize a PrintStream, sets System.out to that stream, and then call ex.printStackTrace(). I don't have a J2ME environment here but I believe that, as long as it won't break when you try to set System.out to something else (nothing says that it's readonly in the docs), you should be able to do it.
After you do that, I would recommend writing it to a RecordStore that you have specifically for that, and then upload the records of that RecordStore to your server so you can get it.
I know it's not very easy but it may work. I would first test the System.out thing. If it works, everything else should work too.
My answer was wrong. As pointed out, the System.out and System.err fields are declared final. If you can't get the stack trace, and if you can't get the error when running the application on your emulator, try creating trace bullets on your code (alerts, logs, whatever you can) to isolate the piece of code where the problem is happening. It has to be something that could change between the emulator and the real device - for example, something related to retrieving/ saving records in a RecordStore, opening a Connection, etc... What did you try to do when you had the problem?
You could use Microlog to send an e-mail when the exception occurs.
Microlog
You could try catching the exception in some high-level try/catch block and then emailing the trace to yourself.