I am very new to JAVA but I have some experience in web programming. I am creating simple jsp pages and using #RequestMapping for page views. But I am facing an exception, I have googled BUT nothing found goods which solved my problem.
Here is the exception with full stack trace :
SEVERE: Allocate exception for servlet [WebAppGraph]
java.lang.ClassNotFoundException: com.WebAppGraph.app at
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1269)
at
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1104)
at
org.apache.catalina.core.DefaultInstanceManager.loadClass(DefaultInstanceManager.java:508)
at
org.apache.catalina.core.DefaultInstanceManager.loadClassMaybePrivileged(DefaultInstanceManager.java:489)
at
org.apache.catalina.core.DefaultInstanceManager.newInstance(DefaultInstanceManager.java:119)
at
org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1041)
at
org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:770)
at
org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:133)
at
org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:96)
at
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:475)
at
org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:140)
at
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:80)
at
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:625)
at
org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:87)
at
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:342)
at
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:498)
at
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:66)
at
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:796)
at
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1372)
at
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
at
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
at
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
at
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.lang.Thread.run(Thread.java:745)
A sample of my code :
indexController.java
package com.WebAppGraph.app;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class indexController {
#RequestMapping("/")
public String home() {
return "index.jsp";
}
#RequestMapping("/test.html")
public String test() {
return "test.jsp";
}
}
Web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>WebAppGraph</servlet-name>
<servlet-class>
com.WebAppGraph.app
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>WebAppGraph</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
WebAppGraph-servlet.xml
<?xml version="1.0" encoding="UTF-8" ?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<context:component-scan base-package="com.WebAppGraph.app"></context:component-scan>
</beans>
POM.xml
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.WebAppGraph.app</groupId>
<artifactId>WebAppGraph</artifactId>
<packaging>war</packaging>
<version>1.0</version>
<name>WebAppGraph Maven Webapp</name>
<url>http://maven.apache.org</url>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<!-- https://mvnrepository.com/artifact/org.springframework/spring-webmvc -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>4.3.10.RELEASE</version>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<version>3.0.1</version>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<finalName>WebAppGraph</finalName>
</build>
</project>
File Structures:
When I try to run my program it opens the index.jsp page, BUT the second page only open when I write localhost:9000/WebAppGraph/test.jsp BUT when I write localhost:9000/WebAppGraph/test.html it doesn't show me the test.jsp and instead shows me the exception I posted above.
Any idea how to solve this ?
For your servlet mapping you can do something like this in web.xml:
<servlet>
<servlet-name>WebAppGraph</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/WebAppGraph-servlet.xml</param-value>
</init-param>
</servlet>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet-mapping>
<servlet-name>WebAppGraph</servlet-name>
<url-pattern>*.html</url-pattern>
<url-pattern>/</url-pattern>
</servlet-mapping>
You need to try a spring-mvc hello world tutorial.
Your class name is com.WebAppGraph.app.indexController not com.WebAppGraph.app and if you are going to put it in the web.xml
<Servlet> tag it needs to extend javax.servlet.Servlet. What you have is a spring bean annotated as a spring MVC controller not a Servlet. You want to put the spring MVC dispatch servlet in the XML:
<servlet>
<servlet-name>Controller</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
And then inject the Controller annotation with a context scan in your spring xml (which you are already doing)
Change the value of the servlet-class tag in web.xml file. You can change as the following (As most of us use DispatcherServlet as servlet-class):
<servlet>
<servlet-name>WebAppGraph</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
An additional thing, If you use default configuration of spring, then you need to remove .jsp from the returned string of controller function as like:
#RequestMapping("/")
public String home() {
return "index";
}
#RequestMapping("/test.html")
public String test() {
return "test";
}
Related
I am trying to build a simple webapp to apply the learnings of spring MVC, the issue occurs while configurating the dispatcher servlet.
I get this message when i click on submit button in index.jsp
HTTP Status 404 – Not Found
Type Status Report
Message The requested resource [/DemoMVC/add] is not available
Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
index.jsp
<html>
<body>
<form action="add">
<input type="text" name="t1"><br>
<input type="text" name="t2"><br>
<input type="submit"><br>
</form>
</body>
</html>
below is the web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<!-- <load-on-startup>1</load-on-startup> -->
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.first</groupId>
<artifactId>DemoMVC</artifactId>
<packaging>war</packaging>
<version>0.0.1-SNAPSHOT</version>
<name>DemoMVC Maven Webapp</name>
<url>http://maven.apache.org</url>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>3.2.3.RELEASE</version>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>8.0.24</version>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
<version>1.2</version>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<version>3.1.0</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>jcl-over-slf4j</artifactId>
<version>1.7.32</version>
</dependency>
</dependencies>
<build>
<finalName>DemoMVC</finalName>
</build>
</project>
dispatcher servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.first"/>
<mvc:default-servlet-handler/>
<!-- ... -->
</beans>
Controller
package com.first;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class AddController
{
#RequestMapping("/add")
public String add()
{
return "welcome";
}
}
First of all you would have to change the name of your dispatcher servlet to xyz-servlet.(here xyz is taken as any name you like but it should be followed by -servlet.)This will help web.xml to map your dispatcher servlet. Also your dispatcher servlet should be in WEB-INF folder.
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>xyz</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>xyz</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
Also don't forget to add suffix and prefix in your xyz-servlet.xml file
Please make the following changes:
Add method attribute in . Example for 'post'
<form action="/add" method="post">
In controller either add method type OR use specific mapping annotation:
#RequestMapping(value="/add", method=RequestMethod.POST) OR #PostMapping("/add")
First I created a constructor in controller to check if controller is working.
#Controller
public class AddController
{
public AddController() {
System.out.println("################000");
}
#RequestMapping(value="/add", method = RequestMethod.GET)
public String add()
{
System.out.println("################12");
return "welcome.jsp";
}
}
and the console was printing ################000 but did not print ################12. Hence there was an issue in request mapping.
After checking
Spring MVC request mapping not working
tried implementing <mvc:annotation-driven /> in servlet and it worked
Ok So if all the things which i told you and others told you aren't working then the problem may be that you have not set the suffix amd prefix in your project.
xyz-servlet.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.first"/>
<mvc:default-servlet-handler/>
<bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name = "prefix" value = "/webapp/jsp/"/><!--Set the path of where your have stored your view files-->
<property name = "suffix" value = ".jsp"/><!--Set the view resolver type eg. html, jsp-->
</bean>
</beans>
Now this may solve your issue!!
I'm trying to write Spring application in Spring 3.0.x (yes I want that version). Made a really simple method that returns String.
package fitnessapp;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
#Controller
public class Hello {
#RequestMapping(value = "/sayHello", method = RequestMethod.GET)
#ResponseBody
public String sayHello() {
return "hello!";
}
}
After calling http://localhost:8080/sayHello I'm getting 404 don't know why.
HTTP/1.1 404
Content-Type: text/html;charset=utf-8
Content-Language: en
Content-Length: 682
Date: Fri, 04 Dec 2020 18:44:04 GMT
Keep-Alive: timeout=20
Connection: keep-alive
<!doctype html>
<html lang="en">
<head><title>HTTP Status 404 – Not Found</title>
<style type="text/css">body {
font-family: Tahoma, Arial, sans-serif;
}
...
</head>
<body><h1>HTTP Status 404 – Not Found</h1>
<hr class="line"/>
<p><b>Type</b> Status Report</p>
<p><b>Description</b> The origin server did not find a current representation for the target resource or is not willing
to disclose that one exists.</p>
<hr class="line"/>
<h3>Apache Tomcat/8.5.60</h3></body>
</html>
I'm using Tomcat 8.5.60.
My pom.xml
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>org.example</groupId>
<artifactId>stara</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>war</packaging>
<properties>
<maven.compiler.source>1.7</maven.compiler.source>
<maven.compiler.target>1.7</maven.compiler.target>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
</dependencies>
</project>
web.xml
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<servlet-name>DispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/spring/webcontext/DispatcherServlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>DispatcherServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
DispartcherServlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="fitnessapp"/>
<mvc:annotation-driven/>
</beans>
In logs I get
04-Dec-2020 21:22:38.073 INFO [RMI TCP Connection(3)-127.0.0.1] org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons Pre-instantiating singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory#2f66c1fd: defining beans [hello,org.springframework.context.annotation.internalConfigurationAnnotationProcessor,org.springframework.context.annotation.internalAutowiredAnnotationProcessor,org.springframework.context.annotation.internalRequiredAnnotationProcessor,org.springframework.context.annotation.internalCommonAnnotationProcessor,org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0,org.springframework.format.support.FormattingConversionServiceFactoryBean#0,org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter#0,org.springframework.web.servlet.handler.MappedInterceptor#0]; root of factory hierarchy
04-Dec-2020 21:22:38.310 INFO [RMI TCP Connection(3)-127.0.0.1] org.springframework.web.servlet.handler.AbstractUrlHandlerMapping.registerHandler Mapped URL path [/sayHello] onto handler 'hello'
04-Dec-2020 21:22:38.310 INFO [RMI TCP Connection(3)-127.0.0.1] org.springframework.web.servlet.handler.AbstractUrlHandlerMapping.registerHandler Mapped URL path [/sayHello.*] onto handler 'hello'
04-Dec-2020 21:22:38.311 INFO [RMI TCP Connection(3)-127.0.0.1] org.springframework.web.servlet.handler.AbstractUrlHandlerMapping.registerHandler Mapped URL path [/sayHello/] onto handler 'hello'
Could you tell me what I'm doing wrong to make this Controller work?
Try this:
<servlet>
<servlet-name>DispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>DispatcherServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
should become:
<servlet>
<servlet-name>myServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>myServlet</servlet-name>
<url-pattern>/sayHello/*</url-pattern>
</servlet-mapping>
and rename your DispartcherServlet-context.xml properly to myServlet-servlet.xml.
Your dependency in the pom should be:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
or something like that.
I keep getting this Error 404 and I've done/looked at almost all the solutions on StackOverflow that are relevant and still haven't fixed my problem. Why am I having this error?
When I do http://localhost:8080 it gives me my index.jsp page, but when I do http://localhost:8080/index.jsp of http://localhost:8080/WebApp/index.jsp it gives me 404 error.
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">
<mvc:annotation-driven />
<context:component-scan base-package="test.app" />
<bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value = "/WEB-INF/views/"/>
<property name="suffix" value=".jsp" />
</bean>
</beans>
applicationContext.xml
index.jsp
<%--
Created by IntelliJ IDEA.
User: reaganyuan
Date: 12/31/17
Time: 12:42 PM
To change this template use File | Settings | File Templates.
--%>
<%# page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>$Title$</title>
</head>
<body>
<p>HELLO WORLD</p>
</body>
</html>
TestController.java
package test.app;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class TestController {
#RequestMapping(value="/")
public String test()
{
return "index";
}
}
pom.xml
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>test</groupId>
<artifactId>app</artifactId>
<version>1.0-SNAPSHOT</version>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>4.3.13.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>4.3.13.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-beans</artifactId>
<version>4.3.13.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>4.3.13.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>4.3.13.RELEASE</version>
</dependency>
</dependencies>
</project>
My Project structure
edit: I changed index() into test() in the controller, but that didn't do anything.
In Web.xml try changing url-pattern to /* as shown below
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
When you hit the url http://localhost:8080/ you are hitting the TestController which has a mapping for "/". It is returning a string "index" which will be resolved by the InternalResourceViewResolver.class into index.jsp.
You do not have any mapping to /index.jsp. In a servlet container you can't access the files like that directly. If you still want you can change your controller like this.
#Controller
public class TestController {
#RequestMapping(value={"/","index.jsp"})
public String test()
{
return "index";
}
}
But my advice is not to do like that. You should keep only the name without extension, like #RequestMapping(value={"/","index"})
I have the following files:
web.xml:
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>To do List</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/tk-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/spring-mvc/*</url-pattern>
</servlet-mapping>
</web-app>
LoginController:
package de.yellowsub.tk.mvc;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;
#Controller
public class LoginController {
#RequestMapping(value = "/login")
#ResponseBody
public String sayHello() {
return "Hello World!";
}
}
Now if I put in localhost:8080/login in the URL I can see "Hello World" in the Browser but not if I write localhost:8080/spring-mvc/login
Any ideas?
Also here is the tk-servlet.xml if it's any use:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/bean/spring-beans.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="de.yellowsub" /> //I also tried "de.yellowsub.*"
<mvc:annotation-driven />
</beans>
Based on your comment you have generated a Spring Boot application. That is quite different from a Spring MVC application, you do not need web.xml or tk-servlet.xml to configure it. You can delete both.
You can add server.contextPath=/spring-mvc to your application.properties (create it in src/main/resources) to set the context path.
Also please find a different tutorial, because pure Spring based MVC application is totally different from Spring Boot web application.
You NEED TO fix the root context for your web application (spring-mvc) to fix the URL
If you are using Maven, you can fix your war name by adding the below tag into the pom.xml:
<build>
<finalName>spring-mvc</finalName>
</build>
Then you should be able to access your application controller always with below url :
http://localhost:8080/spring-mvc/login
if you dont use maven follow this link How to set the context path of a web application in Tomcat 7.0
It seems that dispatcher-servlet unable to perform component scan using.
<context:component-scan base-package="abc" />
In my controller file (HelloController.java) under package abc. Code is written as follows:
#Controller
#RequestMapping("/hello")
public class HelloController {
#RequestMapping(method = RequestMethod.GET)
public String printHello(ModelMap model) {
model.addAttribute("message", "Hello Spring MVC Framework!");
return "hello"; //I have already made hello.jsp in web-inf/jsp/
}
}
My Application name is SpringMiddle. When try url as:
http://localhost:8080/SpringMiddle/hello.htm
I do have following url pattern in web.xml
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
It shows me error HTTP 404 not found.
EDIT: : it shows me warning
WARNING: No mapping found for HTTP request with URI [/SpringMiddle/hello.htm] in DispatcherServlet with name 'dispatcher'
You have to enable MVC in Spring. In xml config you can do it in such way:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<mvc:annotation-driven />
</beans>
and in JavaConfig:
#Configuration
#EnableWebMvc
public class WebConfig {
}
Please refer to Spring documentation
if you are referring to an mkyong tutorial, I didn't use the annotations: #Configuration
#EnableWebMvc, problem is you are using both annotations and xml declaration.
Annotation for setting the url:
#Controller
#RequestMapping("/hello")
you should remove this part:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
and you'll be able to visit the url:
http://localhost:8080/SpringMiddle/hello
Also make sure you have this in your web.xml:
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
the dispatcher-servlet.xml is where the component scanning is declared