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I need to create a test which will have base URL (https://www.horisen.com) and added part with country code (i.e https://www.horisen.com/se). Problem for me is there are 12 countries to be changed.
I tried to create if loop without any success.
So, in summary, I have to go through all 12 different languages, open those pages in current languages, and continue with next lang. I suppose that I need an array of 12 country codes and call that in a loop, but do not know how to acchieve this.
Thank you in advance
String url = htps://www.horisen.com/
int[] array;
array = new int[6];
array[0] = de;
array[1] = se;
array[2] = dk;
array[3] = fr;
array[4] = en;
array[5] = fi;
for(int i=0; i++) {
do not know how to add after string url country code on the ned
}
Next time, please put some actual java code (that compiles) in your example. Perhaps you're looking for something like this:
String url = "https://www.horisen.com/";
String[] countryCodes = {"de", "se", "dk", "fr", "en", "fi"};
for (String countryCode : countryCodes) {
String countryUrl = url + countryCode;
System.out.println(countryUrl);
}
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creditTIDstatusArray=[93312263-1-09722612223, 99802001-1-09102842369, 99802002-1-09102842369];
creditTIDstatusList.addAll(Arrays.asList(creditTIDstatusArry));
searchValue="99802002-1".
int retval=creditTIDstatusList.indexOf("99802002-1");
System.out.println("The element at index is:" retval);
Output: 2
Please let me know how I can find the index of the given above(searchValue)element.
As you never have posted the reproducible code.
Assumptions
creditTIDstatusArray is a String type array.
Your search query always stays in front of each String value in the array.
Multiple indexes may start with the same search value.
String[] creditTIDstatusArray=new String[]{"93312263-1-09722612223", "99802001-1-09102842369", "99802002-1-09102842369"};
String searchValue="99802002-1";
for (int i = 0; i < creditTIDstatusArray.length; i++) {
if(creditTIDstatusArray[i].startsWith(searchValue)){
System.out.println("Index :" + I); // this will print all the indexes that starts with searchvalue
}
}
I am not sure why you have added the array into a list and then searched index of because it will never work as you are searching only part of a String rather than the whole value or object.
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In Python, below code can be run:
str = "i = %s"
print(str % i)
or
str = "i = {}"
print(str.format(i))
I know that Java can format string using
String str = String.format("i = %s", i);
But, I want to separate "i = %s" and i to make "i = %s" variable and use it on other codes, like below:
String pathFormat = "/v2.0/%s/search";
System.out.println(String.format(pathFormat, userId);
Is it possible in Java?
Yes, you can do that in Java just as in your last example.
String numberFormat = "i = %s";
int i = 17;
System.out.println(String.format(numberFormat, i));
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How can I remove multiple characters by their index from a string. I thought to use StringBuilder's deleteCharAt function. But if I delete char one by one, I will not keep track the right index.
For example :
String test = "0123456789"
int[] removingIndice = int[] {2, 4, 0};
// remove character from string
// result = "1356789"
Create a new string builder,
iterate on string, add elements to builder if its index not in the array
StringBuilder sb = new StringBuilder("");
for(int i = 0; i< test.length; i++){
if( !ArrayUtils.contains(removingIndice, i))
{
sb.append(test.charAt(i));
}
}
test = sb.toString();
String is immutable in Java, so you will need to create a new String with characters at positions 0,2,4 removed. As one option, you may use StringBuilder for that, as answered here: How to remove single character from a String
I think, you need to redesign the task:
"new string must contains all characters except ..."
Now, seems weak initial data structure and the goal.
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I have just declared a two-dimensional array in my program:
String[][] choices = new String[4][];
choices[0] = new String[10];
choices[1] = new String[20];
choices[2] = new String[20];
choices[3] = new String[20];
However, IntelliJ Idea, the IDE I am currently using, threw out a bunch of errors starting from the second line. What is wrong with my code? I have checked other questions regarding two-dimensional arrays and found the exact same syntax being used.
EDIT: Based on my code above, I want the arrays to be of different length. Is that possible to make?
Your code snippet works fine, and you can have inner String arrays of different length, e.g.:
String[][] choices = new String[2][];
choices[0] = new String[1];
choices[1] = new String[2];
choices[0][0] = "Foo";
choices[1][0] = "Bar";
choices[1][1] = "Baz";
System.out.println(choices[0][0] + " " + choices[1][0] + " " + choices[1][1]);
Ideone demonstration.
In short, your problem is elsewhere. Read the errors since that's what they're for. They're often descriptive enough.
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I have this string I got from a table via 'string.split(" ");' the problem I have is one of them should include a period. How would I go about searching for this period. I do know I have to search for it because I code in Lua. Though we used String.find() methods.
What is the way I would remove a period from a string in a String[] table?
Thanks in advance :)
This is for school.
If I understand you correctly, you have a String that you've split by delimiting on a space. You now want to search for a period in the resultant array of Strings.
for(String s : stringArray) {
if (s.contains(".")) {
//do something
}
}
Unfortunately, I'm not that clever with RegExp, but you could...
String s = "This.is.a.test";
while (s.contains(".")) {
s = s.replace(".", "");
}
System.out.println(s);
I'm sure there's a wonderful single line RegExp to do the same thing
Updated based on comments
Because String is not mutable, you will need to reassign it back to the original array
String[] apples = {"one", "two.", "three"};
for (int index = 0; index < apples.length; index++) {
String s = apples[index];
while (s.contains(".")) {
s = s.replace(".", "");
}
apples[index] = s;
}
for (String s : apples) {
System.out.println(s);
}