static method in class have same signature as default method in interface - java

I have below scenario :
class C {
static void m1() {}
}
interface I {
default void m1() {}
}
//this will give compilation error : inherited method from C cannot hide public abstract method in I
class Main extends C implements I {
}
Below are my questions:
I am aware that instance method will override the default methods but what if static methods in class have same signature as default method in Interface?
If static method m1() in class C would be public then compilation error will be :
static method m1() conflicts with abstract method in I.
so when the access modifier was default it was trying to hide and when it is public it is conflicting. why is this difference? what is the concept behind it?

Ultimately that boils down to the fact that when you have something like this:
class Me {
public static void go() {
System.out.println("going");
}
}
These both would be allowed:
Me.go();
Me meAgain = new Me();
meAgain.go(); // with a warning here
Intersting is that this would work too for example:
Me meAgain = null;
meAgain.go();
Personally I still see this as design flaw that could not be retracted due to compatibility - but I wish the compiler would not allow me to access the static method from an instance.
Your first question is not related to java-8 per-se, it has been like this before java-8:
interface ITest {
public void go();
}
class Test implements ITest {
public static void go() { // fails to compile
}
}
default methods just follow the same rule here. Why this happens is actually detailed quite a lot on stack overflow - but the underlying idea is that potentially this would cause confusion on which method to call (imagine ITest would be a class that Test would extends and you do ITest test = new Test(); test.go(); -> which method are you calling?)
I think that for the same reasons this is not allowed also (which is basically your second question, otherwise you would have a static and non-static method with the same signatures)
static class Me {
static void go() {
}
void go() {
}
}
It's interesting that this is sort of fixed (I guess that they realized it would be really bad to do the same mistake again) in method references:
static class Mapper {
static int increment(int x) {
return x + 1;
}
int decrement(int x) {
return x - 1;
}
}
Mapper m = new Mapper();
IntStream.of(1, 2, 3).map(m::increment); // will not compile
IntStream.of(1, 2, 3).map(m::decrement); // will compile

Answering your 1st question:
Both the "static method in class" and the "default method in interface" are available to the class Main, and hence if they have the same signature, it will create ambiguity.
For example:
class C{
static void m1(){System.out.println("m1 from C");}
}
public class Main extends C{
public static void main(String[] args) {
Main main=new Main();
main.m1();
}
}
Output: m1 from C
Similarly,
interface I{
default void m1(){System.out.println("m1 from I");}
}
public class Main implements I{
public static void main(String[] args) {
Main main=new Main();
main.m1();
}
}
Output: m1 from I
As you can see, both these can be accessed similarly. So this is also the reason for conflict when you implement I and extend C.
Answering your second question:
If your classed and interfaces are in the same package, the default and public access modifier should work similarly.
Also, m1() in C is static which cannot be overridden, and hence it cannot be considered as implementation of m1() in I and so the compilation issue.
Hope that helps!

I will answer your first question since the second is already answered
I am aware that instance method will override the default methods but
what if static methods in class have same signature as default method
in Interface?
I am assuming you are using JDK 1.8 and hence the confusion. default modifier in an interface method is not talking about its access specifications. Instead it mentions that the interface itself need to implement this method. Access specification for the method is still public. Starting from JDK8 , interfaces allow you specify methods with default modifer to allow to extend interfaces in a backward compatible way.
In your interface you had to give default void m1() {} for the compilation to be successfull. Normally we simply define them in an abstract way like void m1(); in an interface You had to implement the method because you specified the method as default. Hope you understand.

Because class methods in java can also be called using instance variables, this construct will lead to ambiguities:
Main m = new Main();
m.m1();
It is unclear if the last statement should call the class method C.m1() or the instance method I.m1().

Related

Why does this.getClass give it's own class name rather than Anonymous class name?

I have created anonymous class by implementing interface I inside public static void main() method. So, by java 8 for the abstract method test(), the implementation is provided from imple() method of class C.
So, inside public static void main() method, printing _interface.getClass(), I got
package_path.Main$$Lambda$1/310656974 which is absolutely fine. Bacause it print's the anonymous class name.
Also, _interface is pointing to an anonymous object in heap and hence I'm doing _interface.test();
So, the first statement that test() method has now is to print the class name,
But eventually what it print was,
package_path.C (telling me C is the class name). How is that possible? Shouldn't package_path.Main$$Lambda$1/310656974 be printed again? Because 'this' means anonymous inside the test method right?
#java.lang.FunctionalInterface
interface I {
void test();
}
class C {
void imple() {
System.out.println(this.getClass());
System.out.println("Inside Implementation");
}
}
class Main {
public static void main(String[] args) {
I _interface = new C()::imple;
System.out.println(_interface.getClass());
_interface.test();
}
}
Hopefully, this might help you understand, that when you declare
I _interface = new C()::imple;
you've actually implemented the interface somewhat similar to (though not same as):
I _interface = new I() {
#Override
public void test() {
new C().imple(); // creating an instance of class `C` and calling its 'imple' method
}
};
Hence when the test method is called, it first creates an instance of C which prints
class x.y.z.C
as the class.
Because 'this' means anonymous inside the test method right?
Now as you can see above, there is no more anonymous class from which imple
is being called from, hence this is not representing the anonymous class anymore.
As Holger clarified in comments further, despite the representation as lambda or anonymous class at the calling site, the this.getClass() inside a method of class C will evaluate to C.class, regardless of how the caller looks like.
Recommend: Continue to read and follow on Is there any runtime benefit of using lambda expression in Java?

How interfaces create objects when using at anonymous inner classes [duplicate]

This question already has answers here:
Multiple inheritance for an anonymous class
(6 answers)
Closed 4 years ago.
It is clearly stated that interfaces don't have constructors. But when using anonymous inner classes we create an interface object and do overriding it methods. If there is no constructors in interfaces how this is possible.
For an example,
interface A{
void print();
}
class B{
public static void main(String args[]){
A a=new A(){
void print(){
System.out.println("Message");
}
};
}
}
How that A a=new A() is possible if interface is not having constructors?
The code
interface A {
void print();
}
class B {
public static void main(String[] args) {
A a = new A() {
public void print() {
System.out.println("Message");
}
};
}
}
is a shorthand for
interface A {
void print();
}
class B {
public static void main(String[] args) {
class B$1 extends java.lang.Object implements A {
B$1() {
super();
}
public void print() {
System.out.println("Message");
}
}
A a = new B$1();
}
}
With just one exception: If class B$1 is declared explicitly, it is possible to extend from it using class C extends B$1. However, it is not possible to extend from an anonymous class B$1 (JLS §8.1.4), even though it is not final (JLS §8.1.1.2).
That is, anonymous classes are still classes. As all classes (except java.lang.Object itself), even these classes extend java.lang.Object, directly or indirectly. If an anonymous class is specified using an interface, it extends java.lang.Object and implements that interface. If an anonymous class is specified using a class, it extends that class. In case the constuctor has arguments, the arguments are forwarded to super().
You can even (although definitely not recommended at all) insert a A a2 = new B$1(); later in main(), if you like. But really, don't do that, I'm just mentioning it to show what's going on under the hood.
You can observe this yourself by putting your source code in a separate directory, say, into AB.java, compile it, and then
look at the class files that were generated.
Use javap -c B$1 to see how the anonymous class was generated by javac.
Every class has a default constructor which is the no-argument constructor if you don't define another constructor. And the anonymous class implement the interface will automatically generate it unless you define another constructor.

What's the benefit (if there's any) of using interface only with static method? [duplicate]

I was learning through interfaces when I noticed that you can now define static and default methods in an interface.
public interface interfacesample2 {
public static void method() {
System.out.println("hello world");
}
public default void menthod3() {
System.out.println("default print");
}
}
Kindly explain the difference of the two and also if there's an example of when we would use this would be nice. A little confused on Interfaces.
Differences between static and default methods in Java 8:
1) Default methods can be overriden in implementing class, while static cannot.
2) Static method belongs only to Interface class, so you can only invoke static method on Interface class, not on class implementing this Interface, see:
public interface MyInterface {
default void defaultMethod(){
System.out.println("Default");
}
static void staticMethod(){
System.out.println("Static");
}
}
public class MyClass implements MyInterface {
public static void main(String[] args) {
MyClass.staticMethod(); //not valid - static method may be invoked on containing interface class only
MyInterface.staticMethod(); //valid
}
}
3) Both class and interface can have static methods with same names, and neither overrides other!
public class MyClass implements MyInterface {
public static void main(String[] args) {
//both are valid and have different behaviour
MyClass.staticMethod();
MyInterface.staticMethod();
}
static void staticMethod(){
System.out.println("another static..");
}
}
A static method is a method that applies to the class 'namespace', so to speak. So a static method foo of interface Interface is accessed by Interface.foo(). Note that the function call does not apply to any particular instance of the interface.
A default implementation bar on the other hand, is called by
Interface x = new ConcreteClass();
x.bar();
A static interface method cannot know about the this variable, but a default implementation can.
1. explain the difference of the two
Static interface methods are like static class methods(here they belong to Interface only). Where as the default interface methods provide default implementation of interface methods (which implementing classes may override)
But remember in case a class is implementing more than one interface with same default method signature then the implementing class needs to override the default method
You can find a simple example below (can DIY for different cases)
public class Test {
public static void main(String[] args) {
// Accessing the static member
I1.hello();
// Anonymous class Not overriding the default method
I1 t = new I1() {
#Override
public void test() {
System.out.println("Anonymous test");
}
};
t.test();
t.hello("uvw");
// Referring to class instance with overridden default method
I1 t1 = new Test2();
t1.test();
t1.hello("xyz");
}
}
interface I1 {
void test();
//static method
static void hello() {
System.out.println("hello from Interface I1");
}
// default need not to be implemented by implementing class
default void hello(String name) {
System.out.println("Hello " + name);
}
}
class Test2 implements I1 {
#Override
public void test() {
System.out.println("testing 1234...");
}
#Override
public void hello(String name) {
System.out.println("bonjour" + name);
}
}
2. when we would use this would be nice.
That depends on your problem statement. I would say Default methods are useful, if you need same implementation for a method in your specification in all the classes in that contract, Or it may be used like Adapter classes.
here is a good read: https://softwareengineering.stackexchange.com/questions/233053/why-were-default-and-static-methods-added-to-interfaces-in-java-8-when-we-alread
also below oracle doc explains default & static methods for evolving existing interfaces:
Users who have classes that implement interfaces enhanced with new
default or static methods do not have to modify or recompile them to
accommodate the additional methods.
http://docs.oracle.com/javase/tutorial/java/IandI/nogrow.html
Here is my view:
static method in interface:
You can call it directly (InterfacetA.staticMethod())
Sub-class will not be able to override.
Sub-class may have method with same name as staticMethod
default method in interface:
You can not call it directly.
Sub-class will be able to override it
Advantage:
static Method: You don't need to create separate class for utility method.
default Method: Provide the common functionality in default method.
This link has some useful insights, have listed few of them here.
default & static methods have bridged down the differences between interfaces and abstract classes.
Interface default methods:
It helps in avoiding utility classes, such as all the Collections class method can be provided in the interfaces itself.
It helps in extending interfaces without having the fear of breaking implementation classes.
Interface static methods:
They are part of interface, we can’t use it for implementation class objects.
It helps in providing security by not allowing implementation classes to override them.
Like to quote another useful reference.
As per Java14 JLS doc:
Default Method:
It is an instance method declared in an interface with the default
modifier
It can be accessed only by the instance of the implementing class
only
Its body is always represented by a block, which provides a default
implementation or behaviour for any implementing class without
overriding the method
It can never be static or private
Static Method:
It can be invoked by interface without reference to a particular
object, just like class static methods
Static method can be private
The implementing class can not access static method
Lets understand it with the help of below example code:
public interface MyInterface {
private void privateMethod() {
System.out.println("Hi, this is privateMethod");
}
private static void staticPrivateMethod() {
System.out.println("Hi, this is staticPrivateMethod");
}
static void staticMethod() {
//privateMethod(); // Non-static method cannot be referenced from a static contex
System.out.println("Hi, this is staticMethod");
staticPrivateMethod();
}
default void defaultMethod() {
System.out.println("Hi, this is defaultMethod");
}
}
public class MyInterfaceImpl implements MyInterface{
public static void main(String[] args) {
MyInterface.staticMethod();
// myInterface.staticMethod(); // Not allowed
MyInterface myInterface = new MyInterfaceImpl();
myInterface.defaultMethod();
// MyInterface.defaultMethod(); // Not allowed
}
}
According to Oracle's Javadocs: http://docs.oracle.com/javase/tutorial/java/IandI/defaultmethods.html
Default methods enable you to add new functionality to the interfaces of your libraries and ensure binary compatibility with code written for older versions of those interfaces.
A static method is a method that is associated with the class in which it is defined rather than with any object. Every instance of the class shares its static methods.
Normally, static method in interface is used as Helper methods while default method are used as a default implementation for classes that implements that interface.
Example:
interface IDemo {
//this method can be called directly from anywhere this interface is visible
static int convertStrToInt(String numStr) {
return Integer.parseInt(numStr);
}
//getNum will be implemented in a class
int getNum();
default String numAsStr() {
//this.getNum will call the class's implementation
return Integer.toString(this.getNum());
}
}
Interface default methods:
It helps in avoiding utility classes, such as all the Collections class method can be provided in the interfaces itself.
It helps in extending interfaces without having the fear of breaking implementation classes.
Interface static methods:
They are part of interface, we can’t use it for implementation class objects.
It helps in providing security by not allowing implementation classes to override them.
Now how static method providing security. Let's see an example.
interface MyInterface {
/*
* This is a default method so we need not to implement this method in the implementation classes
*/
default void newMethod() {
System.out.println("Newly added default method in Interface");
}
/*
* This is a static method. Static method in interface is similar to default method except that we cannot override them in the implementation classes. Similar to default methods, we need to implement these methods in implementation classes so we can safely add them to the existing interfaces.
*/
static void anotherNewMethod() {
System.out.println("Newly added static method in Interface");
}
/*
* Already existing public and abstract method We must need to implement this method in implementation classes.
*/
void existingMethod(String str);
}
public class Example implements MyInterface {
// implementing abstract method
public void existingMethod(String str) {
System.out.println("String is: " + str);
}
public void newMethod() {
System.out.println("Newly added default method in Class");
}
static void anotherNewMethod() {
System.out.println("Newly added static method in Class");
}
public static void main(String[] args) {
Example obj = new Example();
// calling the default method of class
obj.newMethod();
// calling the static method of class
obj.anotherNewMethod();
// calling the static method of interface
MyInterface.anotherNewMethod();
// calling the abstract method of interface
obj.existingMethod("Java 8 is easy to learn");
}
}
Here obj.newMethod(); printing class implementation logic, means we can change the logic of that method inside implementation class.
But obj.anotherNewMethod(); printing class implementation logic ,but not changed interface implementation. So if any encryption-decryption logic written inside that method you can't change.
we cannot execute Interfacesample2.menthod3(); because it is not static method. In order to execute method3() we need an instance of Interfacesample2 interface.
Please find the following practical example:
public class Java8Tester {
public static void main(String args[]){
// Interfacesample2.menthod3(); Cannot make a static reference to the non-static method menthod3 from the type Interfacesample2
new Interfacesample2(){ }.menthod3();// so in order to call default method we need an instance of interface
Interfacesample2.method(); // it
}
}
interface Interfacesample2 {
public static void method() {
System.out.println("hello world");
}
public default void menthod3() {
System.out.println("default print");
}
}
Starting Java 8 interface can also have static method. Like static method of a class, static method of an interface can be called using Interface name.
Example
public interface Calculator {
int add(int a, int b);
int subtract(int a, int b);
default int multiply(int a, int b) {
throw new RuntimeException("Operation not supported. Upgrade to UltimateCalculator");
}
static void display(String value) {
System.out.println(value);
}
}
Difference between static and default method of interface is default method supports inheritance but static method does not. Default method can be overridden in inheriting interface.
Here is good read about interface default method and static method. Interface Default Method in Java 8
All good answers here. I would like to add another practical usage of the static function in the interface. The tip is coming from the book - Effective Java, 3rd Edition by Joshua Bloch in Chapter2: Creating and Destroying Object.
Static functions can be used for static factory methods.
Static factory method are methods which return an object. They work like constructor. In specific cases, static factory method provides more readable code than using constructor.
Quoting from the book - Effective Java, 3rd Edition by Joshua Bloch
Prior to Java 8, interfaces couldn’t have static methods. By
convention, static factory methods for an interface named Type were
put in a noninstantiable companion class (Item 4) named Types.
Author gives an example of Collections where such static factory method is implemented. Checking on the code, Josh Bloch can be seen as first author of Collections class. Although Collections is a class and not interface. But the concept still applies.
For example, the Java Collections Framework has forty-five utility
implementations of its interfaces, providing unmodifiable collections,
synchronized collections, and the like. Nearly all of these
implementations are exported via static factory methods in one
noninstantiable class (java.util.Collections). The classes of the
returned objects are all nonpublic.
Further he explains that API is not only smaller, it helps with the code readability and API ease..
It is not just the bulk of the API that is reduced but the conceptual
weight: the number and difficulty of the concepts that programmers
must master in order to use the API. The programmer knows that the
returned object has precisely the API specified by its interface, so
there is no need to read additional class documentation for the
implementation class.
Here is one of the static method from java.util.Collections class:
public static <T> Collection<T> unmodifiableCollection(Collection<? extends T> c) {
return new UnmodifiableCollection<>(c);
}
Static Interface Method:
It is a static method which belongs to the interface only. We can
write implementation of this method in interface itself.
Static method can invoke only on interface class not on class.
Interface and implementing class , both can have static method with the same name without overriding each other.
It can be used as a utility method
Default Method:
It is a method with default keyword and class can override this method.
It can be invoked on interface as well as class.
We can override the default method in implementing class.
It can be used to provide common functionality in all implementing classes.
There is a link with detailed explanation. For detailed example: Default method vs static method in an interface in Java?

Why does it called dynamic binding, rather than static binding?

I'm new to Java and I have struck with some doubt. For example, consider the expression like:
a.method()
a.method("string")
people call them "dynamic dispatch". But I'm sure that the type checker makes sure that the methods named method(),method(String a) available for object a.
But why does it called "dynamic"? It isn't static call? Since the compiler found that already?
The example that you have posted will not use dynamic dispatch. You have posted an example of Method Overloading. And decision of method invocation in case of Overloading is done at compile time. It is on the compiler to decide which method will be invoked based on the formal parameters and the actual arguments passed.
Dynamic Binding comes into play when you are working with Method Overriding, where the decision of which method will actually be invoked is delayed till runtime.
For e.g: -
class A {
public void demo() { }
}
class B extends A {
public void demo() { }
}
public class Test {
public static void main(String[] args) {
A a = new B();
a.demo(); // B class method will be invoked.
A obj = new A();
obj.demo(); // A class method will be invoked.
}
}
The decision of which method is invoked is decided on the basis of which class instance the particular reference is pointing to, And that is only known at runtime. And hence Dynamic Dispatch.
The code you are showing doesn't express dynamic dispatch(binding).look at the below code.
class Super {
public void method() {}
}
class Sub extends Super {
public void method() {}
public static void main(String... args) {
Super inst = new Sub();
inst.method(); //Sub's method() would be invoked.(Express's Dynamic Dispatch)
}
}

Why can't static methods be abstract in Java?

The question is in Java why can't I define an abstract static method? for example
abstract class foo {
abstract void bar( ); // <-- this is ok
abstract static void bar2(); //<-- this isn't why?
}
Because "abstract" means: "Implements no functionality", and "static" means: "There is functionality even if you don't have an object instance". And that's a logical contradiction.
Poor language design. It would be much more effective to call directly a static abstract method than creating an instance just for using that abstract method. Especially true when using an abstract class as a workaround for enum inability to extend, which is another poor design example. Hope they solve those limitations in a next release.
You can't override a static method, so making it abstract would be meaningless. Moreover, a static method in an abstract class would belong to that class, and not the overriding class, so couldn't be used anyway.
The abstract annotation to a method indicates that the method MUST be overriden in a subclass.
In Java, a static member (method or field) cannot be overridden by subclasses (this is not necessarily true in other object oriented languages, see SmallTalk.) A static member may be hidden, but that is fundamentally different than overridden.
Since static members cannot be overriden in a subclass, the abstract annotation cannot be applied to them.
As an aside - other languages do support static inheritance, just like instance inheritance. From a syntax perspective, those languages usually require the class name to be included in the statement. For example, in Java, assuming you are writing code in ClassA, these are equivalent statements (if methodA() is a static method, and there is no instance method with the same signature):
ClassA.methodA();
and
methodA();
In SmallTalk, the class name is not optional, so the syntax is (note that SmallTalk does not use the . to separate the "subject" and the "verb", but instead uses it as the statemend terminator):
ClassA methodA.
Because the class name is always required, the correct "version" of the method can always be determined by traversing the class hierarchy. For what it's worth, I do occasionally miss static inheritance, and was bitten by the lack of static inheritance in Java when I first started with it. Additionally, SmallTalk is duck-typed (and thus doesn't support program-by-contract.) Thus, it has no abstract modifier for class members.
I also asked the same question , here is why
Since Abstract class says, it will not give implementation and allow subclass to give it
so Subclass has to override the methods of Superclass ,
RULE NO 1 - A static method cannot be overridden
Because static members and methods are compile time elements , that is why Overloading(Compile time Polymorphism) of static methods are allowed rather then Overriding (Runtime Polymorphism)
So , they cant be Abstract .
There is no thing like abstract static <--- Not allowed in Java Universe
This is a terrible language design and really no reason as to why it can't be possible.
In fact, here is a pattern or way on how it can be mimicked in **Java ** to allow you at least be able to modify your own implementations:
public static abstract class Request {
// Static method
public static void doSomething() {
get().doSomethingImpl();
}
// Abstract method
abstract void doSomethingImpl();
/////////////////////////////////////////////
private static Request SINGLETON;
private static Request get() {
if ( SINGLETON == null ) {
// If set(request) is never called prior,
// it will use a default implementation.
return SINGLETON = new RequestImplementationDefault();
}
return SINGLETON;
}
public static Request set(Request instance){
return SINGLETON = instance;
}
/////////////////////////////////////////////
}
Two implementations:
/////////////////////////////////////////////////////
public static final class RequestImplementationDefault extends Request {
#Override void doSomethingImpl() {
System.out.println("I am doing something AAA");
}
}
/////////////////////////////////////////////////////
public static final class RequestImplementaionTest extends Request {
#Override void doSomethingImpl() {
System.out.println("I am doing something BBB");
}
}
/////////////////////////////////////////////////////
Could be used as follows:
Request.set(new RequestImplementationDefault());
// Or
Request.set(new RequestImplementationTest());
// Later in the application you might use
Request.doSomething();
This would allow you to invoke your methods statically, yet be able to alter the implementation say for a Test environment.
Theoretically, you could do this on a ThreadLocal as well, and be able to set instance per Thread context instead rather than fully global as seen here, one would then be able to do Request.withRequest(anotherRequestImpl, () -> { ... }) or similar.
Real world usually do not require the ThreadLocal approach and usually it is enough to be able to alter implementation for Test environment globally.
Note, that the only purpose for this is to enable a way to retain the ability to invoke methods DIRECTLY, EASILY and CLEANLY which static methods provides while at the same time be able to switch implementation should a desire arise at the cost of slightly more complex implementation.
It is just a pattern to get around having normally non modifiable static code.
An abstract method is defined only so that it can be overridden in a subclass. However, static methods can not be overridden. Therefore, it is a compile-time error to have an abstract, static method.
Now the next question is why static methods can not be overridden??
It's because static methods belongs to a particular class and not to its instance. If you try to override a static method you will not get any compilation or runtime error but compiler would just hide the static method of superclass.
A static method, by definition, doesn't need to know this. Thus, it cannot be a virtual method (that is overloaded according to dynamic subclass information available through this); instead, a static method overload is solely based on info available at compile time (this means: once you refer a static method of superclass, you call namely the superclass method, but never a subclass method).
According to this, abstract static methods would be quite useless because you will never have its reference substituted by some defined body.
I see that there are a god-zillion answers already but I don't see any practical solutions. Of course this is a real problem and there is no good reason for excluding this syntax in Java. Since the original question lacks a context where this may be need, I provide both a context and a solution:
Suppose you have a static method in a bunch of classes that are identical. These methods call a static method that is class specific:
class C1 {
static void doWork() {
...
for (int k: list)
doMoreWork(k);
...
}
private static void doMoreWork(int k) {
// code specific to class C1
}
}
class C2 {
static void doWork() {
...
for (int k: list)
doMoreWork(k);
...
}
private static void doMoreWork(int k) {
// code specific to class C2
}
}
doWork() methods in C1 and C2 are identical. There may be a lot of these calsses: C3 C4 etc. If static abstract was allowed, you'd eliminate the duplicate code by doing something like:
abstract class C {
static void doWork() {
...
for (int k: list)
doMoreWork(k);
...
}
static abstract void doMoreWork(int k);
}
class C1 extends C {
private static void doMoreWork(int k) {
// code for class C1
}
}
class C2 extends C {
private static void doMoreWork(int k) {
// code for class C2
}
}
but this would not compile because static abstract combination is not allowed.
However, this can be circumvented with static class construct, which is allowed:
abstract class C {
void doWork() {
...
for (int k: list)
doMoreWork(k);
...
}
abstract void doMoreWork(int k);
}
class C1 {
private static final C c = new C(){
#Override void doMoreWork(int k) {
System.out.println("code for C1");
}
};
public static void doWork() {
c.doWork();
}
}
class C2 {
private static final C c = new C() {
#Override void doMoreWork(int k) {
System.out.println("code for C2");
}
};
public static void doWork() {
c.doWork();
}
}
With this solution the only code that is duplicated is
public static void doWork() {
c.doWork();
}
Assume there are two classes, Parent and Child. Parent is abstract. The declarations are as follows:
abstract class Parent {
abstract void run();
}
class Child extends Parent {
void run() {}
}
This means that any instance of Parent must specify how run() is executed.
However, assume now that Parent is not abstract.
class Parent {
static void run() {}
}
This means that Parent.run() will execute the static method.
The definition of an abstract method is "A method that is declared but not implemented", which means it doesn't return anything itself.
The definition of a static method is "A method that returns the same value for the same parameters regardless of the instance on which it is called".
An abstract method's return value will change as the instance changes. A static method will not. A static abstract method is pretty much a method where the return value is constant, but does not return anything. This is a logical contradiction.
Also, there is really not much of a reason for a static abstract method.
An abstract class cannot have a static method because abstraction is done to achieve DYNAMIC BINDING while static methods are statically binded to their functionality.A static method means
behavior not dependent on an instance variable, so no instance/object
is required.Just the class.Static methods belongs to class and not object.
They are stored in a memory area known as PERMGEN from where it is shared with every object.
Methods in abstract class are dynamically binded to their functionality.
Declaring a method as static means we can call that method by its class name and if that class is abstract as well, it makes no sense to call it as it does not contain any body, and hence we cannot declare a method both as static and abstract.
As abstract methods belong to the class and cannot be overridden by the implementing class.Even if there is a static method with same signature , it hides the method ,does not override it.
So it is immaterial to declare the abstract method as static as it will never get the body.Thus, compile time error.
A static method can be called without an instance of the class. In your example you can call foo.bar2(), but not foo.bar(), because for bar you need an instance.
Following code would work:
foo var = new ImplementsFoo();
var.bar();
If you call a static method, it will be executed always the same code. In the above example, even if you redefine bar2 in ImplementsFoo, a call to var.bar2() would execute foo.bar2().
If bar2 now has no implementation (that's what abstract means), you can call a method without implementation. That's very harmful.
I believe I have found the answer to this question, in the form of why an interface's methods (which work like abstract methods in a parent class) can't be static. Here is the full answer (not mine)
Basically static methods can be bound at compile time, since to call them you need to specify a class. This is different than instance methods, for which the class of the reference from which you're calling the method may be unknown at compile time (thus which code block is called can only be determined at runtime).
If you're calling a static method, you already know the class where it's implemented, or any direct subclasses of it. If you define
abstract class Foo {
abstract static void bar();
}
class Foo2 {
#Override
static void bar() {}
}
Then any Foo.bar(); call is obviously illegal, and you will always use Foo2.bar();.
With this in mind, the only purpose of a static abstract method would be to enforce subclasses to implement such a method. You might initially think this is VERY wrong, but if you have a generic type parameter <E extends MySuperClass> it would be nice to guarantee via interface that E can .doSomething(). Keep in mind that due to type erasure generics only exist at compile time.
So, would it be useful? Yes, and maybe that is why Java 8 is allowing static methods in interfaces (though only with a default implementation). Why not abstract static methods with a default implementation in classes? Simply because an abstract method with a default implementation is actually a concrete method.
Why not abstract/interface static methods with no default implementation? Apparently, merely because of the way Java identifies which code block it has to execute (first part of my answer).
Because abstract class is an OOPS concept and static members are not the part of OOPS....
Now the thing is we can declare static complete methods in interface and we can execute interface by declaring main method inside an interface
interface Demo
{
public static void main(String [] args) {
System.out.println("I am from interface");
}
}
Because abstract mehods always need implementation by subclass.But if you make any method to static then overriding is not possible for this method
Example
abstract class foo {
abstract static void bar2();
}
class Bar extends foo {
//in this if you override foo class static method then it will give error
}
Static Method
A static method can be invoked without the need for creating an instance of a class.A static method belongs to the class rather than the object of a class.
A static method can access static data member and also it can change the value of it.
Abstract Keyword is used to implement abstraction.
A static method can't be overriden or implemented in child class. So, there is no use of making static method as abstract.
The idea of having an abstract static method would be that you can't use that particular abstract class directly for that method, but only the first derivative would be allowed to implement that static method (or for generics: the actual class of the generic you use).
That way, you could create for example a sortableObject abstract class or even interface
with (auto-)abstract static methods, which defines the parameters of sort options:
public interface SortableObject {
public [abstract] static String [] getSortableTypes();
public String getSortableValueByType(String type);
}
Now you can define a sortable object that can be sorted by the main types which are the same for all these objects:
public class MyDataObject implements SortableObject {
final static String [] SORT_TYPES = {
"Name","Date of Birth"
}
static long newDataIndex = 0L ;
String fullName ;
String sortableDate ;
long dataIndex = -1L ;
public MyDataObject(String name, int year, int month, int day) {
if(name == null || name.length() == 0) throw new IllegalArgumentException("Null/empty name not allowed.");
if(!validateDate(year,month,day)) throw new IllegalArgumentException("Date parameters do not compose a legal date.");
this.fullName = name ;
this.sortableDate = MyUtils.createSortableDate(year,month,day);
this.dataIndex = MyDataObject.newDataIndex++ ;
}
public String toString() {
return ""+this.dataIndex+". "this.fullName+" ("+this.sortableDate+")";
}
// override SortableObject
public static String [] getSortableTypes() { return SORT_TYPES ; }
public String getSortableValueByType(String type) {
int index = MyUtils.getStringArrayIndex(SORT_TYPES, type);
switch(index) {
case 0: return this.name ;
case 1: return this.sortableDate ;
}
return toString(); // in the order they were created when compared
}
}
Now you can create a
public class SortableList<T extends SortableObject>
that can retrieve the types, build a pop-up menu to select a type to sort on and resort the list by getting the data from that type, as well as hainv an add function that, when a sort type has been selected, can auto-sort new items in.
Note that the instance of SortableList can directly access the static method of "T":
String [] MenuItems = T.getSortableTypes();
The problem with having to use an instance is that the SortableList may not have items yet, but already need to provide the preferred sorting.
Cheerio,
Olaf.
First, a key point about abstract classes -
An abstract class cannot be instantiated (see wiki). So, you can't create any instance of an abstract class.
Now, the way java deals with static methods is by sharing the method with all the instances of that class.
So, If you can't instantiate a class, that class can't have abstract static methods since an abstract method begs to be extended.
Boom.
As per Java doc:
A static method is a method that is associated with the class in which
it is defined rather than with any object. Every instance of the class
shares its static methods
In Java 8, along with default methods static methods are also allowed in an interface. This makes it easier for us to organize helper methods in our libraries. We can keep static methods specific to an interface in the same interface rather than in a separate class.
A nice example of this is:
list.sort(ordering);
instead of
Collections.sort(list, ordering);
Another example of using static methods is also given in doc itself:
public interface TimeClient {
// ...
static public ZoneId getZoneId (String zoneString) {
try {
return ZoneId.of(zoneString);
} catch (DateTimeException e) {
System.err.println("Invalid time zone: " + zoneString +
"; using default time zone instead.");
return ZoneId.systemDefault();
}
}
default public ZonedDateTime getZonedDateTime(String zoneString) {
return ZonedDateTime.of(getLocalDateTime(), getZoneId(zoneString));
}
}
Because 'abstract' means the method is meant to be overridden and one can't override 'static' methods.
Regular methods can be abstract when they are meant to be overridden by subclasses and provided with functionality.
Imagine the class Foo is extended by Bar1, Bar2, Bar3 etc. So, each will have their own version of the abstract class according to their needs.
Now, static methods by definition belong to the class, they have nothing to do with the objects of the class or the objects of its subclasses. They don't even need them to exist, they can be used without instantiating the classes. Hence, they need to be ready-to-go and cannot depend on the subclasses to add functionality to them.
Because abstract is a keyword which is applied over Abstract methods do not specify a body. And If we talk about static keyword it belongs to class area.
because if you are using any static member or static variable in class it will load at class loading time.
There is one occurrence where static and abstract can be used together and that is when both of these modifiers are placed in front of a nested class.
In a single line, this dangerous combination (abstract + static) violates the object-oriented principle which is Polymorphism.
In an inheritance situation, the JVM will decide at runtime by the implementation in respect of the type of instance (runtime polymorphism) and not in respect of the type of reference variable (compile-time polymorphism).
With #Overriding:
Static methods do not support #overriding (runtime polymorphism), but only method hiding (compile-time polymorphism).
With #Hiding:
But in a situation of abstract static methods, the parent (abstract) class does not have implementation for the method. Hence, the child type reference is the only one available and it is not polymorphism.
Child reference is the only one available:
For this reason (suppress OOPs features), Java language considers abstract + static an illegal (dangerous) combination for methods.
You can do this with interfaces in Java 8.
This is the official documentation about it:
https://docs.oracle.com/javase/tutorial/java/IandI/defaultmethods.html
Because if a class extends an abstract class then it has to override abstract methods and that is mandatory. And since static methods are class methods resolved at compile time whereas overridden methods are instance methods resolved at runtime and following dynamic polymorphism.

Categories