Rxjava retryWhen called instantly - java

I'm having a very specific problem or misunderstanding with rxjava that someone hopefully can help with.
I'm running rxjava 2.1.5 and have the following code snippet:
public static void main(String[] args) {
final Observable<Object> observable = Observable.create(emitter -> {
// Code ...
});
observable.subscribeOn(Schedulers.io())
.retryWhen(error -> {
System.out.println("retryWhen");
return error.retry();
}).subscribe(next -> System.out.println("subscribeNext"),
error -> System.out.println("subscribeError"));
}
After executing this, the program prints:
retryWhen
Process finished with exit code 0
My question, and what I don't understand is: Why is retryWhen called instantly upon subscribing to an Observable? The observable does nothing.
What I want is retryWhen to be called when onError is called on the emitter. Am I misunderstanding how rx works?
Thanks!
Adding new snippet:
public static void main(String[] args) throws InterruptedException {
final Observable<Object> observable = Observable.create(emitter -> {
emitter.onNext("next");
emitter.onComplete();
});
final CountDownLatch latch = new CountDownLatch(1);
observable.subscribeOn(Schedulers.io())
.doOnError(error -> System.out.println("doOnError: " + error.getMessage()))
.retryWhen(error -> {
System.out.println("retryWhen: " + error.toString());
return error.retry();
}).subscribe(next -> System.out.println("subscribeNext"),
error -> System.out.println("subscribeError"),
() -> latch.countDown());
latch.await();
}
Emitter onNext and complete is called. DoOnError is never called. Output is:
retryWhen: io.reactivex.subjects.SerializedSubject#35fb3008
subscribeNext
Process finished with exit code 0

retryWhen calls the provided function when an Observer subscribes to it so you have a main sequence accompanied by a sequence that emits the Throwable the main sequence failed with. You should compose a logic onto the Observable you get in this Function so at the end, one Throwable will result in a value on the other end.
Observable.error(new IOException())
.retryWhen(e -> {
System.out.println("Setting up retryWhen");
int[] count = { 0 };
return e
.takeWhile(v -> ++count[0] < 3)
.doOnNext(v -> { System.out.println("Retrying"); });
})
.subscribe(System.out::println, Throwable::printStackTrace);
Since the e -> { } function body is executed for each individual subscriber, you can have a per subscriber state such as retry counter safely.
Using e -> e.retry() has no effect because the input error flow never gets its onError called.

One issue is, that you don't receive any more results because you'r creating a Thread using retryWhen() but your app seems to finish. To see that behaviour you may want to have a while loop to keep your app running.
That actually means that you need to add something like that to the end of your code:
while (true) {}
Another issue is that you dont emit any error in your sample. You need to emit at least one value to call onNext() else it wont repeat because it's waiting for it.
Here's a working example which a value, then it emits an error and repeat. you can use
.retryWhen(errors -> errors)
which is the same as
.retryWhen(errors -> errors.retry())
Working sample:
public static void main(String[] args) {
Observable
.create(e -> {
e.onNext("test");
e.onError(new Throwable("test"));
})
.retryWhen(errors -> errors.retry())
.subscribeOn(Schedulers.io())
.subscribe(
next -> System.out.println("subscribeNext"),
error -> System.out.println("subscribeError"),
() -> System.out.println("onCompleted")
);
while (true) {
}
}
The reason why you need to emit a result is, that Observable needs to emit a value, else it wait until it receives a new one.
This is because onError can only be called onec (in subscribe), but onNext emits 1..* values.
You can check this behaviour by using doOnError() which provides you the error everytime it retrys the Observable.
Observable
.create(e -> e.onError(new Exception("empty")))
.doOnError(e -> System.out.println("error received " + e))
.retryWhen(errors -> errors.retry())
.subscribeOn(Schedulers.io())
.subscribe(
nextOrSuccess -> System.out.println("nextOrSuccess " + nextOrSuccess),
error -> System.out.println("subscribeError")
);

Related

How to sequentially chain Vertx CompositeFuture using RXJava?

I need to chain sequentially in order Vertx CompositeFutures in a RxJava style for dependent CompositeFuture, avoiding callback hell.
The use case:
Each CompositeFuture.any/all do some async operations that return futures, lets say myList1, myList2, myList3, but I must wait for CompositeFuture.any(myList1) to complete and return success before doing CompositeFuture.any(myList2), and the same from myList2 to myList3. Naturally, the CompositeFuture itself does the jobs async, but just for its set of operations, since the next set have to be done just after the first set goes well.
Doing it in a "callback-hell style" would be:
public static void myFunc(Vertx vertx, Handler<AsyncResult<CompositeFuture>> asyncResultHandler) {
CompositeFuture.any(myList1 < Future >)
.onComplete(ar1 -> {
if (!ar1.succeeded()) {
asyncResultHandler.handle(ar1);
} else {
CompositeFuture.any(myList2 < Future >)
.onComplete(ar2 -> {
if (!ar2.succeeded()) {
asyncResultHandler.handle(ar2);
} else {
CompositeFuture.all(myList3 < Future >)
.onComplete(ar3 -> {
asyncResultHandler.handle(ar3);
.... <ARROW OF CLOSING BRACKETS> ...
}
Now I tried somenthing like this:
public static void myFunc(Vertx vertx, Handler<AsyncResult<CompositeFuture>> asyncResultHandler) {
Single
.just(CompositeFuture.any(myList1 < Future >))
.flatMap(previousFuture -> rxComposeAny(previousFuture, myList2 < Future >))
.flatMap(previousFuture -> rxComposeAll(previousFuture, myList3 < Future >))
.subscribe(SingleHelper.toObserver(asyncResultHandler));
}
public static Single<CompositeFuture> rxComposeAny(CompositeFuture previousResult, List<Future> myList) {
if (previousResult.failed()) return Single.just(previousResult); // See explanation bellow
CompositeFuture compositeFuture = CompositeFuture.any(myList);
return Single.just(compositeFuture);
}
public static Single<CompositeFuture> rxComposeAll(CompositeFuture previousResult, List<Future> myList) {
if (previousResult.failed()) return Single.just(previousResult);
CompositeFuture compositeFuture = CompositeFuture.any(myList);
return Single.just(compositeFuture);
}
}
Much more compact and clear. But, I am not succeeding in passing the previous fails to the asyncResultHandler.
My idea was as follows: The flatMap passes the previous CompositeFuture result and I want to check if it failed. The next rxComposeAny/All first checks to see if previous failed, if so, just returns the failed CompositeFuture and so on until it hits the handler in the subscriber. If the previous passed the test, I`m ok to continue passing the current result till the last successful CompositeFuture hits the handler.
The problem is that the check
if (previousResult.failed()) return Single.just(previousResult); // See explanation bellow
doesn't work, and all the CompositeFutures are processed, but not tested for successful completion, just the last one ends up being passed to the asyncResultHandler which will test for overall failure (but in the case of my code, it ends up cheking just the last one)
I`m using Vertx 3.9.0 and RxJava 2 Vertx API.
Disclosure: I have experience in Vertx, but I'm totally new in RxJava. So I appreciate any answer, from technical solutions to conceptual explanations.
Thank you.
EDIT (after excellent response of #homerman):
I need to have the exact same behavior of the "callback hell style" of sequentially dependent CompositeFutures, ie, the next must be called after onComplete and test for completed with failure or success. The complexity comes from the fact that:
I have to use vertx CompositeAll/Any methods, not zip. Zip provides behaviour similar to CompositeAll, but not CompositeAny.
CompositeAll/Any return the completed future just inside onComplete method. If I check it before as showed above, since it is async, I will get unresolved futures.
CompositeAll/Any if failed will not throw error, but failed future inside onComplete, so I cannot use onError from rxJava.
For example, I tried the following change in the rxComposite function:
public static Single<CompositeFuture> rxLoadVerticlesAny(CompositeFuture previousResult, Vertx vertx, String deploymentName,
List<Class<? extends Verticle>> verticles, JsonObject config) {
previousResult.onComplete(event -> {
if (event.failed()) {
return Single.just(previousResult);
} else {
CompositeFuture compositeFuture = CompositeFuture.any(VertxDeployHelper.deploy(vertx, verticles, config));
return Single.just(compositeFuture);
}
}
);
}
But naturally it does not compile, since lambda is void. How can I reproduce this exact same behavior it rxJava in Vertx?
Just to clarify something...
Each CompositeFuture.any/all do some async operations that return
futures, lets say myList1, myList2, myList3, but I must wait for
CompositeFuture.any(myList1) to complete and return success before
doing CompositeFuture.any(myList2), and the same from myList2 to
myList3.
You've offered CompositeFuture.any() and CompositeFuture.all() as points of reference, but the behavior you describe is consistent with all(), which is to say the resulting composite will yield success only if all its constituents do.
For the purpose of my answer, I'm assuming all() is the behavior you expect.
In RxJava, an unexpected error triggered by an exception will result in termination of the stream with the underlying exception being delivered to the observer via the onError() callback.
As a small demo, assume the following setup:
final Single<String> a1 = Single.just("Batch-A-Operation-1");
final Single<String> a2 = Single.just("Batch-A-Operation-2");
final Single<String> a3 = Single.just("Batch-A-Operation-3");
final Single<String> b1 = Single.just("Batch-B-Operation-1");
final Single<String> b2 = Single.just("Batch-B-Operation-2");
final Single<String> b3 = Single.just("Batch-B-Operation-3");
final Single<String> c1 = Single.just("Batch-C-Operation-1");
final Single<String> c2 = Single.just("Batch-C-Operation-2");
final Single<String> c3 = Single.just("Batch-C-Operation-3");
Each Single represents a discrete operation to be performed, and they are logically named according to some logical grouping (ie they are meant to be executed together). For example, "Batch-A" corresponds to your "myList1", "Batch-B" to your "myList2", ...
Assume the following stream:
Single
.zip(a1, a2, a3, (s, s2, s3) -> {
return "A's completed successfully";
})
.flatMap((Function<String, SingleSource<String>>) s -> {
throw new RuntimeException("B's failed");
})
.flatMap((Function<String, SingleSource<String>>) s -> {
return Single.zip(c1, c2, c3, (one, two, three) -> "C's completed successfully");
})
.subscribe(
s -> System.out.println("## onSuccess(" + s + ")"),
t -> System.out.println("## onError(" + t.getMessage() + ")")
);
(If you're not familiar, the zip() operator can be used to combine the results of all the sources supplied as input to emit another/new source).
In this stream, because the processing of the B's ends up throwing an exception:
the stream is terminated during the execution of the B's
the exception is reported to the observer (ie the onError() handler is triggered)
the C's are never processed
If what you want, however, is to decide for yourself whether or not to execute each branch, one approach you could take is to pass the results from previous operations down the stream using some sort of state holder, like so:
class State {
final String value;
final Throwable error;
State(String value, Throwable error) {
this.value = value;
this.error = error;
}
}
The stream could then be modified to conditionally execute different batches, for example:
Single
.zip(a1, a2, a3, (s, s2, s3) -> {
try {
// Execute the A's here...
return new State("A's completed successfully", null);
} catch(Throwable t) {
return new State(null, t);
}
})
.flatMap((Function<State, SingleSource<State>>) s -> {
if(s.error != null) {
// If an error occurred upstream, skip this batch...
return Single.just(s);
} else {
try {
// ...otherwise, execute the B's
return Single.just(new State("B's completed successfully", null));
} catch(Throwable t) {
return Single.just(new State(null, t));
}
}
})
.flatMap((Function<State, SingleSource<State>>) s -> {
if(s.error != null) {
// If an error occurred upstream, skip this batch...
return Single.just(s);
} else {
try {
// ...otherwise, execute the C's
return Single.just(new State("C's completed successfully", null));
} catch(Throwable t) {
return Single.just(new State(null, t));
}
}
})
.subscribe(
s -> {
if(s.error != null) {
System.out.println("## onSuccess with error: " + s.error.getMessage());
} else {
System.out.println("## onSuccess without error: " + s.value);
}
},
t -> System.out.println("## onError(" + t.getMessage() + ")")
);
After some research in Vertx source code, I found a public method that the rx version of CompositeFuture uses to convert 'traditional' CompositeFuture to its rx version. The method is io.vertx.reactivex.core.CompositeFuture.newInstance. With this workaround, I could use my traditional method and then convert it to use in the rx chain. This was what I wanted, because it was problematic to change the existing traditional method.
Here is the code with comments:
rxGetConfig(vertx)
.flatMap(config -> {
return rxComposeAny(vertx, config)
.flatMap(r -> rxComposeAny(vertx, config))
.flatMap(r -> rxComposeAll(vertx, config));
})
.subscribe(
compositeFuture -> {
compositeFuture.onSuccess(event -> startPromise.complete());
},
error -> startPromise.fail(error));
public static Single<JsonObject> rxGetConfig(Vertx vertx) {
ConfigRetrieverOptions enrichConfigRetrieverOptions = getEnrichConfigRetrieverOptions();
// the reason we create new vertx is just to get an instance that is rx
// so this ConfigRetriever is from io.vertx.reactivex.config, instead of normal io.vertx.config
ConfigRetriever configRetriever = ConfigRetriever.create(io.vertx.reactivex.core.Vertx.newInstance(vertx), enrichConfigRetrieverOptions);
return configRetriever.rxGetConfig();
}
public static Single<io.vertx.reactivex.core.CompositeFuture> rxComposeAny(Vertx vertx, JsonObject config) {
// instead of adapted all the parameters of myMethodsThatReturnsFutures to be rx compliant,
// we create it 'normally' and the converts bellow to rx CompositeFuture
CompositeFuture compositeFuture = CompositeFuture.any(myMethodsThatReturnsFutures(config));
return io.vertx.reactivex.core.CompositeFuture
.newInstance(compositeFuture)
.rxOnComplete();
}

Emit first element on another thread in RxJava

Good time of day everyone.
I wonder if it's possible to somehow emit element of a Flowable on a different thread than next ones.
For example I have a hot in-memory cache of database objects and I don't want to go to io thread to get elements from there.
Whant I want to do is basically:
if (cache.contains(e)) {
emiter.emit(cache.get(e));
} else {
Io.post(() -> emiter.emit(db.get(e)));
}
I need the same Flowable to use different threads.
I haven't found a way to do this so far.Is it possible?
Consider following method:
private Flowable<String> getDbOnlyIfNotCached(String key) {
if (cache.contains(key)) {
return Flowable.just(cache.get(key));
} else {
return Flowable.fromCallable(() -> db.get(key))
.subscribeOn(Schedulers.io());
}
}
If cache.contains(key) is true, everything will run in the calling thread. If the value is not cached, db.get(key) will be called using the io scheduler.
Update: Examples in Android
You can use above method like this:
getDbOnlyIfNotCached("hit")
.subscribe(s -> {
// If "hit" is cached, this will be executed in the current thread.
Log.d(TAG, Thread.currentThread().getName());
});
getDbOnlyIfNotCached("miss")
.subscribe(s -> {
// If "miss" is cached, this will be executed in another thread.
Log.d(TAG, Thread.currentThread().getName());
});
Or you can use it in a Flowable chain using flatMap.
Flowable.just("hello")
./* some other operators */
.flatMap(s -> getDbOnlyIfNotCached(s))
// If "hit" is cached, chain still runs in the current thread.
.subscribe(s -> {
Log.d(TAG, s + " " + Thread.currentThread().getName());
});
Flowable.just("miss")
./* some other operators */
.flatMap(s -> getDbOnlyIfNotCached(s))
// If "miss" is cached, chain switches to another thread.
.subscribe(s -> {
Log.d(TAG, Thread.currentThread().getName());
});
If you want to observe on the main thread, then specify observeOn at the end of the chain.
Flowable.just("miss")
./* some other operators */
.flatMap(s -> getDbOnlyIfNotCached(s))
// if "miss" is cached, chain switches to another thread.
.observeOn(AndroidSchedulers.mainThread())
// Now switched to the main thread.
.subscribe(s -> {
Log.d(TAG, Thread.currentThread().getName());
});

Polling server for answer, return exception if fails after n times

I'm trying to create a server call using RxJava2 library that will try to poll server for answer and if receives exception 3 times in a row to return that exception
I've set up a basic call that fetches the response from the server
final Observable<ResponseValue> responseValueObservable = Observable
.fromCallable((Callable) (c) -> return getDispatcher().performSubmit(submitValue);
}
});
return responseValueObservable
.retry(3)
.subscribeOn(Schedulers.io()
.onError((t) -> { log.error(t); Observable.timer(2, SECONDS);}
.retryUntil(() -> { return retryIsEnabled }
so getDispatcher().performSubmit(submitValue) returns either SubmitException or ResponseValue object.
I need the code to retry 3 times, pausing after each exception for 2 seconds and return either ResponseValue or the last SubmitException
So after reading Dan Lew's Blog from previous answer I was able to put together this piece of code which does exactly what I wanted to. retryWhen() on re-subscribes automatically after waiting 2 seconds. With the first successful reply from server it stops.
Observable.fromCallable((d::performSubmit))
.subscribeOn(Schedulers.io())
.doOnSubscribe(subscription -> System.out.println("Subscribing"))
.retryWhen(errors -> {
AtomicInteger counter = new AtomicInteger();
return errors
.takeWhile(e -> counter.incrementAndGet() < 3)
.flatMap(e -> {
System.out.println("delay retry by 2 second(s)");
return Observable.timer(2, TimeUnit.SECONDS);
});
}).blockingSubscribe(res -> result = Optional.of(res), throwable -> t = Optional.of((Exception) throwable));
Use the retryWhen() operator to customize the response to errors. From the excellent overview at Dan Lew's Blog:
responseValueObservable
.retryWhen( errorObservable -> errorObservable
.zipWith(Observable.range(1, 3), (n, i) -> i)
.flatMap(retryCount -> Observable.timer(2, TimeUnit.SECONDS)))
...

Keep interval Observable running in Java

I am new to threading in Java and was wondering how I can keep the following Observable running,
private void init() {
System.out.println("Running...");
Observable o = Observable.interval(5, TimeUnit.SECONDS)
.flatMap(o -> serverService.listServers("all"))
.retryWhen(o -> o.flatMap(s -> Observable.timer(30, TimeUnit.SECONDS)))
.subscribe(serverModels -> System.out.println("onNext"),
e -> System.out.println("ERROR " + e),
() -> System.out.println("Completed"));
}
If I call this method from main(), the process exits immediately. How do I refrain from a process exit?
Sleeping can cause bugs. Instead checkout the blockingSubscribe operator.

RxJava debounce

I'm trying to debounce a 100ms producer within a 1000ms window.
I would expect to see the subscription being updated every 1 second with the last value emitted that period, however I am not getting anything.
What am I missing here?
public static void main(String[] args) throws InterruptedException {
Observable
.interval(100, TimeUnit.MILLISECONDS)
.debounce(1000, TimeUnit.MILLISECONDS)
.subscribe(
update -> System.out.println(new Date().toString() + " " + update),
error -> System.out.println("ERROR")
);
Thread.sleep(20000);
}
Found it. I was trying to find in RXJava an operator equivalent to RxJS's debounceTime(), which happen to be sample() or throttleLast().

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