After deserializing my string and converting it to JSON using the code below:
JSONObject returnValue = new JSONObject();
String toJson = null;
try
{
Object otherObjectValue = SerializationUtils
.deserialize(myBytesArray);
Gson gson = new Gson();
toJson = gson.toJson(otherObjectValue);
returnValue.put(key, toJson);
}
some part of the JSON still has something like:
{ "key":"ATTRIBUTE_LIST", "value":"{\"attributeContract\":[{\"scope\":\"sso\",\"name\":\"SAML_SUBJECT\",\"description\":\"Click to Edit\",\"required\":true}]}"}
which means everything in:
"{\"attributeContract\":[{\"scope\":\"sso\",\"name\":\"SAML_SUBJECT\",\"description\":\"Click to Edit\",\"required\":true}]}"
is one string instead being another object with fields. Is there something I can do to sanitize by JSONObject to make it properly JSON?
The key part is OK, means the whole String is JSON formatted.
For the value part, /shows that the value of value is JSON formatted already.
So you may "deserialize" the value of value again to retrieve an Object result. Or you may ask the creator of origin JSON, to serialize origin Object one time into JSON format.
Related
I am currently using JsonObject and JsonParser of com.google.gson api (using gson-2.8.5 version) to parse and read the value form input JSON.
I have JSON filed like , smaple "resultCode":"SUCCESS", when I try to read the same value from json it gives the result as ""SUCCESS"" .
Every value I am reading, getting with double "" not sure why ? You can refer below screen of my debugging screen.
I am new to Json and parser, is that default behavior ?
I am expecting "SUCCESS", "S", "00000000" not like ""SUCCESS"" or ""S""
or ""00000000""
same I have highlighted in the below image .
Please share any idea how we can get apbsolute vlaue of string without """" double quote string it causing my string comparison fail.
String response_result = "{\"response\": {\"head\": {\"function\": \"acquiring.order.create\",\"version\": \"2.0\",\"clientId\": \"201810300000\",\"reqMsgId\": \"56805892035\",\"respTime\": \"2019-09-13T13:18:08+08:00\"},\"body\": {\"resultInfo\": {\"resultCode\": \"SUCCESS\",\"resultCodeId\": \"00000000\",\"resultStatus\": S,\"resultMsg\": \"SUCCESS\"},\"acquirementId\": \"2018080834569894848930\",\"merchantTransId\": \"5683668701112717398\",\"checkoutUrl\": \"http://localhost:8081/crm/operator/operator-search-init.action\"}},\"signature\":\"d+TUYLvt1a491R1e6aO8i9VwXWzVhfNgnhD0Du74f4RgBQ==\"}";
HttpInvoker.Result result = i.new Result(200, response_result);
JsonObject jo = new JsonParser().parse(response_result).getAsJsonObject();
String resultCode = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().get("resultCode").toString();
String resultCodeId = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().get("resultCodeId").toString();
String resultStatus = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().get("resultStatus").toString();
String checkoutUrl = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("checkoutUrl").toString();
if ( RESULT_CODE_GCASH_SUCCESS.equals(resultCode)
&& RESULT_STATUS_SUCCESS.equals(resultStatus)
&& StringUtils.isNotEmpty(checkoutUrl)) {
log.error("Testing ".concat(resultCode).concat(resultStatus).concat(checkoutUrl));
}
log.error("Testing ".concat(resultCode).concat(resultStatus).concat(checkoutUrl));
}
This is my input JSON
{
"response":{
"head":{
"function":"acquiring.order.create",
"version":"2.0",
"clientId":"201810300000",
"reqMsgId":"56805892035",
"respTime":"2019-09-13T13:18:08+08:00"
},
"body":{
"resultInfo":{
"resultCode":"SUCCESS",
"resultCodeId":"00000000",
"resultStatus":"S",
"resultMsg":"SUCCESS"
},
"acquirementId":"2018080834569894848930",
"merchantTransId":"5683668701112717398",
"checkoutUrl":"http://localhost:8081/crm/operator/operator-search-init.action"
}
},
"signature":"d+TUYLvtI38YL2hresd98Ixu1BXccvvh1IQMiHuMXUEeW/N5exUsW491R1e6aO8i9VwXWzVhfNgnhD0Du74f4RgBQ=="
}
JsonParser parses your json into JsonElement structure. The behaviour that you see is a normal since you are using toString method of JsonElement. To achieve your goal just use JsonElement::getAsString method :
String resultCode = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().get("resultCode").getAsString();
which gives SUCCESS instead of "SUCCESS"
Note that JsonElement is an abstract class and classes, that extend this class, will override those helper getAs... methods. In your case JsonPrimitive::getAsString will be invoked.
Also you could create a POJO class for your json and use Gson::fromJson to parse json into object of your POJO class.
With the input from #Michalk:
I understand that easy way to read JSON data is using Gson::fromJson and creating POJO class for out json.
I have generated POJO Classes supplying my sample input JSON using this link
and Now I have POJO Classes called : CreateOrderJSONResponse
Gson::fromJson
Sample :
Gson gson = new Gson();
CreateOrderJSONResponse responseJson = gson.fromJson(inputJSON, CreateOrderJSONResponse.class);
Accessubg data :
String resultCodeText = responseJson.getResponse().getBody().getResultInfo().getResultCode();
String resultCodeId = responseJson.getResponse().getBody().getResultInfo().getResultCodeId();
String resultStatus = responseJson.getResponse().getBody().getResultInfo().getResultStatus();
String checkoutUrl = responseJson.getResponse().getBody().getCheckoutUrl();
Above Gson::fromJson example works smooth and it looks neat compare to direct accessing the filed with below sample code :
JsonObject jo = parser.parse(inputJSON).getAsJsonObject();
String resultCodeText = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().getAsJsonPrimitive("resultCode").getAsString();
String resultCodeId = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().getAsJsonPrimitive("resultCodeId").getAsString();
String resultStatus = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().get("resultInfo").getAsJsonObject().getAsJsonPrimitive("resultStatus").getAsString();
String checkoutUrl = jo.get("response").getAsJsonObject().get("body").getAsJsonObject().getAsJsonPrimitive("checkoutUrl").getAsString();
Note :
I have found this link of JSON or JAVA, SCALA, POJO generator tools as GitHub access you can access here
My servlet recieves/loads multiple parameters from/for an article (price, id, count, name).
While they are saved in the session for other purposes I want to display them in a Shopping cart.
So my idea was to get all values into a json like this
{"id":1, "prductName":"article1"}
but my json always ends up empty.
I had two approaches:
String prname = request.getParameter("name");
String anz = String.valueOf(session.getAttribute("Anzahl"));
String prid = request.getParameter("id");
String price = request.getParameter("price");
These are my parameters:
First try:
class ToJson{
String prname1 = String.valueOf(session.getAttribute("prname"));
String anz1 = String.valueOf(session.getAttribute("Anzahl"));
String prid1 = String.valueOf(session.getAttribute("id"));
String price1 = String.valueOf(session.getAttribute("price"));
}
ToJson obj = new ToJson();
Jsonb jsonb = JsonbBuilder.create();
String jsn1 = jsonb.toJson(obj);
Ends up with: {}
Second try:
ArrayList<String> ar = new ArrayList<String>();
ar.add(prname);
ar.add(price);
ar.add(prid);
ar.add(anz);
ToJson obj = new ToJson();
Jsonb jsonb = JsonbBuilder.create();
String jsn = jsonb.toJson(ar);
Ends up with: ["P1neu","25","1","145"]
It isn't in a format I wanted and I also don't know how to access the seperate values here, I tried jsn[1] but it didnt work.
Could you help me, please?
To your first question, why JSON object is printing empty:
You are missing getters & setters in the ToJSON class for JSON Builder/Parser to access the properties/fields, and that's why its printing as empty object.
To your second question, how do I access JSON properties:
JSON representation is a natively a string representation, and you can't read part of string as jsn[1].
For reading JSON object properties, you convert it into POJO using available any of preferred open source parser libraries like Jacksons, Gson etc. And then access POJO properties using standard java getter/setters.
I have a malformed json array string which I get from an API call as follows:
[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Processed successfully\"}]\"}]
There is a double quote before open square bracket in the value of Response Msg property.
Is there a way to convert this into Java object ?
What I have tried so far:
I have used Jackson to parse it as follows but it gives error
ObjectMapper mapper = new ObjectMapper();
mapper.setPropertyNamingStrategy(new ResponseNameStrategy());
Response[] response = mapper.readValue(strOutput1, Response[].class);
Error: Can not deserialize instance of java.util.ArrayList out of VALUE_STRING token
I have also tried using Gson to parse it but it also gives error
Gson gson = new GsonBuilder()
.setFieldNamingPolicy(FieldNamingPolicy.UPPER_CAMEL_CASE)
.create();
Response[] response = gson.fromJson(strOutput1, Response[].class);
Error: Expected BEGIN_ARRAY but was STRING at line 1 column 35 path $[0].ResponseMsg
I have gone through the following links on StackOverflow but none of them has addressed my issue:
How to Convert String Array JSON in a Java Object
Convert a JSON string to object in Java ME?
JSON Array to Java objects
Convert json String to array of Objects
converting 'malformed' java json object to javascript
I think the answer is in the comments, you appear to be trying to solve the issue on the wrong place.
You are receiving json which you wish to parse into java objects, unfortunately the json is malformed so will not parse.
As a general rule you should never be trying to solve the symptom, but should look for the root cause and fix that, it may sound trivial but fixing symptoms leads to messy, unpredictable, and unmaintainable systems.
So the answer is fix the json where it is being broken. If this is something or of your control, while you wait for the fix, you could put a hack in to fix the json before you parse it.
This way you won't compromise your parsing, and only have a small piece of string replacement to remove when the third party has fixed the issue. But do not go live with the hack, it should only be used during development.
As i mentioned in the comment, you should prepare your service response in order to parse it.
I implemented an example:
public class JsonTest {
public static void main(String args[]) throws JsonProcessingException, IOException{
String rawJson =
"[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Processed successfully\"}]\"}]";
String goodJson = "{"+rawJson.split("[{{.}]")[2]+"}";
ObjectMapper mapper = new ObjectMapper();
final ObjectNode node = mapper.readValue(goodJson, ObjectNode.class);
System.out.println("Pretty Print: " + mapper.writerWithDefaultPrettyPrinter().writeValueAsString(node));
System.out.println("Just code: " + node.get("Code"));
}
}
Which returns:
This is how I finally solved my issue:
String inputJsonStr = "[{\"ResponseCode\":1,\"ResponseMsg\":\"[{\"Code\":\"CA2305181\",\"Message\":\"Claim has been added successfully.\"}"
+ "]\"}]";
int indexOfRes = inputJsonStr.indexOf("ResponseMsg");
if(inputJsonStr.substring(indexOfRes+13,indexOfRes+14).equals("\""))
{
inputJsonStr = inputJsonStr.substring(0,indexOfRes+13) + inputJsonStr.substring(indexOfRes+14);
}
int indexOfFirstClosingSquare = inputJsonStr.indexOf("]");
if(inputJsonStr.substring(indexOfFirstClosingSquare+1, indexOfFirstClosingSquare+2).equals("\"")) {
inputJsonStr = inputJsonStr.substring(0, indexOfFirstClosingSquare+1)+inputJsonStr.substring(indexOfFirstClosingSquare+2);
}
Now inputJsonStr contains a valid json array which can be parsed into Java custom object array easily with gson as given in this SO link:
Convert json String to array of Objects
I am storing a json string into a text field in mysql.
After the insertion, i want to update my json string and add the mysql line id into it with jackson json.
I have a java String which is in Json format
{
"thing":"val"
}
I'm looking to add another K/V without writing lines of codes.
to finally have this :
{
"thing":"val"
"mysqlId":10
}
I can convert my String to a JsonNode :
ObjectMapper mapper = new ObjectMapper();
JsonNode json = mapper.readTree( jsonStr);
Looking to do something like this
json.put("mysqlId",10);
json.toString();
then update in my text field with new json string in mysql
I can't make it.
I don't want use many class is there a simple way to do so with jackson?
Try casting your JsonNode to an com.fasterxml.jackson.databind.node.ObjectNode and then calling put set (or replace) on it.
I have an API Output like this:
{"user" : {"status" : {"stat1" : "54", "stats2" : "87"}}}
I create a simple JSONObject from this API with:
JSONObject json = getJSONfromURL(URL);
After this I can read the data for User like this:
String user = json.getString("user");
But how do I get the Data for stat1 and stat2?
JSONObject provides accessors for a number of different data types, including nested JSONObjects and JSONArrays, using JSONObject.getJSONObject(String), JSONObject.getJSONArray(String).
Given your JSON, you'd need to do something like this:
JSONObject json = getJSONfromURL(URL);
JSONObject user = json.getJSONObject("user");
JSONObject status = user.getJSONObject("status");
int stat1 = status.getInt("stat1");
Note the lack of error handling here: for instance the code assumes the existence of the nested members - you should check for null - and there's no Exception handling.
JSONObject mJsonObject = new JSONObject(response);
JSONObject userJObject = mJsonObject.getJSONObject("user");
JSONObject statusJObject = userJObject.getJSONObject("status");
String stat1 = statusJObject.getInt("stat1");
String stats2 = statusJObject.getInt("stats2");
from your response user and status is Object so for that use getJSONObject and stat1 and stats2 is status object key so for that use getInt() method for getting integer value and use getString() method for getting String value.
To access properties in an JSON you can parse the object using JSON.parse and then acceess the required property like:
var star1 = user.stat1;
Using Google Gson Library...
Google Gson is a simple Java-based library to serialize Java objects to JSON and vice versa. It is an open-source library developed by Google.
// Here I'm getting a status object inside a user object. Because We need two fields in user object itself.
JsonObject statusObject= tireJsonObject.getAsJsonObject("user").getAsJsonObject("status");
// Just checking whether status Object has stat1 or not And Also Handling NullPointerException.
String stat1= statusObject.has("stat1") && !statusObject.get("stat1").isJsonNull() ? statusObject.get("stat1").getAsString(): "";
//
String stat2= statusObject.has("stat2") && !statusObject.get("stat2").isJsonNull() ? statusObject.get("stat2").getAsString(): "";
If You have any doubts , Please let me know in comments ...