Can you help me with this, please?
I would like to get only specified WORD from the below String.
String test1="This is WORD test".
I did this:
String regex = "\\s*\\bWORD\\b\\s*";
Text= test1.replaceAll(regex, " ");
and I get this: This is test
But what I want is the opposite: I want only the part matching the regex.
Sometime my String could be:
String test2="WORD it is the text"
String test3="Text WORD"
But all the time I would like to cut only specified word and put into other string. Thanks
Simple solution using regular expression where I only check for the word being either surrounded by space or at the beginning of the line with space after or at the end of the line with space before.
String regex = "( WORD )|(^WORD )|( WORD$)";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(test1);
if (m.find()) {
System.out.println("[" + m.group(0).trim() + "]");
}
EDIT
A possible way to solve this
String test1 = "This is WORD test";
String wordToFind = "WORD";
String message = "";
int k = 0;
for (int i = -1; (i = test1.indexOf(wordToFind, i + 1)) != -1; i++) {
k = i;
}
String s = test1.substring(k, k+ (wordToFind.length()));
if(s.equals(wordToFind)){
message = s;
} else {
message = "The word \"" + wordToFind + "\" was not found in \"" + test1 + "\"";
}
System.out.print(message);
I have tried using
title.substring(title.lastIndexOf("(") + 1, title.indexOf(")"));
I only want to extract year like 1899.
It works well for string like "hadoop (1899)" but is throwing errors for string "hadoop(yarn)(1980)"
Simply replace all but the digits within parenthesis with a regex
String foo = "hadoop (1899)"; // or "hadoop(yarn)(1980)"
System.out.println(foo.replaceAll(".*\\((\\d+)\\).*", "$1"));
Hi check this example. This is regex for extracting numbers surrounded by brackets.
Here is usable code you can use:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
final String regex = "(?<=\\()\\d+(?=\\))";
final String string = "\"hadoop (1899)\" \"hadoop(yarn)(1980)\"";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
I have a string which looks like below.
{(firstName1,lastName1,College1,{(24,25)},{(Street,23)},City1,Country1)}
I need to extract the details/values from the above and add them to a list. By details I mean:
["firstName1","lastName1","College1","24","25","Street","23","City1", "country1"]
How can I achieve the above? I tried the below method but not sure how to get all curly braces and brackets into the pattern.
private static String flattenPigBag(String pigdata) {
String s = "";
Pattern p = Pattern.compile("\\{(.*)}");
Matcher m = p.matcher(pigdata);
while (m.find()) {
s = m.group(1);
System.out.println("answer : " + s);
}
return s;
}
Try this:
String[] parts = str.replaceAll("}|\\{", "").split(",");
Are you forced to use a pattern? If not, feel free to use this.
private static List<String> flattenPigBag(String s) {
return Arrays.asList(s.replaceAll("[(){}]", "").split(","));
}
Output:
[firstName1, lastName1, College1, 24, 25, Street, 23, City1, Country1]
I assume you need to extract the individual fields for further processing. So here is what I would do. In my test program I just print out the fields, but I imagine in your program you may take those field values and use them somehow (e.g. apply them to some setters of a Java object)
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexMatchingWithNamedCaptureGroup {
public static void main(String[] args) {
String regex = "\\{(\\("
+ "(?<firstName>[^,]*)"
+ ",(?<lastName>[^,]*)"
+ ",(?<college>[^,]*)"
+ ",\\{\\("
+ "(?<num1>\\d*)"
+ ",(?<num2>\\d*)\\)\\}"
+ ",\\{\\((?<street>[^,]*)"
+ ",(?<streetNum>\\d*)\\)\\}"
+ ",(?<city>[^,]*)"
+ ",(?<country>[^,]*)"
+ "\\))\\}";
String input
= "{(firstName1,lastName1,College1,{(24,25)},{(Street,23)},City1,Country1)}";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(input);
if (m.find()) {
String firstName = m.group("firstName");
String lastName = m.group("lastName");
String college = m.group("college");
String num1 = m.group("num1");
String num2 = m.group("num2");
String street = m.group("street");
String streetNum = m.group("streetNum");
String city = m.group("city");
String country = m.group("country");
System.out.println(firstName
+ "," + lastName
+ "," + college
+ "," + num1
+ "," + num2
+ "," + street
+ "," + streetNum
+ "," + city
+ "," + country
);
} else {
System.err.println("Does not match!");
}
}
}
The output of this program is this:
firstName1,lastName1,College1,24,25,Street,23,City1,Country1
I have encrypted text wraped with brackets, i'm trying to get only the text [|kXS6k~R5I~Q5gHR&f3gzJ[X] -->|kXS6k~R5I~Q5gHR&f3gzJ[X
Found this pattern [\[\](){}] , it works but split until first brackets or if there are parenthesesit will split the text untill them .
thanks
You can try this: "\[(.*?)\]". And don't forget to have the backslash escaped in your string otherwise it will give you error
String string = "[AA{R7QHQ8onQ~QXR7UXQzM\e{J6Y]";
String regex = "\\[(.*?)\\]";
String string = "[AA{R7QHQ8onQ~QXR7UXQzM\\e{J6Y]";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
I've been trying to replace this mathematical function x^2*sqrt(x^3) to this pow(x,2)*Math.sqrt(pow(x,3))
so this is the regex
/([0-9a-zA-Z\.\(\)]*)^([0-9a-zA-Z\.\(\)]*)/ pow(\1,\2)
it works in ruby, but I can't find a way to do it in java, I tried this method
String function= "x^2*sqrt(x^3)";
Pattern p = Pattern.compile("([a-z0-9]*)^([a-z0-9]*)");
Matcher m = p.matcher(function);
String out = function;
if(m.find())
{
System.out.println("GRUPO 0:" + m.group(0));
System.out.println("GRUPO 1:" + m.group(1));
out = m.replaceFirst("pow(" + m.group(0) + ", " + m.group(1) + ')');
}
String funcformat = out;
funcformat = funcformat.replaceAll("sqrt\\(([^)]*)\\)", "Math.sqrt($1)");
System.out.println("Return Value :"+ funcion );
System.out.print("Return Value :"+ funcformat );
But still doesn´t work, the output is: pow(x, )^2*Math.sqrt(x^3) as I said before it should be pow(x,2)*Math.sqrt(pow(x,3)).
Thank you!!
As others have commented, regex is not the way to go. You should use a parser. But if you want some quick and dirty:
From Matcher:
Capturing groups are indexed from left to right, starting at one.
Group zero denotes the entire pattern, so the expression m.group(0)
is equivalent to m.group().
So you need to use m.group(1) and m.group(2). And escape the caret ^ in your regex.
import java.util.regex.*;
public class Replace {
public static void main(String[] args) {
String function= "x^2*sqrt(3x)";
Pattern p = Pattern.compile("([a-z0-9]*)\\^([0-9]*)");
Matcher m = p.matcher(function);
String out = function;
if (m.find()) {
System.out.println("GRUPO 0:" + m.group(1));
System.out.println("GRUPO 1:" + m.group(2));
out = m.replaceFirst("pow(" + m.group(1) + ", " + m.group(2) + ')');
}
String funcformat = out;
funcformat = funcformat.replaceAll("sqrt\\(([a-z0-9]*)\\^([0-9]*)]*\\)", "Math.sqrt(pow($1, $2))");
System.out.println("Return Value :"+ function );
System.out.print("Return Value :"+ funcformat );
}
}