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I want to get last date of the month and add n months to it but calendar instance is taking only 30 days in Java

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Calendar calender = Calendar.getInstance();
calender.set(Calendar.DAY_OF_MONTH, calender.getActualMaximum(Calendar.DATE));
int months = 1;
calender.add(Calendar.MONTH, months );
String time = sdf .format(calender .getTime());
System.out.println(time);
Since current month is April and last date is 2020-04-30
Next month last date I should get 2020-05-31
but I am getting last date as 2020-05-30
Any thing am i doing wrong ?

java.time
I recommend that you use java.time, the modern Java date and time API, for your date work. It’s much nicer to work with than the old classes Calendar and SimpleDateFormat.
LocalDate endOfNextMonth =
YearMonth // Represent an entire month in a particular year.
.now(ZoneId.of("Europe/Volgograd")) // Capture the current year-month as seen in a particular time zone. Returns a `YearMonth` object.
.plusMonths(1) // Move to the next month. Returns another `YearMonth` object.
.atEndOfMonth(); // Determine the last day of that year-month. Returns a `LocalDate` object.
String time = endOfNextMonth.toString(); // Represent the content of the `LocalDate` object by generating text in standard ISO 8601 format.
System.out.println("Last day of next month: " + time);
Output when running today:
Last day of next month: 2020-05-31
A YearMonth, as the name maybe says, is a year and month without day of month. It has an atEndOfMonth method that conveniently gives us the last day of the month as a LocalDate. A LocalDate is a date without time of day, so what we need here. And its toString method conveniently gives the format that you wanted (it’s ISO 8601).
Depending on the reason why you want the last day of another month there are a couple of other approaches you may consider. If you need to handle date ranges that always start and end on month boundaries, you may either:
Represent your range as a range of YearMonth objects. Would this free you from knowing the last day of the month altogether?
Represent the end of your range as the first of the following month exclusive. Doing math on the 1st of each month is simpler since it is always day 1 regardless of the length of the month.
What went wrong in your code?
No matter if using Calendar, LocalDate or some other class you need to do things in the opposite order: first add one month, then find the end of the month. As you know, months have different lengths, so the important part is getting the end of that month where you want to get the last day. Putting it the other way: setting either a LocalDate or a Calendar to the last day of the month correctly sets it to the last day of the month in qustion but does not instruct it to stay at the last day of the month after subsequent changes to its value, such as adding a month. If you add a month to April 29, you get May 29. If you add a month to April 30, you get May 30. Here it doesn’t matter that 30 is the last day of April while 30 is not the last day of May.
Links
Oracle tutorial: Date Time explaining how to use java.time.
Wikipedia article: ISO 8601

You'd better use LocalDate like this:
LocalDate now = LocalDate.now();
LocalDate lastDay = now.withDayOfMonth(now.lengthOfMonth());
LocalDate nextMonth = lastDay.plusMonths(1);

Don't use deprecated classes from java.util.*.
Use classes from java.time.*.
Example with LocalDate :
public class Testing {
public static void main(String args[]) {
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
LocalDate date = LocalDate.now();
int months = 1;
date = date.plusMonths(months);
date = date.withDayOfMonth(date.lengthOfMonth());
System.out.println(date.format(dateTimeFormatter));
}
}
Output :
2020-05-31
Example with Calendar :
public class Testing {
public static void main(String args[]) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Calendar calender = Calendar.getInstance();
int months = 1;
calender.add(Calendar.MONTH, months);
calender.set(Calendar.DAY_OF_MONTH, calender.getActualMaximum(Calendar.DAY_OF_MONTH));
String time = sdf.format(calender.getTime());
System.out.println(time);
}
}
Output :
2020-05-31

Java8 java.time: how to change the day of the week and the start time of the day?

Say I want my week to start on Tuesday, and the day should start at 5:30 am.
This means, code like this should work:
// LocalDateTimes created with the "standard" ISO time
LocalDateTime tuesday_4_30 = LocalDateTime.now()
.with(TemporalAdjusters.next(DayOfWeek.TUESDAY))
.withHour(4).withMinute(30);
LocalDateTime tuesday_6_30 = tuesday_4_30.withHour(6).withMinute(30);
LocalDateTime previous_monday = tuesday_4_30.minusDays(1);
// eventual adjustment using TemporalAdjusters here? like this?
// tuesday_4_30 = tuesday_4_30.with(new MyTemporalAdjuster(DayOfWeek.TUESDAY, 5, 30));
// <do the same for 6_30 and previous monday>
// or possibly change some global parameter like Chronology, Locale, or such..
Assert.assertEquals(tuesday_4_30.getDayOfWeek(), DayOfWeek.MONDAY);
Assert.assertEquals(tuesday_6_30.getDayOfWeek(), DayOfWeek.TUESDAY);
// there is 1 week between the previous monday and the next tuesday 6:30
Assert.assertEquals( ChronoUnit.WEEKS.between(previous_monday,tuesday_6_30), 1);
// there is 0 week between the previous monday and the next tuesday 4:30
Assert.assertEquals( ChronoUnit.WEEKS.between(previous_monday,tuesday_4_30), 0);
// 1 day between tuesday_4_30 and tuesday_6_30
Assert.assertEquals( ChronoUnit.DAYS.between(tuesday_4_30,tuesday_6_30), 1);
// 0 day between previous_monday and tuesday_4_30
Assert.assertEquals( ChronoUnit.DAYS.between(previous_monday,tuesday_4_30), 1);
I am tempted to use temporal adjusters here, and I'm quite sure I could offset the hours and minute so that the day starts at 5:30, but I can't figure out how to modify the start of the week.
Note that I looked into WeekFields but I can't make it work with ChronoUnit.XXX.between(), so I didn't go too far. It looks like I would have to code my own Chronology, which seemed too far strectched.
Can you help me?

Note: ChronoUnit.WEEKS.between counts the number of entire weeks (a period of 7 days) between two dates. In your case, there is only one days between the Monday and the Tuesday so it will return 0. You probably meant to compare the week of year fields instead.
Unless you want to write your own chronology (that's going to be a pain), you could "fake" your calendar by:
converting back and forth between UTC and UTC+5:30 to represent your cut-off time / or just subtract 5:30 from the dates
adding some simple logic for the week calculations
See below a rough example based on your code, that makes all the tests pass - you may want to extract the logic into a separate class etc. This is a bit hacky but may be enough for your use case.
#Test
public void test() {
LocalDateTime tuesday_4_30 = LocalDateTime.now()
.with(TemporalAdjusters.next(DayOfWeek.TUESDAY))
.withHour(4).withMinute(30);
LocalDateTime tuesday_6_30 = tuesday_4_30.withHour(6).withMinute(30);
LocalDateTime previous_monday = tuesday_4_30.minusDays(1);
// eventual adjustment using TemporalAdjusters here? like this?
// tuesday_4_30 = tuesday_4_30.with(new MyTemporalAdjuster(DayOfWeek.TUESDAY, 5, 30));
// <do the same for 6_30 and previous monday>
// or possibly change some global parameter like Chronology, Locale, or such..
assertEquals(dayOfWeek(tuesday_4_30), DayOfWeek.MONDAY);
assertEquals(dayOfWeek(tuesday_6_30), DayOfWeek.TUESDAY);
// there is 1 week between the previous monday and the next tuesday 6:30
assertEquals(weekBetween(previous_monday, tuesday_6_30), 1);
// there is 0 week between the previous monday and the next tuesday 4:30
assertEquals(weekBetween(previous_monday, tuesday_4_30), 0);
// 1 day between tuesday_4_30 and tuesday_6_30
assertEquals(weekBetween(tuesday_4_30, tuesday_6_30), 1);
// 0 day between previous_monday and tuesday_4_30
assertEquals(weekBetween(previous_monday, tuesday_4_30), 0);
}
private static DayOfWeek dayOfWeek(LocalDateTime date) {
return date.atOffset(ZoneOffset.ofHoursMinutes(5, 30)).withOffsetSameInstant(UTC).getDayOfWeek();
}
private static int weekBetween(LocalDateTime date1, LocalDateTime date2) {
OffsetDateTime date1UTC = date1.atOffset(ZoneOffset.ofHoursMinutes(5, 30)).withOffsetSameInstant(UTC);
OffsetDateTime date2UTC = date2.atOffset(ZoneOffset.ofHoursMinutes(5, 30)).withOffsetSameInstant(UTC);
int w1 = date1UTC.get(IsoFields.WEEK_OF_WEEK_BASED_YEAR);
if (dayOfWeek(date1).getValue() >= TUESDAY.getValue()) w1++;
int w2 = date2UTC.get(IsoFields.WEEK_OF_WEEK_BASED_YEAR);
if (dayOfWeek(date2).getValue() >= TUESDAY.getValue()) w2++;
return w2 - w1;
}
Alternative implementation, maybe cleaner:
private static DayOfWeek dayOfWeek(LocalDateTime date) {
return adjust(date).getDayOfWeek();
}
private static int weekBetween(LocalDateTime date1, LocalDateTime date2) {
int w1 = adjust(date1).get(IsoFields.WEEK_OF_WEEK_BASED_YEAR);
if (dayOfWeek(date1).getValue() >= TUESDAY.getValue()) w1++;
int w2 = adjust(date2).get(IsoFields.WEEK_OF_WEEK_BASED_YEAR);
if (dayOfWeek(date2).getValue() >= TUESDAY.getValue()) w2++;
return w2 - w1;
}
private static LocalDateTime adjust(LocalDateTime date) {
return date.minusHours(5).minusMinutes(30);
}

Determine which day of week is each date of the month

I want to create a calendar with Java 8. So far I have this:
YearMonth yearMonthObject = YearMonth.of(year, month);
int daysOfCurrentMonth = yearMonthObject.lengthOfMonth();
int i = 1;
ArrayList<Integer> Dayes = new ArrayList<Integer>();
for(i=1; i<=daysOfCurrentMonth; i++){
Dayes.add(i);
}
Dayes.forEach(value -> System.out.print(value));
which prints the days of the current month (for example May).
How can I determine that 1 is Sunday, 2 is Monday, 3 is Tuesday, ..., 8 is Sunday (next week), etc.?

You have a YearMonth object. For each day of the month, you can call atDay(dayOfMonth) to return a LocalDate at that specific day of month. With that LocalDate, you can then call:
getDayOfMonth() to get back the day of the month as an int;
getDayOfWeek() to get the day of the week as a DayOfWeek. This is an enumeration of all the days of the week.
As such, you should change your Dayes list to hold LocalDates instead of Integers, and then you can have, for example:
YearMonth yearMonthObject = YearMonth.of(year, month);
int daysOfCurrentMonth = yearMonthObject.lengthOfMonth();
ArrayList<LocalDate> dayes = new ArrayList<LocalDate>();
for(int i = 1; i <= daysOfCurrentMonth; i++){
dayes.add(yearMonthObject.atDay(i));
}
dayes.forEach(value -> System.out.println(value.getDayOfMonth() + " " + value.getDayOfWeek()));
This will print each day of that month followed by the corresponding day of the week.
As a side-note, you can get a real display value for the day of week (instead of the name() of the enum like above) by calling getDisplayName(style, locale). The style represents how to write the days (long form, short form...) and the locale is the locale to use for the display name. An example would be:
value.getDayOfWeek().getDisplayName(TextStyle.FULL, Locale.ENGLISH)
which would output the full text of the day of the week in English. Sample output for 04/2016 with the above change:
1 Friday
2 Saturday
3 Sunday
4 Monday
5 Tuesday

This may be a bit of a 'hack' solution, but if you are trying to make a calendar for any year, you may have to use an 'anchor date' (Such as January 1, 1800 as a Wednesday). You then could calculate the number of days that happened between January 1st, 1800 and your current year/month/day. Once you figured out how many days have passed, using Modular 7 you could determine what day it is, and then populate the calendar for the month from there.

How to extract the data basis on it is Monday or Thursday in YYYYMMDD format?

I am trying to get the date of Monday or Thurday in this format YYYYMMDD
For Monday it should give me this - 20130224 (as an example)
For Thursday it should give me this - 20130227 (as an example)
Now, if I am running my program after Thursday or on Thursday, it should print date for Thursday in this format YYYYMMDD which can be 20130227 (coming thursday in this week).
And If I am running my program after Monday or on Monday, then it should print date for Monday in the same format YYYYMMMDD which can be 20130224 (yesterday Monday date as an example)
How would I do this in Java?
Below is what I have tried -
Calendar cal = Calendar.getInstance();
SimpleDateFormat formatter = new SimpleDateFormat("EEE");
String text = formatter.format(cal.getTime());
System.out.println(text);
// but how do I check if it is Tuesday but less than Thursday
if(text.equalsIgnoreCase("Tue")) {
// get previous Monday date in YYYYMMDD
}
// and how do I check if it is thursday or greater than Thursday?
else if(text.equalsIgnoreCase("Thur")) {
// get previous Thursday date in YYYYMMDD
}
Update:-
In a particular week, if I am running my program on Thursday or after Thursday then it should return me date for Thursday in the same week in YYYYMMDD format, but if I am running my program on Monday or after Monday, then it should return me date for Monday in the same week in YYYYMMDD format.
For example, In this week, if I am running my program on Thursday or after Thursday, then it should return date for Thursday. But if I am running my program on Monday or Tuesday or Wednesday in this same week, then it should return me date for Monday.
Code:-
Below is my code -
public static void main(String[] args) {
try {
Calendar cal = Calendar.getInstance();
SimpleDateFormat toDateFormat = new SimpleDateFormat("yyyyMMdd");
int dow = cal.get(Calendar.DAY_OF_WEEK);
switch (dow) {
case Calendar.THURSDAY:
case Calendar.FRIDAY:
case Calendar.SATURDAY:
case Calendar.SUNDAY:
while (cal.get(Calendar.DAY_OF_WEEK) != Calendar.THURSDAY) {
cal.add(Calendar.DATE, -1);
}
break;
case Calendar.MONDAY:
case Calendar.TUESDAY:
case Calendar.WEDNESDAY:
while (cal.get(Calendar.DAY_OF_WEEK) != Calendar.MONDAY) {
cal.add(Calendar.DATE, -1);
}
break;
}
System.out.println(date);
System.out.println(cal.getTime());
System.out.println(toDateFormat.format(cal.getTime()));
} catch (ParseException exp) {
exp.printStackTrace();
}
}

Start by parsing the text value to a Date value...
String dateText = "20130224";
SimpleDateFormat toDateFormat = new SimpleDateFormat("yyyyMMdd");
Date date = toDateFormat.parse(dateText);
This gives you the starting point. Next you need to use a Calendar which will allow you move backwards and forwards, automatically rolling the date internally for you (so if you roll over week, month or year boundaries)
For example...
try {
String dateText = "20130227";
SimpleDateFormat toDateFormat = new SimpleDateFormat("yyyyMMdd");
Date date = toDateFormat.parse(dateText);
Calendar cal = Calendar.getInstance();
cal.setTime(date);
int dow = cal.get(Calendar.DAY_OF_WEEK);
switch (dow) {
case Calendar.THURSDAY:
case Calendar.FRIDAY:
case Calendar.SATURDAY:
case Calendar.SUNDAY:
while (cal.get(Calendar.DAY_OF_WEEK) != Calendar.THURSDAY) {
cal.add(Calendar.DATE, -1);
}
break;
case Calendar.MONDAY:
case Calendar.TUESDAY:
case Calendar.WEDNESDAY:
while (cal.get(Calendar.DAY_OF_WEEK) != Calendar.MONDAY) {
cal.add(Calendar.DATE, -1);
}
break;
}
System.out.println(date);
System.out.println(cal.getTime());
} catch (ParseException exp) {
exp.printStackTrace();
}
So, based on this example, it would output...
Wed Feb 27 00:00:00 EST 2013
Mon Feb 25 00:00:00 EST 2013
For 20130224 (which is a Sunday) it will give
Sun Feb 24 00:00:00 EST 2013
Thu Feb 21 00:00:00 EST 2013
I should also add, there's probably a much easier way to do this with JodaTime, but this is what I was able to wipe up quickly. Yes, I know the case statement is little winded, but SUNDAY is equal to 0, which is a little annoying ;)

What? Moving to a new question with the same contents?
String[] weeks = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
DateFormat df = new SimpleDateFormat("yyyyMMdd");
Calendar c = Calendar.getInstance();
c.setTime(new Date()); // Now use today date.
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK); // Sun=1, Mon=2, ... Sat=7
System.out.println("Today " + df.format(c.getTime()) + " is " + weeks[dayOfWeek-1]);
c.add(Calendar.DATE, 7); // Adding 7 days
System.out.println("Next " + weeks[dayOfWeek-1] + " is " + df.format(c.getTime()));
// Should display:
// Today 20140225 is Tuesday
// Next Tuesday is 20140304

I would use the calendar class day to get the day of the week. Calendar.DAY_OF_WEEK function returns 1 - 7 for Sunday - Saturday. This way you can do numeric comparison and not mess around with comparing the strings for the weekdays (which would be a mess if your app needs to support multiple languages).
See:
http://docs.oracle.com/javase/7/docs/api/java/util/Calendar.html

If I understood what you're after, then this should work
private static final java.text.SimpleDateFormat sdf =
new java.text.SimpleDateFormat("yyyyMMdd");
public static String calculateCorrectDate(
java.util.Date d) {
java.util.Calendar cal = java.util.Calendar
.getInstance();
cal.setTime(d);
int dayOfWeek = cal
.get(java.util.Calendar.DAY_OF_WEEK);
if (dayOfWeek >= java.util.Calendar.MONDAY
&& dayOfWeek < java.util.Calendar.THURSDAY) {
cal.set(java.util.Calendar.DAY_OF_WEEK,
java.util.Calendar.MONDAY);
} else {
cal.set(java.util.Calendar.DAY_OF_WEEK,
java.util.Calendar.THURSDAY);
}
return sdf.format(cal.getTime());
}
public static void main(String[] args) {
java.util.List<java.util.Date> dates = new java.util.ArrayList<java.util.Date>();
java.util.Calendar cal = java.util.Calendar
.getInstance();
String today = sdf.format(cal.getTime());
cal.add(java.util.Calendar.DAY_OF_WEEK, -10);
for (int i = 0; i < 20; i++) {
dates.add(cal.getTime());
cal.add(java.util.Calendar.DAY_OF_WEEK, 1);
}
for (java.util.Date d : dates) {
if (sdf.format(d).equals(today)) {
System.out.println("TODAY!");
}
System.out.println(calculateCorrectDate(d));
}
}
Which gives the output
20140213
20140220
20140217
20140217
20140217
20140220
20140220
20140220
20140227
20140224
TODAY!
20140224
20140224
20140227
20140227
20140227
20140306
20140303
20140303
20140303
20140306
or with a few import(s),
// Import Static
// This simplifies accessing the Calendar fields. Use sparingly.
import static java.util.Calendar.DAY_OF_WEEK;
import static java.util.Calendar.MONDAY;
import static java.util.Calendar.THURSDAY;
// The other imports.
import java.util.Calendar;
import java.util.Date;
Then you can use,
public static String calculateCorrectDate(Date d) {
Calendar cal = Calendar.getInstance();
cal.setTime(d);
// By using import static this remains concise and correct.
int dayOfWeek = cal.get(DAY_OF_WEEK);
if (dayOfWeek >= MONDAY && dayOfWeek < THURSDAY) {
cal.set(DAY_OF_WEEK, MONDAY);
} else {
cal.set(DAY_OF_WEEK, THURSDAY);
}
return sdf.format(cal.getTime());
}

Joda-Time
UPDATE: The Joda-Time project is now in maintenance mode, with the team advising migration to the java.time classes. This Answer is left intact as history. See my modern Answer instead.
Yes, Joda-Time is the solution.
Or the new java.time package in Java 8. Inspired by Joda-Time but re-architected. Defined by JSR 310.
Next Monday/Thursday
Search StackOverflow for getting first or last day of week. That will show you how to get next monday or thursday. I won't cover that part of your question here.
Testing Day Of Week
Testing for the day of week by the English word is prone to break if you ever happen to run where English is not the default locale. Instead, get day of week by number. Joda-Time uses ISO 8601 as its defaults, so Monday = 1, Sunday = 7. Constants are provided, so you needn't memorize the numbers.
Date Without Time
If you truly don't care about time-of-day, only date, then we can use LocalDate rather than DateTime.
Example Code
Some code to get you started, using Joda-Time 2.3.
String input = "20130224";
DateTimeFormatter formatterInput = DateTimeFormat.forPattern( "yyyyMMdd" );
LocalDate localDate = formatterInput.parseLocalDate( input );
int dayOfWeek = localDate.getDayOfWeek();
boolean isMonday = ( localDate.getDayOfWeek() == DateTimeConstants.MONDAY );
boolean isThursday = ( localDate.getDayOfWeek() == DateTimeConstants.THURSDAY );
Dump to console…
System.out.println( "localDate: " + localDate );
System.out.println( "dayOfWeek: " + dayOfWeek );
System.out.println( "isMonday: " + isMonday );
System.out.println( "isThursday: " + isThursday );
When run…
localDate: 2013-02-24
dayOfWeek: 7
isMonday: false
isThursday: false

tl;dr
If:
EnumSet.range( DayOfWeek.MONDAY , DayOfWeek.WEDNESDAY ) // Monday, Tuesday, & Wednesday.
contains( LocalDate.now().getDayOfWeek() ) // If today’s date is a day-of-week that happens to be a member of that `Set`.
…then, apply:
TemporalAdjusters.previousOrSame( DayOfWeek.MONDAY ) // Adjust into an earlier `LocalDate` that is a Monday, unless today already is Monday.
…else apply:
TemporalAdjusters.previousOrSame( DayOfWeek.THURSDAY ) // Otherwise move to a Thursday.
java.time
The modern approach uses the java.time classes. So much easier to solve this Question.
LocalDate
The LocalDate class represents a date-only value without time-of-day and without time zone.
A time zone is crucial in determining a date. For any given moment, the date varies around the globe by zone. For example, a few minutes after midnight in Paris France is a new day while still “yesterday” in Montréal Québec.
If no time zone is specified, the JVM implicitly applies its current default time zone. That default may change at any moment, so your results may vary. Better to specify your desired/expected time zone explicitly as an argument.
Specify a proper time zone name in the format of continent/region, such as America/Montreal, Africa/Casablanca, or Pacific/Auckland. Never use the 3-4 letter abbreviation such as EST or IST as they are not true time zones, not standardized, and not even unique(!).
ZoneId z = ZoneId.of( "America/Montreal" ) ;
LocalDate today = LocalDate.now( z ) ;
If you want to use the JVM’s current default time zone, ask for it and pass as an argument. If omitted, the JVM’s current default is applied implicitly. Better to be explicit.
ZoneId z = ZoneId.systemDefault() ; // Get JVM’s current default time zone.
Or specify a date. You may set the month by a number, with sane numbering 1-12 for January-December.
LocalDate ld = LocalDate.of( 1986 , 2 , 23 ) ; // Years use sane direct numbering (1986 means year 1986). Months use sane numbering, 1-12 for January-December.
Or, better, use the Month enum objects pre-defined, one for each month of the year. Tip: Use these Month objects throughout your codebase rather than a mere integer number to make your code more self-documenting, ensure valid values, and provide type-safety.
LocalDate ld = LocalDate.of( 1986 , Month.FEBRUARY , 23 ) ;
DayOfWeek enum
The DayOfWeek enum defines a set of seven objects, one for each day of the week.
An EnumSet is a highly-optimized implementation of Set for collecting enum objects. So we can make a pair of EnumSet objects to hold a collection of DayOfWeek objects to define your two conditions: (Monday & Tuesday) versus (Thursday…Sunday).
Despite mysteriously failing to implement SortedSet, an EnumSet is indeed sorted in the natural order (declared order) of the enum. For DayOfWeek that would be Monday-Sunday, numbered 1-7 though you may never need those numbers.
Set < DayOfWeek > mondayDays = EnumSet.range( DayOfWeek.MONDAY , DayOfWeek.WEDNESDAY ); // Monday, Tuesday, & Wednesday.
Set < DayOfWeek > thursdayDays = EnumSet.range( DayOfWeek.THURSDAY , DayOfWeek.SUNDAY ); // Thursday, Friday, Saturday, Sunday.
Get the day-of-week for our source date. Prepare to match that against our enum sets.
LocalDate ld = LocalDate.now( ZoneId.of( "Africa/Tunis" ) ) ; // Get today’s current date in a particular time zone.
DayOfWeek dow = ld.getDayOfWeek();
LocalDate target = LocalDate.EPOCH; // Or null. The `LocalDate.EPOCH` is first moment of 1970 in UTC, 1970-01-01T00:00:00Z.
See which Set has the day-of-week of our date. From there, adjust into a previous or same date for the desired day-of-week (Monday or Thursday).
if ( mondayDays.contains( dow ) )
{
target = ld.with( TemporalAdjusters.previousOrSame( DayOfWeek.MONDAY ) );
} else if ( thursdayDays.contains( dow ) )
{
target = ld.with( TemporalAdjusters.previousOrSame( DayOfWeek.THURSDAY ) );
} else
{
System.out.println( "ERROR - Unexpectedly reached IF-ELSE. " );
}
Generate string in your desired format. Your chosen format happens to be the “basic” version of standard ISO 8601 format where the use of delimiters is minimized.
String output = target.format( DateTimeFormatter.BASIC_ISO_DATE ) ; // YYYY-MM-DD
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
Where to obtain the java.time classes?
Java SE 8, Java SE 9, and later
Built-in.
Part of the standard Java API with a bundled implementation.
Java 9 adds some minor features and fixes.
Java SE 6 and Java SE 7
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
Later versions of Android bundle implementations of the java.time classes.
For earlier Android, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above). See How to use ThreeTenABP….
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.

Joda-Time: convert day of week from joda to java.util [duplicate]

How do you determine which day of the week is considered the “start” according to a given Locale using Joda-Time?
Point: Most countries use the international standard Monday as first day of week (!). A bunch others use Sunday (notably USA). Others apparently Saturday. Some apparently Wednesday?!
Wikipedia "Seven-day week"#Week_number

Joda-Time uses the ISO standard Monday to Sunday week.
It does not have the ability to obtain the first day of week, nor to return the day of week index based on any day other than the standard Monday. Finally, weeks are always calculated wrt ISO rules.

There's no reason you can't make use of the JDK at least to find the "customary start of the week" for the given Locale. The only tricky part is translating constants for weekdays, where both are 1 through 7, but java.util.Calendar is shifted by one, with Calendar.MONDAY = 2 vs. DateTimeConstants.MONDAY = 1.
Anyway, use this function:
/**
* Gets the first day of the week, in the default locale.
*
* #return a value in the range of {#link DateTimeConstants#MONDAY} to
* {#link DateTimeConstants#SUNDAY}.
*/
private static final int getFirstDayOfWeek() {
return ((Calendar.getInstance().getFirstDayOfWeek() + 5) % 7) + 1;
}
Add a Locale to Calendar.getInstance() to get a result for some Locale other than the default.

Here is how one might work around Joda time to get the U.S. first day of the week:
DateTime getFirstDayOfWeek(DateTime other) {
if(other.dayOfWeek.get == 7)
return other;
else
return other.minusWeeks(1).withDayOfWeek(7);
}
Or in Scala
def getFirstDayOfWeek(other: DateTime) = other.dayOfWeek.get match {
case 7 => other
case _ => other.minusWeeks(1).withDayOfWeek(7)
}

Seems like you're out of luck, it looks like all of the provided Chronologies inherit the implementation from baseChronology, which supports only ISO definitions,
i.e. Monday=1 ... Sunday=7.
You would have to define your own LocaleChronology, possibly modeled on StrictChronology or LenientChronology, add a factory method:
public static LocaleChronology getInstance(Chronology base, Locale locale)
and override the implementation of
public final DateTimeField dayOfWeek()
with a re-implementation of java.util.Calendar.setWeekCountData(Locale desiredLocale) which relies on sun.util.resources.LocaleData..getCalendarData(desiredLocale).

This is what I came up with. The startOfWeek will always be the start of a Sunday and the endOfweek will always be an end of a Saturday(Start a of Monday).
DateTime startOfWeek;
DateTime endOfWeek;
// make sure Sunday is the first day of the week, not Monday
if (dateTime.getDayOfWeek() == 7) {
startOfWeek = dateTime.plusDays(1).weekOfWeekyear().roundFloorCopy().minusDays(1);
endOfWeek = dateTime.plusDays(1).weekOfWeekyear().roundCeilingCopy().minusDays(1);
} else {
startOfWeek = dateTime.weekOfWeekyear().roundFloorCopy().minusDays(1);
endOfWeek = dateTime.weekOfWeekyear().roundCeilingCopy().minusDays(1);
}

Here is the Scala code to get start and end day of week dynamically.
Note:- Make sure start and end are in order for example when start day is Sunday then Monday is end day of week
def shiftWeeksBy(startDayOfWeek: Int, currentWeekDay: Int) : Int = (startDayOfWeek, currentWeekDay) match {
case (s, c) if s <= c | s == 1 => 0 //start day of week is Monday -OR- start day of week <= current week day
case _ => 1
}
def getStartAndEndDays(initialTime: DateTime, startDayOfWeek: Int, endDayOfWeek: Int): (Option[DateTime], Option[DateTime]) = {
val currentDateWeekDay = initialTime.dayOfWeek.get
(Some(initialTime.minusWeeks(shiftWeeksBy(startDayOfWeek, currentDateWeekDay)).withDayOfWeek(startDayOfWeek).withTimeAtStartOfDay()),
Some(initialTime.plusWeeks(shiftWeeksBy(currentDateWeekDay, endDayOfWeek)).withDayOfWeek(endDayOfWeek)))
}
Output:- For 5th Jan 2021 start day of week is Thursday and end day of week is Wednesday then week begins with 2020-12-31 and end with 2021-01-06.
scala> getStartAndEndDays(new DateTime("2021-01-05T00:00:00.000"), 4, 3)
res5: (Option[org.joda.time.DateTime], Option[org.joda.time.DateTime]) = (Some(2020-12-31T00:00:00.000+05:30),Some(2021-01-06T00:00:00.000+05:30))

So your question is, how to get the DayOfWeek from a Joda DateTime object? What about this:
DateTime dt = new DateTime().withYear(2009).plusDays(111);
dt.toGregorianCalendar().getFirstDayOfWeek();

I used the following stub in Scala to obtain first and last days of the week from Joda DateTime
val today: DateTime = new DateTime()
val dayOfWeek: DateTime.Property = today.dayOfWeek()
val firstDayOfWeek: DateTime = dayOfWeek.withMinimumValue().minusDays(1)
val lastDayOfWeek: DateTime = dayOfWeek.withMaximumValue().minusDays(1)
Note: The minusDays(1) is only meant to make the week span from Sunday to Saturday (instead of the default Monday to Sunday known to Joda). For US (and other similar) locales, you can ignore this part