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How to put new string between commas in original string

I have this original string and I want to insert new string between two dots of original string. I did it this way, but having errors.
String originalString ="asdASfasdlpe.hereNeedToPutNewString.asdasfdfepw";
String stringForReplace = "NewString";
String new = originalString.replace(originalString.substring(originalString.indexOf(".") + 1), stringForReplace);
it gives me: "asdASfasdlpe.NewString"
Result should be: "asdASfasdlpe.NewString.asdasfdfepw"

I would do it like so.
from the question it looks like you want to replace the first occurrence so use replaceFirst
(?<=\\.) - look behind assertion - so start with following character
(?=\\.) - look ahead assertion - so end prior to that
.*? - reluctant quantifier to limit to just characters between two periods. Use * in case you have two adjacent periods since the string could be empty.
String s = "first.oldstring.third.fourth.fifth";
String n = "second";
s = s.replaceFirst("(?<=\\.).*?(?=\\.)",n);
System.out.println(s);
prints
first.second.third.fourth.fifth

String originalString ="asdASfasdlpe.hereNeedToPutNewString.asdasfdfepw";
String stringForReplace = "NewString";
String a[]=originalString.split("[.]");
String newString="";
if(a.length==3) {
newString=originalString.replace(a[1], stringForReplace);
}
System.out.println(newString);
Or with ternary operator:
newString=(a.length== 3 ? originalString.replace(a[1], stringForReplace):null);
System.out.println(newString);

One shorter solution is to use regex with a lookahead and lookbehind
String replaced = originalString.replaceAll("(?<=\\.).+(?=\\.)", stringForReplace);

The problem with your code is due to using this particular piece of code:
originalString.substring(originalString.indexOf(".") + 1)
The reason is that indexof() function will only give the index on which "." was found on, and substring will only know where to start taking the substring from, but it wouldn't know where to end it.
Try this:
String originalString ="asdASfasdlpe.hereNeedToPutNewString.asdasfdfepw";
String stringForReplace = "NewString";
String newString = originalString.replace(originalString.split("[.]", 3)[1], stringForReplace);
System.out.println(newString);
The split function in this piece of code will break the whole string by "."
and you will have the string you want to replace available to you.
originalString.split("[.]", 3)[1]

You could try the following:
public static void main(String[] args) {
String originalString ="asdASfasdlpe.hereNeedToPutNewString.asdasfdfepw";
String stringForReplace = "NewString";
String newStr = originalString.replaceAll("(?<=\\.).*(?=\\.)", stringForReplace);
//using lookahead and lookbehind regex
String newStr2 = originalString.replaceAll("\\..*\\.", "."+stringForReplace+".");
System.out.println(newStr);
System.out.println(newStr2);
}
One option uses lookahead and lookbehinds, you could opt to not use that if it is not supported.
Output:
asdASfasdlpe.NewString.asdasfdfepw
asdASfasdlpe.NewString.asdasfdfepw

Here You go:
String new = originalString.replace(originalString.substring(originalString.indexOf(".") + 1), stringForReplace)+originalString.substring(originalString.indexOf(".",originalString.indexOf(".")+1),originalString.length());
What I have done is adding the resultant string to the new String.indexOf function takes another argument too, which is the position the search will start

Split string using reges

I have following string
String str = "url:http://www.google.com"
Now I want to split the above string using :.
If I split above string using : then above string split into 3 segments.
But I want whole URL in one segment. How can I get the whole URL?
Three is an one way that I found using substring
String webURL = str.substring(4, str.length());
Is there any other best way to that?

You can call String.split(String, int) where the second argument is a limit (or count). Something like,
String str = "url:http://www.google.com";
String[] arr = str.split(":", 2);
System.out.println(arr[1]);
Output is (as requested)
http://www.google.com

String str= "url:http://www.google.com";
// find the first : and take string beyond that
str = str.substring(str.indexOf(':')+1);
System.out.println(str);

String replace according to position?

I have this String 11101011.I want to replace last three char '011' with 101.is there any function of String in java to do so?

Use string.replaceAll function.
string.replaceAll(".{3}$", "101");
.{3} matches exactly three characters and $ asserts that the match must be followed by an end of the line.
Example:
String name = "11101011";
String result = name.replaceAll(".{3}$", "101");
System.out.println(result);
Output:
11101101

Using String replace and regular expressions for this task seems like breaking butterflies on a wheel - just cut the last three characters off and append the new suffix (ultimately verbose solution):
final String oldString = "11101011";
final String oldSuffix = oldString.substring(5);
final String reducedOldString = oldString.substring(0, oldString.length() - oldSuffix.length());
final String newSuffix = "101";
final String newString = reducedOldString.concat(newSuffix);
System.out.println("newString = " + newString);

Use replace method of String class
String s="11101011";
System.out.println(s.replace("011","101"));
O/P:
11101101

Split Java String

Title seems to be simple. But I don't get a good Idea. This is the situation
I have String like this in my Java program
String scz="3282E81WHT-22/24";
I want to split the above string into 3 Strings, such that
first string value should be 3282e81,
Next string should be WHT(ie, the String part of above string and this part is Always of 3 Characters ),
Next String value should be 22/24 (Which will always occur after -)
In short
String first= /* do some expression on scz And value should be "3282e81" */;
String second= /* do some expression on scz And value should be "WHT" */;
String third= /* do some expression on scz And value should be "22/24" */;
Input can also be like
scz="324P25BLK-12";
So 324P25 will be first String, BLK will be second (of 3 Characters). 12 will be third ( After - symbol )
How to solve this?

You can use a regex like this (\d+[A-Z]\d+)([A-Z]+)-([/\d]+) and using Matcher.group(int) method you can get your string splitted into three groups.
Code snippet
String str = "3282E81WHT-22/24";
//str = "324P25BLK-12";
Pattern pattern = Pattern.compile("(\\d+[A-Z]\\d+)([A-Z]+)-([/\\d]+)");
Matcher match = pattern.matcher(str);
System.out.println(match.matches());
System.out.println(match.group(1));
System.out.println(match.group(2));
System.out.println(match.group(3));
Output
true
3282E81
WHT
22/24

Use this to split the entire string in to two
String[] parts = issueField.split("-");
String first = parts[0];
String second= parts[1];
Use this to split the first string into two
if (first!=null && first.length()>=3){
String lastThree=first.substring(first.length()-3);
}

if your String's Second part (WHT) etc will always be of 3 Characters then following code will surely help you
String scz = "3282E81WHT-22/24";
String Third[] = scz.split("-");
String rev = new StringBuilder(Third[0]).reverse().toString();
String Second=rev.substring(0,3);
String First=rev.substring(3,rev.length());
// here Reverse your String Back to Original
First=new StringBuilder(First).reverse().toString();
Second=new StringBuilder(Second).reverse().toString();
System.out.println(First + " " + Second + " " + Third[1]);

You can use subString() method to get this goals.
subString has numbers of overloads.
for first string
String first=scz.subString(0,6);
String second=scz.subString(7,9);

You can use following regex to take out the above type string:
\d+[A-Z]\d{2}|[A-Z]{3}|(?<=-)[\d/]+
In Java, you can use above regex in following way:
Pattern pattern = Pattern.compile("\\d+[A-Z]\\d{2}|[A-Z]{3}|(?<=-)[\\d/]+");
Matcher matcher = pattern.matcher("3282E81WHT-22/24");
while (matcher.find()) {
System.out.println(matcher.group());
}
Output:
3282E81
WHT
22/24

You could us a char array instead of a string so you can access specific characters withing the array.
Example
char scz[] = "3282E81WHT-22/24";
and access the separate characters just by specifying the place in which the array you want to use.

You can try this
String scz="3282E81WHT-22/24";
String[] arr=scz.split("-");
System.out.println("first: "+arr[0].substring(0,7));
System.out.println("second: "+arr[0].substring(7,10));
System.out.println("third: "+arr[1])

Check out my solution -
class Main {
public static void main(String[] args) {
String first = "";
String second = "";
String third = "";
String scz="3282E81WHT-22/24";
String[] portions = scz.split("-");
if (portions.length > 1) {
third = portions[1];
}
String[] anotherPortions = portions[0].split("[a-zA-Z]+$");
if (anotherPortions.length > 0) {
first = anotherPortions[0];
}
second = portions[0].substring(first.length());
System.out.println(first);
System.out.println(second);
System.out.println(third);
}
}
Live Demo.

String scz="3282E81WHT-22/24";
String[] array = scz.split("-");
String str1 = (String) array[0].subSequence(0, 7);
String str2 = array[0].substring(7);
Then the split will be in this order :)
str1
str2
array[1]

if the length of string is fixed for scz, first,second and third the you can use
String first=scz.subString(0,6);
String second=scz.subString(7,9);
String third=scz.subString(10,scz.length());

What is the best way to extract the first word from a string in Java?

Trying to write a short method so that I can parse a string and extract the first word. I have been looking for the best way to do this.
I assume I would use str.split(","), however I would like to grab just the first first word from a string, and save that in one variable, and and put the rest of the tokens in another variable.
Is there a concise way of doing this?

The second parameter of the split method is optional, and if specified will split the target string only N times.
For example:
String mystring = "the quick brown fox";
String arr[] = mystring.split(" ", 2);
String firstWord = arr[0]; //the
String theRest = arr[1]; //quick brown fox
Alternatively you could use the substring method of String.

You should be doing this
String input = "hello world, this is a line of text";
int i = input.indexOf(' ');
String word = input.substring(0, i);
String rest = input.substring(i);
The above is the fastest way of doing this task.

To simplify the above:
text.substring(0, text.indexOf(' '));
Here is a ready function:
private String getFirstWord(String text) {
int index = text.indexOf(' ');
if (index > -1) { // Check if there is more than one word.
return text.substring(0, index).trim(); // Extract first word.
} else {
return text; // Text is the first word itself.
}
}

The simple one I used to do is
str.contains(" ") ? str.split(" ")[0] : str
Where str is your string or text bla bla :). So, if
str is having empty value it returns as it is.
str is having one word, it returns as it is.
str is multiple words, it extract the first word and return.
Hope this is helpful.

import org.apache.commons.lang3.StringUtils;
...
StringUtils.substringBefore("Grigory Kislin", " ")

You can use String.split with a limit of 2.
String s = "Hello World, I'm the rest.";
String[] result = s.split(" ", 2);
String first = result[0];
String rest = result[1];
System.out.println("First: " + first);
System.out.println("Rest: " + rest);
// prints =>
// First: Hello
// Rest: World, I'm the rest.
API docs for: split

for those who are searching for kotlin
var delimiter = " "
var mFullname = "Mahendra Rajdhami"
var greetingName = mFullname.substringBefore(delimiter)

like this:
final String str = "This is a long sentence";
final String[] arr = str.split(" ", 2);
System.out.println(Arrays.toString(arr));
arr[0] is the first word, arr[1] is the rest

You could use a Scanner
http://download.oracle.com/javase/1.5.0/docs/api/java/util/Scanner.html
The scanner can also use delimiters
other than whitespace. This example
reads several items in from a string:
String input = "1 fish 2 fish red fish blue fish";
Scanner s = new Scanner(input).useDelimiter("\\s*fish\\s*");
System.out.println(s.nextInt());
System.out.println(s.nextInt());
System.out.println(s.next());
System.out.println(s.next());
s.close();
prints the following output:
1
2
red
blue

None of these answers appears to define what the OP might mean by a "word". As others have already said, a "word boundary" may be a comma, and certainly can't be counted on to be a space, or even "white space" (i.e. also tabs, newlines, etc.)
At the simplest, I'd say the word has to consist of any Unicode letters, and any digits. Even this may not be right: a String may not qualify as a word if it contains numbers, or starts with a number. Furthermore, what about hyphens, or apostrophes, of which there are presumably several variants in the whole of Unicode? All sorts of discussions of this kind and many others will apply not just to English but to all other languages, including non-human language, scientific notation, etc. It's a big topic.
But a start might be this (NB written in Groovy):
String givenString = "one two9 thr0ee four"
// String givenString = "oňňÜÐæne;:tŵo9===tĥr0eè? four!"
// String givenString = "mouse"
// String givenString = "&&^^^%"
String[] substrings = givenString.split( '[^\\p{L}^\\d]+' )
println "substrings |$substrings|"
println "first word |${substrings[0]}|"
This works OK for the first, second and third givenStrings. For "&&^^^%" it says that the first "word" is a zero-length string, and the second is "^^^". Actually a leading zero-length token is String.split's way of saying "your given String starts not with a token but a delimiter".
NB in regex \p{L} means "any Unicode letter". The parameter of String.split is of course what defines the "delimiter pattern"... i.e. a clump of characters which separates tokens.
NB2 Performance issues are irrelevant for a discussion like this, and almost certainly for all contexts.
NB3 My first port of call was Apache Commons' StringUtils package. They are likely to have the most effective and best engineered solutions for this sort of thing. But nothing jumped out... https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html ... although something of use may be lurking there.

You could also use http://download.oracle.com/javase/6/docs/api/java/util/StringTokenizer.html

I know this question has been answered already, but I have another solution (For those still searching for answers) which can fit on one line:
It uses the split functionality but only gives you the 1st entity.
String test = "123_456";
String value = test.split("_")[0];
System.out.println(value);
The output will show:
123

The easiest way I found is this:
void main()
String input = "hello world, this is a line of text";
print(input.split(" ").first);
}
Output: hello

Assuming Delimiter is a blank space here:
Before Java 8:
private String getFirstWord(String sentence){
String delimiter = " "; //Blank space is delimiter here
String[] words = sentence.split(delimiter);
return words[0];
}
After Java 8:
private String getFirstWord(String sentence){
String delimiter = " "; //Blank space is delimiter here
String firstWord = Arrays.stream(sentence.split(delimiter))
.findFirst()
.orElse("No word found");
}

String anotherPalindrome = "Niagara. O roar again!";
String roar = anotherPalindrome.substring(11, 15);
You can also do like these