This is my web.xml.
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>NewsPortal</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>javax.ws.rs.core.Application</servlet-name>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.newsportal</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>javax.ws.rs.core.Application</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
There may be something wrong with web.xml but I am not sure.
Here is my web service .
package com.newsportal;
import javax.ws.rs.Consumes;
import javax.ws.rs.FormParam;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import com.newsportal.utility.ErrorReporting;
#Path("/Authentication")
public class AuthenticationResource {
#POST
#Consumes(MediaType.APPLICATION_FORM_URLENCODED)
#Produces(MediaType.APPLICATION_JSON)
#Path("/login")
public Response login(#FormParam("emailOrPhone") String emailOrPhone,#FormParam("password") String password){
String response ="";
try{
}catch(Exception ex){
ErrorReporting.webServiceError(ex);
}
return Response.ok(response)
.header("Access-Control-Allow-Origin", "*")
.build();
}
}
This is JAX-RS i think here most of the code looks fine .
Here is my jquery I am trying to invoke this login method
var Index = function() {
var handleIndexLoad = function() {
// no authentication at load
}
var handlelogin = function() {
var emailOrPhone='admin#nextolive.com';
var password ='12345';
$.ajax({
method : "POST",
url : "Authentication/login/",
data :'emailOrPhone='+ emailOrPhone +'&password='+password,
}).done(function(response) {
console.log(response);
});
}
return {
// main function to initiate the module
init : function() {
handleIndexLoad();
handlelogin();
}
};
}();
This is index.js file . I think here also things are fine .
To be honest I am new to Java so , i am not really sure if I am following
the right pattern .
Please tell me what i need to do fix it .
Related
My pom is as follow:
<modelVersion>4.0.0</modelVersion>
<groupId>net.codejava</groupId>
<artifactId>EhrmsWs</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>
and in eclipse,web project settings, context root is
EhrmsWs
but when I add this webapp to wildfly runtime, there is a name
MyWebsite-0.0.1-SNAPSHOT.war
where does this name come from and what does it represents?
my context root is still
http://127.0.0.1:8080/EhrmsWs
?
the application is a simple web service example, I access using postman, request is
http://127.0.0.1:8080/EhrmsWs/rest/products/
but it returns 404 - Not Found, why?
the web.xml setting is as follow:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>EhrmsWs</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>net.codejava.ws</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
the service class is as follow:
package net.codejava.ws;
import java.net.URI;
import java.net.URISyntaxException;
import java.util.List;
import javax.ws.rs.Consumes;
import javax.ws.rs.DELETE;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.PUT;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
#Path("/products")
public class ProductResource {
private ProductDAO dao = ProductDAO.getInstance();
#GET
#Produces(MediaType.APPLICATION_JSON)
public Response list() {
List<Product> listProducts = dao.listAll();
if (listProducts.isEmpty()) {
return Response.noContent().build();
}
return Response.ok(listProducts).build();
}
//.....
}
[Edit on 20220816]
Now the request
http://localhost:8080/EhrmsWs/rest/products
can pass to resource ProductResource.java, but I write a similar resource TrainingHist.java with similar method as follow:
package net.codejava.ws;
import java.util.List;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
#Path("/trainingHist")
public class TrainingHistResource {
private TrainingHistDAO dao = TrainingHistDAO.getInstance();
#GET
#Produces(MediaType.APPLICATION_JSON)
public Response list() {
List<TrainingHist> listTrainingHists = dao.listAll();
if (listTrainingHists.isEmpty()) {
return Response.noContent().build();
}
return Response.ok(listTrainingHists).build();
}
}
then I send the get request
http://localhost:8080/EhrmsWs/rest/trainingHist
but it returns 404 not found, why?
Hi I am trying to run my controller java but I am getting error of There are no servelet mappings specified in web.xml for controller servelet
I just wanted to ask how can to do servelet mapping I will really appreciate any advice thank you
here is my controller code
package com.kb.model;
import com.kb.model.tbl_batch;
import java.io.IOException;
import java.util.ArrayList;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import javax.faces.bean.ManagedBean;
#ManagedBean
public class Controller extends HttpServlet {
static final long serialVersionUID = 1L;
#Override
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
HttpSession httpSession = request.getSession();
tbl_dao dao = new tbl_dao();
ArrayList<tbl_batch> list = dao.getData();
httpSession.setAttribute("studentDetails", list);
RequestDispatcher dispatcher = request
.getRequestDispatcher("500kusers_hibernate.jsp");
dispatcher.forward(request, response);
}
}
this my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com
/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Pager Tag</display-name>
<welcome-file-list>
<welcome-file>500kusers_hibernate.jsp</welcome-file>
</welcome-file-list>
<servlet>
<display-name>Controller</display-name>
<servlet-name>Controller</servlet-name>
<servlet-class>
com.kb.model.Controller
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/Controller</url-pattern>
</servlet-mapping>
I have an App Engine backend with Google Cloud Messaging setup in my local Android Studio.
It has the original endpoints as follows:
Messaging Endpoint
Registration Endpoint
I have created a new Java file and added a new class called UserRegistration as follows:
package com.xxxxx.gcmbackend;
import com.google.api.server.spi.config.Api;
import com.google.api.server.spi.config.ApiMethod;
import com.google.api.server.spi.config.ApiNamespace;
import com.google.api.server.spi.response.CollectionResponse;
import java.util.List;
import java.util.logging.Logger;
import javax.inject.Named;
import static com.xxxxxx.gcmbackend.OfyService.ofy;
#Api(
name = "register",
version = "v1",
namespace = #ApiNamespace(
ownerDomain = "gcmbackend.xxxxx.com",
ownerName = "gcmbackend.xxxxx.com",
packagePath=""
)
)
public class UserRegistrationEndpoint {
private static final Logger log = Logger.getLogger(RegistrationEndpoint.class.getName());
#ApiMethod(name = "register")
public void registerDevice(#Named("regId") String regId, #Named("username") String username, #Named("phone") String phone) {
if(findRecord(regId) != null) {
log.info("Device " + regId + " already registered, skipping register");
return;
}
RegistrationRecord record = new RegistrationRecord();
record.setRegId(regId);
record.setUsername(username);
record.setPhone(phone);
ofy().save().entity(record).now();
}
private RegistrationRecord findRecord(String regId) {
return ofy().load().type(RegistrationRecord.class).filter("regId", regId).first().now();
}
}
However, when deployed, I don't see this endpoint in the API explorer. How do I add a new working endpoint to an App Engine backend with Google Cloud Messaging?
Going through existing code structure, I found out that every new API must be added to the web.xml file. I added my new endpoint as:
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" version="2.5">
<filter>
<filter-name>ObjectifyFilter</filter-name>
<filter-class>com.googlecode.objectify.ObjectifyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>ObjectifyFilter</filter-name>
<url-pattern></url-pattern>
</filter-mapping>
<servlet>
<servlet-name>SystemServiceServlet</servlet-name>
<servlet-class>com.google.api.server.spi.SystemServiceServlet</servlet-class>
<init-param>
<param-name>services</param-name>
<param-value>com.xxxxx.gcmbackend.RegistrationEndpoint, com.xxxxx.gcmbackend.MessagingEndpoint, com.xxxxx.gcmbackend.UserRegistrationEndpoint</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/spi/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
I am new to developing REST API with Java. I made a very simple one using the mkyong tutorials, where it only says "hello". I am using Apache Tomcat.
Now I am trying to develop a one where it will return the JSON objects. I am attempting the example here - http://www.mkyong.com/webservices/jax-rs/json-example-with-jersey-jackson/. Some of the code are changed (ex: package name).Below is my code.
Track.java
package com.tutorialspoint;
/**
*
* #author Yohan
*/
public class Track {
String title;
String singer;
public String getTitle() {
return title;
}
public void setTitle(String title) {
this.title = title;
}
public String getSinger() {
return singer;
}
public void setSinger(String singer) {
this.singer = singer;
}
#Override
public String toString() {
return "Track [title=" + title + ", singer=" + singer + "]";
}
}
JsonService.java
package com.tutorialspoint;
import javax.ws.rs.Consumes;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
/**
*
* #author Yohan
*/
#Path("/json/metallica")
public class JsonService {
#GET
#Path("/get")
#Produces(MediaType.APPLICATION_JSON)
public Track getTrackInJSON() {
Track track = new Track();
track.setTitle("Enter Sandman");
track.setSinger("Metallica");
return track;
}
#POST
#Path("/post")
#Consumes(MediaType.APPLICATION_JSON)
public Response createTrackInJSON(Track track) {
String result = "Track saved : " + track;
return Response.status(201).entity(result).build();
}
}
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>Restful Web Application</display-name>
<servlet>
<servlet-name>NewServlet</servlet-name>
<servlet-class>NewServlet</servlet-class>
</servlet>
<servlet>
<servlet-name>Jersey RESTful Application</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.tutorialspoint</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>NewServlet</servlet-name>
<url-pattern>/NewServlet</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Jersey RESTful Application</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>
My application is not a marven project. So the added libraries are below.
I tested the application with the below URL.
http://localhost:8080/RESTFUL_API_SAMPLE/rest/json/metallica/get
All I got is the below page
Any idea about why I am not getting the expected result?
Currently you don't have any JSON/POJO support. The jersey-json jar and the POJOMappingFeature configuration in your web.xml is for Jersey 1.x, which won't work for Jersey 2.x. For all the jars you need for Jersey 2.x support, see this answer.
This is my ajax code, here I send json object as Request payload.
$(document).ready(function() {
var firstName = $("#firstName").val();
var lastName = $("#lastName").val();
var address = $("#address").val();
$("#studentInsert").click(function() {
student.presonal_details = {
firstName: $("#firstName").val(),
lastName: $("#lastName").val(),
address: $("#address").val(),
}
$.ajax({
type: "post",
url: "http://localhost:8080/RestJersey/rest/jsonRequestReceiver/saveStudentDeta il",
contentType: "application/json; charset=utf-8",
data: JSON.stringify(student.presonal_details),
success: function(data) {
console.log(data);
}
});
});
});
Java Code:
I want to know how do I write REST service API code for receiving the json Object.
#POST
#Path("/saveStudentDetail")
#Consumes(MediaType.APPLICATION_JSON)
public void saveStudentDetail() {
}
This is my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID"
version="3.0">
<display-name>RestJersey</display-name>
<welcome-file-list>
<!-- <welcome-file>index1.html</welcome-file> -->
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>jersey-servlet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>jersey-servlet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
And may POJO class:
package com.rest.test.to;
import javax.xml.bind.annotation.XmlRootElement;
#XmlRootElement
public class StudentDetailsTO {
private String firstName;
private String lastName;
private String address;
// getters and setters
}
Use below code
#POST
#Path("/saveStudentDetail")
#Consumes(MediaType.APPLICATION_JSON)
public void saveStudentDetail(StudentDetailsTO student){
String fname= student.getFirstName();
String lname= student.getLastName();
String address= student.getAddress();
}