I have a text file with letters up and I want to make them lower letters. It is the code but it becomes only the last line
BufferedReader in = new BufferedReader(new FileReader("C:\Users\xxx\Desktop\j.txt"));
String line;
while((line = in.readLine()) != null)
{
blig=line.toUpperCase();
}
try (BufferedWriter writer = new BufferedWriter(new FileWriter("C:\Users\xxx\Desktop\j.txt"))) {
writer.write(blig);
}
You are traversing through the whole file but just storing the last line. In order to get all the lines, you need to store all the lines you are reading, convert them to uppercase, then write them back to the file:
List<String> upper = new ArrayList<>();
try(BufferedReader in = new BufferedReader(new FileReader("C:\Users\xxx\Desktop\j.txt")))
{
String line;
while((line = in.readLine()) != null)
{
// upper.add(line.toUpperCase()); // if you need upper case
upper.add(line.toLowerCase()); // if you need lower case
}
}
try(BufferedWriter writer = new BufferedWriter(new FileWriter("C:\Users\xxx\Desktop\j.txt")))
{
for(String str : upper)
{
writer.write(str);
writer.newLine(); // remove if not needed.
}
}
BufferedReader in = new BufferedReader(new FileReader("C:\Users\xxx\Desktop\j.txt"));
BufferedWriter writer = new BufferedWriter(new FileWriter("C:\Users\xxx\Desktop\lowerJ.txt"));
String line;
while((line = in.readLine()) != null) {
writer.write(line.toLowerCase());
}
If you are trying to lower the case of characters, then why use to Uper?
blig=line.toUpperCase();
It sould be bling=line.toLowerCase();
Because you are writing only the last line while you are not concatenating all the result.
replace the while statement by
blig += line.toUpperCase() + "\\n";
Related
How do I skip the first element from a String Array?
Another quick approach is to control the line reads through flag like below:
public List<Beruf> fileRead(String filePath) throws IOException {
List<Beruf> berufe = new ArrayList<Beruf>();
String line = "";
try {
FileReader fileReader = new FileReader(filePath);
BufferedReader reader = new BufferedReader(fileReader);
Boolean firstLine = Boolean.TRUE;
while ((line = reader.readLine()) != null) {
if(firstLine) {
firstLine = Boolean.FALSE;
continue;
}
String[] attributes = line.split(";");
Beruf beruf = createBeruf(attributes);
berufe.add(beruf);
}
reader.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
return berufe;
}
The easiest way to remove the header line would be to just read it before you enter your while loop.
String filePath = path;
FileReader fileReader = new FileReader(filePath);
BufferedReader reader = new BufferedReader(fileReader);
String headers = reader.readLine(); //This removes the first line from the BufferedReader
while ((line = reader.readLine()) != null) {
String[] attributes = line.split(";");
Beruf beruf = createBeruf(attributes);
berufe.add(beruf);
}
reader.close();
If you use java 8 or higher and are allowed to use streams you could also use the lines method of the Files class
Files.lines(Paths.get(filePath))
.skip(1) // skipping the headers
.map(line -> line.split(";"))
.map(attributes -> createBeruf(attributes))
.forEach(beruf -> berufe.add(beruf));
The code below only brings up the first line of code and stops. I would like to return each line of code until there are no more.
private String GetPhoneAddress() {
File directory = Environment.getExternalStorageDirectory();
File myFile = new File(directory, "mythoughtlog.txt");
//File file = new File(Environment.getExternalStorageDirectory() + "mythoughtlog.txt");
if (!myFile.exists()){
String line = "Need to add smth";
return line;
}
String line = null;
//Read text from file
//StringBuilder text = new StringBuilder();
try {
BufferedReader br = new BufferedReader(new FileReader(myFile));
line = br.readLine();
}
catch (IOException e) {
//You'll need to add proper error handling here
}
return line;
}
You could loop over the results of readLine() and accumulate them until you get a null, indicating the end of the file (BTW, note that your snippet neglected to close the reader. A try-with-resource structure could handle that):
try (BufferedReader br = new BufferedReader(new FileReader(myFile))) {
String line = br.readLine();
if (line == null) {
return null;
}
StringBuilder retVal = new StringBuilder(line);
line = br.readLine();
while (line != null) {
retVal.append(System.lineSeparator()).append(line);
line = br.readLine();
}
return retVal.toString();
}
if you're using Java 8, you can save a lot of this boiler-plated code with the newly introduced lines() method:
try (BufferedReader br = new BufferedReader(new FileReader(myFile))) {
return br.lines().collect(Collectors.joining(System.lineSeparator()));
}
A considerably less verbose solution:
try (BufferedReader br = new BufferedReader(new FileReader(myFile))) {
StringBuilder retVal = new StringBuilder();
while ((line = br.readLine()) != null) {
retVal.append(line).append(System.lineSeparator());
}
return retVal.toString();
}
private static void readFile1(String in, String out) throws IOException
{
FileInputStream fis = new FileInputStream(new File(in));
BufferedReader br = new BufferedReader(new InputStreamReader(fis));
BufferedWriter writer = null;
writer = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream(out), "utf-8"));
String line = null;
while ((line = br.readLine()) != null)
{
if(line.length() > 0)
{
String[] words = line.split("\\s+");
for(String word : words)
{
if(word.charAt(0)=='*')
{
//System.out.println(word);
writer.write(word);
writer.newLine();
}
}
}
}
br.close();
writer.close();
fis.close();
}
}
Can someone help me with this one?
In cmd i get something like "Exception in thread "main" java.lang.StringIndexOutOfBoundsException:String index out of range:0
The only place you seem to be referencing an index on a string is this if-statement:
if(word.charAt(0)=='*')
Change your if statement to be:
if(!word.isEmpty() && word.charAt(0)=='*')
This will first check if the word is empty and if it is not, then it will look for the proper char
UPDATE
You should add in a NULL check on word as well, just to avoid a NullPointerException
if(word != null && !word.isEmpty() && word.charAt(0)=='*')
I have a text file -> 23/34 <- and I'm working on a Java program.
I want to store them out in String One = 23 and anotherString = 34 and put them together to one string to write them down in a text file, but it dosen't work. :( Everytime it makes a break. Maybe because the split method but I don't know how to separate them.
try {
BufferedReader in = new BufferedReader (new FileReader (textfile) );
try {
while( (textfile= in.readLine()) != null ) {
String[] parts = textfileString.split("/");
String one = parts[0];
}
}
}
When I print or store one + "/" + anotherString, it makes a line-break at one but I want it all in one line. :(
public static void main(String[] args) throws Exception {
File file = new File("output.txt");
if (!file.exists()) {
file.createNewFile();
}
BufferedWriter bw = new BufferedWriter(new FileWriter(file.getAbsoluteFile()));
BufferedReader br = new BufferedReader(new FileReader("input.txt"));
String line = null;
while ((line = br.readLine()) != null) {
String string1 = line.split("/")[0];
String string2 = line.split("/")[1];
bw.write(string1 + string2 + "\n");
bw.flush();
}
br.close();
bw.close();
}
On file:
23/34
Resulted in output.txt containing:
2334
You need to read in each line, and split it on your designated character ("/"). Then assign string1 to the first split, and string2 to the second split. You can then do with the variables as you want. To output them to a file, you simply append them together with a + operator.
You have never shown us how you are writing the file, so we can't really help you with your code. This is a bit of a more modern approach, but I think it does what you want.
File infile = new File("input.txt");
File outfile = new File("output.txt");
try (BufferedReader reader = Files.newBufferedReader(infile.toPath());
BufferedWriter writer = Files.newBufferedWriter(outfile.toPath())) {
String line;
while ((line = reader.readLine()) != null) {
String parts[] = line.split("/");
String one = parts[0];
String two = parts[1];
writer.write(one + "/" + two);
}
} catch (IOException ex) {
System.err.println(ex.getLocalizedMessage());
}
InputStream stream = this.getClass().getResourceAsStream("./test.txt");
BufferedReader reader = new BufferedReader(new InputStreamReader(stream));
String currentLine;
try {
while ((currentLine = reader.readLine()) != null) {
String[] parts = currentLine.split("/");
System.out.println(parts[0] + "/" + parts[1]);
}
} catch (IOException e) {
e.printStackTrace();
} finally{
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
Lets say I have a text file called: data.txt (contains 2000 lines)
How do I read given specific line from: 500-1500 and then 1500-2000
and display the output of specific line?
this code will read whole files (2000 line)
public static String getContents(File aFile) {
StringBuffer contents = new StringBuffer();
try {
BufferedReader input = new BufferedReader(new FileReader(aFile));
try {
String line = null;
while (( line = input.readLine()) != null){
contents.append(line);
contents.append(System.getProperty("line.separator"));
}
}
finally {
input.close();
}
}
catch (IOException ex){
ex.printStackTrace();
}
return contents.toString();
}
How do I modify above code to read specific line?
I suggest java.io.LineNumberReader. It extends BufferedReader and
you can use its LineNumberReader.getLineNumber(); to get the current line number
You can also use Java 7 java.nio.file.Files.readAllLines which returns a List<String> if it suits you better
Note:
1) favour StringBuilder over StringBuffer, StringBuffer is just a legacy class
2) contents.append(System.getProperty("line.separator")) does not look nice
use contents.append(File.separator) instead
3) Catching exception seems irrelevant, I would also suggest to change your code as
public static String getContents(File aFile) throws IOException {
BufferedReader rdr = new BufferedReader(new FileReader("aFile"));
try {
StringBuilder sb = new StringBuilder();
// read your lines
return sb.toString();
} finally {
rdr.close();
}
}
now code looks cleaner in my view. And if you are in Java 7 use try-with-resources
try (BufferedReader rdr = new BufferedReader(new FileReader("aFile"))) {
StringBuilder sb = new StringBuilder();
// read your lines
return sb.toString();
}
so finally your code could look like
public static String[] getContents(File aFile) throws IOException {
try (LineNumberReader rdr = new LineNumberReader(new FileReader(aFile))) {
StringBuilder sb1 = new StringBuilder();
StringBuilder sb2 = new StringBuilder();
for (String line = null; (line = rdr.readLine()) != null;) {
if (rdr.getLineNumber() >= 1500) {
sb2.append(line).append(File.pathSeparatorChar);
} else if (rdr.getLineNumber() > 500) {
sb1.append(line).append(File.pathSeparatorChar);
}
}
return new String[] { sb1.toString(), sb2.toString() };
}
}
Note that it returns 2 strings 500-1499 and 1500-2000
A slightly more cleaner solution would be to use FileUtils in apache commons.
http://commons.apache.org/io/api-release/org/apache/commons/io/FileUtils.html
Example snippet:
String line = FileUtils.readLines(aFile).get(lineNumber);
The better way is to use BufferedReader. If you want to read line 32 for example:
for(int x = 0; x < 32; x++){
buf.readLine();
}
lineThreeTwo = buf.readLine();
Now in String lineThreeTwo you have stored line 32.