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Why is System.out.println("Hello World"); O(1) and System.out.println(str); O(N)? Can somebody explain the difference?
"Hello World" is a constant so it is O(1) whereas string str is variable of length n so the complexity is O(n)
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Given a circular, integer array nums, return the next greater number for every element in nums.
Input
[9,1,2,4,3,5,8]
Output
[-1,2,3,5,4,8,9]
In other words:
9->-1
1->2
2->3
4->5
3->4
5->8
8->9
I'm very confused how to solve this problem. Please help me.
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I want to make a method return that return several times a String from a list of String. any idea ??
How about something like this:
String getRandomString(List<String> list) {
return list.get(new Random().nextInt(list.size()));
}
This isn't the most efficient way, but should do the job.
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If I have an initialized array in Java and I want to do a method to one element in that array I would do
array[n].method();
but how do I do the same thing with an arraylist?
arraylist[n].method() gives me an error.
With Java use get method with ArrayList:
arraylist.get(n).method();
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What is the best way to parse a String value that looks like this id#1 ...id#398, so I can get de number after the id# String in JAVA.
If id# is a fixed prefix in every ID, I would have used
stringValue.split("id#")[0]
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For (int i=1; i <=n;i/=2){
System.out.println(i);
}
For the time complexity about the above coding, is ot log (n)?
Thanks!
If n > 0: It's time complexity is O(∞) because the loop will never end
If n <= 0: It's time complexity is O(1)
because the loop will not be executed