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Sound will not play in JAR file

I have a problem and I hope you can help me.
Some talk about what I am doing so you know what's going on: So at the moment I'm trying to program a litte piece of software which can play me some music files (mp3 files to be exact, so i'm using the jLayer API). I'm working with Netbeans and I have succesfully imported a music file in the project. If I build my program and open the resulting JAR file with an archive program, I can find my music file in there. My function which I'm using goes like this:
public static String play(String file) {
File test = new File(file);
try {
FileInputStream in = new FileInputStream(test);
Player pl = new Player(in);
pl.play();
return "success";
}
catch (Exception e) {
return e.toString();
}
}
As you can see I'm getting a String with the Path Name and refactor him so I can play the file. I'm calling the function with the following code (the music file is saved in the ressources package):
MP3.play(getClass().getResource("/ressources/angel.mp3").getPath())
So if I start the programm via Netbeans everything works perfectly fine. But if I create a JAR file and start the program nothing happens. The Exception getting is the following:
java.io.FileNotFoundException: file:\C:\Users\Raphael\Documents\NetBeansProjects\MP3\dist\MP3.jar!\ressources\angel.mp3
It says the File does not exist but if I check my JAR the file is there......
Another strange thing I found out is the following: If I use the following function to play the music file:
public static String play(InputStream test) {
try {
Player pl = new Player(test);
pl.play();
return "success";
}
catch (Exception e) {
return e.toString();
}
}
and call the function with the following argument:
MP3.play(getClass().getResourceAsStream("/ressources/angel.mp3"));
Everything works fine in both Netbeans and the final JAR. Can anybody explain me what I'm doing wrong and only the second function works in the JAR version?
It would be really nice if you could help me in this matter.
Greetings,
xXKnightRiderXx

I am assuming that you have 2 packages 1 is src where your .java files is located and other is resources where your sound files is located
So i suggest you to use
MP3.play(getClass().getResourceAsStream("/angel.mp3"));
Because GetResource() automatically finds the resource package

Run Existing Project That Uses some Static Files

I've created this class for access/create some files:
public static File getFile(String filePath) throws IOException {
File file = new File(filePath);
if (file.exists() && !file.isDirectory()) {
return file;
} else {
file.createNewFile();
byte[] dataToWrite = "some text".getBytes();
FileOutputStream out = new FileOutputStream(file);
out.write(dataToWrite);
out.close();
return file;
}
}
I'm calling the class this Way:
getFile("myfile.txt");
The application tries to access the file, if there isn't specific file, it'll be created.
The problem is when I run this code under non-admin account, I'll get IOException for permission issues. I know that the file will be created in eclipse folder. Also I shouldn't use static file path for my project, It should work dynamically. What should I do?

Unless this is a class assignment, I would not write low-level File code any more. Look at Apache Commons IO and/or Google Guava.
Also, without any more detailed path, the file is looked for (and created) in whatever location the app is run in. In Eclipse, that's the project's root folder by default, you can change it in the Launch Configuration. Launch Configurations are created automatically when you do Run as... on a project or file; they can be edited via the Run > Run Configurations... or Run > Debug Configurations... menu. Note that Run and Debug configurations are actually the same under the covers, the only difference is how Eclipse launches the JVM (either in debug mode or not).
You can also invoke and/or edit them via toolbar buttons:
See more info at http://help.eclipse.org/luna/index.jsp?topic=%2Forg.eclipse.jdt.doc.user%2Ftasks%2Ftasks-java-local-configuration.htm

Regarding the permission issue there is no going around that. You should capture the Exception and interact with the user telling that the user doesn't have permission and should/could provide another path.
You have to capture the path from the user maybe from the console, application parameters or another file.
One of the options is to capture the arguments when the application is called, for example:
public static void main (String args [])
{
//First argument is the file path
String path = args[0];
File theFile = null;
if(args[0] != null){
try{
File theFile = File getFile(path);
//do stuff with the file
}catch(IOException ioe){
//NManage the Exception here
}
}
}

File not found exception with external files

Hi i have made a small program that reads a config file. This file is stored outside the actual jar file. On the same level as the jarfile actually.
When i start my program from a commandline in the actual directory (ie. D:\test\java -jar name.jar argument0 argument1) in runs perfectly.
But when i try to run the program from another location then the actual directory i get the filenotfound exception (ie. D:\java -jar D:\test\name.jar argument0 argument1).
The basic functionality does seem to work, what am i doing wrong?
As requested a part of the code:
public LoadConfig() {
Properties properties = new Properties();
try {
// load the properties file
properties.load(new FileInputStream("ibantools.config.properties"));
} catch (IOException ex) {
ex.printStackTrace();
} // end catch
// get the actual values, if the file can't be read it will use the default values.
this.environment = properties.getProperty("application.environment","tst");
this.cbc = properties.getProperty("check.bankcode","true");
this.bankcodefile = properties.getProperty("check.bankcodefile","bankcodes.txt");
} // end loadconfig
The folder looks like this:
This works:
This doesn't:
The jar doesn't contain the text file.

When reading a File using the String/path constructors of File, FileInpustream, etc.. a relative path is derived from the working directory - the directory where you started your program.
When reading a file from a Jar, the file being external to the jar, you have at least two options :
Provide an absolute path: D:/blah/foo/bar
Make the directory where your file is located part of the class path and use this.getClass().getClassLoader().getResourceAsStream("myfile")
The latter is probably more appropriate for reading configuration files stored in a path relative to the location of your application.

There could be one more possibility:
If one part of your code is writing the file and another one is reading, then it is good to consider that the reader is reading before the writer finishes writing the file.
You can cross check this case by putting your code on debug mode. If it works fine there and gives you FileNotFoundException, then surely this could be the potential reason of this exception.
Now, how to resolve:
You can use retry mechanism something similar to below code block
if(!file..exists()){
Thread.sleep(200);
}
in your code and change the sleep value according to your needs.
Hope that helps.!!

The system cannot find the file specified in java

I am making a program that opens and reads a file.
This is my code:
import java.io.*;
public class FileRead{
public static void main(String[] args){
try{
File file = new File("hello.txt");
System.out.println(file.getCanonicalPath());
FileInputStream ft = new FileInputStream(file);
DataInputStream in = new DataInputStream(ft);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strline;
while((strline = br.readLine()) != null){
System.out.println(strline);
}
in.close();
}catch(Exception e){
System.err.println("Error: " + e.getMessage());
}
}
}
but when I run, I get this error:
C:\Users\User\Documents\Workspace\FileRead\hello.txt
Error: hello.txt (The system cannot find the file specified)
my FileRead.java and hello.txt where in the same directory that can be found in:
C:\Users\User\Documents\Workspace\FileRead
I'm wondering what I am doing wrong?

Try to list all files' names in the directory by calling:
File file = new File(".");
for(String fileNames : file.list()) System.out.println(fileNames);
and see if you will find your files in the list.

I have copied your code and it runs fine.
I suspect you are simply having some problem in the actual file name of hello.txt, or you are running in a wrong directory. Consider verifying by the method suggested by #Eng.Fouad

You need to give the absolute pathname to where the file exists.
File file = new File("C:\\Users\\User\\Documents\\Workspace\\FileRead\\hello.txt");

In your IDE right click on the file you want to read and choose "copy path"
then paste it into your code.
Note that windows hides the file extension so if you create a text file "myfile.txt" it might be actually saved as "myfile.txt.txt"

Generally, just stating the name of file inside the File constructor means that the file is located in the same directory as the java file. However, when using IDEs like NetBeans and Eclipse i.e. not the case you have to save the file in the project folder directory. So I think checking that will solve your problem.

How are you running the program?
It's not the java file that is being ran but rather the .class file that is created by compiling the java code. You will either need to specify the absolute path like user1420750 says or a relative path to your System.getProperty("user.dir") directory. This should be the working directory or the directory you ran the java command from.

First Create folder same as path which you Specified. after then create File
File dir = new File("C:\\USER\\Semple_file\\");
File file = new File("C:\\USER\\Semple_file\\abc.txt");
if(!file.exists())
{
dir.mkdir();
file.createNewFile();
System.out.println("File,Folder Created.);
}

When you run a jar, your Main class itself becomes args[0] and your filename comes immediately after.
I had the same issue: I could locate my file when provided the absolute path from eclipse (because I was referring to the file as args[0]). Yet when I run the same from jar, it was trying to locate my main class - which is when I got the idea that I should be reading my file from args[1].

Locating default root folder for an Eclipse project

I am reading a file as follows:
File imgLoc = new File("Player.gif");
BufferedImage image = null;
try {
image = ImageIO.read(imgLoc);
}
catch(Exception ex)
{
System.out.println("Image read error");
System.exit(1);
}
return image;
I do not know where to place my file to make the Eclipse IDE, and my project can detect it when I run my code.
Is there a better way of creating a BufferedImage from an image file stored in your project directory?

Take a look in the comments for Class.getResource and Class.getResourceAsStream. These are probably what you really want to use as they will work whether you are running from within the directory of an Eclipse project, or from a JAR file after you package everything up.
You use them along the lines of:
InputStream in = MyClass.class.getResourceAsStream("Player.gif");
In this case, Java would look for the file "Player.gif" next to the MyClass.class file. That is, if the full package/class name is "com.package.MyClass", then Java will look for a file in "[project]/bin/com/package/Player.gif". The comments for getResourceAsStream indicate that if you lead with a slash, i.e. "/Player.gif", then it'll look in the root (i.e. the "bin" directory).
Note that you can drop the file in the "src" directory and Eclipse will automatically copy it to the "bin" directory at build time.

In the run dialog you can choose the directory. The default is the project root.

From my experience it seems to be the containing projects directory by default, but there is a simple way to find out:
System.out.println(new File(".").getAbsolutePath());

Are you trying to write a plugin for Eclipse or is it a regular project?
In the latter case, wouldn't that depend on where the program is installed and executed in the end?
While trying it out and running it from Eclipse, I'd guess that it would find the file in the project workspace. You should be able to find that out by opening the properties dialog for the project, and looking under the Resource entry.
Also, you can add resources to a project by using the Import menu option.

The default root folder for any Eclipse project is also a relative path of that application.
Below are steps I used for my Eclipse 4.8.0 and Java 1.8 project.
I - Place your file you want to interact with along the BIN and SRS folders of your project and not in one of those folders.
II - Implement below code in your main() method.
public static void main(String [] args) throws IOException {
FileReader myFileReader;
BufferedReader myReaderHelper;
try {
String localDir = System.getProperty("user.dir");
myFileReader = new FileReader(localDir + "\\yourFile.fileExtension");
myReaderHelper = new BufferedReader(myFileReader);
if (myReaderHelper.readLine() != null) {
StringTokenizer myTokens =
new StringTokenizer((String)myReaderHelper.readLine(), "," );
System.out.println(myTokens.nextToken().toString()); // - reading first item
}
} catch (FileNotFoundException myFileException) {
myFileException.printStackTrace(); } } // End of main()
III - Implement a loop to iterate through elements of your file if your logic requires this.